Selina Class 9 ICSE Solutions Mathematics : Chapter 24- Solution of Right Triangles
Selina Class 9 ICSE Solutions Mathematics : Chapter 24- Solution of Right Triangles

Class 9: Maths Chapter 24 solutions. Complete Class 9 Maths Chapter 24 Notes.

Selina Class 9 ICSE Solutions Mathematics : Chapter 24- Solution of Right Triangles

Selina 9th Maths Chapter 24, Class 9 Maths Chapter 24 solutions

Exercise 24

Solution 1:
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Solution 2:
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Solution 3:
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Solution 4:
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Solution 5:
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Solution 6:
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Solution 7:
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Thus AB = AC + CD + BD = 54.64 cm.

Solution 8:
First draw two perpendiculars to AB from the point D and C respectively. Since AB|| CD therefore PMCD will be a rectangle.
Consider the figure,
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Solution 9:
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Solution 10:
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Solution 11:
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Solution 12:
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Solution 13:
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Solution 14:
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Solution 15:
Given that the ladder makes an angle of 30o with the ground and reaches upto a height of 15 m of the tower which is shown in the figure below:
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Solution 16:
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Solution 17:
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Solution 18:
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Solution 19:
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Solution 20:
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We also know that in rhombus diagonals bisect each other perpendicularly and diagonal bisect the angle at vertex.
Hence POR is a right angle triangle and
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Selina Class 9 ICSE Solutions Mathematics : Chapter 21- Solids [Surface Area and Volume of 3-D Solids]

Download PDF: Selina Class 9 ICSE Solutions Mathematics : Chapter 21- Solids [Surface Area and Volume of 3-D Solids] PDF

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