Class 10: Maths Chapter 11 solutions. Complete Class 10 Maths Chapter 11 Notes.
RS Aggarwal Solutions for Class 10 Maths Chapter 11–T Ratios Of Some Particular Angles
RS Aggarwal 10th Maths Chapter 11, Class 10 Maths Chapter 11 solutions
Question 1.
Solution:
On substituting the value of various T-ratios, we get
sin60° cos30° + cos60° sin30°
Question 2.
Solution:
On substituting the value of various T-ratios, we get
cos60° cos30° – sin60° sin30°
Question 3.
Solution:
On substituting the value of various Tratios, we get
cos45° cos30° + sin45° sin30°
Question 4.
Solution:
On substituting the value of various Tratios, we get
Question 5.
Solution:
Question 6.
Solution:
On substituting the value of various Tratios, we get
Question 7.
Solution:
On substituting the value of various Tratios, we get
Question 8.
Solution:
On substituting the value of various Tratios, we get
Question 9.
Solution:
On substituting the value of various Tratios, we get
Question 10.
Solution:
(i)
(ii)
Question 11.
Solution:
(i)
R.H.S. = L.H.S.
Hence, sin60° cos30° – cos60° sin30° = sin30°
(ii)
L.H.S. = cos60° cos30° + sin60° sin30°
(iii)
R.H.S. = L.H.S.
Hence,2sin30° cos30° = sin60°
(iv)
R.H.S. = sin90° = 1
R.H.S. = L.H.S.
Hence, 2 sin 45° cos45° = sin90°
Question 12.
Solution:
A = 45° 2 A = 90°
(i)Sin 2A = sin90° = 1
(ii) cos2A = cos90° = 0
Question 13.
Solution:
A = 30 ⇒ 2A = 60
(i)
(ii)
(iii)
Question 14.
Solution:
(i)
(ii)
Question 15.
Solution:
(i)
(ii)
(iii)
Question 16.
Solution:
Hence, (A + B) = 45
Question 17.
Solution:
Putting A = 30° 2 A = 60°
Question 18.
Solution:
Putting A = 30° 2 A = 60°
Question 19.
Solution:
Putting A = 30° 2 A = 60°
Question 20.
Solution:
From right angled ∆ABC,
Question 21.
Solution:
From right angled ∆ABC,
Question 22.
Solution:
From right angled ∆ABC,
(i)
(ii)
By Pythagoras theorem
Hence, (i) BC = 3cm and (ii) AB = 3cm.
Question 23.
Solution:
sin (A + B)= 1 sin (A + B) = sin90°
Adding (1) and (2), we get
2A = 90° ⇒ A = 45°
Putting A = 45° in (1) we get
45° + B = 90° ⇒ B = 45°
Hence, A = 45° and B = 45°.
Question 24.
Solution:
Solving (1) and (2), we get
2A = 90° ⇒ A = 45°
Putting A = 45° in (1), we get
45° – B = 30° ⇒ B = 45 – 30° = 15°
Hence, A = 45°, B = 15°.
Question 25.
Solution:
Solving (1) and (2), we get
2A = 90° ⇒ A = 45°
Putting A = 45° in (1), we get
45° – B = 30° ⇒ B = 45° – 30° = 15°
A = 45°, B = 15°
Question 26.
Solution:
Question 27.
Solution:
RS Aggarwal Solutions for Class 10 Maths Chapter 11: Download PDF
RS Aggarwal Solutions for Class 10 Maths Chapter 11–T Ratios Of Some Particular Angles
Chapterwise RS Aggarwal Solutions for Class 10 Maths :
- Chapter 1–Real Numbers
- Chapter 2–Polynomials
- Chapter 3–Linear Equations In Two Variables
- Chapter 4–Quadratic Equations
- Chapter 5–Arithmetic Progression
- Chapter 6–Coordinate Geometry
- Chapter 7–Triangles
- Chapter 8–Circles
- Chapter 9–Constructions
- Chapter 10–Trigonometric Ratios
- Chapter 11–T Ratios Of Some Particular Angles
- Chapter 12–Trigonometric Ratios Of Some Complementary Angles
- Chapter 13–Trigonometric Identities
- Chapter 14–Height and Distance
- Chapter 15–Perimeter and Areas of Plane Figures
- Chapter 16–Areas of Circle, Sector and Segment
- Chapter 17–Volume and Surface Areas of Solids
- Chapter 18–Mean, Median, Mode of Grouped Data
- Chapter 19–Probability
About RS Aggarwal Class 10 Book
Investing in an R.S. Aggarwal book will never be of waste since you can use the book to prepare for various competitive exams as well. RS Aggarwal is one of the most prominent books with an endless number of problems. R.S. Aggarwal's book very neatly explains every derivation, formula, and question in a very consolidated manner. It has tonnes of examples, practice questions, and solutions even for the NCERT questions.
He was born on January 2, 1946 in a village of Delhi. He graduated from Kirori Mal College, University of Delhi. After completing his M.Sc. in Mathematics in 1969, he joined N.A.S. College, Meerut, as a lecturer. In 1976, he was awarded a fellowship for 3 years and joined the University of Delhi for his Ph.D. Thereafter, he was promoted as a reader in N.A.S. College, Meerut. In 1999, he joined M.M.H. College, Ghaziabad, as a reader and took voluntary retirement in 2003. He has authored more than 75 titles ranging from Nursery to M. Sc. He has also written books for competitive examinations right from the clerical grade to the I.A.S. level.
FAQs
Why must I refer to the RS Aggarwal textbook?
RS Aggarwal is one of the most important reference books for high school grades and is recommended to every high school student. The book covers every single topic in detail. It goes in-depth and covers every single aspect of all the mathematics topics and covers both theory and problem-solving. The book is true of great help for every high school student. Solving a majority of the questions from the book can help a lot in understanding topics in detail and in a manner that is very simple to understand. Hence, as a high school student, you must definitely dwell your hands on RS Aggarwal!
Why should you refer to RS Aggarwal textbook solutions on Indcareer?
RS Aggarwal is a book that contains a few of the hardest questions of high school mathematics. Solving them and teaching students how to solve questions of such high difficulty is not the job of any neophyte. For solving such difficult questions and more importantly, teaching the problem-solving methodology to students, an expert teacher is mandatory!
Does IndCareer cover RS Aggarwal Textbook solutions for Class 6-12?
RS Aggarwal is available for grades 6 to 12 and hence our expert teachers have formulated detailed solutions for all the questions of each edition of the textbook. On our website, you'll be able to find solutions to the RS Aggarwal textbook right from Class 6 to Class 12. You can head to the website and download these solutions for free. All the solutions are available in PDF format and are free to download!