{"id":625661,"date":"2023-09-07T11:53:21","date_gmt":"2023-09-07T11:53:21","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=625661"},"modified":"2023-09-07T11:53:26","modified_gmt":"2023-09-07T11:53:26","slug":"kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/","title":{"rendered":"KC Sinha: Exercise 3.3 – Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923"},"content":{"rendered":"\n

<\/p>\n\n\n\n

Question 1<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947:<\/p>\n\n\n\n

(i)<\/strong> 3x-5y-4=0<\/strong><\/p>\n\n\n\n

9x=2y+7<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

3x-5y-4=0..(i)\u00d73<\/p>\n\n\n\n

9x-2y=7..(ii)\u00d71<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘3’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘1’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n\n\n\n

$\\begin{aligned}9x-15y&=12\\\\9x-2y&=7\\\\ -\\phantom{9x}+\\phantom{2y}&=-\\phantom{7}\\\\ \\hline -13y&=5\\end{aligned}$<\/p>\n\n\n\n

$y=\\frac{-5}{13}$<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930<\/p>\n\n\n\n

3x-5y=4<\/p>\n\n\n\n

$3x-5\\left(\\frac{-5}{13}\\right)=4$<\/p>\n\n\n\n

$3x+\\frac{25}{13}=4$<\/p>\n\n\n\n

$3x=4-\\frac{25}{13}$<\/p>\n\n\n\n

$3x=\\frac{52-25}{13}$<\/p>\n\n\n\n

$3 x=\\frac{27}{13}$<\/p>\n\n\n\n

$x=\\frac{27}{13 \\times {3}}=\\frac{9}{13}$<\/p>\n\n\n\n

$\\therefore x=\\frac{9}{13}, y=\\frac{-5}{13}$<\/p>\n\n\n\n

(ii) <\/strong>3x+4y=10<\/strong><\/p>\n\n\n\n

2x\u20132y=2<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

3x+4y=10..(i)\u00d71<\/p>\n\n\n\n

2x-2y=2..(ii)\u00d72<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘1’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘2’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930 <\/p>\n\n\n\n

$\\begin{aligned}3 x+4 y&=10\\\\4 x-4 y&=4\\\\ \\hline 7x=&14\\end{aligned}$<\/p>\n\n\n\n

$x=\\frac{14}{7}$<\/p>\n\n\n\n

=2<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930 <\/p>\n\n\n\n

3x+4y=10<\/p>\n\n\n\n

3(2)+4y=10<\/p>\n\n\n\n

6+4y=10<\/p>\n\n\n\n

4y=4<\/p>\n\n\n\n

$y=\\frac{4}{4}$<\/p>\n\n\n\n

y=1<\/p>\n\n\n\n

\u2234x=2, y=1<\/p>\n\n\n\n

(vii) 0.4x \u2013 1.5y = 6.5<\/strong>
0.3x + 0.2y = 0.9<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u0926\u094b\u0928\u094b \u0938\u092e\u0940\u0915\u0930\u0923 \u092e\u0947 10 \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

4x-15y=65..(i)\u00d73<\/p>\n\n\n\n

3x+2y=9..(ii)\u00d74<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘3’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘4’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\begin{aligned}12 x-45 y&=195\\\\ 12x+8y&=36\\\\ -\\phantom{12x}-\\phantom{8y}&=-\\phantom{36}\\\\ \\hline -53&=159\\end{aligned}$<\/p>\n\n\n\n

$y=\\frac{159}{-5}$<\/p>\n\n\n\n

y=-3<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

4x-15y=65<\/p>\n\n\n\n

4x-15(-3)=65<\/p>\n\n\n\n

4x+45=65<\/p>\n\n\n\n

4x=20<\/p>\n\n\n\n

$x=\\frac{20}{4}$<\/p>\n\n\n\n

x=5<\/p>\n\n\n\n

\u2234x=5 ,y=-3<\/p>\n\n\n\n

(viii) \u221a2x-\u221a3y=0<\/strong><\/p>\n\n\n\n

\u221a5x+\u221a2y=0<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u221a2x-\u221a3y=0..(i)\u00d7\u221a2<\/p>\n\n\n\n

\u221a5x+\u221a2y=0..(ii)\u00d7\u221a3<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘\u221a2’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘\u221a3’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\begin{aligned}2 x-\\sqrt{6} y&=0\\\\\\sqrt{15 x}+\\sqrt{6} y&=0 \\\\ \\hline 2x+\\sqrt{15}x&=0\\end{aligned}$<\/p>\n\n\n\n

$(2+\\sqrt{1} 5) x=0$<\/p>\n\n\n\n

x=0<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\sqrt{5} x+\\sqrt{2} y=0$<\/p>\n\n\n\n

$\\sqrt{5} \\times 0+\\sqrt{2} y=0$<\/p>\n\n\n\n

$\\sqrt{2} y=0 \\Rightarrow y=0$<\/p>\n\n\n\n

\u2234x=0, y=0<\/p>\n\n\n\n

Question 2<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u0930\u094d\u092e\u093e\u0902\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947\u0902\u0964<\/p>\n\n\n\n

(i) <\/strong>$\\frac{x}{2}+\\frac{2 y}{3}=-1$<\/p>\n\n\n\n

$x-\\frac{y}{3}=3$<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$\\frac{x}{2}+\\frac{2 y}{3}=-1$<\/p>\n\n\n\n

$\\frac{3 x+4 y}{6}=-1$<\/p>\n\n\n\n

3x+4y=-6..(i)<\/p>\n\n\n\n

$x-\\frac{y}{3}=3$<\/p>\n\n\n\n

$\\frac{3 x-y}{3}=3$<\/p>\n\n\n\n

3x-y=9..(ii)<\/p>\n\n\n\n

(ii) <\/strong>$\\frac{x}{6}+\\frac{y}{15}=4$<\/p>\n\n\n\n

$\\frac{x}{3}-\\frac{y}{12}=\\frac{19}{4}$<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

(iii) <\/strong>$x+\\frac{6}{y}=6$<\/p>\n\n\n\n

$3 x-\\frac{8}{y}=5$<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$x+\\frac{6}{y}=6$..(i)\u00d74<\/p>\n\n\n\n

$3 x-\\frac{8}{y}=5$\u00d73<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘4’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘3’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930 ,<\/p>\n\n\n\n

$\\begin{aligned}4 x+\\frac{24}{y}&=24\\\\9 x-\\frac{24}{y}&=15\\\\ \\hline 13 x&=39\\end{aligned}$<\/p>\n\n\n\n

x=3<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0924\u0915\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$x+\\frac{6}{y}=6$<\/p>\n\n\n\n

$3+\\frac{6}{y}=6$<\/p>\n\n\n\n

$\\Rightarrow \\frac{6}{y}=3$3y=6<\/p>\n\n\n\n

y=2<\/p>\n\n\n\n

\u2234x=3, y=2<\/p>\n\n\n\n

Question 3<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923\u094b \u0915\u094b \u0935\u093f\u0932\u094b\u092e \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947:<\/p>\n\n\n\n

(i) 37x+43y=123<\/strong><\/p>\n\n\n\n

43x+37y=117<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

37x+43y=123..(i)<\/p>\n\n\n\n

43x+37y=117..(ii)<\/p>\n\n\n\n

\u091c\u094b\u0921\u093c\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\begin{aligned}37 x+43 y&=123\\\\43 x+37 y&=117\\\\ \\hline80 x+80 y&=240\\end{aligned}$<\/p>\n\n\n\n

80(x+y)=240<\/p>\n\n\n\n

$x+y=\\frac{240}{80}$<\/p>\n\n\n\n

x+y=3..(iii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 (ii) \u0915\u094b \u0918\u091f\u093e\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\begin{aligned}37 x+43 y&=123\\\\43 x+37 y&=117\\\\-\\phantom{43x}-\\phantom{37y} &=-\\phantom{117}\\\\ \\hline -6 x+6 y&=6\\end{aligned}$<\/p>\n\n\n\n

-6(x-y)=6<\/p>\n\n\n\n

x-y=-1..(iv)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (iii) \u0924\u0925\u093e (iv) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}x+y&=3\\\\x-y&=-1\\\\ \\hline2 x&=2\\end{aligned}$<\/p>\n\n\n\n

x=1<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (iv) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

x+y=3<\/p>\n\n\n\n

1+y=3<\/p>\n\n\n\n

y=2<\/p>\n\n\n\n

\u2234 x=1, y=2<\/p>\n\n\n\n

(ii) 217x+131y=913<\/strong><\/p>\n\n\n\n

131x+217y=827<\/strong><\/p>\n\n\n\n

(iii) 99x+101y=499<\/strong><\/p>\n\n\n\n

101x+99y=501<\/strong><\/p>\n\n\n\n

(iv) 29x-23y=110<\/strong><\/p>\n\n\n\n

23x-29y=98<\/strong><\/p>\n\n\n\n

Question 4<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947\u0902<\/p>\n\n\n\n

(i)<\/strong> $\\frac{1}{x}-\\frac{1}{y}=1$<\/p>\n\n\n\n

$\\frac{1}{x}+\\frac{1}{y}=7 \\cdot x \\neq 0, y \\neq 0$<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$\\begin{aligned}\\frac{1}{2}-\\frac{1}{y}&=1..(i)\\\\\\frac{1}{x}+\\frac{1}{y}&=7..(ii)\\\\ \\hline \\frac{2}{x}&=8\\end{aligned}$<\/p>\n\n\n\n

8x=2 <\/p>\n\n\n\n

$x=\\frac{1}{4}$<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\frac{1}{x}+\\frac{1}{y}=7$<\/p>\n\n\n\n

$\\frac{1}{\\frac{1}{4}}+\\frac{1}{y}=7$<\/p>\n\n\n\n

$4+\\frac{1}{y}=7$<\/p>\n\n\n\n

$\\frac{1}{y}=3$<\/p>\n\n\n\n

3y=1<\/p>\n\n\n\n

$y=\\frac{1}{3}$<\/p>\n\n\n\n

$x=\\frac{1}{4}, y= \\frac{1}{3}$<\/p>\n\n\n\n

$\\frac{1}{x}=a, \\frac{1}{y}=b$<\/p>\n\n\n\n

$\\begin{aligned}a-b&=1..(i)\\\\a+b&=7..(ii)\\\\ \\hline 2 a&=8 \\end{aligned}$<\/p>\n\n\n\n

$a=\\frac{8}{2}=4$<\/p>\n\n\n\n

a \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

a+b=7<\/p>\n\n\n\n

4+b=7<\/p>\n\n\n\n

b=3<\/p>\n\n\n\n

$\\because \\frac{1}{x}=a, \\frac{1}{y}=b$<\/p>\n\n\n\n

$\\frac{1}{x}=4 , \\frac{1}{y}=3$<\/p>\n\n\n\n

4x=1 ,3y=1<\/p>\n\n\n\n

$x=\\frac{1}{4} , y=\\frac{1}{3}$<\/p>\n\n\n\n

(ii)<\/strong> $\\frac{2}{x}+\\frac{3}{y}=13$<\/p>\n\n\n\n

$\\frac{5}{x}-\\frac{4}{y}=-2, x \\neq 0, y \\neq 0$<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

Let $\\frac{1}{x}=a, \\frac{1}{y}=b$<\/p>\n\n\n\n

2a+3b=13..(i)\u00d74<\/p>\n\n\n\n

5a-4b=-2..(ii)\u00d73<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘4’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘3’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930<\/p>\n\n\n\n

$\\begin{aligned}8 a+12 b&=52\\\\15 a-12 b&=-6\\\\ \\hline23 a&=46\\end{aligned}$<\/p>\n\n\n\n

$a=\\frac{46}{23}=2$<\/p>\n\n\n\n

a \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u092e (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

2a+3b=13<\/p>\n\n\n\n

2(2)+3b=13<\/p>\n\n\n\n

2(2)+3b=13<\/p>\n\n\n\n

4+3b=13<\/p>\n\n\n\n

3b=9<\/p>\n\n\n\n

$b=\\frac{9}{3}=3$<\/p>\n\n\n\n

\u2235$\\frac{1}{x}=a, \\frac{1}{y}=b$<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘4’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘3’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\begin{aligned}8 a+12 b&=52\\\\15 a-12 b&=-6\\\\ \\hline23 a&=46 \\end{aligned}$<\/p>\n\n\n\n

$a=\\frac{46}{23}=2$<\/p>\n\n\n\n

a \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

2a+3b=13<\/p>\n\n\n\n

2(2)+3b=13<\/p>\n\n\n\n

$\\frac{1}{x}=2, \\frac{1}{y}=3$<\/p>\n\n\n\n

2x=1. 3y=1<\/p>\n\n\n\n

$x=\\frac{1}{2}, y=\\frac{1}{3}$<\/p>\n\n\n\n

(iv)<\/strong> $\\frac{3 a}{x}-\\frac{2 b}{y}+5=0, \\frac{a}{x}+\\frac{3 b}{y}-2=0$ (x\u22600,y\u22600)<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$\\frac{3 a}{x}-\\frac{2 b}{y}+5=0$…(i)\u00d73<\/p>\n\n\n\n

$\\frac{a}{x}+\\frac{3 b}{y}-2=0$…(ii)\u00d72<\/p>\n\n\n\n

$\\begin{aligned}\\frac{9a}{x}-\\frac{6 b}{y}+15&=0\\\\\\frac{2 a}{x}+\\frac{6 b}{y}-4&=0\\\\ \\hline \\frac{119}{x}+11&=0\\end{aligned}$<\/p>\n\n\n\n

$\\frac{11a}{x}=-11$<\/p>\n\n\n\n

-11x=11a<\/p>\n\n\n\n

x=-a<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\frac{a}{x}+\\frac{3 b}{y}-2=0$<\/p>\n\n\n\n

$\\frac{a}{-a}+\\frac{3 b}{y}-2=0$<\/p>\n\n\n\n

$\\frac{3b}{y}-3=0$<\/p>\n\n\n\n

$\\frac{3 b}{y}=3$<\/p>\n\n\n\n

3y=3b<\/p>\n\n\n\n

$y=\\frac{3 b}{3}$<\/p>\n\n\n\n

y=b<\/p>\n\n\n\n

\u2234x=-a, y=b<\/p>\n\n\n\n

Let $\\frac{1}{x}=u, \\frac{1}{y}=v$<\/p>\n\n\n\n

3au-2bv+5=0..(i)<\/p>\n\n\n\n

4a+3bv-2=0..(ii)<\/p>\n\n\n\n

Question 5<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923-\u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947\u0902<\/p>\n\n\n\n

(i) <\/strong>$\\frac{2 x+5 y}{x y}=6, \\frac{4 x-5 y}{x y}=-3$, \u091c\u0939\u093e\u0901 x\u22600 \u0914\u0930 y\u22600<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$\\frac{2x}{x y}+\\frac{5 x}{x y}=6$<\/p>\n\n\n\n

$\\frac{2}{y}+\\frac{5}{x}=6$..(i)<\/p>\n\n\n\n

$\\frac{4 x}{x y}-\\frac{5 y}{x y}=-3$<\/p>\n\n\n\n

$\\frac{4}{y}-\\frac{5}{x}=-3$..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}\\frac{2}{y}+\\frac{5}{x}&=6\\\\\\frac{4}{y}-\\frac{5}{x}&=-3\\\\ \\hline\\frac{6}{y}&=3\\end{aligned}$<\/p>\n\n\n\n

3y=6<\/p>\n\n\n\n

$y=\\frac{6}{3}=2$<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\frac{2}{y}+\\frac{5}{x}=6$<\/p>\n\n\n\n

$\\frac{2}{2}+\\frac{5}{x}=6$<\/p>\n\n\n\n

$\\frac{5}{x}=5$<\/p>\n\n\n\n

5x=5<\/p>\n\n\n\n

$x=\\frac{5}{5}=1$<\/p>\n\n\n\n

\u2234x=1, y=2<\/p>\n\n\n\n

$\\begin{array}{l|l}\\frac{2 y}{x y}+\\frac{5 y}{x y}=6&\\frac{4 x}{x y}-\\frac{5 y}{x y}=-3\\\\\\frac{2}{y}+\\frac{5}{x}=6&\\frac{4}{y}-\\frac{5}{x}=-3\\end{array}$<\/p>\n\n\n\n

Let $\\frac{1}{y}=a, \\quad \\frac{1}{x}=b$<\/p>\n\n\n\n

$\\begin{aligned}2a+5b&=6..(i)<\/p>\n\n\n\n

4a-5b&=-3..(ii)\\\\ \\hline 6a=3\\end{aligned}$<\/p>\n\n\n\n

6a=3<\/p>\n\n\n\n

$a=\\frac{3}{6}$<\/p>\n\n\n\n

$a=\\frac{1}{2}$<\/p>\n\n\n\n

a \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

2a+5b=6<\/p>\n\n\n\n

$2\\left(\\frac{1}{2}\\right)+5 b=6$<\/p>\n\n\n\n

5b=5<\/p>\n\n\n\n

$b=\\frac{5}{5}=1$<\/p>\n\n\n\n

\u2235 $\\frac{1}{x}=b , \\frac{1}{y}=a$<\/p>\n\n\n\n

$\\frac{1}{x}=1, \\frac{1}{y}=\\frac{1}{2}$<\/p>\n\n\n\n

x=1 ,y=2<\/p>\n\n\n\n

(ii) x+y=2xy<\/strong><\/p>\n\n\n\n

x-y=6xy<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

x+y=2xy<\/p>\n\n\n\n

$\\frac{x+y}{x y}=2$<\/p>\n\n\n\n

$\\frac{x}{x y}+\\frac{y}{x{y}}=2$<\/p>\n\n\n\n

$\\frac{1}{y}+\\frac{1}{x}=2$..(i)<\/p>\n\n\n\n

x-y=6xy<\/p>\n\n\n\n

$\\frac{x-y}{xy}=6$<\/p>\n\n\n\n

$\\frac{x}{x y}-\\frac{y}{x{y}}=6$<\/p>\n\n\n\n

$\\frac{1}{y}-\\frac{1}{x}=6$..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}\\frac{1}{y}+\\frac{1}{x}&=2\\\\\\frac{1}{y}-\\frac{1}{x}&=6\\\\\\hline \\frac{2}{y}&=8\\end{aligned}$<\/p>\n\n\n\n

8y=2<\/p>\n\n\n\n

$y=\\frac{2}{8}=\\frac{1}{4}$<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

$\\frac{1}{y}+\\frac{1}{x}=2$<\/p>\n\n\n\n

$\\frac{1}{\\frac{1}{4}}+\\frac{1}{x}=2$<\/p>\n\n\n\n

$4+\\frac{1}{x}=2$<\/p>\n\n\n\n

$\\frac{1}{x}=-2$<\/p>\n\n\n\n

-2x=1<\/p>\n\n\n\n

$x=-\\frac{1}{2}$<\/p>\n\n\n\n

\u2234$x=-\\frac{1}{2}, y=\\frac{1}{4}$<\/p>\n\n\n\n

Question 6<\/h4>\n\n\n\n

\u0928\u093f\u0930\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b x \u0914\u0930 y \u0915\u0947 \u0932\u093f\u090f \u0939\u0932 \u0915\u0930\u0947\u0902<\/p>\n\n\n\n

(i)<\/strong> $\\frac{1}{2(2 x+3 y)}+\\frac{12}{7(3 x-2 y)}=\\frac{1}{2}, \\frac{7}{(2 x+3 y)}+\\frac{4}{(3 x-2 y)}=2$<\/p>\n\n\n\n

\u091c\u0939\u093e\u0901 (2x+3y)\u22600 \u0914\u0930 (3x-2y)\u22600<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

Let $\\frac{1}{2 x+3 y}=a, \\frac{1}{3 x-2 y}=b$<\/p>\n\n\n\n

$\\frac{a}{2}+\\frac{12}{7} b=\\frac{1}{2}$<\/p>\n\n\n\n

$\\frac{7 a+24 b}{14}=\\frac{1}{2}$<\/p>\n\n\n\n

7a+24b=7..(i)<\/p>\n\n\n\n

7a+4b=2..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}7a+24b&=7\\\\7a+4b&=2\\\\-\\phantom{7a}-\\phantom{4b}&=-\\phantom{2}\\end{aligned}$<\/p>\n\n\n\n

20b=5<\/p>\n\n\n\n

$b=\\frac{5}{20}=\\frac{1}{4}$<\/p>\n\n\n\n

b \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930<\/p>\n\n\n\n

7a+4b=2<\/p>\n\n\n\n

$7 a+4\\left(\\frac{1}{4}\\right)=2$<\/p>\n\n\n\n

7a=1<\/p>\n\n\n\n

$a=\\frac{1}{7}$<\/p>\n\n\n\n

$\\because \\frac{1}{2 x+3 y}=a, \\frac{1}{3 x-2 y}=b$<\/p>\n\n\n\n

$\\frac{1}{2 x+3 y}=\\frac{1}{7}, \\frac{1}{3 x-2 y}=\\frac{1}{4}$<\/p>\n\n\n\n

2x+3y=7..(iii)\u00d72 ,3x-2y=4..(iv)\u00d73<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (iii) \u0924\u0925\u093e (iv) \u0938\u0947<\/p>\n\n\n\n

$\\begin{aligned}4x+6y&=14\\\\9x-6y&=12\\\\13x&=26\\end{aligned}$<\/p>\n\n\n\n

x=2<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (iii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930 ,<\/p>\n\n\n\n

2x+3y=7<\/p>\n\n\n\n

2(2)+3y=7<\/p>\n\n\n\n

4+3y=7<\/p>\n\n\n\n

3y=3<\/p>\n\n\n\n

$y=\\frac{3}{3}=1$<\/p>\n\n\n\n

\u2234x=2,y=1<\/p>\n\n\n\n

(ii) <\/strong>$\\frac{2}{x-1}+\\frac{3}{y+1}=2$<\/p>\n\n\n\n

$\\frac{3}{x-1}+\\frac{2}{y+1}=\\frac{13}{6}$, x\u22601,y\u2260-1<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

$\\frac{2}{x-1}+\\frac{3}{y+1}=2$..(i)\u00d72<\/p>\n\n\n\n

$\\frac{3}{x-1}+\\frac{2}{y+1}=\\frac{13}{6}$..(ii)\u00d73<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947<\/p>\n\n\n\n

$\\begin{aligned}\\frac{4}{x-1}+\\frac{6}{y+1}&=4\\\\\\frac{9}{x-1}+\\frac{6}{y+1}&=\\frac{13}{2}\\\\ -\\phantom{\\frac{9}{x-1}}-\\phantom{\\frac{6}{y+1}}&=-\\phantom{\\frac{13}{2}}\\\\ \\hline \\frac{-5}{x-1}&=4-\\frac{13}{2}\\end{aligned}$<\/p>\n\n\n\n

$-\\frac{5}{x-1}=\\frac{8-13}{2}$<\/p>\n\n\n\n

$\\frac{-5}{x-1}=\\frac{-5}{2}$<\/p>\n\n\n\n

x-1=2<\/p>\n\n\n\n

x=3<\/p>\n\n\n\n

x \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930<\/p>\n\n\n\n

$\\frac{2}{x-1}+\\frac{3}{y+1}=2$<\/p>\n\n\n\n

$\\frac{2}{3-1}+\\frac{3}{y+1}=2$<\/p>\n\n\n\n

$\\frac{2}{2}+\\frac{3}{y+1}=2$<\/p>\n\n\n\n

$\\frac{3}{y+1}=1$<\/p>\n\n\n\n

y=1=3<\/p>\n\n\n\n

y=2<\/p>\n\n\n\n

\u2234x=3, y=2<\/p>\n\n\n\n

Put $\\frac{1}{x-1}=a, \\frac{1}{y+1}=b$<\/p>\n\n\n\n

2a+3b=2..(i)<\/p>\n\n\n\n

$3a+2b=\\frac{13}{6}$..(ii)<\/p>\n\n\n\n

Question 7<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092a\u094d\u0930\u0936\u094d\u0928\u094b\u0902 \u0915\u0947 \u0932\u093f\u090f \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923 \u092f\u0941\u0917\u094d\u092e \u092c\u0928\u093e\u092f\u0947\u0902 \u0914\u0930 \u0935\u093f\u0932\u093e\u092a\u0947\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0909\u0928\u0915\u0947 \u0939\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0902\u0964<\/p>\n\n\n\n

(i)<\/strong> \u0906\u092b\u0924\u093e\u092c \u0905\u092a\u0928\u0940 \u092a\u0941\u0924\u094d\u0930\u0940 \u0938\u0947 \u0915\u0939\u0924\u093e \u0939\u0948, “7 \u0935\u0930\u094d\u0937 \u092a\u0939\u0932\u0947 \u092e\u0947\u0930\u0940 \u0909\u092e\u094d\u0930 \u0924\u0941\u092e\u094d\u0939\u093e\u0930\u0940 \u0909\u0938 \u0938\u092e\u092f \u0915\u0940 \u0909\u092e\u094d\u0930 \u0915\u0940 \u0938\u093e\u0924 \u0917\u0941\u0928\u0940 \u0925\u0940\u0964\u0906\u091c \u0938\u0947 3 \u0935\u0930\u094d\u0937 \u092c\u093e\u0926 \u092e\u0947\u0930\u0940 \u0909\u092e\u094d\u0930, \u0924\u0941\u092e\u094d\u0939\u093e\u0930\u0940 \u0909\u092e\u094d\u0930 (\u0924\u0940\u0928 \u0935\u0930\u094d\u0937 \u092c\u093e\u0926) \u0915\u0940 \u0924\u093f\u0917\u0941\u0928\u0940 \u0939\u094b \u091c\u093e\u090f\u0917\u0940\u0964” \u0909\u0928\u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0964<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u092e\u093e\u0928\u093e \u0906\u092b\u0924\u093e\u092c \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930=x \u0935\u0930\u094d\u0937<\/p>\n\n\n\n

\u0906\u092b\u0924\u093e\u092c \u0915\u0940 \u092a\u0941\u0924\u094d\u0930\u0940 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930=y \u0935\u0930\u094d\u0937<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 \u0938\u0947,<\/p>\n\n\n\n

x-7=7(y-7)<\/p>\n\n\n\n

x-7=7y-49<\/p>\n\n\n\n

x-7y=-49+7<\/p>\n\n\n\n

x-7y=-42..(i)<\/p>\n\n\n\n

\u0905\u092c,<\/p>\n\n\n\n

x+3=3(y+3)<\/p>\n\n\n\n

x+3=3y+9<\/p>\n\n\n\n

x-3y=9-3<\/p>\n\n\n\n

x-3y=6..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947<\/p>\n\n\n\n

$\\begin{aligned}x-7y&=-42\\\\x-3y&=6\\\\ -\\phantom{x}+\\phantom{3y}&=-\\phantom{6} \\hline -4y&=-48\\end{aligned}$<\/p>\n\n\n\n

$y=\\frac{48}{4}$<\/p>\n\n\n\n

y=12<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

x-3y=6<\/p>\n\n\n\n

x-3(12)=6<\/p>\n\n\n\n

x-36=6<\/p>\n\n\n\n

x=6+36=42<\/p>\n\n\n\n

\u2234 \u0906\u092b\u0924\u093e\u092c \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930=42 \u0935\u0930\u094d\u0937<\/p>\n\n\n\n

\u0906\u092b\u0924\u093e\u092c \u0915\u0940 \u092a\u0941\u0924\u094d\u0930\u0940 \u0915\u093e \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930=12 \u0935\u0930\u094d\u0937<\/p>\n\n\n\n

(ii)<\/strong> 5 \u0935\u0930\u094d\u0937 \u092a\u0939\u0932\u0947 \u0928\u0942\u0930\u0940 \u0915\u0940 \u0909\u092e\u094d\u0930 \u0938\u094b\u0928\u0942 \u0915\u0940 \u0909\u092e\u094d\u0930 \u0915\u0940 \u0924\u0940\u0928 \u0917\u0941\u0928\u0940 \u0925\u0940\u0964\u0926\u0938 \u0935\u0930\u094d\u0937 \u092c\u093e\u0926 \u0928\u0942\u0930\u0940 \u0915\u0940 \u0909\u092e\u094d\u0930 \u0938\u094b\u0928\u0942 \u0915\u0940 \u0909\u092e\u094d\u0930 \u0915\u0940 \u0926\u0941\u0917\u0941\u0928\u0940 \u0939\u094b \u091c\u093e\u092f\u0917\u0940 \u0964 \u0928\u0942\u0930\u0940 \u0914\u0930 \u0938\u094b\u0928\u0942 \u0915\u0940 \u0909\u092e\u094d\u0930 \u0915\u093f\u0924\u0928\u0940 \u0939\u0948?<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u092e\u093e\u0928\u093e \u0928\u0942\u0930\u0940 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930 =x \u0935\u0930\u094d\u0937 <\/p>\n\n\n\n

\u0938\u094b\u0928\u0942 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930 =y \u0935\u0930\u094d\u0937 <\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 \u0938\u0947,<\/p>\n\n\n\n

x-5=3(y-5)<\/p>\n\n\n\n

x-5=3y-15<\/p>\n\n\n\n

x-3y=-15+5<\/p>\n\n\n\n

x-3y=-10..(i)<\/p>\n\n\n\n

\u0905\u092c,<\/p>\n\n\n\n

x+10=2(y+10)<\/p>\n\n\n\n

x+10=2y+20<\/p>\n\n\n\n

x-2y=10..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}x-3y&=-10\\\\x-2y&=10\\\\ -\\phantom{x}+\\phantom{2y}&=-\\phantom{10}\\\\ \\hline -y=-20\\end{aligned}$<\/p>\n\n\n\n

y=20<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

x-2y=10<\/p>\n\n\n\n

x-2(20)=10<\/p>\n\n\n\n

x-40=10<\/p>\n\n\n\n

x=50<\/p>\n\n\n\n

\u2234 \u0928\u0942\u0930\u0940 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930 =50 \u0935\u0930\u094d\u0937 <\/p>\n\n\n\n

\u0938\u094b\u0928\u0942 \u0915\u0940 \u0935\u0930\u094d\u0924\u092e\u093e\u0928 \u0909\u092e\u094d\u0930 =20 \u0935\u0930\u094d\u0937 <\/p>\n\n\n\n

(iii)<\/strong> \u0926\u094b \u0938\u0902\u0916\u094d\u092f\u093e\u0913 \u0915\u093e \u0905\u0928\u094d\u0924\u0930 26 \u0939\u0948 \u0914\u0930 \u090f\u0915 \u0938\u0902\u0916\u094d\u092f\u093e \u0926\u0942\u0938\u0930\u0947 \u0915\u0940 \u0924\u0940\u0928 \u0917\u0941\u0928\u093e \u0939\u0948\u0964 \u0907\u0928 \u0938\u0902\u0916\u094d\u092f\u093e\u0913 \u0915\u094b \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947\u0964<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

\u092e\u093e\u0928\u093e \u092a\u0939\u0932\u0940 \u0938\u0902\u0916\u094d\u092f\u093e=x<\/p>\n\n\n\n

\u0926\u0942\u0938\u0930\u0940 \u0938\u0902\u0916\u094d\u092f\u093e=y, x>y<\/p>\n\n\n\n

\u092a\u094d\u0930\u0936\u094d\u0928 \u0938\u0947,<\/p>\n\n\n\n

x-y=26..(i)<\/p>\n\n\n\n

x=3y<\/p>\n\n\n\n

x-3y=0..(ii)<\/p>\n\n\n\n

\u0938\u092e\u0940\u0915\u0930\u0923 (i) \u0924\u0925\u093e (ii) \u0938\u0947,<\/p>\n\n\n\n

$\\begin{aligned}x-y=&26\\\\x-3 y&=0\\\\ -\\phantom{x}+\\phantom{3 y}&=-\\phantom{0}\\\\ \\hline 2y&=26\\end{aligned}$<\/p>\n\n\n\n

y=13<\/p>\n\n\n\n

y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,<\/p>\n\n\n\n

x-y=26<\/p>\n\n\n\n

x-13=26<\/p>\n\n\n\n

x=26+13<\/p>\n\n\n\n

x=39<\/p>\n\n\n\n

\u2234 \u092a\u0939\u0932\u0940 \u0938\u0902\u0916\u094d\u092f\u093e=32<\/p>\n\n\n\n

\u0926\u0942\u0938\u0930\u0940 \u0938\u0902\u0916\u094d\u092f\u093e=13<\/p>\n\n\n\n

KC Sinha Solutions<\/a><\/div>
KC Sinha Class 10 Solutions<\/a><\/div> <\/div> <\/p>\n","protected":false},"excerpt":{"rendered":"

Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 ‘3’ \u0938\u0947 \u0924\u0925\u093e \u0938\u092e\u0940\u0915\u0930\u0923 (ii) \u092e\u0947 ‘1’ \u0938\u0947 \u0917\u0941\u0923\u093e \u0915\u0930\u0928\u0947 \u092a\u0930 $\\begin{aligned}9x-15y&=12\\\\9x-2y&=7\\\\ -\\phantom{9x}+\\phantom{2y}&=-\\phantom{7}\\\\ \\hline -13y&=5\\end{aligned}$ $y=\\frac{-5}{13}$ y \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930 3x-5y=4 $3x-5\\left(\\frac{-5}{13}\\right)=4$ $3x+\\frac{25}{13}=4$ $3x=4-\\frac{25}{13}$ $3x=\\frac{52-25}{13}$ $3 x=\\frac{27}{13}$ $x=\\frac{27}{13 \\times {3}}=\\frac{9}{13}$ $\\therefore […]<\/p>\n","protected":false},"author":302,"featured_media":625663,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[24],"tags":[],"boards":[],"class_list":["post-625661","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-10","entry"],"yoast_head":"\nKC Sinha: Exercise 3.3 - Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 '3' \u0938\u0947 \u0924\u0925\u093e\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"KC Sinha: Exercise 3.3 - Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923\" \/>\n<meta property=\"og:description\" content=\"Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 '3' \u0938\u0947 \u0924\u0925\u093e\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-07T11:53:21+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-09-07T11:53:26+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1600\" \/>\n\t<meta property=\"og:image:height\" content=\"901\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"KC Sinha: Exercise 3.3 – Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923\",\"datePublished\":\"2023-09-07T11:53:21+00:00\",\"dateModified\":\"2023-09-07T11:53:26+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\"},\"wordCount\":1438,\"publisher\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#organization\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg\",\"articleSection\":[\"Class 10\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\",\"url\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/\",\"name\":\"KC Sinha: Exercise 3.3 - 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Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923 - IndCareer Schools","description":"Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 '3' \u0938\u0947 \u0924\u0925\u093e","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/","og_locale":"en_US","og_type":"article","og_title":"KC Sinha: Exercise 3.3 - Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923","og_description":"Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 '3' \u0938\u0947 \u0924\u0925\u093e","og_url":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/","og_site_name":"IndCareer Schools","article_publisher":"https:\/\/www.facebook.com\/indcareer","article_published_time":"2023-09-07T11:53:21+00:00","article_modified_time":"2023-09-07T11:53:26+00:00","og_image":[{"width":1600,"height":901,"url":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg","type":"image\/jpeg"}],"author":"Pooja","twitter_card":"summary_large_image","twitter_creator":"@indcareer","twitter_site":"@indcareer","twitter_misc":{"Written by":"Pooja","Est. reading time":"6 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#article","isPartOf":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/"},"author":{"name":"Pooja","@id":"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e"},"headline":"KC Sinha: Exercise 3.3 – Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923","datePublished":"2023-09-07T11:53:21+00:00","dateModified":"2023-09-07T11:53:26+00:00","mainEntityOfPage":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/"},"wordCount":1438,"publisher":{"@id":"https:\/\/www.indcareer.com\/schools\/#organization"},"image":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#primaryimage"},"thumbnailUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg","articleSection":["Class 10"],"inLanguage":"en-US"},{"@type":"WebPage","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/","url":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/","name":"KC Sinha: Exercise 3.3 - Mathematics Solution Class 10 Chapter 3 \u0926\u094b \u091a\u0930 \u0935\u093e\u0932\u0947 \u0930\u0948\u0916\u093f\u0915 \u0938\u092e\u0940\u0915\u0930\u0923 - IndCareer Schools","isPartOf":{"@id":"https:\/\/www.indcareer.com\/schools\/#website"},"primaryImageOfPage":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#primaryimage"},"image":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#primaryimage"},"thumbnailUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg","datePublished":"2023-09-07T11:53:21+00:00","dateModified":"2023-09-07T11:53:26+00:00","description":"Question 1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u092e\u0940\u0915\u0930\u0923 \u0928\u093f\u0915\u093e\u092f \u0915\u094b \u0935\u093f\u0932\u094b\u092a\u0928 \u0935\u093f\u0927\u093f \u0938\u0947 \u0939\u0932 \u0915\u0930\u0947: (i) 3x-5y-4=0 9x=2y+7 Sol : 3x-5y-4=0..(i)\u00d73 9x-2y=7..(ii)\u00d71 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 '3' \u0938\u0947 \u0924\u0925\u093e","breadcrumb":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-3-mathematics-solution-class-10-chapter-3do-char-wale-raikhik-samikaran\/#primaryimage","url":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg","contentUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-4-1-scaled.jpg","width":1600,"height":901,"caption":"KC Sinha: Exercise 3.5 - 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