Class 6: Maths Chapter 18 solutions. Complete Class 6 Maths Chapter 18 Notes.
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Selina Class 6 ICSE Solutions Mathematics : Chapter 18- Fundamental Concepts
Selina 6th Maths Chapter 18, Class 6 Maths Chapter 18 solutions
Exercise 18(A)
1. Express each of the following statements in algebraic form:
(i) The sum of 8 and x is equal to y.
(ii) x decreased by 5 is equal to y.
(iii) The sum of 2 and x is greater than y.
(iv) The sum of x and y is less than 24.
(v) 15 multiplied by m gives 3n.
(vi) Product of 8 and y is equal to 3x.
(vii) 30 divided by b is equal to p.
(viii) z decreased by 3x is equal to y.
(ix) 12 times of x is equal to 5z.
(x) 12 times of x is greater than 5z.
(xi) 12 times of x is less than 5z.
(xii) 3z subtracted from 45 is equal to y.
(xiii) 8x divided by y is equal to 2z.
(xiv) 7y subtracted from 5x gives 8z.
(xv) 7y decreased by 5x gives 8z.
Solution:
(i) The sum of 8 and x is equal to y in algebraic form is written as,
8 + x = y
(ii) x decreased by 5 is equal to y in algebraic form is written as,
x – 5 = y
(iii) The sum of 2 and x is greater than y in algebraic form is written as,
2 + x > y
(iv) The sum of x and y is less than 24 in algebraic form is written as,
x + y < 24
(v) 15 multiplied by m gives 3n in algebraic form is written as,
15 × m = 3n
(vi) Product of 8 and y is equal to 3x in algebraic form is written as,
8 × y = 3x
(vii) 30 divided by b is equal to p in algebraic form is written as,
30 ÷ b = p
(viii) z decreased by 3x is equal to y in algebraic form is written as,
z – 3x = y
(ix) 12 times of x is equal to 5z in algebraic form is written as,
12 × x = 5z
(x) 12 times of x is greater than 5z in algebraic form is written as,
12 × x > 5z
(xi) 12 times of x is less than 5z in algebraic form is written as,
12 × x < 5z
(xii) 3z subtracted from 45 is equal to y in algebraic form is written as,
45 – 3z = y
(xiii) 8x divided by y is equal to 2z in algebraic form is written as,
8x ÷ y = 2z
(xiv) 7y subtracted from 5x gives 8z in algebraic form is written as,
5x – 7y = 8z
(xv) 7y decreased by 5x gives 8z in algebraic form is written as,
7y – 5x = 8z
2. For each of the following algebraic expressions, write a suitable statement in words:
(i) 3x + 8 = 15
(ii) 7 – y > x
(iii) 2y – x < 12
(iv) 5 ÷ z = 5
(v) a + 2b > 18
(vi) 2x – 3y = 16
(vii) 3a – 4b > 14
(viii) b + 7a < 21
(ix) (16 + 2a) – x > 25
(x) (3x + 12) – y < 3a
Solution:
(i) The algebraic expression 3x + 8 = 15 in words is expressed as,
3x plus 8 is equal to 15
(ii) The algebraic expression 7 – y > x in words is expressed as,
7 decreased by y is greater than x
(iii) The algebraic expression 2y – x < 12 in words is expressed as,
2y decreased by x is less than 12
(iv) The algebraic expression 5 ÷ z = 5 in words is expressed as,
5 divided by z is equal to 5
(v) The algebraic expression a + 2b > 18 in words is expressed as,
a increased by 2b is greater than 18
(vi) The algebraic expression 2x – 3y = 16 in words is written as,
2x decreased by 3y is equal to 16
(vii) The algebraic expression 3a – 4b > 14 in words is written as,
3a decreased by 4b is greater than 14
(viii) The algebraic expression b + 7a < 21 in words is written as,
b increased by 7a is less than 21
(ix) The algebraic expression (16 + 2a) – x > 25 in words is written as,
The sum of 16 and 2a decreased by x is greater than 25
(x) The algebraic expression (3x + 12) – y < 3a in words is written as,
The sum of 3x and 12 decreased by y is less than 3a
Exercise 18(B)
1. Separate the constants and the variables from each of the following:
6, 4y, -3x, 5 / 4, (4 / 5)xy, az, 7p, 0, 9x / y, 3 / 4x, – xz / 3y
Solution:
6, 5 / 4and 0 are the constants
4y, -3x, (4 / 5)xy, az, 7p, 9x / y, 3 / 4x and – xz / 3y are the variables
2. Group the like terms together:
(i) 4x, -3y, -x, (2 / 3)x, (4 / 5)y and y.
(ii) (2 / 3) xy, -4yx, 2yz, (-2 / 3)yz, zy / 3 and yx.
(iii) –ab2, b2a2, 7b2a, -3a2b2 and 2ab2
(iv) 5ax, -5by, by / 7, 7xa and 2ax / 3
Solution:
(i) 4x, -3y, -x, (2 / 3)x, (4 / 5)y and y.
Here, the like term are as follows
4x, -x, (2 / 3)x and -3y, (4 / 5)y, y
(ii) (2 / 3) xy, -4yx, 2yz, (-2 / 3)yz, zy / 3 and yx.
Here, the like terms are as follows
(2 / 3) xy, -4yx, yx and 2yz, (-2 / 3)yz, zy / 3
(iii) –ab2, b2a2, 7b2a, -3a2b2 and 2ab2
Here, the like terms are as follows
-ab2, 7b2a, 2ab2 and b2a2, -3a2b2
(iv) 5ax, -5by, by / 7, 7xa and 2ax / 3
Here, the like terms are as follows
5ax, 7xa, 2ax / 3 and – 5by, by / 7
3.State whether true or false:
(i) 16 is a constant and y is a variable but 16y is variable
(ii) 5x has two terms 5 and x
(iii) The expression 5 + x has two terms 5 and x
(iv) The expression 2x2 + x is a trinomial
(v) ax2 + bx + c is a trinomial
(vi) 8 × ab is a binomial
(vii) 8 + ab is a binomial
(viii) x3 – 5xy + 6x + 7 is a polynomial
(ix) x3 – 5xy + 6x + 7 is a multinomial
(x) The coefficient of x in 5x is 5x
(xi) The coefficient of ab in –ab is -1
(xii) The coefficient of y in -3xy is -3
Solution:
(i) 16 is a constant and y is a variable but 16y is variable
The given statement is true
(ii) 5x has two terms 5 and x
The given statement is false
(iii) The expression 5 + x has two terms 5 and x
The given statement is true
(iv) The expression 2x2 + x is a trinomial
The given statement is false
(v) ax2 + bx + c is a trinomial
The given statement is true
(vi) 8 × ab is a binomial
The given statement is false
(vii) 8 + ab is a binomial
The given statement is true
(viii) x3 – 5xy + 6x + 7 is a polynomial
The given statement is true
(ix) x3 – 5xy + 6x + 7 is a multinomial
The given statement is true
(x) The coefficient of x in 5x is 5x
The given statement is false
(xi) The coefficient of ab in –ab is -1
The given statement is true
(xii) The coefficient of y in -3xy is -3
The given statement is false
4. State the number of terms in each of the following expressions:
(i) 2a – b
(ii) 3 × x + a / 2
(iii) 3x – x / p
(iv) a ÷ x × b + c
(v) 3x ÷ 2 + y + 4
(vi) xy ÷ 2
(vii) x + y ÷ a
(viii) 2x + y + 8 ÷ y
(ix) 2 × a + 3 ÷ b + 4
Solution:
(i) 2a – b
The number of terms in given expression is two
(ii) 3 × x + a / 2
The number of terms in given expression is two
(iii) 3x – x / p
The number of terms in given expression is two
(iv) a ÷ x × b + c
The number of terms in given expression is two
(v) 3x ÷ 2 + y + 4
The number of terms in given expression is three
(vi) xy ÷ 2
The number of terms in given expression is one
(vii) x + y ÷ a
The number of terms in given expression is two
(viii) 2x + y + 8 ÷ y
The number of terms in given expression is three
(ix) 2 × a + 3 ÷ b + 4
The number of terms in given expression is three
5. State whether true or false:
(i) xy and –yx are like terms.
(ii) x2y and –y2x are like terms.
(iii) a and –a are like terms.
(iv) –ba and 2ab are unlike terms.
(v) 5 and 5x are like terms.
(vi) 3xy and 4xyz are unlike terms.
Solution:
(i) xy and –yx are like terms
Yes, xy and –yx are like terms. Hence, the given statement is true
(ii) x2y and –y2x are like terms
No, x2y and –y2x are not like terms. Hence, the given statement is false
(iii) a and –a are like terms.
Yes, a and –a are like terms. Hence, the given statement is true
(iv) –ba and 2ab are unlike terms.
No, –ba and 2ab are like terms. Hence, the given statement is false
(v) 5 and 5x are like terms.
No, 5 and 5x are not like terms. Hence, the given statement is false
(vi) 3xy and 4xyz are unlike terms.
Yes, 3xy and 4xyz are unlike terms. Hence, the given statement is true
6. For each expression, given below, state whether it is a monomial, or a binomial or a trinomial.
(i) xy
(ii) xy + x
(iii) 2x ÷ y
(iv) –a
(v) ax2 – x + 5
(vi) -3bc + d
(vii) 1 + x + y
(viii) 1 + x ÷ y
(ix) x + xy – y2
Solution:
(i) xy
Here xy has one term
Therefore, xy is a monomial
(ii) xy + x
Here xy + x has two terms
Therefore, xy + x is a binomial
(iii) 2x ÷ y
Here 2x ÷ y has one term
Therefore, 2x ÷ y is monomial
(iv) –a
Here –a has one term
Therefore, –a is a monomial
(v) ax2 – x + 5
Here ax2 – x + 5 has three terms
Therefore, ax2 – x + 5 is a trinomial
(vi) -3bc + d
Here -3bc + d has two terms
Therefore, -3bc + d is a binomial
(vii) 1 + x + y
Here 1 + x + y has three terms
Therefore, 1 + x + y is a trinomial
(viii) 1 + x ÷ y
Here 1 + x ÷ y has two terms
Therefore, 1 + x ÷ y is a binomial
(ix) x + xy – y2
Here x + xy – y2 has three terms
Therefore, x + xy – y2 is a trinomial
7. Write down the coefficient of x in the following monomial:
(i) x
(ii) –x
(iii) -3x
(iv) -5ax
(v) 3 / 2 xy
(vi) ax / y
Solution:
(i) x
The coefficient of x in the given monomial x is 1
(ii) – x
The coefficient of x in the given monomial –x is -1
(iii) -3x
The coefficient of x in the given monomial -3x is -3
(iv) -5ax
The coefficient of x in the given monomial -5ax is -5a
(v) 3 / 2 xy
The coefficient of x in the given monomial is (3 / 2)y
(vi) ax / y
The coefficient of x in the given monomial is (a / y)
8. Write the coefficient of:
(i) x in -3xy2
(ii) x in –ax
(iii) y in –y
(iv) y in (2 / a)y
(v) xy in -2xyz
(vi) ax in –axy2
(vii) x2y in -3ax2y
(viii) xy2 in 5axy2
Solution:
(i) x in -3xy2
– 3y2 is the coefficient of x in -3xy2
(ii) x in –ax
– a is the coefficient of x in –ax
(iii) y in –y
-1 is the coefficient of y in –y
(iv) y in (2 / a)y
(2 / a) is the coefficient of y in (2 / a)y
(v) xy in -2xyz
– 2z is the coefficient of xy in -2xyz
(vi) ax in –axy2
– y2 is the coefficient of ax in –axy2
(vii) x2y in -3ax2y
– 3a is the coefficient of x2y in -3ax2y
(viii) xy2 in 5axy2
5a is the coefficient of xy2 in 5axy2
9. State the numeral coefficient of the following monomials:
(i) 5xy
(ii) abc
(iii) 5pqr
(iv) -2x / y
(v) (2 / 3) xy2
(vi) -15xy / 2z
(vii) -7x ÷ y
(viii) -3x ÷ (2y)
Solution:
(i) 5xy
The numeral coefficient of the given monomial is 5
(ii) abc
The numeral coefficient of the given monomial is 1
(iii) 5pqr
The numeral coefficient of the given monomial is 5
(iv) -2x / y
The numeral coefficient of the given monomial is -2
(v) (2 / 3) xy2
The numeral coefficient of the given monomial is (2 / 3)
(vi) -15xy / 2z
The numeral coefficient of the given monomial is (-15 / 2)
(vii) -7x ÷ y
The numeral coefficient of the given monomial is -7 ÷ 1 = -7
(viii) -3x ÷ (2y)
The numeral coefficient of the given monomial is -3 ÷ 2 i.e. (-3 / 2)
10. Write the degree of each of the following polynomials:
(i) x + x2
(ii) 5x2 – 7x + 2
(iii) x3 – x8 + x10
(iv) 1 – 100x20
(v) 4 + 4x – 4x3
(vi) 8x2y – 3y2 + x2y5
(vii) 8z3 – 8y2z3 + 7yz5
(viii) 4y2 – 3x3 + y2x7
Solution:
(i) x + x2
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial x + x2 is 2
(ii) 5x2 – 7x + 2
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 5x2 – 7x + 2 is 2
(iii) x3 – x8 + x10
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial x3 – x8 + x10 is 10
(iv) 1 – 100x20
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 1 – 100x20 is 20
(v) 4 + 4x – 4x3
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 4 + 4x – 4x3 is 3
(vi) 8x2y – 3y2 + x2y5
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 8x2y – 3y2 + x2y5 is 7
(vii) 8z3 – 8y2z3 + 7yz5
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 8z3 – 8y2z3 + 7yz5 is 6
(viii) 4y2 – 3x3 + y2x7
The degree of the polynomial is the greatest of sums of degree of two or more variables of the given polynomial
Therefore, the degree of the given polynomial 4y2 – 3x3 + y2x7 is 9
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Selina Class 6 ICSE Solutions Mathematics : Chapter 18- Fundamental Concepts
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Chapterwise Selina Publishers ICSE Solutions for Class 6 Mathematics :
- Chapter 1- Number System
- Chapter 2- Estimation
- Chapter 3- Numbers In Indian And International Systems
- Chapter 4- Place Value
- Chapter 5- Natural Numbers And Whole Numbers
- Chapter 6- Negative Numbers And Integers
- Chapter 7- Number Line
- Chapter 8- HCF And LCM
- Chapter 9- Playing With Numbers
- Chapter 10- Sets
- Chapter 11- Ratio
- Chapter 12- Proportion
- Chapter 13- Unitary Method
- Chapter 14- Fractions
- Chapter 15- Decimal Fractions
- Chapter 16- Percent (Percentage)
- Chapter 17- Idea of Speed, Distance and Time
- Chapter 18- Fundamental Concepts
- Chapter 19- Fundamental Operations
- Chapter 20- Substitution
- Chapter 21- Framing Algebraic Expressions (Including Evaluation)
- Chapter 22- Simple (Linear) Equations
- Chapter 23- Fundamental Concepts
- Chapter 24- Angles
- Chapter 25- Properties of Angles and Lines
- Chapter 26- Triangles
- Chapter 27- Quadrilateral
- Chapter 28- Polygons
- Chapter 29- The Circle
- Chapter 30- Revision Exercise Symmetry
- Chapter 31- Recognition of Solids
- Chapter 32- Perimeter and Area of Plane Figures
- Chapter 33- Data Handling
- Chapter 34- Mean and Median
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