{"id":625594,"date":"2023-09-07T08:48:24","date_gmt":"2023-09-07T08:48:24","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=625594"},"modified":"2023-09-07T08:48:29","modified_gmt":"2023-09-07T08:48:29","slug":"kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/","title":{"rendered":"KC Sinha: Exercise 4.1 – Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901"},"content":{"rendered":"\n\n\n\n\n

Question 1<\/h4>\n\n\n\n

\u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f
(i) (x+3)(x+3)<\/strong>
Sol :
Here we use identity
(x+a)(x+a)=x2<\/sup>+(a+b)x+ab
a=3 , b=3
\u21d2x2<\/sup>+(3+3)x+3\u00d73
\u21d2x2<\/sup>+6x+9<\/p>\n\n\n\n

(ii) (x-3)(x+5)<\/strong>
Sol :
Using identity:
(x+a)(x+b)=x2<\/sup>+(a+b)x+ab
a=-3 , b=5
\u21d2x2<\/sup>+(-3+5)x+(-3)(5)
\u21d2x2<\/sup>+2x-15<\/p>\n\n\n\n

(iii) (5x+2)(5x-3)<\/strong>
Sol:
Using identity:
(x+a)(x+b)=x2<\/sup>+(a+b)x+ab
replace x=5x , a=2 , b=-3
\u21d2(5x)2<\/sup>+(2-3)5x+(2)(-3)
\u21d225x2<\/sup>-5x-6<\/p>\n\n\n\n

(iv) $\\left(y^2-\\dfrac{5}{2}\\right)\\left(y^2+\\dfrac{7}{2}\\right)$<\/strong>
Sol :
Using identity :
(x+a)(x+b)=x2<\/sup>+(a+b)x+ab
Replace x=y2<\/sup> , $a=-\\dfrac{5}{2},b=\\dfrac{7}{2}$
\u21d2$(y^2)^2+\\left(-\\dfrac{5}{2}+\\dfrac{7}{2}\\right)y^2+\\left(-\\dfrac{5}{2}\\right)\\left(\\dfrac{7}{2}\\right)$
\u21d2$y^4+\\left(\\dfrac{-5+7}{2}\\right)y^2-\\dfrac{35}{4}$
\u21d2$y^4+y^2-\\dfrac{35}{4}$<\/p>\n\n\n\n

(v) (2x-1)(2x+5)<\/strong>
Sol :
Using identity :
(x+a)(x+b)=x2<\/sup>+(a+b)x+ab
Replace x=2x , a=-1 ,b=5
\u21d2(2x)2<\/sup>+(-1+5)2x+(-1)(5)
\u21d24x2<\/sup>+8x-5<\/p>\n\n\n\n

(vi) (5+2x)(5-2x)<\/strong>
Sol :
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
Replace a=5 ,b=2x
\u21d252<\/sup>-(2x)2<\/sup>
\u21d225-4x2<\/sup><\/p>\n\n\n\n

(vii) $\\left(y-\\dfrac{x}{10}\\right)\\left(y+\\dfrac{x}{10}\\right)$<\/strong>
Sol:
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
Replace $a=y ,b=\\dfrac{x}{10}$
\u21d2$y^2-\\left(\\dfrac{x}{10}\\right)^2$
\u21d2$y^2-\\dfrac{x^2}{100}$<\/p>\n\n\n\n

(viii) $\\left(x+\\dfrac{3}{5}\\right)\\left(x-\\dfrac{3}{5}\\right)$<\/strong>
Sol :
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
Replace $a=x ,b=\\dfrac{3}{5}$
\u21d2$x^2-\\left(\\dfrac{3}{5}\\right)^2$
\u21d2$x^2-\\dfrac{9}{25}$<\/p>\n\n\n\n

Question 2<\/h4>\n\n\n\n

\u0938\u0940\u0927\u0947 \u0917\u0941\u0923\u093e \u0915\u093f\u090f \u092c\u093f\u0928\u093e \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932\u094b \u0915\u0947 \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f:
(i) 105\u00d7106<\/strong>
Sol :
$\\dfrac{105+106}{2}=105.5$<\/p>\n\n\n\n

(i) 105\u00d7106<\/strong>
Sol :
$\\dfrac{105+106}{2}=105.5$
Hence , we can express 105 and 106 in terms of 105.5 as follows
\u21d2105\u00d7106
\u21d2(105.5-0.5)(105.5+0.5)
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
\u092c\u0926\u0932\u0928 \u0915\u0947 a=105.5 ,b=0.5
\u21d2(105.5)2<\/sup>-(0.5)2<\/sup>
\u21d211130.25-0.25
\u21d211130<\/p>\n\n\n\n

ALTERNATE METHOD<\/strong>
\u21d2105\u00d7106=(100+5)(100+6)<\/p>\n\n\n\n

=(100)2<\/sup>+(5+6)100+5\u00d76<\/p>\n\n\n\n

=10000+1100+30
=11130<\/p>\n\n\n\n

(ii) 103\u00d798<\/strong>
Sol :
$\\dfrac{103+98}{2}=100.5$
Hence , we can express 103 and 98 in terms of 100.5 as follows
\u21d2103\u00d798
\u21d2(100.5+2.5)(100.5-2.5)
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
\u092c\u0926\u0932\u0928 \u0915\u0947 a=100.5 ,b=2.5
\u21d2(100.5)2<\/sup>-(2.5)2<\/sup>
\u21d210100.25-6.25
\u21d210094<\/p>\n\n\n\n

(iii) 97\u00d798<\/strong>
Sol :
$\\dfrac{97+98}{2}=97.5$
Hence , we can express 97 and 98 in terms of 97.5 as follows
\u21d297\u00d798
\u21d2(97.5-0.5)(97.5+0.5)
Using identity :
a2<\/sup>-b2<\/sup>=(a+b)(a-b)
\u092c\u0926\u0932\u0928 \u0915\u0947 a=97.5 ,b=0.5
\u21d2(97.5)2<\/sup>-(0.5)2<\/sup>
\u21d29506.25-0.25
\u21d29506<\/p>\n\n\n\n

Question 3<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0915\u094b \u092a\u094d\u0930\u0938\u093e\u0930\u093f\u0924 \u0930\u0941\u092a \u092e\u0947 \u0932\u093f\u0916\u093f\u090f\u0964
(i) (3a+4b+5c)2<\/sup><\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace a=3a,b=4b ,c=5c
\u21d2(3a)2<\/sup>+(4b)2<\/sup>+(5c)2<\/sup>+2(3a)(4b)+2(4b)(5c)+2(5c)(3a)
\u21d29a2<\/sup>+16b2<\/sup>+25c2<\/sup>+24ab+40bc+30ac<\/p>\n\n\n\n

(ii) (4a-2b-3c)2<\/sup><\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace a=4a,b=-2b,c=-3c
\u21d2(4a)2<\/sup>+(-2b)2<\/sup>+(-3c)2<\/sup>+2(4a)(-2b)+2(-2b)(-3c)+2(-3c)(4a)
\u21d216a2<\/sup>+4b2<\/sup>+9c2<\/sup>-16ab+12bc-24ac<\/p>\n\n\n\n

(iii) (2x-y+z)2<\/sup><\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace a=2x,b=-y,c=-z
\u21d2(2x)2<\/sup>+(-y)2<\/sup>+(-z)2<\/sup>+2(2x)(-y)+2(-y)(-z)+2(-z)(2x)
\u21d24x2<\/sup>+y2<\/sup>+z2<\/sup>-4xy-2yz+4zx<\/p>\n\n\n\n

(iv) (2x+3y+z)2<\/sup><\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace a=2x,b=3y,c=z
\u21d2(2x)2<\/sup>+(3y)2<\/sup>+(z)2<\/sup>+2(2x)(3y)+2(3y)(z)+2(z)(2x)
\u21d24x2<\/sup>+9y2<\/sup>+z2<\/sup>+12xy+6yz+4zx<\/p>\n\n\n\n

(v) $\\left(\\dfrac{a}{3}-\\dfrac{b}{2}+2\\right)^2$<\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace $a=\\dfrac{a}{3},b=-\\dfrac{b}{2},c=2$
\u21d2$\\left(\\dfrac{a}{3}\\right)^2+\\left(-\\dfrac{b}{2}\\right)^2+(2)^2+2\\left(\\dfrac{a}{3}\\right)\\left(-\\dfrac{b}{2}\\right)+2\\left(-\\dfrac{b}{2}\\right)(2)+2(2)\\left(\\dfrac{a}{3}\\right)$
\u21d2$\\dfrac{a^2}{9}+\\dfrac{b^2}{4}+4-\\dfrac{ab}{3}+\\dfrac{4}{3}a-2b$<\/p>\n\n\n\n

(vi) (-2x+5y-3z)2<\/sup><\/strong>
Sol :
Using identity :
(a+b+c)2<\/sup>=a2<\/sup>+b2<\/sup>+c2<\/sup>+2ab+2bc+2ca
Replace a=-2x, b=5y, c=-3z
\u21d2(-2x)2<\/sup>+(5y)2<\/sup>+(-3z)2<\/sup>+2(-2x)(5y)+2(5y)(-3z)+2(-3z)(-2x)
\u21d24x2<\/sup>+25y2<\/sup>+9z2<\/sup>-20xy-30yz+12zx<\/p>\n\n\n\n

Question 4<\/h4>\n\n\n\n

\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0918\u0928\u094b \u0915\u094b \u092a\u094d\u0930\u0938\u093e\u0930\u093f\u0924 \u0930\u0941\u092a \u092e\u0947 \u0932\u093f\u0916\u093f\u090f
(i) (3a+4b)3<\/sup><\/strong>
Sol :
Using identity:
(x+y)3<\/sup>=x3<\/sup>+y3<\/sup>+3x2<\/sup>y+3xy2<\/sup>
Replace x=3a , y=4b
\u21d2(3a)3<\/sup>+(4b)3<\/sup>+3(3a)2<\/sup>(4b)+3(3a)(4b)2<\/sup>
\u21d227a3<\/sup>+64b3<\/sup>+108a2<\/sup>b+144ab2<\/sup><\/p>\n\n\n\n

(ii) (5p-3q)3<\/sup><\/strong>
Sol :
Using identity:
(x-y)3<\/sup>=x3<\/sup>-y3<\/sup>-3x2<\/sup>y+3xy2<\/sup>
Replace x=5p , y=3q
\u21d2(5p)3<\/sup>+(3q)3<\/sup>+3(5p)2<\/sup>(3q)+3(5p)(3q)2<\/sup>
\u21d2125p3<\/sup>-225p2<\/sup>q+135pq2<\/sup>-27q3<\/sup><\/p>\n\n\n\n

(iii) $\\left(3p-\\dfrac{1}{6}\\right)^3$<\/strong>
Sol :
Using identity:
(x-y)3<\/sup>=x3<\/sup>-y3<\/sup>-3x2<\/sup>y+3xy2<\/sup>
Replace x=3p , $y=\\dfrac{1}{6}$
\u21d2$(3p)^3-\\left(\\dfrac{1}{6}\\right)^3-3(3p)^2\\left(\\dfrac{1}{6}\\right)+3(3p)\\left(\\dfrac{1}{6}\\right)^2$
\u21d2$27p^3-\\dfrac{1}{216}-\\dfrac{9}{2}p^2+\\dfrac{1}{4}p$<\/p>\n\n\n\n

(iv) (4a-3b)3<\/sup><\/strong>
Sol :
Using identity:
(x-y)3<\/sup>=x3<\/sup>-y3<\/sup>-3x2<\/sup>y+3xy2<\/sup>
Replace x=3p , $y=\\dfrac{1}{6}$
\u21d2$(4a)^3-\\left(\\dfrac{1}{6}\\right)-3(3p)^2\\left(\\dfrac{1}{6}\\right)+3(3p)\\left(\\dfrac{1}{6}\\right)^2$
\u21d264a3<\/sup>-27b3<\/sup>-144a2<\/sup>b+108ab2<\/sup><\/p>\n\n\n\n

Question 5<\/h4>\n\n\n\n

\u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u092a\u094d\u0930\u092f\u094b\u0917 \u0915\u0930, \u0928\u093f\u092e\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947 \u0938\u0947 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f
(i) (104)3<\/sup><\/strong>
Sol :
=(100+4)3<\/sup>
Using identity:
(x+y)3<\/sup>=x3<\/sup>+y3<\/sup>+3x2<\/sup>y+3xy2<\/sup>
Replace x=100 , y=4
\u21d2(100)3<\/sup>+(4)3<\/sup>+3(100)2<\/sup>(4)+3(100)(4)2<\/sup>
\u21d21000000+64+3\u00d710000\u00d74+3\u00d7100\u00d716
\u21d21124864<\/p>\n\n\n\n

(ii) (999)3<\/sup><\/strong>
Sol :
=(1000-1)3<\/sup>
Using identity:
(x-y)3<\/sup>=x3<\/sup>-y3<\/sup>-3x2<\/sup>y+3xy2<\/sup>
Replace x=1000 , y=1
\u21d2(1000)3<\/sup>-(1)3<\/sup>-3(1000)2<\/sup>(1)+3(1000)(1)2<\/sup>
\u21d21000000000-1-3000000+3000
\u21d2997002999<\/p>\n\n\n\n

\n
KC Sinha Solutions<\/a><\/div>\n\n\n\n
KC Sinha Class 9 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 , b=3\u21d2x2+(3+3)x+3\u00d73\u21d2x2+6x+9 (ii) (x-3)(x+5)Sol :Using identity:(x+a)(x+b)=x2+(a+b)x+aba=-3 , b=5\u21d2x2+(-3+5)x+(-3)(5)\u21d2x2+2x-15 (iii) (5x+2)(5x-3)Sol:Using identity:(x+a)(x+b)=x2+(a+b)x+abreplace x=5x , a=2 , b=-3\u21d2(5x)2+(2-3)5x+(2)(-3)\u21d225×2-5x-6 (iv) $\\left(y^2-\\dfrac{5}{2}\\right)\\left(y^2+\\dfrac{7}{2}\\right)$Sol :Using identity :(x+a)(x+b)=x2+(a+b)x+abReplace x=y2 , $a=-\\dfrac{5}{2},b=\\dfrac{7}{2}$\u21d2$(y^2)^2+\\left(-\\dfrac{5}{2}+\\dfrac{7}{2}\\right)y^2+\\left(-\\dfrac{5}{2}\\right)\\left(\\dfrac{7}{2}\\right)$\u21d2$y^4+\\left(\\dfrac{-5+7}{2}\\right)y^2-\\dfrac{35}{4}$\u21d2$y^4+y^2-\\dfrac{35}{4}$ (v) (2x-1)(2x+5)Sol :Using identity :(x+a)(x+b)=x2+(a+b)x+abReplace x=2x , a=-1 ,b=5\u21d2(2x)2+(-1+5)2x+(-1)(5)\u21d24×2+8x-5 (vi) (5+2x)(5-2x)Sol :Using identity :a2-b2=(a+b)(a-b)Replace a=5 ,b=2x\u21d252-(2x)2\u21d225-4×2 […]<\/p>\n","protected":false},"author":302,"featured_media":625596,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[921],"tags":[],"boards":[],"class_list":["post-625594","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-9","entry"],"yoast_head":"\nKC Sinha: Exercise 4.1 - Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"KC Sinha: Exercise 4.1 - Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901\" \/>\n<meta property=\"og:description\" content=\"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-07T08:48:24+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-09-07T08:48:29+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1600\" \/>\n\t<meta property=\"og:image:height\" content=\"901\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"KC Sinha: Exercise 4.1 – Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901\",\"datePublished\":\"2023-09-07T08:48:24+00:00\",\"dateModified\":\"2023-09-07T08:48:29+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\"},\"wordCount\":783,\"publisher\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#organization\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg\",\"articleSection\":[\"class 9\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\",\"url\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\",\"name\":\"KC Sinha: Exercise 4.1 - Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901 - IndCareer Schools\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg\",\"datePublished\":\"2023-09-07T08:48:24+00:00\",\"dateModified\":\"2023-09-07T08:48:29+00:00\",\"description\":\"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,\",\"breadcrumb\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage\",\"url\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg\",\"contentUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg\",\"width\":1600,\"height\":901,\"caption\":\"KC Sinha: Exercise 4.4 - 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Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901 - IndCareer Schools","description":"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/","og_locale":"en_US","og_type":"article","og_title":"KC Sinha: Exercise 4.1 - Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901","og_description":"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,","og_url":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/","og_site_name":"IndCareer Schools","article_publisher":"https:\/\/www.facebook.com\/indcareer","article_published_time":"2023-09-07T08:48:24+00:00","article_modified_time":"2023-09-07T08:48:29+00:00","og_image":[{"width":1600,"height":901,"url":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg","type":"image\/jpeg"}],"author":"Pooja","twitter_card":"summary_large_image","twitter_creator":"@indcareer","twitter_site":"@indcareer","twitter_misc":{"Written by":"Pooja","Est. reading time":"3 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#article","isPartOf":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/"},"author":{"name":"Pooja","@id":"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e"},"headline":"KC Sinha: Exercise 4.1 – Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901","datePublished":"2023-09-07T08:48:24+00:00","dateModified":"2023-09-07T08:48:29+00:00","mainEntityOfPage":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/"},"wordCount":783,"publisher":{"@id":"https:\/\/www.indcareer.com\/schools\/#organization"},"image":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage"},"thumbnailUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg","articleSection":["class 9"],"inLanguage":"en-US"},{"@type":"WebPage","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/","url":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/","name":"KC Sinha: Exercise 4.1 - Mathematics Solution Class 9 Chapter 4 \u092c\u0940\u091c\u0940\u092f \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u090f\u0901 - IndCareer Schools","isPartOf":{"@id":"https:\/\/www.indcareer.com\/schools\/#website"},"primaryImageOfPage":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage"},"image":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage"},"thumbnailUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg","datePublished":"2023-09-07T08:48:24+00:00","dateModified":"2023-09-07T08:48:29+00:00","description":"Question 1 \u0909\u092a\u092f\u0941\u0915\u094d\u0924 \u0938\u0930\u094d\u0935\u0938\u092e\u093f\u0915\u093e\u0913 \u0915\u093e \u0909\u092a\u092f\u094b\u0917 \u0915\u0930 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0917\u0941\u0923\u0928\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f(i) (x+3)(x+3)Sol :Here we use identity(x+a)(x+a)=x2+(a+b)x+aba=3 ,","breadcrumb":{"@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-4-1-mathematics-solution-class-9-chapter-4-bijiy-sarvasamikaye\/#primaryimage","url":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg","contentUrl":"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-1-3-scaled.jpg","width":1600,"height":901,"caption":"KC Sinha: Exercise 4.4 - 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