{"id":624306,"date":"2023-09-01T08:06:18","date_gmt":"2023-09-01T08:06:18","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=624306"},"modified":"2023-09-01T08:06:26","modified_gmt":"2023-09-01T08:06:26","slug":"kc-sinha-exercise-7-4-mathematics-solution-class-10-chapter-7-quadratic-equations","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-7-4-mathematics-solution-class-10-chapter-7-quadratic-equations\/","title":{"rendered":"KC Sinha: Exercise 7.4 &#8211; Mathematics Solution Class 10 Chapter 7 Quadratic Equations"},"content":{"rendered":"\n\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-a\">Question 1 A<\/h4>\n\n\n\n<p><strong>Write the discriminate of each of the following quadratic equation:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;+ 4x + 3 =0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (4)<sup>2<\/sup>&nbsp;\u2013 4 (1) (3)<br>d = 16 \u2013 12<br>d = 4<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-b-nbsp\">Question 1 B&nbsp;<\/h4>\n\n\n\n<p><strong>Write the discriminate of each of the following quadratic equation:<\/strong><\/p>\n\n\n\n<p><strong>4x<sup>2<\/sup>&nbsp;+ 5x + 7 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (5)<sup>2<\/sup>&nbsp;\u2013 4 (4) (7)<br>d = 25 \u2013 112<br>d = \u201387<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-c\">Question 1 C<\/h4>\n\n\n\n<p><strong>Write the discriminate of each of the following quadratic equation:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>&nbsp;+ 4x + 5 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (4)<sup>2<\/sup>&nbsp;\u2013 4 (2) (5)<br>d = 16 \u2013 40<br>d = \u201324<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-d\">Question 1 D<\/h4>\n\n\n\n<p><strong>Write the discriminate of each of the following quadratic equation:<\/strong><\/p>\n\n\n\n<p><strong>3x<sup>2<\/sup>&nbsp;+ 5x + 6 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (5)<sup>2<\/sup>&nbsp;\u2013 4 (3) (6)<br>d = 25 \u2013 72<br>d = \u201347<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-e\">Question 1 E<\/h4>\n\n\n\n<p><strong>Write the discriminate of each of the following quadratic equation:<\/strong><\/p>\n\n\n\n<p><strong>\u221a3 x<sup>2<\/sup>&nbsp;\u2014 2\u221a2&nbsp;\u2013&nbsp;2\u221a3 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>\u2013&nbsp;4ac<br>d = (\u20132\u221a2)<sup>2<\/sup>&nbsp;\u2013 4 (\u221a3) (\u20132\u221a3)<br>d = 8 + 24<br>d = 32<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-a\">Question 2 A<\/h4>\n\n\n\n<p><strong>Examine whether the following quadratic equations have real roots or not:<\/strong><\/p>\n\n\n\n<p><strong>7x<sup>2<\/sup>&nbsp;+ 8x \u2014 1 = 0<\/strong><br>Sol :<br>TO CHECK REAL ROOTS, \u2018d\u2019 SHOULD BE GREATER THAN 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (8)<sup>2<\/sup>2 \u2013 4 (7) (\u20131)<br>d = 64 \u2013 28<br>d = 92<br>Yes, roots are real.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-b-nbsp\">Question 2 B&nbsp;<\/h4>\n\n\n\n<p><strong>Examine whether the following quadratic equations have real roots or not:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>&nbsp;+ 3x + 4 = 0<\/strong><br>Sol :<br>TO CHECK REAL ROOTS, \u2018d&#8217; SHOULD BE GREATER THAN 0.<br>d = b<sup>2<\/sup>\u2013&nbsp;4ac<br>d = (3)<sup>2<\/sup>&nbsp;\u2013&nbsp;4(2)(4)<br>d = 9&nbsp;\u2013&nbsp;32<br>d =&nbsp;\u2013&nbsp;23<br>No, roots aren\u2019t real.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-c\">Question 2 C<\/h4>\n\n\n\n<p><strong>Examine whether the following quadratic equations have real roots or not:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;\u2014 12x \u2014 16 = 0<\/strong><br>Sol :<br>TO CHECK REAL ROOTS, \u2018d&#8217; SHOULD BE GREATER THAN 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u201312)<sup>2<\/sup>&nbsp;\u2013 4 (1) (\u201316)<br>d = 144 \u2013 64<br>d = 208<br>Yes, roots are real .<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-d\">Question 2 D<\/h4>\n\n\n\n<p><strong>Examine whether the following quadratic equations have real roots or not:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;+ x \u2013 1= 0<\/strong><br>Sol :<br>TO CHECK REAL ROOTS, \u2018d&#8217; SHOULD BE GREATER THAN 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (1)<sup>2<\/sup>&nbsp;\u2013 4 (1) (\u20131)<br>d = 1 + 4<br>d = 5<br>Yes, roots are real.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-e\">Question 2 E<\/h4>\n\n\n\n<p><strong>Examine whether the following quadratic equations have real roots or not:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;\u2014 10x + 2 = 0<\/strong><br>Sol :<br>TO CHECK REAL ROOTS, \u2018d&#8217; SHOULD BE GREATER THAN 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u201310)<sup>2<\/sup>&nbsp;\u2013 4 (1) (2)<br>d = 100 \u2013 8<br>d = 92<br>Yes, roots are real.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-a\">Question 3 A<\/h4>\n\n\n\n<p><strong>Find whether the following quadratic equations have a repeated root :<\/strong><\/p>\n\n\n\n<p><strong>9x<sup>2<\/sup>\u2014 12x + 4 = 0<\/strong><br>Sol :<br>REPEATED ROOTS MEAN d = 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u201312)<sup>2<\/sup>&nbsp;\u2013 4(9)(4)<br>d = 144 \u2013 144<br>d = 0<br>Yes, roots are repeated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-b-nbsp\">Question 3 B&nbsp;<\/h4>\n\n\n\n<p><strong>Find whether the following quadratic equations have a repeated root :<\/strong><\/p>\n\n\n\n<p><strong>y<sup>2<\/sup>&nbsp;\u2014 6y + 6 = 0<\/strong><br>Sol :<br>REPEATED ROOTS MEAN d = 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20136)<sup>2<\/sup>&nbsp;\u2013 4(1)(6)<br>d = 36 \u2013 24<br>d = 12<br>\u2234&nbsp;roots are not repeated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-c\">Question 3 C<\/h4>\n\n\n\n<p><strong>Find whether the following quadratic equations have a repeated root :<\/strong><\/p>\n\n\n\n<p><strong>9x<sup>2<\/sup>&nbsp;+ 4x + 6 = 0<\/strong><br>Sol :<br>REPEATED ROOTS MEAN d = 0.<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (4)<sup>2<\/sup>&nbsp;\u2013 4 (9) (6)<br>d = 16 \u2013 216<br>d = \u2013200<br>\u2234&nbsp;roots are not repeated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-d\">Question 3 D<\/h4>\n\n\n\n<p><strong>Find whether the following quadratic equations have a repeated root :<\/strong><\/p>\n\n\n\n<p><strong>16y<sup>2<\/sup>\u2014 40y + 25 = 0<\/strong><br>Sol :<br>REPEATED ROOTS MEAN d = 0 .<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u201340)<sup>2<\/sup>&nbsp;\u2013 4 (16) (25)<br>d = 1600 \u2013 1600<br>d = 0<br>\u2234&nbsp;roots are repeated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-e\">Question 3 E<\/h4>\n\n\n\n<p><strong>Find whether the following quadratic equations have a repeated root :<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;+ 6x + 9 = 0<\/strong><br>Sol :<\/p>\n\n\n\n<p>REPEATED ROOTS MEAN d = 0 .<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (6)<sup>2<\/sup>&nbsp;\u2013 4(1)(9)<br>d = 36 \u2013 36<br>d = 0<br>\u2234&nbsp;roots are repeated.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4-a\">Question 4 A<\/h4>\n\n\n\n<p><strong>Comment upon the nature of roots of the following equations:<\/strong><\/p>\n\n\n\n<p><strong>4x<sup>2<\/sup>&nbsp;+ 7x + 2 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (7)<sup>2<\/sup>&nbsp;\u2013 4 (4) (2)<br>d = 49 \u2013 32<br>d = 17<br>Since, d&gt;0, roots are unique and real.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4-b-nbsp\">Question 4 B&nbsp;<\/h4>\n\n\n\n<p><strong>Comment upon the nature of roots of the following equations:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;+ 10x + 39 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (10)<sup>2<\/sup>&nbsp;\u2013 4 (1) (39)<br>d = 100 \u2013 156<br>d = \u201356<br>Since, d &lt; 0, no real roots exists.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-5-a\">Question 5 A<\/h4>\n\n\n\n<p><strong>Without solving, determine whether the following equations have real roots or not. If yes, find them:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>\u2014 4x + 3 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20134)<sup>2<\/sup>&nbsp;\u2013 4 (2) (3)<br>d = 16 \u2013 24<br>d = \u20138<br>Since, d &lt; 0, no real roots exist for the given equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-5-b\">Question 5 B<\/h4>\n\n\n\n<p><strong>Without solving, determine whether the following equations have real roots or not. If yes, find them:<\/strong><\/p>\n\n\n\n<p>y2\u221223y+19=0<\/p>\n\n\n\n<p>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d=(\u221223)2\u22124(1)(19)<br>d=49\u221249<br>d = 0<br>Since, d = 0, roots are real and equal for the given equation.<br>x=\u2212b\u00b1d\u221a2a<br>x=\u2212(\u221223)\u00b10\u221a2\u00d71<br>x=23\u00d712<br>x=13<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-6-a\">Question 6 A<\/h4>\n\n\n\n<p><strong>Without finding the roots, comment upon the nature of roots of each of the following quadratic equations:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>\u2014 6x + 3 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20136)<sup>2<\/sup>&nbsp;\u2013 4 (2) (3)<br>d = 36 \u2013 24<br>d = 12<br>\u2234&nbsp;Roots are real and unique.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-6-b\">Question 6 B<\/h4>\n\n\n\n<p><strong>Without finding the roots, comment upon the nature of roots of each of the following quadratic equations:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>&nbsp;\u2014 5x \u2014 3 = 0<\/strong><br>Sol :<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20135)<sup>2<\/sup>&nbsp;\u2013 4 (2) (\u20133)<br>d = 25 + 24<br>d = 49<br>\u2234&nbsp;Roots are real and unique.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-7-a-nbsp\">Question 7 A&nbsp;<\/h4>\n\n\n\n<p><strong>Find the value of k for which the quadratic equation<\/strong><\/p>\n\n\n\n<p><strong>4x<sup>2<\/sup>&nbsp;\u2014 2 (k + 1) x + (k + 4) = 0 has equal roots.<\/strong><br>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 \u2026.(1)<br>4x<sup>2<\/sup>&nbsp;\u2014 2 (k + 1) x + (k + 4) = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20132 (k + 1)<sup>2<\/sup>&nbsp;\u2013 4 (4) (k + 4)<br>d = (\u2013 2k \u2013 2)<sup>2<\/sup>&nbsp;\u2013 16k \u2013 64<br>d = 4k<sup>2<\/sup>&nbsp;+ 4 + 8k \u2013 16k \u2013 64<br>(\u2235&nbsp;(a \u2013 b)<sup>2<\/sup>&nbsp;= a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>&nbsp;\u2013 2ab)<br>d = 4k<sup>2<\/sup>&nbsp;\u2013 8k \u2013 60<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>4k<sup>2<\/sup>&nbsp;\u2013 8k \u2013 60 = 0<br>Dividing by 4<br>k<sup>2<\/sup>&nbsp;\u2013 2k \u2013 15 = 0<br>4k<sup>2<\/sup>&nbsp;\u2013 5k + 3k \u2013 15 = 0<br>k (k \u2013 5) + 3(k \u2013 5) = 0<br>(k \u2013 5) (k + 3) = 0<br>K \u2013 5 = 0 k + 3 = 0<br>K = 5 k = \u20133<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-7-b\">Question 7 B<\/h4>\n\n\n\n<p><strong>Find the value of k, so that the quadratic equation<\/strong><\/p>\n\n\n\n<p><strong>(k + 1) x<sup>2<\/sup>&nbsp;\u2013 2 (k \u2014 1) x + 1 = 0 has equal roots.<\/strong><br>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 \u2026.(1)<br>(k + 1)x<sup>2<\/sup>&nbsp;\u2014 2 (k \u2013 1) x + 1 = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20132(k\u20131))<sup>2<\/sup>\u2013 4(k+1)(1)<br>d = (\u20132k+2)<sup>2<\/sup>&nbsp;\u2013 4k \u2013 4<br>d=4k<sup>2<\/sup>&nbsp;+ 4 \u2013 8k \u2013 4k \u2013 4<br>(\u2235&nbsp;(a + b)<sup>2<\/sup>&nbsp;= a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>&nbsp;+ 2ab)<br>d = 4k<sup>2<\/sup>&nbsp;\u2013 12k<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>0 = 4k<sup>2<\/sup>&nbsp;\u2013 12k<br>4k<sup>2<\/sup>&nbsp;= 12k<br>k2=124k<br>k<sup>2<\/sup>&nbsp;= 3k<br>k<sup>2<\/sup>&nbsp;\u2013 3k = 0<br>k(k \u2013 3) = 0<br>k = 0 or k \u2013 3 = 0<br>k = 3<br>\u2234&nbsp;Values of k are 0, 3.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-8-a\">Question 8 A<\/h4>\n\n\n\n<p><strong>For what values of k, does the following quadratic equation has equal roots.<\/strong><\/p>\n\n\n\n<p><strong>9x<sup>2<\/sup>&nbsp;+ 8kx + 16 = 0<\/strong><br>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 (1)<br>9x<sup>2<\/sup>&nbsp;+ 8kx + 16 = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (8k)<sup>2<\/sup>&nbsp;\u2013 4 (9) (16)<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>0 = 64k<sup>2<\/sup>&nbsp;\u2013 576<br>k2=57664<br>k<sup>2<\/sup>&nbsp;= 9<br>k = \u00b1\u221a9<br>k = 3, \u20133<br>\u2234&nbsp;values of k are \u20133, 3 .<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-8-b\">Question 8 B<\/h4>\n\n\n\n<p><strong>(k + 4)x<sup>2<\/sup>&nbsp;+ (k + 1)x + 1 = 0<\/strong><\/p>\n\n\n\n<p>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 (1)<br>(k + 4)x<sup>2<\/sup>&nbsp;+ (k + 1)x + 1 = 0<br>d=b<sup>2<\/sup>\u20134ac<br>d = (k \u2013 1)<sup>2<\/sup>\u2013 4 (k + 4) (1)<br>d = (\u20132k + 2)<sup>2<\/sup>&nbsp;\u2013 4k \u2013 4<br>d = k<sup>2<\/sup>&nbsp;+ 1+ 2k \u2013 4k \u2013 16<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>0 = k<sup>2<\/sup>&nbsp;+ 1 + 2k \u2013 4k \u2013 16<br>k<sup>2<\/sup>&nbsp;\u2013 2k \u2013 15 = 0<br>k<sup>2<\/sup>&nbsp;\u2013 5k + 3k \u2013 15 = 0<br>k(k \u2013 5) + 3 (k \u2013 5) = 0<br>(k \u2013 5) (k + 3) = 0<br>K \u2013 5 = 0 k + 3 = 0<br>k = 5 k = \u20133<br>\u2234&nbsp;Values of k are \u20133, 5.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-8-c\">Question 8 C<\/h4>\n\n\n\n<p><strong>k<sup>2<\/sup>x<sup>2<\/sup>&nbsp;\u2014 2(2k \u2014 1)x + 4 = 0<\/strong><\/p>\n\n\n\n<p>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 (1)<br>k<sup>2<\/sup>x<sup>2<\/sup>&nbsp;\u2014 2(2k \u2014 1)x + 4 = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20132(k\u20131))<sup>2<\/sup>&nbsp;\u2013 4 (k<sup>2<\/sup>) (4)<br>d = (\u20132k+2)<sup>2<\/sup>&nbsp;\u2013 4k \u2013 4<br>d = (\u20134k+2)<sup>2<\/sup>&nbsp;\u2013 16k<sup>2<\/sup><br>(\u2235&nbsp;(a \u2013 b)<sup>2<\/sup>&nbsp;= a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>&nbsp;\u2013 2ab)<br>d = 16k<sup>2<\/sup>&nbsp;\u2013 16k + 4 \u2013 16k<sup>2<\/sup><br>d = \u201316k + 4<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>0 = \u201316k + 4<br>16k = 4<br><img loading=\"lazy\" decoding=\"async\" height=\"42\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1545983036542730.png\" width=\"53\"><br><img loading=\"lazy\" decoding=\"async\" height=\"42\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1545983037270313.png\" width=\"43\"><br>\u2234&nbsp;Values of k are is&nbsp;<img loading=\"lazy\" decoding=\"async\" height=\"32\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/09\/1545983037998861.png\" width=\"7\">.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-9-nbsp\">Question 9&nbsp;<\/h4>\n\n\n\n<p><strong>If the roots of the equation (a \u2014 b)x<sup>2<\/sup>&nbsp;+ (b \u2014 c) x + (c \u2014 a) = 0 are equal, prove that 2a = b + c.<\/strong><\/p>\n\n\n\n<p>Sol :<br>Since roots are equal<br>\u2234&nbsp;d=0 (1)<br>(a \u2014 b)x<sup>2<\/sup>&nbsp;+ (b \u2014 c) x + (c \u2014 a) = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (b\u2013c)<sup>2<\/sup>&nbsp;\u2013 4 (a\u2013b) (c\u2013a)<br>d = b<sup>2<\/sup>&nbsp;+ c<sup>2<\/sup>&nbsp;\u2013 2bc \u20134 [a (c \u2013 a) \u2013 b (c \u2013 a)]<br>d = b<sup>2<\/sup>&nbsp;+ c<sup>2<\/sup>&nbsp;\u2013 2bc \u2013 4 [ac \u2013 a<sup>2<\/sup>&nbsp;\u2013 bc + ba]<br>From (1), d = 0<br>\u2234&nbsp;Equation will be:<br>0 = b<sup>2<\/sup>&nbsp;+ c<sup>2<\/sup>&nbsp;\u2013 2bc \u2013 4ac + 4a<sup>2<\/sup>&nbsp;+ 4bc \u2013 4ba<br>b<sup>2<\/sup>&nbsp;+ c<sup>2<\/sup>&nbsp;\u2013 (2a)<sup>2<\/sup>&nbsp;2bc + 2c (\u20132a) + 2(\u20132a)b = 0<br>(b + c \u2013 2a)<sup>2<\/sup>&nbsp;= 0<br>(b + c \u2013 2a) = 0<br>b + c = 2a<br>Hence proved.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-10\">Question 10<\/h4>\n\n\n\n<p><strong>If \u2014 5 is a root of the quadratic equation 2x<sup>2<\/sup>&nbsp;+ 2px \u2014 15 = 0 and the quadratic equation p (x<sup>2<\/sup>&nbsp;+ x) + k = 0 has equal roots, find the value of k.<\/strong><\/p>\n\n\n\n<p>Sol :<br>2x<sup>2<\/sup>&nbsp;+ 2px \u2014 15 = 0<br>Put x = \u20135<br>2(\u20135)<sup>2<\/sup>&nbsp;+ 2p(\u20135) \u2014 15 = 0<br>50 \u2013 10p \u2013 15 = 0<br>35 = 10p<br>p = 3.5<br>Equation p (x<sup>2<\/sup>&nbsp;+ x) + k = 0 has equal roots i.e. d = 0<br>p (x<sup>2<\/sup>&nbsp;+ x) + k = 0<br>p = 3.5<br>3.5 (x<sup>2<\/sup>&nbsp;+ x) + k = 0<br>3.5x<sup>2<\/sup>&nbsp;+ 3.5x + k = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (3.5)<sup>2<\/sup>&nbsp;\u2013 4(3.5)(k)<br>d = 12.25 \u2013 14k<br>Putting d = 0<br>\u2234&nbsp;Equation will be:<br>0 = 12.25 \u2013 14k<br>14k = 12.25<br>k=12.2514<br>k = 0.875<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11-a\">Question 11 A<\/h4>\n\n\n\n<p><strong>Find the values of k, for which the given equation has real roots:<\/strong><\/p>\n\n\n\n<p><strong>2x<sup>2<\/sup>&nbsp;\u2014 10x + k = 0<\/strong><\/p>\n\n\n\n<p>Sol :<br>Roots are equal<br>\u2234&nbsp;d = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u201310)<sup>2<\/sup>&nbsp;\u2013 4 (2) (k)<br>d = 100 \u2013 8k<br>Put d = 0<br>0 = 100 \u2013 8k<br>8k = 100<\/p>\n\n\n\n<p>k=1008<\/p>\n\n\n\n<p>k=252<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11-b\">Question 11 B<\/h4>\n\n\n\n<p><strong>Find the values of k, for which the given equation has real roots:<\/strong><\/p>\n\n\n\n<p><strong>kx<sup>2<\/sup>&nbsp;\u2014 6x \u2014 2 = 0<\/strong><br>Sol :<br>Roots are equal<br>\u2234&nbsp;d = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20136)<sup>2<\/sup>&nbsp;\u2013 4 (\u20132) (k)<br>d = 36 + 8k<br>Put d = 0<br>0 = 36 + 8k<br>\u20138k = 36<\/p>\n\n\n\n<p>k=\u2212368<\/p>\n\n\n\n<p>k=\u221292<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11-c\">Question 11 C<\/h4>\n\n\n\n<p><strong>Find the values of k, for which the given equation has real roots:<\/strong><\/p>\n\n\n\n<p><strong>kx<sup>2<\/sup>+ 4x + 1 = 0<\/strong><br>Sol :<br>Roots are equal<br>\u2234&nbsp;d = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (4)<sup>2<\/sup>&nbsp;\u2013 4 (1) (k)<br>d = 16 \u2013 4k<br>Put d = 0<br>0 = 16 \u2013 4k<br>4k = 16<br>k = 4<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11-d\">Question 11 D<\/h4>\n\n\n\n<p><strong>Find the values of k, for which the given equation has real roots:<\/strong><\/p>\n\n\n\n<p><strong>kx<sup>2<\/sup>&nbsp;\u2013 2\u221a5x + 4 = 0<\/strong><br>Sol :<br>Roots are equal<br>\u2234&nbsp;d = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (\u20132\u221a5)<sup>2<\/sup>&nbsp;\u2013 4 (k) (4)<br>d = 20 \u2013 16k<br>Put d = 0<br>0 = 20 \u2013 16k<br>16k = 20<\/p>\n\n\n\n<p>k=2016<\/p>\n\n\n\n<p>k=54<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11-e\">Question 11 E<\/h4>\n\n\n\n<p><strong>Find the values of k, for which the given equation has real roots:<\/strong><\/p>\n\n\n\n<p><strong>x<sup>2<\/sup>&nbsp;+ k(4x + k \u2014 1) + 2 = 0<\/strong><br>Sol :<br>Roots are equal<br>\u2234&nbsp;d = 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (4k)<sup>2<\/sup>&nbsp;\u2013 4 (k<sup>2<\/sup>&nbsp;\u2013 k + 2) (1)<br>d = 16k<sup>2<\/sup>&nbsp;\u2013 4k<sup>2<\/sup>&nbsp;+ 4k \u2013 8<br>Put d = 0<br>0 = 16k<sup>2<\/sup>&nbsp;\u2013 4k<sup>2<\/sup>&nbsp;+ 4k \u2013 8<br>12k<sup>2<\/sup>&nbsp;+ 4k<sup>2<\/sup>&nbsp;+ 4k \u2013 8 = 0 (divide by 4)<br>3k<sup>2<\/sup>&nbsp;+ k \u2013 2 = 0<br>3k<sup>2<\/sup>&nbsp;+ 3k \u2013 2k \u2013 2 = 0<br>3k (k + 1) \u2013 2k (k + 1) = 0<br>(3k\u20132k)(k+1) = 0<br>(3k\u20132k)=0 or (k+1) = 0<br>k = 0 k = \u20131<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-12\">Question 12<\/h4>\n\n\n\n<p><strong>Prove that the equation x<sup>2<\/sup>(a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>) + 2x(ac + bd) + (c<sup>2<\/sup>&nbsp;+ d<sup>2<\/sup>)= 0 has no real root, if ad \u2260 bc.<\/strong><\/p>\n\n\n\n<p>Sol :<br>x<sup>2<\/sup>(a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>) + 2x(ac + bd) + (c<sup>2<\/sup>&nbsp;+ d<sup>2<\/sup>)= 0<br>d = b<sup>2<\/sup>&nbsp;\u2013 4ac<br>d = (2ac + 2bd)<sup>2<\/sup>&nbsp;\u2013 4 (a<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>) (c<sup>2<\/sup>&nbsp;+ d<sup>2<\/sup>)<br>d = 4a<sup>2<\/sup>c<sup>2<\/sup>&nbsp;+ 4b<sup>2<\/sup>d<sup>2<\/sup>&nbsp;+ 8abcd \u2013 4 [a<sup>2<\/sup>&nbsp;(c<sup>2<\/sup>&nbsp;+ d<sup>2<\/sup>) + b<sup>2<\/sup>&nbsp;(c<sup>2<\/sup>+d<sup>2<\/sup>)]<br>d = 4a<sup>2<\/sup>c<sup>2<\/sup>&nbsp;+ 4b<sup>2<\/sup>d<sup>2<\/sup>&nbsp;+ 8abcd \u2013 4 [a<sup>2<\/sup>c<sup>2<\/sup>&nbsp;+ a<sup>2<\/sup>d<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>c<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>d<sup>2<\/sup>]<\/p>\n\n\n\n<p>d = 4a<sup>2<\/sup>c<sup>2<\/sup>&nbsp;+ 4b<sup>2<\/sup>d<sup>2<\/sup>&nbsp;+ 8abcd \u2013 4a<sup>2<\/sup>c<sup>2<\/sup>&nbsp;\u2013 4a<sup>2<\/sup>d<sup>2<\/sup>&nbsp;\u2013 4b<sup>2<\/sup>c<sup>2<\/sup>&nbsp;\u2013 4b<sup>2<\/sup>&nbsp;d<sup>2<\/sup><br>d = 8abcd \u2013 4a<sup>2<\/sup>d<sup>2<\/sup>&nbsp;\u2013 4b<sup>2<\/sup>c<sup>2<\/sup><br>d = 8abcd \u2013 4(a<sup>2<\/sup>d<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>&nbsp;c<sup>2<\/sup>)<br>d = \u20134 (a<sup>2<\/sup>&nbsp;d<sup>2<\/sup>&nbsp;+ b<sup>2<\/sup>c<sup>2<\/sup>&nbsp;\u2013 2abcd)<br>d = \u20134 [(ad + bc)<sup>2<\/sup>]<br>For ad \u2260 bc<br>d= \u20134 \u00d7 [value of (ad + bc)<sup>2<\/sup>]<br>\u2234&nbsp;d is always negative<br>So, d &lt; 0<br>The given equation has no real roots.<\/p>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solutions\/\">KC Sinha Solutions<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solution-for-class-10\/\">KC Sinha Class 10 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Question 1 A Write the discriminate of each of the following quadratic equation: x2&nbsp;+ 4x + 3 =0Sol :d = b2&nbsp;\u2013 4acd = (4)2&nbsp;\u2013 4 (1) (3)d = 16 \u2013 12d = 4 Question 1 B&nbsp; Write the discriminate of each of the following quadratic equation: 4&#215;2&nbsp;+ 5x + 7 = 0Sol :d = b2&nbsp;\u2013 [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":624299,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[24],"tags":[],"boards":[],"class_list":["post-624306","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-10","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>KC Sinha: Exercise 7.4 - Mathematics Solution Class 10 Chapter 7 Quadratic Equations - IndCareer 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