NCERT Exemplar Class 10 Maths Chapter 3: Pair of Linear Equations in Two Variables. NCERT Exemplar Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables prepare students for their Class 10 exams thoroughly.

Maths problems and solutions for the Class 10 pdf are provided here which are similar to the questions being asked in the previous year’s board.

Contents

- 1 NCERT Exemplar Class 10 Maths Chapter 3: Pair of Linear Equations in Two Variables
- 1.1 Multiple Choice Questions (Solved Examples)
- 1.2 Multiple Choice Questions (Exercise)
- 1.3 Short Answer Questions with Reasoning (Solved Examples)
- 1.4 Short Answer Questions with Reasoning (Exercise)
- 1.5 Short Answer Type Questions (Solved Examples)
- 1.6 Short Answer Type Questions (Exercise)
- 1.7 Long Answer Type Questions (Solved Examples)
- 1.8
- 1.9
- 1.10 Long Answer Type Questions (Exercise)
- 1.11

- 2 Answers

**NCERT Exemplar Class 10 Maths Chapter 3: Pair of Linear Equations in Two Variables**

Class 10 : Maths Chapter 3 solutions. Complete Class 10 Maths Chapter 3 Notes.

**Main Concepts and Results**

The pair of linear equations can also be solved geometrically/graphically.

### Multiple Choice Questions (Solved Examples)

### Multiple Choice Questions (Exercise)

### Short Answer Questions with Reasoning (Solved Examples)

### Short Answer Questions with Reasoning (Exercise)

**Exercise- 3.2**

### Short Answer Type Questions (Solved Examples)

We observe that there is a point R (2, 4) common to both the lines AB and PQ.

The triangle formed by these lines and the *x- axis* is BQR.

The vertices of this triangle are B (–2, 0), Q (1, 0) and R (2, 4).

We know that;

### Short Answer Type Questions (Exercise)

**Exercise- 3.3**

### Long Answer Type Questions (Solved Examples)

C is a point on the x-axis at a distance of 2 units to the left of y-axis. So, the coordinates of C are (–2, 0)

B is the solution of the pair of equations *x* = –2 and *y* = 3. So, the coordinates of B are (–2, 3) So, the vertices of the rectangle OABC are O (0, 0), A (0, 3), B (–2, 3), C (–2, 0)

The length and breadth of this rectangle are 2 units and 3 units, respectively.

As the area of a rectangle = length × breadth,

the area of rectangle OABC = 2 × 3 = 6 *sq.* units.** Sample Question 2:** Determine, algebraically, the vertices of the triangle formed by the lines

5*x* – *y* = 5, *x* + 2*y* = 1 and 6*x* + *y* = 17.

5*x* – *y* = 5

6*x* + *y* = 17,

we get *x* = 2, *y* = 5.

So, the third vertex of the triangle is (2, 5). So, the three vertices of the triangle are

(1, 0), (3, –1) and (2, 5).** Sample Question 3: **Jamila sold a table and a chair for Rs 1050, thereby making a profit

of 10% on the table and 25% on the chair. If she had taken a profit of 25% on the table and

10% on the chair she would have got Rs 1065. Find the cost price of each.** Solution: **Let the cost price of the table be Rs x and the cost price of the chair be Rs *y*.

### Long Answer Type Questions (Exercise)

**Exercise- 3.4**