NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency
NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency

Class 11: Economics Chapter 5 solutions. Complete Class 11 Economics Chapter 5 Notes.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency

NCERT 11th Economics Chapter 5, class 11 Economics chapter 5 solutions

Page No: 71

Exercises

1. Which average would be suitable in the following cases?

(i) Average size of readymade garments.

► Mode

(ii) Average intelligence of students in a class.

► Median

(iii) Average production in a factory per shift.

► Arithmetic average

(iv) Average wages in an industrial concern.

► Arithmetic average

(v) When the sum of absolute deviations from average is least.

► Median

(vi) When quantities of the variable are in ratios.
► Arithmetic average

(vii) In case of open-ended frequency distribution.
► Median

NCERT 11th Economics Chapter 5, class 11 Economics chapter 5 solutions

2. Indicate the most appropriate alternative from the multiple choices provided against each question.

(i) The most suitable average for qualitative measurement is

(a) arithmetic mean
(b) median
(c) mode
(d) geometric mean
(e) none of the above

► (b) median

(ii) Which average is affected most by the presence of extreme items?

(a) median
(b) mode
(c) arithmetic mean
(d) none of the above

► (c) arithmetic mean

(iii) The algebraic sum of deviation of a set of n values from A.M. is
(a) n
(b) 0
(c) 1
(d) none of the above

► (b) 0

3. Comment whether the following statements are true or false.

(i) The sum of deviation of items from median is zero.

► False

(ii) An average alone is not enough to compare series.

► True

(iii) Arithmetic mean is a positional value.

► False

(iv) Upper quartile is the lowest value of top 25% of items.

► True

(v) Median is unduly affected by extreme observations.

► False

NCERT 11th Economics Chapter 5, class 11 Economics chapter 5 solutions

4. If the arithmetic mean of the data given below is 28, find (a) the missing frequency, and (b) the median of the series:

Profit per retail shop (in Rs)0-1010-2020-3030-4040-5050-60
Number of retail shops121827176

(a) Let the missing frequency be x
Arithmetic mean = 28 (given)

Profit per retail shop (in Rs) Class IntervalNo. of retail shops Frequency (f)Mid Value (m)fm
0-1012560
10-201815270
20-302725675
30-40x3535x
40-501745765
50-60655330
 Σf = 80 + xΣfx = 2100 + 35x

Mean = Σfxf
⇒ 28 = 2100 + 35x/80 + x

⇒ 2240 + 28x = 2100 + 35

⇒ 2240 – 2100 = 35x – 25x

⇒ 140 = 7x

⇒  x = 140/7 = 20

Missing frequency = 20

(b)

Class IntervalFrequency (f)Cumulative frequency (CF)
0-101212
10-201830
20-302757
30-40x77
40-501794
50-606100
Total Σf = 100

Median = Size of (N/2)th item
             = 100/2 = 50th item
It lies in class 20-30.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 4

NCERT 11th Economics Chapter 5, class 11 Economics chapter 5 solutions

5. The following table gives the daily income of ten workers in a factory. Find the arithmetic mean.

WorkersABCDEFGHIJ
Daily Income (in Rs) 120150180200250300220350370260

Answer

WorkersDaily Income (in Rs) X
A120
B150
C180
D200
E250
F300
G220
H350
I370
J260
Total ΣX = 2400

N = 10
Arithmetic Mean = ΣX/N
                            = 2400/10
                            = 240
Arithmetic Mean = 240

NCERT 11th Economics Chapter 5, class 11 Economics chapter 5 solutions

6. Following information pertains to the daily income of 150 families. Calculate the arithmetic mean.

Income (in Rs)Number of families
More than 75150
More than 85140
More than 95115
More than 10595
More than 11570
More than 12560
More than 13540
More than 14525

Answer

IncomeNo. of families Frequency (f)Mid Class

(x)

fx

75-85

10

80

800

85-95

25

90

2250

95-105

20

100

2000

105-115

25

110

2750

115-125

10

120

1200

125-135

20

130

2600 135-145 15

140

2100 145-155 25

150

3750
150
17450 Arithmetic Mean = Σfxf
                            = 17450/150
                            = 116.33

7. The size of land holdings of 380 families in a village is given below. Find the median size of land holdings.

Size of Land Holdings (in acres)Less than 100100-200200-300300-400400 and above
Number of families40891486439

Answer

Size of Land Holdings
       Class Interval
Number of families (f)Cumulative frequency (CF)
0-1004040
100-20089129
200-300148277
300-40064341
400-50039380
Total Σf = 380

Σf = N = 380
Median = Size of (N/2)th item
             = 380/2 = 190th item
It lies in class 200-300.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 7


Median size of land holdings = 241.22 acres

8. The following series relates to the daily income of workers employed in a firm. Compute (a) highest income of lowest 50% workers (b) minimum income earned by the top 25% workers and (c) maximum income earned by lowest 25% workers.

Daily Income (in Rs)10-1415-1920-2425-2930-3435-39
Number of workers5101520105

(Hint: Compute median, lower quartile and upper quartile.)

Answer

Daily Income (in Rs)
      Class Interval
No of workers (f)Cumulative frequency (CF)
9.5-14.555
14.5-19.51015
19.5-24.51530
24.5-29.52050
29.5-34.51060
34.5-39.5565
Total Σf = 65

(a) Σf = N = 65
Median = Size of (N/2)th item
             = 65/2 = 32.5th item
It lies in class 24.5-29.5.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 8

Highest income of lowest 50% workers = Rs 25.12

(b) First, we need to find Q1
Class interval of Q1 = (N/4)th items
                                 = (65/4)th items = 16.25th item
It lies in class 19.5-24.5.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 8

Minimum income earned by the top 25% workers = Rs 19.92

(c) First, we need to find Q3
Class interval of Q= 3 (N/4)th items
                                 = 3 (65/4)th items = 3 × 16.25th item
                                 = 48.75th item
It lies in class 24.5-29.5.

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 8

Maximum income earned by lowest 25% workers = Rs 29.19


9. The following table gives production yield in kg. per hectare of wheat of 150 farms in a village. Calculate the mean, median and mode values.

Production yield (kg. per hectare)50-5353-5656-5959-6262-6565-6868-7171-7474-77
Number of workers381430362816105

Answer

Production Yield
 (kg. per hectare)
No. of farms Frequency (f)Mid Class (x)fxCumulative frequency (CF)
50-53351.5154.53
53-56854.543611
56-591457.580525
59-623060.5181555
62-653663.5228691
65-682866.51862119
68-711669.51112135
71-741072.5725145
74-77575.5377.5150
Σf = 150Σfx = 9573

Mean = Σfxf  = 9573/150 = 63.82 hectare

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 9

Modal Class = 62-65

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency Que. 9

NCERT Solutions for 11th Class Economics: Chapter 5: Download PDF

NCERT Solutions for 11th Class Economics: Chapter 5-Measures of Central Tendency

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