NCERT Solutions Class 6, Maths Chapter 2- IndCareer Schools

Class 6: Maths Chapter 2 solutions. Complete Class 6 Maths Chapter 2 Notes.

Contents

1 NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers
- - 1.0.1 Exercise 2.1
2 NCERT Solutions for 6th Class Maths: Chapter 2: Download PDF
3 Chapterwise NCERT Solutions for Class 6 Maths :
4 About NCERT

NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers

NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions

Page No: 31

Exercise 2.1

1. Write the next three natural numbers after 10999.

Answer

11000 , 11001, 11002

2. Write the three whole numbers occurring just before 10001.

Answer

10000, 9999,9998

3. Which is the smallest whole number?

Answer

0 is the smallest whole number.

4. How many whole numbers are there between 32 and 53?

(33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52)

There are 20 whole numbers lie between 32 and 53.

5. Write the successor of :
(a) 2440701
(b) 100199
(c) 1099999
(d) 2345670

Answer

a) 2440701 = 2440701 + 1 = 2440702.

b) 100199 = 100199 + 1 = 100200

c) 1099999 = 1099999 + 1 = 1100000

d) 2345670 = 2345670 + 1 = 2345671

6. Write the predecessor of :
(a) 94
(b) 10000
(c) 208090
(d) 7654321

Answer

(a) 94 = 94 – 1 = 93

(b) 10000 = 10000 – 1= 9999

(d) 7654321 = 7654321 – 1 = 76543210

7. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>,< ) between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001

Answer

(a) 530 > 503
530 is on the left side of number line.

(b) 370 > 307
370 is on the left side of number line.

(d) 9830415 < 10023001
10023001 is the left side of the number line.

8. Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.
Answer

(a) 0 is not a natural number (false)

(b) Predecessor of 399 is 398 (false)

(d) 599 + 1 = 600 (true)

(e) True

(f) 0 is whole number but not natural numbers.(false)

(g) False

(h) 0 is the smallest whole number (false)

(i) True

(j) False

(k) False

(l) True

(m) False

Page No: 40

Exercise 2.2

1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647

Answer

(a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408

(b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (647 + 453)
= 3500 + 1100 = 4600

2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25

Answer

(a) 2 × 50 × 1768 = 176,800

(b) 166 × 25 × 4 = 16600

(d) 285 × 60 × 5 = 2790000

(e) 285 × 60 × 3 = 85500

(f) 125 × 40 × 25 × 8 = 1000000

3. Find the value of the following:
(a) 297 × 17 + 297 × 3
(b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69
(d) 3845 × 5 × 782 + 769 × 25 × 218

Answer

(a) 297 × (17 + 3 ) = 297 × 20 = 5940.

(b) 54279 × (92 + 8)
= 54279 × 100 = 5427900.

(d) 3845 × 5 × 782 + 769 × 5 × 5 × 218
= 3845 × 5 × (782 + 218)
= 19225 × 1000 = 19225000.

4. Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168

Answer

(a) 738 × 103
= (738 × 100) + (738 × 3)
= 73800 + 2214 = 76014

(b) 854 × 102
= (854 × 100) + (854 × 2)
= 85400 + 1708 = 87108

(d) 1005 × 168 = (1000 + 5) × 168
= (1000 × 168) + (5 × 168)
= 168000 + 840 = 168840

5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?

Answer

Petrol filled on Monday = 40 litres
Petrol next day filled = 50 litres
Total quantity of petrol filled = (40 +50) litres
Cost of petrol per litres = 44

Total amount of money spent on petrol = 44 × (40 + 50)
= 44 × 90 = Rs 3960

Page No: 41

6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day?

Answer

In the morning vendor supplies = 32 litres.
In the evening vendor supplies = 68 litres.
Cost of milk per litre = Rs 15
Total cost of per day = 15 × ( 32 + 68)
= 15 × 100 = Rs 1500

7. Match the following:

Answer
(i) ➝ C
(ii) ➝ A

(iii) ➝ B

Page No: 43

Exercise 2.3

1. Which of the following will not represent zero:

(a) 1 + 0

(b) 0 × 0

(c) 0 / 2

(d) (10 – 10)/2

Answer

(a) 1 + 0 = 1 (not represent zero)

(b) 0 × 0 = 0 (it represent zero)

(d) (10 – 10)/ 2 = 0 (it represent zero)

2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Answer

Product of two whole number is zero then both of them may be zero

0 × 3 =0

1 × 3 = 3

3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.

Answer

Product of two whole number is 1 , both number is equal to 1.

For example , 1 × 1 = 1 , 1 × 6 = 6

In both example, number is multiplied by 1.

4. Find using distributive property :

(a) 728 × 101

(b) 5437 × 1001

(c) 824 × 25

(d) 4275 × 125

(e) 504 × 35

Answer

(a) 728 × 101

= (728 × 100) + (728 × 1)

= 72800 + 728

= 73528

(b) 5437 × 1001

= (5437 × 1000) + (5437 × 1)

= 5437000 + 5437

= 5442437

= (800 + 24) × 25

= (800 + 25 – 1) × 25

= (800 × 25) + ( 25 × 25) – (1 × 25)

= (20000 × (625 – 25)

= 20000 + 600 = 20600

(d) 4275 × 125

= (4000 + 25 + 200 + 50) × (100 + 25)

= (4000×100) + (25×100) + (200×100) + (50×100) + (4000×25) + (25×25) + (200×25) + (50×25)

= 400000 + 2500 + 20000 + 5000 + 100000 + 625 + 5000 + 1250

= 534375

(e) 504 × 35

= (500 + 4) × 35

= (500 × 35) + (4 × 35)

= 17500 + 140 = 17640

5. Study the pattern : 1 × 8 + 1 = 9

1234 × 8 + 4 = 9876

12 × 8 + 2 = 98

12345 × 8 + 5 = 98765

123 × 8 + 3 = 987

Write the next two steps. Can you say how the pattern works? (Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).

Answer

123456 × 8 + 6 = 987648 + 6 = 987654

1234567 × 8 + 7 = 9876536 + 7 = 9876543

Pattern are use in following ways

123456 = 123456 × 8 (111111+11111+1111+111+11+1) × 8

= 111111 × 8 + 11111 × 8 +1111 × 8 + 111 × 8 + 11 × 8 + 1× 8

= 888888 + 88888 +8888 +888 +88 + 8 = 987648

123456 × 8 +6 = 987648 + 6 = 987654

NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions

NCERT Solutions for 6th Class Maths: Chapter 2: Download PDF

NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers

Download PDF: NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers PDF

Chapterwise NCERT Solutions for Class 6 Maths :

About NCERT

The National Council of Educational Research and Training is an autonomous organization of the Government of India which was established in 1961 as a literary, scientific, and charitable Society under the Societies Registration Act. Its headquarters are located at Sri Aurbindo Marg in New Delhi. Visit the Official NCERT website to learn more.

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NCERT Solutions for Class 6

NCERT Solutions for Class 6 Maths