Class 6: Maths Chapter 30 solutions. Complete Class 6 Maths Chapter 30 Notes.
Contents
Selina Class 6 ICSE Solutions Mathematics : Chapter 30- Revision Exercise Symmetry
Selina 6th Maths Chapter 30, Class 6 Maths Chapter 30 solutions
Exercise 30
1. State, whether true or false:
(i) The letter B has one line of symmetry
(ii) The letter F has no line of symmetry
(iii) The letter O has only two lines of symmetry
(iv) The figure
has no line of symmetry
(v) The letter N has one line of symmetry
Solution:
(i) The letter B has one line of symmetry. Hence, the given statement is true
(ii) The letter F has no line of symmetry. Hence, the given statement is true
(iii) The letter O has many line of symmetry. Hence, the given statement is false
(iv) The figure has two line of symmetry. Hence, the given statement is false
(v) The letter N has no line of symmetry. Hence, the given statement is false
2. Construct a triangle ABC, in which AB = AC = 5 cm and BC = 6 cm. Draw all its lines of Symmetry.
Solution:
Steps of Construction:
(i) Draw a line BC of length 6 cm

(ii) With the help of compass, taking B as centre and radius 5 cm, draw an arc
(iii) Now, taking C as centre and radius 5 cm draw another arc which cuts the previous arc at point A
(iv) Join AB and AC
(v) The required triangle ABC is obtained. Line of symmetry is shown in above figure
3. Examine each of the following figures carefully, draw line(s) of symmetry in which ever figure possible:


Solution:
(i) There is no line of symmetry in the given figure
(ii) The line of symmetry for isosceles right angled triangle is shown in figure below

(iii) The line of symmetry for isosceles triangle is shown in below figure

(iv) A quadrilateral with only one line of symmetry is shown in below figure

(v) A line of symmetry is shown in below figure

4. Construct a triangle XYZ, in which XY = YZ = ZX = 4.5 cm. Draw all its lines of symmetry.
Solution:
Steps of Construction:
(i) Draw a line XY of length 4.5 cm

(ii) Taking X as centre and radius 4.5 cm draw an arc with the help of compass at point Z.
(iii) Taking Y as centre and radius 4.5 cm draw another arc which cuts the previous arc at point Z.
(iv) Now, join XZ and YZ
(v) The required triangle XYZ is obtained and lines of symmetry is shown in above figure
5. Construct a triangle ABC, in which AB = BC = 4 cm and ∠ABC = 600. Draw all its lines of symmetry.
Solution:
Steps of Construction:
(i) Draw a line segment AB = 4 cm

(ii) Taking B as centre, draw an angle 600 with the help of compass
(iii) Again taking B as centre and radius 4 cm draw an arc at point C such that BC = 4 cm
(iv) Now, join AC
(v) △ABC formed is the required triangle and line of symmetry is shown in centre of the figure
6. Draw the line(s) of symmetry for each figure drawn below:

Solution:

7. In each of the following case, construct a point that is symmetric to the given point P with respect to the given line AB.

Solution:

(i) Draw PQ perpendicular to AB from P and produce PO to Q such that OQ = OP
Hence, point Q is symmetric to the given point P with respect to the given line AB.
(ii) Draw PQ perpendicular to AB from P and produce PQ to Q such that OQ = PO
Hence, point Q is symmetric to the given point P with respect to the given line AB
(iii) Draw PQ perpendicular to AB from P and produce PO to Q such that OQ = OP
Hence, point Q is symmetric to the given point P with respect to the given line AB
8. Mark two points A and B 5.5 cm apart. Draw a line PQ so that A and B are symmetric with respect to the line PQ. Give a special name to line PQ.
Solution:
Steps of Construction:

(i) Take point A and B as 5.5 cm apart
(ii) Draw perpendicular bisect of the line segment AB
(iii) Now, the perpendicular bisector PQ is the required line of symmetry with respect to points A and B
(iv) Hence, PQ is the perpendicular bisector of AB
9. For each letter of the English alphabet, draw the maximum possible number of lines of symmetry.
Solution:
The alphabets which do not have any lines of symmetry are F, G, J, L, N, P, Q, R, S and Z.
Alphabets which have lines of symmetry are as follows:

10. Draw all the possible lines of symmetry for each figure given below:

Solution:
The lines of symmetry for each figure are as follows:

(i) A parallelogram has no line of symmetry
(ii) A rectangle has two lines of symmetry
(iii) A square has four lines of symmetry
(iv) A semicircle has one line of symmetry
(v) A quadrant has one line of symmetry
11. For each shaded portion given below, draw all the possible lines of symmetry:
Solution:

(i) In the given figure, a minor segment has one line of symmetry
(ii) In the given figure, a major segment has one line of symmetry
(iii) In the given figure, a quadrant has one line of symmetry
(iv) The given figure has one line of symmetry
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Selina Class 6 ICSE Solutions Mathematics : Chapter 30- Revision Exercise Symmetry
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Chapterwise Selina Publishers ICSE Solutions for Class 6 Mathematics :
- Chapter 1- Number System
- Chapter 2- Estimation
- Chapter 3- Numbers In Indian And International Systems
- Chapter 4- Place Value
- Chapter 5- Natural Numbers And Whole Numbers
- Chapter 6- Negative Numbers And Integers
- Chapter 7- Number Line
- Chapter 8- HCF And LCM
- Chapter 9- Playing With Numbers
- Chapter 10- Sets
- Chapter 11- Ratio
- Chapter 12- Proportion
- Chapter 13- Unitary Method
- Chapter 14- Fractions
- Chapter 15- Decimal Fractions
- Chapter 16- Percent (Percentage)
- Chapter 17- Idea of Speed, Distance and Time
- Chapter 18- Fundamental Concepts
- Chapter 19- Fundamental Operations
- Chapter 20- Substitution
- Chapter 21- Framing Algebraic Expressions (Including Evaluation)
- Chapter 22- Simple (Linear) Equations
- Chapter 23- Fundamental Concepts
- Chapter 24- Angles
- Chapter 25- Properties of Angles and Lines
- Chapter 26- Triangles
- Chapter 27- Quadrilateral
- Chapter 28- Polygons
- Chapter 29- The Circle
- Chapter 30- Revision Exercise Symmetry
- Chapter 31- Recognition of Solids
- Chapter 32- Perimeter and Area of Plane Figures
- Chapter 33- Data Handling
- Chapter 34- Mean and Median
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