{"id":625669,"date":"2023-09-07T12:12:12","date_gmt":"2023-09-07T12:12:12","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=625669"},"modified":"2023-09-07T12:12:17","modified_gmt":"2023-09-07T12:12:17","slug":"kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/","title":{"rendered":"KC Sinha: Exercise 4.1 – Mathematics Solution Class 10 Chapter 4 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923"},"content":{"rendered":"\n\n\n\n\n

Type-1 : \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0964<\/p>\n\n\n\n

(i) (x-2)(x+1)=(x-1)(x+3)<\/strong><\/p>\n\n\n\n

\u21d2x(x+1)-2(x+1)=x(x+3)-1(x+3)<\/p>\n\n\n\n

\u21d2x2<\/sup>+x-2x-2=x2<\/sup>+3x-x-3<\/p>\n\n\n\n

\u21d2x2<\/sup>-x-2=x2<\/sup>+2x-3<\/p>\n\n\n\n

\u21d2x2<\/sup>-x-2-x2<\/sup>-2x+3=0<\/p>\n\n\n\n

\u21d2-3x+1=0<\/p>\n\n\n\n

\u21d2-(3x-1)=0<\/p>\n\n\n\n

\u21d23x-1=0 <\/p>\n\n\n\n

\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902 \u0939\u0948\u0964<\/p>\n\n\n\n

(ii) (x-2)2<\/sup>+1=2x-3<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u21d2x2<\/sup>-2\u00d7x\u00d72+(2)2<\/sup>+1=2x-3<\/p>\n\n\n\n

\u21d2x2<\/sup>-4x+4+1=2x-3<\/p>\n\n\n\n

\u21d2x2<\/sup>-4x+5-2x+3=0<\/p>\n\n\n\n

\u21d2x2<\/sup>-6x+8=0<\/p>\n\n\n\n

(iii) x(x+1)+8=(x+2)(x-2)<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u21d2x2<\/sup>+x+8=x2<\/sup>-22<\/sup><\/p>\n\n\n\n

\u21d2x2<\/sup>+x+8=x2<\/sup>-4<\/p>\n\n\n\n

\u21d2x2<\/sup>+x+8-x2<\/sup>+4=0<\/p>\n\n\n\n

(iv) (x-2)(2x+1)=x(x+5)
<\/strong> Sol :
\u21d2x(2x+1)-2(2x+1)=x2<\/sup>+5x
\u21d22x2<\/sup>+x-4x-2=x2<\/sup>+5x
\u21d22x2<\/sup>+x-4 x-2-x2<\/sup>-5 x=0
\u21d2x2<\/sup>-8 x-2=0<\/p>\n\n\n\n

\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948\u0964<\/p>\n\n\n\n

(v) x(2 x+3)=x2<\/sup>+1
<\/strong> Sol :
\u21d22x2<\/sup>+3x=x2<\/sup>+1
\u21d22x2<\/sup>+3x-x2<\/sup>-1=0
\u21d2x2<\/sup>+3x-1=0<\/p>\n\n\n\n

\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948\u0964<\/p>\n\n\n\n

(vi) x2<\/sup>+3 x+1=(x-2)2<\/sup>
<\/strong> Sol :
\u21d2x2<\/sup>+3x+1=(x)2<\/sup>-2x \u2715 x2<\/sup>+(2)2<\/sup>
\u21d2x2<\/sup>+3x+1=x2<\/sup>-4x+4
\u21d2x2<\/sup>+3x+1-x2<\/sup>+4x-4=0
\u21d27x-3=0<\/p>\n\n\n\n

\u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902 \u0939\u0948\u0964<\/p>\n\n\n\n

(vii) (x+1)(x-1)=(x+2)(x+3)
<\/strong> Sol :
\u21d2x(x-1)+1(x-1)=x(x+3)+2(x+3)
\u21d2x2<\/sup>-x+x-1=x2<\/sup>+3 x+2x+6
\u21d2x2<\/sup>-1=x2<\/sup>+5 x+6
\u21d2x2<\/sup>-1-x2<\/sup>-5 x-6=0<\/p>\n\n\n\n

\u21d2-5x-7=0<\/p>\n\n\n\n

\n
KC Sinha Solutions<\/a><\/div>\n\n\n\n
KC Sinha Class 10 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Type-1 : \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0964 (i) (x-2)(x+1)=(x-1)(x+3) \u21d2x(x+1)-2(x+1)=x(x+3)-1(x+3) \u21d2x2+x-2x-2=x2+3x-x-3 \u21d2x2-x-2=x2+2x-3 \u21d2x2-x-2-x2-2x+3=0 \u21d2-3x+1=0 \u21d2-(3x-1)=0 \u21d23x-1=0  \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u0939\u0940\u0902 \u0939\u0948\u0964 (ii) (x-2)2+1=2x-3 Sol : \u21d2x2-2\u00d7x\u00d72+(2)2+1=2x-3 \u21d2x2-4x+4+1=2x-3 \u21d2x2-4x+5-2x+3=0 \u21d2x2-6x+8=0 (iii) x(x+1)+8=(x+2)(x-2) Sol : \u21d2x2+x+8=x2-22 \u21d2x2+x+8=x2-4 \u21d2x2+x+8-x2+4=0 (iv) (x-2)(2x+1)=x(x+5) Sol :\u21d2x(2x+1)-2(2x+1)=x2+5x\u21d22×2+x-4x-2=x2+5x\u21d22×2+x-4 x-2-x2-5 x=0\u21d2x2-8 x-2=0 \u092f\u0939 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948\u0964 (v) x(2 x+3)=x2+1 […]<\/p>\n","protected":false},"author":302,"featured_media":625671,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[24],"tags":[],"boards":[],"class_list":["post-625669","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-10","entry"],"yoast_head":"\nKC Sinha: Exercise 4.1 - Mathematics Solution Class 10 Chapter 4 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Type-1 : \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0964 (i) (x-2)(x+1)=(x-1)(x+3) \u21d2x(x+1)-2(x+1)=x(x+3)-1(x+3) \u21d2x2+x-2x-2=x2+3x-x-3\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"KC Sinha: Exercise 4.1 - Mathematics Solution Class 10 Chapter 4 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\" \/>\n<meta property=\"og:description\" content=\"Type-1 : \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0964 (i) (x-2)(x+1)=(x-1)(x+3) \u21d2x(x+1)-2(x+1)=x(x+3)-1(x+3) \u21d2x2+x-2x-2=x2+3x-x-3\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-07T12:12:12+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-09-07T12:12:17+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-5-1-scaled.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1600\" \/>\n\t<meta property=\"og:image:height\" content=\"901\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"KC Sinha: Exercise 4.1 – Mathematics Solution Class 10 Chapter 4 \u0926\u094d\u0935\u093f\u0918\u093e\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\",\"datePublished\":\"2023-09-07T12:12:12+00:00\",\"dateModified\":\"2023-09-07T12:12:17+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\"},\"wordCount\":177,\"publisher\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#organization\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-5-1-scaled.jpg\",\"articleSection\":[\"Class 10\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\",\"url\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-10-chapter-4-dvighat-samikaran\/\",\"name\":\"KC Sinha: Exercise 4.1 - 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