RS Aggarwal Solutions for Class 7 Maths Chapter 4–Rational Numbers

Class 7: Maths Chapter 4 solutions. Complete Class 7 Maths Chapter 4 Notes.

RS Aggarwal Solutions for Class 7 Maths Chapter 4–Rational Numbers

RS Aggarwal 7th Maths Chapter 4, Class 7 Maths Chapter 4 solutions

Ex 4A Solutions

Question 1.
Solution:
(i) Rational numbers: The numbers of the form pq where p and q are integers and q ≠ 0, are called rational numbers.

(iv) Yes, there is one rational number (0) which is neither positive nor negative.

Question 2.
Solution:

(viii) 01 are all rational number but 10 and 00 are not rational number as their denominator is zero.

Question 3.
Solution:
(i) Numerator = 8, denominator =19
(ii) Numerator = 5, denominator = – 8
(iii) Numerator =-13, denominator =15
(iv) Numerator = – 8, denominator = -11
(v) Numerator = 9, denominator = 1

Question 4.
Solution:

Question 5.
Solution:
According to the definition, a rational number is positive if both of numerator and denominator have same signs. Therefore
(iii), (iv) and (vi) 8 are positive rational numbers.

Question 6.
Solution:
According to the definition, a rational number is negative if numerator and denominator have opposite sign. Therefore.
(iii), (iv), (v), (vi) are all negative rational numbers.

Question 7.
Solution:
Equivalent rational numbers of each are given below:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

Question 16.
Solution:

Question 17.
Solution:

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:

Question 21.
Solution:

Question 22.
Solution:
(i) False, as there is no end of smallest and largest rational number,
(ii) True.
(iii) False, as zero is a rational number but the division of zero is meaningless.
(iv) True.
(v) False, every rational is not a fraction
In a fraction, numerator and denominators is a whole number but the denominator can’t be zero

Ex 4B Solutions

Question 1.
Solution:
(i) Draw a number line and locate a point O on it. Let it represent 0 Now 13 has been presented on the number line given below.

(ii) Draw a number line and locate a point O on it. Let it represent 0. The number 27 has been represented on the number line given below:

(iii) Draw a number line and locate a point O on it. Let it represent 0. The number 73 has been represented on the number line given below:

(iv) Draw a number line and locate a point O on it. Let it represent 0. The number 73 has been represented on it as given below:

(v) Draw a number line and locate a point O on it. Let it represented 0. The number 378 has been represented on it as given below:
378 = 458

(vi) Draw a number line and locate a point O on it. Let it represent 0. The number −13 has been represented on it as given below:

(vii) Draw a number line and locate a point O on it. Let it represent 0. The number −34 has been represented on it is as given below:

(viii) Draw a number line and locate a point on it. Let it represent 0. The number −127 has been represented on it as given below:

(ix) Draw a number line and locate a point O on it. Let it represent 0. The number 36−5 has been represented on it as given below:

(x) Draw a number line and locate is point O on it. Let is represent 0. The number −439 has been represented on it as given below:

Question 2.
Solution:
(i) 56 or 0, 56 is greater as any positive number is always greater than 0.

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:
(i) True: All negative numbers lie on the left of 0.
(ii) False: All negative numbers lie on the left of 0.
(iii) True: All positive numbers lie on the right of 0 and all negative numbers on the left of 0.
(iv) False: −18−13 = 1813 which is positive and positive number lie on the left of 0.
(v) True: −5−8 = 58 which is positive and all positive number lie on the right of negative numbers.
(i), (iii) and (iv) are true.

Question 8.
Solution:
5 rational numbers between -3 and -2.

Question 9.
Solution:

Question 10.
Solution:
L.C.M. of 5 and 2 = 10

Ex 4C Solutions

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:

Ex 4D Solutions

Question 1.
Solution:
(i) Additive inverse of 5 = -5
(ii) Additive inverse of -9 = – (-9) = 9

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:

Question 8.
Solution:

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:
The required number = −11 – 29

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

Question 16.
Solution:

Ex 4E Solutions

Question 1.
Solution:

Question 2.
Solution:

Question 3.
Solution:

Question 4.
Solution:

Question 5.
Solution:
Cost of 1 metre of cloth

Question 6.
Solution:

Ex 4F Solutions

Question 1.
Solution:

(vii) Reciprocal of -1 = -1
(viii) Reciprocal of 0 does not exist.

Question 2.
Solution:

Question 3.
Solution:

Question 5.
Solution:

Question 6.
Solution:

Question 7.
Solution:
Product of two number = 10
One number = -8
Second number = 10 ÷ (-8)

Question 8.
Solution:
Product of two rational numbers = – 9
One number = -12
Second number = (-9) ÷ (-12)

Question 9.
Solution:

Question 10.
Solution:

Question 11.
Solution:
Cloth required for 24 pairs of trousers =54 m
Cloth required for one pair = (54 ÷ 24) m

Question 12.
Solution:
Total length of rape = 30 m

Question 13.
Solution:

Ex 4G Solutions

OBJECTIVE QUESTIONS
Mark (✓) against the correct answer in each of the following:
Question 1.
Solution:
(b)

Question 2.
Solution:
(b)

Question 3.
Solution:
(a)

Question 4.
Solution:
(c)

Question 5.
Solution:
(b)

Question 6.
Solution:
(a)

Question 7.
Solution:
(a)

Question 8.
Solution:
(c)

Question 9.
Solution:
(b)

Question 10.
Solution:

Question 11.
Solution:

Question 12.
Solution:

Question 13.
Solution:

Question 14.
Solution:

Question 15.
Solution:

Question 16.
Solution:

Question 17.
Solution:

Question 18.
Solution:

Question 19.
Solution:

Question 20.
Solution:

RS Aggarwal Solutions for Class 7 Maths Chapter 4: Download PDF

RS Aggarwal Solutions for Class 7 Maths Chapter 4–Rational Numbers

Download PDF: RS Aggarwal Solutions for Class 7 Maths Chapter 4–Rational Numbers PDF

Chapterwise RS Aggarwal Solutions for Class 7 Maths :

• Chapter 1–Integers
• Chapter 2–Fractions
• Chapter 3–Decimals
• Chapter 4–Rational Numbers
• Chapter 5–Exponents
• Chapter 6–Algebraic Expressions
• Chapter 7–Linear Equations in One Variable
• Chapter 8–Ratio and Proportion
• Chapter 9–Unitary Method
• Chapter 10–Percentage
• Chapter 11–Profit and Loss
• Chapter 12–Simple Interest
• Chapter 13–Lines and Angles
• Chapter 14–Properties of Parallel Lines
• Chapter 15–Properties of Triangles
• Chapter 16–Congruence
• Chapter 17–Constructions
• Chapter 18–Reflection and Rotational Symmetry
• Chapter 19–Three-Dimensional Shapes
• Chapter 20–Mensuration
• Chapter 21–Collection and Organisation of Data (Mean, Median and Mode)
• Chapter 22–Bar Graphs
• Chapter 23–Probability

About RS Aggarwal Class 7 Book

Investing in an R.S. Aggarwal book will never be of waste since you can use the book to prepare for various competitive exams as well. RS Aggarwal is one of the most prominent books with an endless number of problems. R.S. Aggarwal’s book very neatly explains every derivation, formula, and question in a very consolidated manner. It has tonnes of examples, practice questions, and solutions even for the NCERT questions.

He was born on January 2, 1946 in a village of Delhi. He graduated from Kirori Mal College, University of Delhi. After completing his M.Sc. in Mathematics in 1969, he joined N.A.S. College, Meerut, as a lecturer. In 1976, he was awarded a fellowship for 3 years and joined the University of Delhi for his Ph.D. Thereafter, he was promoted as a reader in N.A.S. College, Meerut. In 1999, he joined M.M.H. College, Ghaziabad, as a reader and took voluntary retirement in 2003. He has authored more than 75 titles ranging from Nursery to M. Sc. He has also written books for competitive examinations right from the clerical grade to the I.A.S. level.

FAQs

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RS Aggarwal is one of the most important reference books for high school grades and is recommended to every high school student. The book covers every single topic in detail. It goes in-depth and covers every single aspect of all the mathematics topics and covers both theory and problem-solving. The book is true of great help for every high school student. Solving a majority of the questions from the book can help a lot in understanding topics in detail and in a manner that is very simple to understand. Hence, as a high school student, you must definitely dwell your hands on RS Aggarwal!

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RS Aggarwal is a book that contains a few of the hardest questions of high school mathematics. Solving them and teaching students how to solve questions of such high difficulty is not the job of any neophyte. For solving such difficult questions and more importantly, teaching the problem-solving methodology to students, an expert teacher is mandatory!

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RS Aggarwal is available for grades 6 to 12 and hence our expert teachers have formulated detailed solutions for all the questions of each edition of the textbook. On our website, you’ll be able to find solutions to the RS Aggarwal textbook right from Class 6 to Class 12. You can head to the website and download these solutions for free. All the solutions are available in PDF format and are free to download!

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