{"id":624351,"date":"2023-09-01T10:38:02","date_gmt":"2023-09-01T10:38:02","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=624351"},"modified":"2023-09-01T10:38:33","modified_gmt":"2023-09-01T10:38:33","slug":"kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry\/","title":{"rendered":"KC Sinha: Exercise 10.1 &#8211; Mathematics Solution Class 10 Chapter 10 Coordinate Geometry"},"content":{"rendered":"\n<p> <\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-d\">Question 1 D<\/h4>\n\n\n\n<p><strong>In which quadrants do the following points lie:<\/strong><br><img loading=\"lazy\" decoding=\"async\" height=\"59\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711220764979.png\" width=\"59\"><\/p>\n\n\n\n<p>Sol :<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" height=\"233\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711221464160.jpg\" width=\"334\"><br>Given coordinate&nbsp;\\left(\\frac{3}{2}, 5\\right)lies,&nbsp;in Quadrant I because as shown in the figure that those coordinate who have (+, +) sign lies in IV quadrants or can say whose x-axis is \u201c+\u201d and y-axis is also \u201c+\u201c lies in I Quadrant.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-e\">Question 1 E<\/h4>\n\n\n\n<p><strong>In which quadrants do the following points lie:<\/strong><br><strong>(3, 0)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"233\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711222908923.jpg\" width=\"334\"><br>Given coordinate is (3,0). This point lies on the x-axis because its y-axis is on origin. Therefore, it lies on the x-axis between the Quadrant I and Quadrant IV.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-f\">Question 1 F<\/h4>\n\n\n\n<p><strong>In which quadrants do the following points lie:<\/strong><br><strong>(0, -5)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"233\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711223623860.jpg\" width=\"334\"><br>Given coordinate is (0, -5). This point lies on the y-axis because its x-axis is on origin. Therefore, it lies on the y-axis between the Quadrant III and Quadrant IV.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-a\">Question 2 A<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(4, 5)<\/strong><\/p>\n\n\n\n<p>Sol :<br>Here is the graph for coordinate (4,5)<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711224330238.png\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-b\">Question 2 B<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(-2,-7)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"494\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711225054619.png\" width=\"508\"><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-c\">Question 2 C<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(6,-2)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"334\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711225787447.jpg\" width=\"526\"><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-d\">Question 2 D<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(-4, 2)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"391\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711226718945.jpg\" width=\"484\"><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-e\">Question 2 E<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(4, 0)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"472\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711227704934.png\" width=\"544\"><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-f\">Question 2 F<\/h4>\n\n\n\n<p><strong>Plot the following points in a rectangular coordinate system:<\/strong><br><strong>(0, 3)<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"449\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/156171122843100.png\" width=\"468\"><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3\">Question 3<\/h4>\n\n\n\n<p><strong>Where does the point having y-coordinate -5 lie?<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"440\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711229172341.png\" width=\"509\"><\/p>\n\n\n\n<p>The point having -5 lies on the on the y-axis on the negative side because here x-axis is 0 and when x-axis is 0 then points lies on the y-axis and when y-axis is 0 then point lies on the x-axis.<\/p>\n\n\n\n<p>We can show it on graph with points (0, -5).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4\">Question 4<\/h4>\n\n\n\n<p><strong>If three vertices of a rectangle are (-2, 0), (2, 0), (2, 1) find the coordinates of the fourth vertex.<\/strong><\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" height=\"307\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711229914951.png\" width=\"491\"><br>Sol :<br>Here we have three vertices of rectangle say A (-2, 0) B (2, 0) and C (2, 1) so when we start graphing it on the graph as shown in the graph below then after plotting all three vertices you will get something like this.<\/p>\n\n\n\n<p>Therefore, after joining all the vertices with a line segment, we will get our&nbsp;fourth vertex because in rectangle opposites sides are parallel and all the angles are right angle so, by joining all the lines according to properties of the rectangle you will get the fourth vertex. So fourth vertex of a rectangle is (-2, 1).<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711231105140.png\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-5\">Question 5<\/h4>\n\n\n\n<p><strong>Draw the triangle whose vertices are (2, 3), (-4, 2) and (3, -1).<\/strong><\/p>\n\n\n\n<p>Sol :<br>It is easy to draw a triangle when it\u2019s all vertices are given. We have to just locate all the given points on the graph and join them with a line as shown in the graph below.<\/p>\n\n\n\n<p>Step 1. Locate all the vertices on the graph.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711232065242.png\" alt=\"\"\/><\/figure>\n\n\n\n<p>Step 2. Joins all the vertices with a line and it will form a triangle.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711233024550.png\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-6\">Question 6<\/h4>\n\n\n\n<p><strong>The base of an equilateral triangle with side 2a lies along the y-axis such that the mid-point of the base is at the origin. Find <\/strong><strong>the vertices of the triangle.<\/strong><\/p>\n\n\n\n<p>Sol :<br><img loading=\"lazy\" decoding=\"async\" height=\"258\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711234202628.jpg\" width=\"347\"><\/p>\n\n\n\n<p>Given that the base of the equilateral triangle is on the y-axis and mid-point of the base is at the origin, so its figure will be like this as shown.<\/p>\n\n\n\n<p>So here, O(0,0) is the midpoint of the base.<\/p>\n\n\n\n<p>An equilateral&nbsp;triangle has all sides equal so if O is the mid-point of the base BC, so B and C are the two vertices of the triangle. Now we have two vertices of the triangle, which is the base of equilateral triangle lying on the y-axis. Now if base in on y-axis then x-axis are as bisector of the base and so our third vertices will be on the x-axis either left or right.<\/p>\n\n\n\n<p>So now in right \u2206BOA<\/p>\n\n\n\n<p>Pythagoras Theorem: In a right-angled triangle the square of the biggest side(hypotenuse) equals the sum of the squares of the other two sides(Perpendicular and base).<\/p>\n\n\n\n<p>BO<sup>2<\/sup>&nbsp;+ OA<sup>2<\/sup>&nbsp;= AB<sup>2<\/sup>&nbsp;{ By Pythagoras theorem}<\/p>\n\n\n\n<p>a<sup>2<\/sup>&nbsp;+ OA<sup>2<\/sup>&nbsp;= (2a)&nbsp;<sup>2<\/sup><\/p>\n\n\n\n<p>OA<sup>2<\/sup>&nbsp;= 4a<sup>2<\/sup>&#8211; a<sup>2<\/sup><\/p>\n\n\n\n<p>OA<sup>2<\/sup>&nbsp;= 3a<sup>2<\/sup><\/p>\n\n\n\n<p>OA = \u00b1a\u221a3<br>So vertices of triangle are A(\u00b1a\u221a3,0) B(0,a)and C(0,-a).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-7\">Question 7<\/h4>\n\n\n\n<p><strong>Let ABCD be a rectangle such that AB = 10 units and BC = 8 units. Taking AB and AD as x and y-axes respectively, find the coordinates of A, B, C and D.<\/strong><\/p>\n\n\n\n<p>Sol :<br>Since AB and AD both have as an endpoint, we can find the coordinate of A by finding the intersection of the two sides.<\/p>\n\n\n\n<p>So the coordinates of A will be where the x-axis and y-axis intersect.<\/p>\n\n\n\n<p>As we know AB lies on the x-axis so the coordinates of B can be found by using the coordinates of A and changing the x-coordinate by the measure of AB.<\/p>\n\n\n\n<p>As we know the opposite side of a rectangle, AD and BC are congruent. Now if we have a measure of BC, we can simply find the y-coordinate of D.<\/p>\n\n\n\n<p>Since AB and AD are the x and y-axes, A is at(0,0), B is at (10,0), C is at (10,8), and D is at (0,8).<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/156171123490326.jpg\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-8\">Question 8<\/h4>\n\n\n\n<p><strong>ABCD is a square having a length of a side 20 units. Taking the centre of the square as the origin and x and y-axes parallel to AB and AD respectively, find the coordinates of A, B, C and D.<\/strong><\/p>\n\n\n\n<p>Sol :<br>Square ABCD. Center = O(0,0) Origin.<\/p>\n\n\n\n<p>AB = BC = 20 units.<\/p>\n\n\n\n<p>Y-coordinates of AB = \\frac{0-20}{2}&nbsp;= -10<\/p>\n\n\n\n<p>Y-coordinates of AD = \\frac{0+20}{2}&nbsp;= 10<\/p>\n\n\n\n<p>\u2234the coordinates are :-<\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" height=\"276\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1561711237303880.jpg\" width=\"279\"><br>A(-10,-10)<br>B(10,-10)<br>C(10,10)<br>D(-10,10)<\/p>\n\n\n\n<p>      <div class=\"wp-block-buttons\"> <div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solutions\/\">KC Sinha Solutions<\/a><\/div>   <div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solution-for-class-10\/\">KC Sinha Class 10 Solutions<\/a><\/div> <\/div> <\/p>\n","protected":false},"excerpt":{"rendered":"<p>Question 1 D In which quadrants do the following points lie: Sol : Given coordinate&nbsp;\\left(\\frac{3}{2}, 5\\right)lies,&nbsp;in Quadrant I because as shown in the figure that those coordinate who have (+, +) sign lies in IV quadrants or can say whose x-axis is \u201c+\u201d and y-axis is also \u201c+\u201c lies in I Quadrant. Question 1 E [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":624428,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[24],"tags":[],"boards":[],"class_list":["post-624351","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-10","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>KC Sinha: Exercise 10.1 - Mathematics Solution Class 10 Chapter 10 Coordinate Geometry - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Question 1 D In which quadrants do the following points lie: Sol : Given coordinate&nbsp;left(frac{3}{2}, 5right)lies,&nbsp;in Quadrant I because as\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"KC Sinha: Exercise 10.1 - Mathematics Solution Class 10 Chapter 10 Coordinate Geometry\" \/>\n<meta property=\"og:description\" content=\"Question 1 D In which quadrants do the following points lie: Sol : Given coordinate&nbsp;left(frac{3}{2}, 5right)lies,&nbsp;in Quadrant I because as\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2023-09-01T10:38:02+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-09-01T10:38:33+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/indcareer-schools-2-21-scaled.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1600\" \/>\n\t<meta property=\"og:image:height\" content=\"901\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"8 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-10-1-mathematics-solution-class-10-chapter-10-coordinate-geometry\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"KC Sinha: Exercise 10.1 &#8211; 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