{"id":625591,"date":"2023-09-07T08:38:56","date_gmt":"2023-09-07T08:38:56","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=625591"},"modified":"2023-09-07T08:39:01","modified_gmt":"2023-09-07T08:39:01","slug":"kc-sinha-exercise-3-2-mathematics-solution-class-9-chapter-3-bahupad","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-3-2-mathematics-solution-class-9-chapter-3-bahupad\/","title":{"rendered":"KC Sinha: Exercise 3.2 – Mathematics Solution Class 9 Chapter 3 \u092c\u0939\u0941\u092a\u0926"},"content":{"rendered":"\n\n\n\n\n

Question 1<\/h4>\n\n\n\n

\u0930\u093f\u0915\u094d\u0924 \u0938\u094d\u0925\u093e\u0928\u094b \u0915\u094b \u092d\u0930\u0947:
(i)<\/strong> x2<\/sup>+2x-3 \u0915\u094b x-1 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932=__
Sol :
p(x)=x2<\/sup>+2x-3
x-1=0<\/p>\n\n\n\n

x=1 \u092a\u0930,<\/p>\n\n\n\n

p(1)=(1)2<\/sup>+2(1)-3
=1+2-3
=0<\/p>\n\n\n\n

(ii)<\/strong> \u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 x-2 \u0939\u0948 \u0924\u094b p(2)=__
Sol :<\/p>\n\n\n\n

Question 2<\/h4>\n\n\n\n

y4<\/sup>+3y2<\/sup>+2y+1 \u0915\u094b y-1 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932 \u0915\u094d\u092f\u093e \u0939\u094b\u0917\u093e ?
Sol :
p(y)=y4<\/sup>+3y2<\/sup>+2y+1
y-1=0
y=1<\/p>\n\n\n\n

p(1)=(1)4<\/sup>+3(1)2<\/sup>+2(1)+1
=1-3+2+1
=1<\/p>\n\n\n\n

Question 3<\/h4>\n\n\n\n

Question 4<\/h4>\n\n\n\n

\u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u0947 \u0932\u093f\u090f p(-1)=3 \u0939\u094b \u0924\u094b \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u094b x+1 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932 \u0915\u094d\u092f\u093e \u0939\u094b\u0917\u093e?
Sol :
x+1=0
x=-1<\/p>\n\n\n\n

 \u0936\u0937\u092b\u0932=3<\/p>\n\n\n\n

Question 5<\/h4>\n\n\n\n

\u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u0947 \u0932\u093f\u090f $p\\left(\\frac{-2}{3}\\right)=0$ \u0924\u094b \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0932\u093f\u0916\u0947\u0964
Sol :
$x=-\\frac{2}{3}$
3x=-2
3x+2=0<\/p>\n\n\n\n

3x+2<\/p>\n\n\n\n

Question 6<\/h4>\n\n\n\n

\u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u0947 \u0932\u093f\u090f p(-3)=2 \u0939\u094b \u0924\u094b p(x)-2 \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0932\u093f\u0916\u0947 \u0964
Sol :
x=-3 , p(-3)=2<\/p>\n\n\n\n

p(x)-2=p(-3)-2
=2-2
=0<\/p>\n\n\n\n

x=-3
x+3=0<\/p>\n\n\n\n

\u2234x+3 , p(x)-2 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

Question 7<\/h4>\n\n\n\n

x3<\/sup>+3x2<\/sup>+3x+1 \u0915\u094b \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f \u0964
(i)<\/strong> x+1
Sol :
p(x)=x3<\/sup>+3x2<\/sup>+3x+1
x+1=0
x=-1<\/p>\n\n\n\n

p(-1)=(-1)3<\/sup>+3(-1)2<\/sup>+3(1)+1<\/p>\n\n\n\n

=-1+3-3+1<\/p>\n\n\n\n

=0<\/p>\n\n\n\n

(ii)<\/strong> $x-\\frac{1}{2}$
Sol :
$x-\\frac{1}{2}=0$<\/p>\n\n\n\n

$x=\\frac{1}{2}$<\/p>\n\n\n\n

$p\\left(\\frac{1}{2}\\right)=\\left(\\frac{1}{2}\\right)^3+3\\left(\\frac{1}{2}\\right)^2+3\\left(\\frac{1}{2}\\right)+1$<\/p>\n\n\n\n

$=\\frac{1}{8}+\\frac{3}{4}+\\frac{3}{2}+1$<\/p>\n\n\n\n

$=\\frac{1+6+12+8}{8}=\\frac{27}{8}$<\/p>\n\n\n\n

Question 12<\/h4>\n\n\n\n

\u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u092a\u094d\u0930\u092e\u0947\u092f \u0915\u093e \u092a\u094d\u0930\u092f\u094b\u0917 \u0915\u0930 \u092c\u0924\u093e\u092f\u0947 \u0915\u093f \u0915\u094d\u092f\u093e x-1 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 ?
(i)<\/strong> x3<\/sup>+x2<\/sup>-2x+1
Sol :
x-1=0
x=1
p(x)=x3<\/sup>+x2<\/sup>-2x+1
p(1)=13<\/sup>+12<\/sup>-2(1)+1<\/p>\n\n\n\n

=1+1-2+1<\/p>\n\n\n\n

=1<\/p>\n\n\n\n

x-1,x3<\/sup>+x2<\/sup>-2x+1 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0928\u0939\u0940 \u0939\u0948 \u0964<\/p>\n\n\n\n

(ii)<\/strong> 8x4<\/sup>-12x3<\/sup>+18x+14
Sol :<\/p>\n\n\n\n

(iii)<\/strong> x3<\/sup>+8x2<\/sup>-7x-2
Sol :<\/p>\n\n\n\n

(iv)<\/strong> $2\\sqrt{2}x^3+5\\sqrt{2}x^2-7\\sqrt{2}$
Sol :
x-1=0
x=1<\/p>\n\n\n\n

p(x)=$2\\sqrt{2}x^3+5\\sqrt{2}x^2-7\\sqrt{2}$<\/p>\n\n\n\n

p(1)=$2\\sqrt{2}(1)^3+5\\sqrt{2}(1)^2-7\\sqrt{2}$<\/p>\n\n\n\n

=2\u221a2+5\u221a2-7\u221a2<\/p>\n\n\n\n

=0<\/p>\n\n\n\n

\u2234x-1 , 2\u221a2x3<\/sup>+5\u221a2x3<\/sup>-7\u221a2 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

Question 13<\/h4>\n\n\n\n

\u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u092a\u094d\u0930\u092e\u0947\u092f \u0932\u093e\u0917\u0942 \u0915\u0930\u0915\u0947 \u092c\u0924\u093e\u0907\u090f \u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u094d\u0925\u093f\u0924\u093f\u092f\u094b \u092e\u0947 \u0938\u0947 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0938\u094d\u0925\u093f\u0924\u093f \u092e\u0947 g(x),p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940<\/p>\n\n\n\n

(i) p(x)=2x3<\/sup>+x2<\/sup>-2x-1 , g(x)=x+1<\/strong><\/p>\n\n\n\n

Sol :
x+1=0
x=-1<\/p>\n\n\n\n

p(-1)=2(-1)3<\/sup>+(-1)2<\/sup>-2(-1)-1
=-2+1+2-1
=0<\/p>\n\n\n\n

g(x),p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948<\/p>\n\n\n\n

(ii) p(x)=x3<\/sup>+3x2<\/sup>+3x+1 , g(x)=x+2<\/strong><\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

(iii) p(x)=x3<\/sup>-4x2<\/sup>+x+6 , g(x)=x-3<\/strong>
Sol :<\/p>\n\n\n\n

Question 14<\/h4>\n\n\n\n

(i)<\/strong> \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f 7+3x,3x3<\/sup>+7x \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940\u0964
Sol :
7+3x=0
3x=-7
$x=\\frac{-7}{3}$<\/p>\n\n\n\n

p(x)=3x3<\/sup>+7x
$p\\left(\\frac{-7}{3}\\right)=3\\left(\\frac{-7}{3}\\right)^3+7\\left(\\frac{-7}{3}\\right)$
$=3\\left(\\frac{-343}{7}\\right)-\\frac{49}{3}$
$=\\frac{-343}{9}-\\frac{49}{3}$<\/p>\n\n\n\n

7+3x, 3x3<\/sup>+7x \u0915\u0940 \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0928\u0939\u0940 \u0939\u0948 \u0964<\/p>\n\n\n\n

(ii)<\/strong> \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f x+2 \u092c\u0939\u0941\u092a\u0926\u094b x3<\/sup>+3x2<\/sup>+5x+6 \u0914\u0930 2x+4 \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940 \u0964
Sol :
x+2=0
x=-2<\/p>\n\n\n\n

p(x)=x3<\/sup>+3x2<\/sup>+5x+6 , g(x)=2x+4
p(-2)=(-2)3<\/sup>+3(-2)2<\/sup>+5(-2)+6
=-8+12-10+6
=-18+18
=0<\/p>\n\n\n\n

x+2, p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

g(-2)=2(-2)+4
=-4+4
=0<\/p>\n\n\n\n

x+2,g(x) \u0915\u093e  \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

(iii)<\/strong> \u091c\u093e\u0901\u091a \u0915\u0940\u091c\u093f\u090f \u0915\u093f \u092c\u0939\u0941\u092a\u0926\u094b q(t)=4t3<\/sup>+4t2<\/sup>-t-1 , 2t+1 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u092f\u093e \u0928\u0939\u0940 \u0964<\/p>\n\n\n\n

Sol :<\/p>\n\n\n\n

2t+1<\/p>\n\n\n\n

2t=-1<\/p>\n\n\n\n

$t=-\\frac{1}{2}$<\/p>\n\n\n\n

$q\\left(-\\frac{1}{2}\\right)=4\\left(-\\frac{1}{2}\\right)^2-\\left(-\\frac{1}{2}\\right)-1$
$=4\\left(-\\frac{1}{8}\\right)+4\\left(\\frac{1}{4}\\right)+\\frac{1}{2}+1$
$=-\\frac{1}{2}+1+\\frac{1}{2}-1$
=0<\/p>\n\n\n\n

\u0905\u0924\u0903 q(t) , 2t+1 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

Question 18<\/h4>\n\n\n\n

k \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0940\u091c\u093f\u090f \u091c\u092c\u0915\u093f \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u0938\u094d\u0925\u093f\u0924\u093f\u092f\u094b  \u092e\u0947 \u0938\u0947 \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0938\u094d\u0925\u093f\u0924\u093f \u092e\u0947 (x-1) , p(x) \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u094b
(i)<\/strong> p(x)=2x2<\/sup>+kx+\u221a2
x-1=0
x=1<\/p>\n\n\n\n

x-1 , p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

p(1)=0
2(1)2<\/sup>+k(1)+\u221a2=0
2+k+\u221a2=0
k=-(2+\u221a2)
=-2-\u221a2<\/p>\n\n\n\n

(ii)<\/strong> p(x)=kx2<\/sup>-3x+k
Sol :
x-1=0
x=1<\/p>\n\n\n\n

x-1 , p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

p(1)=0
k(1)2<\/sup>-3(1)+k=0
k-3+k=0
2k=3
$k=\\frac{3}{2}$<\/p>\n\n\n\n

Question 19<\/h4>\n\n\n\n

(a)<\/strong> \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092c\u0939\u0941\u092a\u0926\u094b\u0902 \u092e\u0947 \u092f\u0926\u093f \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092c\u0939\u0941\u092a\u0926 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u092e\u094d\u0921 x-2 \u0939\u094b, \u0924\u094b \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0938\u094d\u0925\u093f\u0924\u093f \u092e\u0947 a \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964
(i)<\/strong> x2<\/sup>-3x+5a
(ii)<\/strong> x3<\/sup>-2ax2<\/sup>+ax-1
Sol :
(ii) x-2=0
x=2
x=2<\/p>\n\n\n\n

x-2 , \u092c\u0939\u0941\u092a\u0926 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948<\/p>\n\n\n\n

(2)3<\/sup>-2a(2)2<\/sup>+a(2)-1
-6a+7=0
-6a=-7
$a=\\frac{7}{6}$<\/p>\n\n\n\n

(b)<\/strong> \u092f\u0926\u093f x-1 \u092c\u0939\u0941\u092a\u0926 ax3<\/sup>-4ax+4a-1 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0924\u094b a \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964<\/p>\n\n\n\n

(c)<\/strong> \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092c\u0939\u0941\u092a\u0926\u094b \u092e\u0947 \u092f\u0926\u093f x+a \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092c\u0939\u0941\u092a\u0926 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 , \u0924\u094b \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u0938\u094d\u0925\u093f\u0924\u093f \u092e\u0947 a \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964
(i)<\/strong> x3<\/sup>+ax2<\/sup>-2x+a+4
(ii)<\/strong> x4<\/sup>-a2<\/sup>x2<\/sup>+3x-a<\/p>\n\n\n\n

Sol :
(i)
x+a=0
x=-a<\/p>\n\n\n\n

x+a \u092c\u0939\u0941\u092a\u0926 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

(-a)3<\/sup>+a(-a)2<\/sup>-2(-a)+a+4=0
3a=-4
$a=-\\frac{4}{3}$<\/p>\n\n\n\n

(d)<\/strong> \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092c\u0939\u0941\u092a\u0926\u094b \u092e\u0947 \u092f\u0926\u093f x-a \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 \u092c\u0939\u0941\u092a\u0926 \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 , \u0924\u094b a \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964<\/p>\n\n\n\n

(i)<\/strong> x3<\/sup>-a2<\/sup>x+x+2<\/p>\n\n\n\n

(ii)<\/strong> x5<\/sup>-a2<\/sup>x3<\/sup>+2x+a+4<\/p>\n\n\n\n

Question 20<\/h4>\n\n\n\n

\u092f\u0926\u093f p(x)=x3<\/sup>+kx2<\/sup>+hx+6 \u0914\u0930 x+1 \u0924\u0925\u093e x-2 , p(x) \u0915\u0947 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 , \u0924\u094b h \u0914\u0930 k \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964
Sol :
x+1=0
x=-1<\/p>\n\n\n\n

x+1,p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

(-1)3<\/sup>+k(-1)2<\/sup>+h(-1)+6
-1+k-h+6=0
k-h+5=0
k-h=-5
k=h-5..(i)<\/p>\n\n\n\n

x-2=0
x=2
x-2, p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0939\u0948 \u0964<\/p>\n\n\n\n

(2)3<\/sup>+k(2)2<\/sup>+h(2)+6=0
8+4k+2h+6=0
4k+2h+14=0
2(2k+h+7)=0
2k+h+7=0<\/p>\n\n\n\n

k \u0915\u093e \u092e\u093e\u0928 \u0930\u0916\u0928\u0947 \u092a\u0930,
2(h-5)+h+7=0
2h-10+h+7=0
3h-3=0
3h=3
$h=\\frac{3}{3}$
h=1<\/p>\n\n\n\n

h \u0915\u093e \u092e\u093e\u0928 \u0938\u092e\u0940\u0915\u0930\u0923 (i) \u092e\u0947 \u0930\u0916\u0928\u0947 \u092a\u0930,
k=h-5
k=1-5
k=-4<\/p>\n\n\n\n

Question 23<\/h4>\n\n\n\n

\u092f\u0926\u093f (x-1) \u0924\u0925\u093e (x+4) \u092c\u0939\u0941\u092a\u0926 p(x)=(x2<\/sup>-3x+2)(x2<\/sup>+7x+a) \u0914\u0930 q(x)=(x2<\/sup>+5x+4)(x2<\/sup>-5x+b) \u0915\u0947 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 \u0939\u0948 \u0924\u094b a \u0914\u0930 b \u0915\u093e \u092e\u093e\u0928 \u091c\u094d\u091e\u093e\u0924 \u0915\u0930\u0947 \u0964
Sol :
x-1=0
x=1<\/p>\n\n\n\n

x-1,q(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0939\u0948 \u0964
(12<\/sup>-5(1)+4)(12<\/sup>-5(1)+b)=0
10(-4+b)=0<\/p>\n\n\n\n

-4+b=0<\/p>\n\n\n\n

b=4<\/p>\n\n\n\n

x+4=0
x=-4<\/p>\n\n\n\n

x+4,p(x) \u0915\u093e \u0917\u0941\u0923\u0928\u0916\u0902\u0921 \u0939\u0948 \u0964
((-4)2<\/sup>-3(-4)+2)(12<\/sup>+7(-4)+a)=0
30(-12+a)=0
-12+a=0
a=12<\/p>\n\n\n\n

Question 24<\/h4>\n\n\n\n

\u092f\u0926\u093f f(x)=x2<\/sup>+px+q ,g(x)=x2<\/sup>+lx+m \u0924\u0925\u093e \u092a\u094d\u0930\u0924\u094d\u092f\u0947\u0915 x+a \u0938\u0947 \u0935\u093f\u092d\u093e\u091c\u093f\u0924 \u0939\u094b\u0924\u093e \u0939\u0948 \u0924\u094b \u0926\u093f\u0916\u093e\u092f\u0947 \u0915\u093f $a=\\frac{m-q}{l-p}$
Sol :
x+a=0
x=-a<\/p>\n\n\n\n

x+a , \u0926\u094d\u0935\u093e\u0930\u093e f(x) \u0924\u0925\u093e g(x) \u0926\u094b\u0928\u094b \u0935\u093f\u092d\u093e\u091c\u0940\u0924 \u0939\u0948 \u0964
(-a)2<\/sup>+p(-a)+q=(-a)2<\/sup>+l(-a)+m<\/p>\n\n\n\n

(-a)2<\/sup>-pa+q=(-a)2<\/sup>-la+m<\/p>\n\n\n\n

la-pa=m-q<\/p>\n\n\n\n

(l-p)a=m-q<\/p>\n\n\n\n

$a=\\frac{m-q}{l-p}$<\/p>\n\n\n\n

\n
KC Sinha Solutions<\/a><\/div>\n\n\n\n
KC Sinha Class 9 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

Question 1 \u0930\u093f\u0915\u094d\u0924 \u0938\u094d\u0925\u093e\u0928\u094b \u0915\u094b \u092d\u0930\u0947:(i) x2+2x-3 \u0915\u094b x-1 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932=__Sol :p(x)=x2+2x-3x-1=0 x=1 \u092a\u0930, p(1)=(1)2+2(1)-3=1+2-3=0 (ii) \u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u093e \u090f\u0915 \u0917\u0941\u0923\u0928\u0916\u0923\u094d\u0921 x-2 \u0939\u0948 \u0924\u094b p(2)=__Sol : Question 2 y4+3y2+2y+1 \u0915\u094b y-1 \u0938\u0947 \u092d\u093e\u0917 \u0926\u0947\u0928\u0947 \u092a\u0930 \u0936\u0947\u0937\u092b\u0932 \u0915\u094d\u092f\u093e \u0939\u094b\u0917\u093e ?Sol :p(y)=y4+3y2+2y+1y-1=0y=1 p(1)=(1)4+3(1)2+2(1)+1=1-3+2+1=1 Question 3 Question 4 \u092f\u0926\u093f \u092c\u0939\u0941\u092a\u0926 p(x) \u0915\u0947 \u0932\u093f\u090f p(-1)=3 […]<\/p>\n","protected":false},"author":302,"featured_media":625593,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[921],"tags":[],"boards":[],"class_list":["post-625591","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-9","entry"],"yoast_head":"\nKC Sinha: Exercise 3.2 - 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