ML Aggarwal Solutions for Class 7 Maths Chapter 9- Linear Equations and Inequalities
ML Aggarwal Solutions for Class 7 Maths Chapter 9- Linear Equations and Inequalities

Class 7: Maths Chapter 9 solutions. Complete Class 7 Maths Chapter 9 Notes.

ML Aggarwal Solutions for Class 7 Maths Chapter 9- Linear Equations and Inequalities

ML Aggarwal 7th Maths Chapter 9, Class 7 Maths Chapter 9 solutions

1. Solve the following equations:

(i) 2 (3 – 2x) = 13

(ii) (3 / 5) y – 2 = (7 / 10)

Solution:

(i) Given

2 (3 – 2x) = 13

6 – 4x = 13

Transposing 6 to R.H.S. we get,

– 4x = 13 – 6

– 4x = 7

We get,

x = (7 / – 4)

x = (- 7 / 4)

(ii) (3 / 5) y – 2 = (7 / 10)

Multiplying both sides by 5, we get,

3y – 10 = (7 / 10) × 5

3y – 10 = (7 / 2)

Transposing -10 to R.H.S. we get,

3y = (7 / 2) + 10

On taking L.C.M. we get,

3y = {(7 + 20) / 2}

3y = (27 / 2)

y = {27 / (2 × 3)}

We get,

y = (9 / 2)

y =ML Aggarwal Solutions Class 7 Maths Chapter 9 - 1

2.

(i) (x / 2) = 5 + (x / 3)

(ii) 2 {x – (3 / 2)} = 11

Solution:

(i) (x / 2) = 5 + (x / 3)

On multiplying both sides by 6, we get,

6 × (x / 2) = 6 {5 + (x / 3)}

3x = 30 + 2x

Transposing 2x to L.H.S. we get,

3x – 2x = 30

We get,

x = 30

(ii) 2 {x – (3 / 2)} = 11

2x – 3 = 11

Transposing -3 to R.H.S. we get,

2x = 11 + 3

2x = 14

We get,

x = (14 / 2)

x = 7

3.

(i) 7 (x – 2) = 2 (2x – 4)

(ii) 21 – 3(x – 7) = x + 20

Solution:

(i) 7 (x – 2) = 2 (2x – 4)

7x – 14 = 4x – 8

On transposing 4x to L.H.S. and -14 to R.H.S. we get,

7x – 4x = – 8 + 14

3x = 6

x = (6 / 3)

x = 2

(ii) 21 – 3 (x – 7) = x + 20

21 – 3x + 21 = x + 20

On further calculation, we get,

42 – 3x = x + 20

On transposing x to L.H.S. and 42 to R.H.S. we get,

– 3x – x = 20 – 42

– 4x = -22

x = (22 / 4)

We get,

x = (11 / 2)

x =ML Aggarwal Solutions Class 7 Maths Chapter 9 - 2

4. If 7 is added to five times a number, the result is 57. Find the number.

Solution:

Let the required number be x

Five times of this number = 5x

If 7 is added, then the number becomes = 7 + 5x

As per the given condition,

7 + 5x = 57

5x = 57 – 7

5x = 50

x = (50 / 5)

We get,

x = 10

Therefore, the required number = 10

5. Find a number, such that one-fourth of the number is 3 more than 7.

Solution:

Let the required number = x

According to the condition,

(1 / 4) x – 3 = 7

Transposing -3 to R.H.S. we get,

(1 / 4) x = 7 + 3

(1 / 4) x = 10

x = 10 × 4

We get,

x = 40

Therefore, the required number is 40

6. If the replacement set is (-5, -3, -1, 0, 1, 3, 4), find the solution set of:

(i) x < -2

(ii) x > 1

(iii) x ≥ -1

(iv) -5 < x < 3

(v) -3 ≤ x < 4

(vi) 0 ≤ x < 7

Solution:

Given

Replacement set = {-5, -3, -1, 0, 1, 3, 4}

(i) The solution set of x < -2 = {-5, -3}

(ii) The solution set of x > 1 = {3, 4}

(iii) The solution set of x ≥ -1 = {-1, 0, 1, 3, 4}

(iv) The solution set of -5 < x < 3 = {-3, -1, 0, 1}

(v) The solution set of -3 ≤ x < 4 = {-3, -1, 0, 1, 3}

(vi) The solution set of 0 ≤ x < 7 = {0, 1, 3, 4}

7. Represent the following inequations graphically:

(i) x ≤ 3, x ∈ N

(ii) x < 4, x ∈ W

(iii) -2 ≤ x < 4, x ∈ l

(iv) -3 ≤ x ≤ 2, x ∈ l

Solution:

Given

x ≤ 3, x ∈ N

Therefore,

The solution set = {1, 2, 3}

The solution set is shown be thick dots on the number line below

ML Aggarwal Solutions Class 7 Maths Chapter 9 - 3

(ii) x < 4, x ∈ W

Therefore,

The solution set = {0, 1, 2, 3}

The solution set is shown by thick dots on the number line below

ML Aggarwal Solutions Class 7 Maths Chapter 9 - 4

(iii) -2 ≤ x < 4, x ∈ l

Therefore,

The solution set = {-2, -1, 0, 1, 2, 3}

The solution set is shown by thick dots on the number line below

ML Aggarwal Solutions Class 7 Maths Chapter 9 - 5

(iv) -3 ≤ x ≤ 2, x ∈ l

Therefore,

The solution set = {-3, -2, -1, 0, 1, 2}

The solution set is shown by thick dots on the number line below

ML Aggarwal Solutions Class 7 Maths Chapter 9 - 6

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ML Aggarwal Solutions for Class 7 Maths Chapter 9- Linear Equations and Inequalities

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About ML Aggarwal

M. L. Aggarwal, is an Indian mechanical engineer, educator. His achievements include research in solutions of industrial problems related to fatigue design. Recipient Best Paper award, Manipal Institute of Technology, 2004. Member of TSTE.