{"id":624298,"date":"2023-09-01T07:44:22","date_gmt":"2023-09-01T07:44:22","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=624298"},"modified":"2023-09-01T07:44:27","modified_gmt":"2023-09-01T07:44:27","slug":"kc-sinha-exercise-7-2-mathematics-solution-class-10-chapter-7-quadratic-equations","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-7-2-mathematics-solution-class-10-chapter-7-quadratic-equations\/","title":{"rendered":"KC Sinha: Exercise 7.2 &#8211; Mathematics Solution Class 10 Chapter 7 Quadratic Equations"},"content":{"rendered":"\n\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-a-nbsp\">Question 1 A&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>(x \u2212 2) (x + 1) = (x \u2212 1) (x + 3)<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; (x \u2212 2) (x + 1) = (x \u2212 1) (x + 3)<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ x \u2212 2x \u2212 2 = x<sup>2<\/sup>&nbsp;+ 3x \u2212 x \u2212 3<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 x \u2212 2 \u2212 x<sup>2<\/sup>&nbsp;\u2212 2x + 3 = 0<br>\u21d2&nbsp;\u22123x + 1 = 0<br>\u2235&nbsp;The highest power of x in the equation is 1;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-b-nbsp\">Question 1 B&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>(x \u2212 2)<sup>2<\/sup>&nbsp;+ 1 = 2x \u2212 3<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; (x \u2212 2)<sup>2<\/sup>&nbsp;+ 1 = 2x \u2212 3<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 2x + 4 + 1 = 2x \u2212 3<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 2x + 5 \u2212 2x + 3 = 0<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 4x + 8 = 0<br>\u2235&nbsp;The highest power of x in the equation is 2;<br>\u2234&nbsp;It is a quadratic equation<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-c-nbsp\">Question 1 C&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>x (x + 1) + 8 = (x + 2) (x \u2212 2)<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; x (x + 1) + 8 = (x + 2) (x \u2212 2)<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ x + 8 = x<sup>2<\/sup>&nbsp;\u2212 2<sup>2<\/sup><br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ x + 8 \u2212 x<sup>2<\/sup>&nbsp;+ 4 = 0<br>\u21d2&nbsp;x + 12 = 0<br>\u2235&nbsp;The highest power of x in the equation is 1;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-d-nbsp\">Question 1 D&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>(x \u2212 3) (2x + 1) = x (x + 5)<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; (x \u2212 3) (2x + 1) = x (x + 2)<br>\u21d2&nbsp;2x<sup>2<\/sup>&nbsp;+ x \u2212 6x \u2212 3 = x<sup>2<\/sup>&nbsp;+ 5x<br>\u21d2&nbsp;2x<sup>2<\/sup>&nbsp;+ x \u2212 6x \u2212 3 \u2212 x<sup>2<\/sup>&nbsp;\u2212 5x = 0<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 10x \u2212 3 = 0<br>\u2235&nbsp;The highest power of x in the equation is 2;<br>\u2234&nbsp;It is a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-e-nbsp\">Question 1 E&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>x (2x + 3) = x<sup>2<\/sup>&nbsp;+ 1<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; x (2x + 3) = x<sup>2<\/sup>&nbsp;+ 1<br>\u21d2&nbsp;2x<sup>2<\/sup>&nbsp;+ 3x = x<sup>2<\/sup>&nbsp;+ 1<br>\u21d2&nbsp;2x<sup>2<\/sup>&nbsp;+ 3x \u2212 x<sup>2<\/sup>&nbsp;\u2212 1 = 0<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+3x \u2212 1 = 0<br>\u2235&nbsp;The highest power of x in the equation is 2;<br>\u2234&nbsp;It is a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-f-nbsp\">Question 1 F&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>x<sup>2<\/sup>&nbsp;+ 3x + 1 = (x \u2212 2)<sup>2<\/sup><\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; x<sup>2<\/sup>&nbsp;+ 3x + 1 = (x \u2212 2)<sup>2<\/sup><br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ 3x + 1 = x<sup>2<\/sup>&nbsp;\u2212 4x + 4<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ 3x + 1 \u2212 x<sup>2<\/sup>&nbsp;\u2212 4x \u2212 4 = 0<br>\u21d2&nbsp;\u2212x \u2212 3 = 0<br>\u2235&nbsp;The highest power of x in the equation is 1;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-g-nbsp\">Question 1 G&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><br><strong>(x + 1) (x \u2212 1) = (x + 2) (x + 3)<\/strong><\/p>\n\n\n\n<p>Sol :<br>Given; (x + 1) (x \u2212 1) = (x + 2) (x + 3)<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 1<sup>2<\/sup>&nbsp;= x<sup>2<\/sup>&nbsp;+ 5x + 6<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 1 \u2212 x<sup>2<\/sup>&nbsp;\u2212 5x \u2212 6 = 0<br>\u21d2&nbsp;\u22125x \u2212 7 = 0<br>\u2235&nbsp;The highest power of x in the equation is 1;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-h-nbsp\">Question 1 H&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><\/p>\n\n\n\n<p><strong>(x \u2212 1)<sup>2<\/sup>&nbsp;= (x + 1)<sup>2<\/sup><\/strong><br>Sol :<br>Given; (x \u2212 1)<sup>2<\/sup>&nbsp;= (x + 1)<sup>2<\/sup><br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 x + 1<sup>2<\/sup>&nbsp;= x<sup>2<\/sup>&nbsp;+ x + 1<sup>2<\/sup><br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 x + 1 \u2212 x<sup>2<\/sup>&nbsp;\u2212 x \u2212 1 = 0<br>\u21d2&nbsp;\u22122x = 0<br>\u2235&nbsp;The highest power of x in the equation is 1;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-a-nbsp\">Question 2 A&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><\/p>\n\n\n\n<p><strong>(x + 2)<sup>3<\/sup>&nbsp;= x<sup>3<\/sup>&nbsp;\u2212 4<\/strong><br>Sol :<br>Given; (x + 2)<sup>3<\/sup>&nbsp;= x<sup>3<\/sup>&nbsp;\u2212 4<br>\u21d2&nbsp;x<sup>3<\/sup>&nbsp;+ 6x<sup>2<\/sup>&nbsp;+ 12x + 2<sup>3<\/sup>&nbsp;= x<sup>3<\/sup>&nbsp;\u2212 4<br>\u21d2&nbsp;x<sup>3<\/sup>&nbsp;+ 6x<sup>2<\/sup>&nbsp;+ 12x + 2<sup>3<\/sup>\u2212 x<sup>3<\/sup>&nbsp;+ 4 = 0<br>\u21d2&nbsp;6x<sup>2<\/sup>&nbsp;+ 12x + 12 = 0<br>\u2235&nbsp;The highest power of x in the equation is 2;<br>\u2234&nbsp;It is a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-b-nbsp\">Question 2 B&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations:<\/strong><\/p>\n\n\n\n<p>x\u22121x=8<br>Sol :<br>Given; x\u22121x=8<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 1 = 8x<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 8x \u2212 1 = 0<br>\u2235&nbsp;The highest power of x in the equation is 2;<br>\u2234&nbsp;It is a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-c-nbsp\">Question 2 C&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations :<\/strong><\/p>\n\n\n\n<p><strong>2&#215;2\u22123x\u2212\u2212\u221a+5=0<\/strong><br>Sol :<br>Given; 2&#215;2\u22123x\u2212\u2212\u221a+5=0<br>\u21d2&nbsp;2&#215;2+5=3x\u2212\u2212\u221a<br>\u21d2&nbsp;(2&#215;2+5)2=(3x\u2212\u2212\u221a)2<br>\u21d2&nbsp;4x<sup>4<\/sup>&nbsp;+ 20x<sup>2<\/sup>&nbsp;+ 25 = 9x<br>\u21d2&nbsp;4x<sup>4<\/sup>&nbsp;+ 20x<sup>2<\/sup>&nbsp;\u2212 9x + 25 = 0<br>\u2235&nbsp;The highest power of x in the equation is 4;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-d-nbsp\">Question 2 D&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations :<\/strong><\/p>\n\n\n\n<p><strong>x2+1x=5<\/strong><br>Sol :<br>Given; x2+1x=5<br>\u21d2&nbsp;x<sup>3<\/sup>&nbsp;+ 1 = 5x<br>\u21d2&nbsp;x<sup>3<\/sup>\u2212&nbsp;5x + 1&nbsp;= 0<br>\u2235&nbsp;The highest power of x in the equation is 3;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2-e-nbsp\">Question 2 E&nbsp;<\/h4>\n\n\n\n<p><strong>Check whether the following are quadratic equations :<\/strong><\/p>\n\n\n\n<p><strong>x2\u22121&#215;2=8<\/strong><br>Sol :<br>Given; x2\u22121&#215;2=8<br>\u21d2&nbsp;x<sup>4<\/sup>\u2212&nbsp;1 = 8x<sup>2<\/sup><br>\u21d2&nbsp;x<sup>4<\/sup>\u2212&nbsp;8x<sup>2<\/sup>\u2212&nbsp;1&nbsp;= 0<br>\u2235&nbsp;The highest power of x in the equation is 4;<br>\u2234&nbsp;It is not a quadratic equation.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-a-nbsp\">Question 3 A&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations mathematically:<\/strong><br><strong>John and Jivanti together have 45 marbles. Both of them lost 5 marbles each and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.<\/strong><\/p>\n\n\n\n<p>Sol :<br>Let \u2018x\u2019 be the number of marbles John had.<br>\u2234&nbsp;Jivanti will have 45 \u2212 x marbles.<br>[\u2235&nbsp;the total number of marbles is 45]<br>As both of them lost 5 marbles each; marbles they now have will be x \u2212 5 and 40 \u2212 x respectively.<br>\u21d2&nbsp;Product of the number of marbles = (x \u2212 5) (40 \u2212 x)<\/p>\n\n\n\n<p>\u2234&nbsp;40x \u2212 x<sup>2<\/sup>&nbsp;\u2212 200 + 5x = 124 [\u2235&nbsp;the product is 124]<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 45x + 324 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-b-nbsp\">Question 3 B&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations mathematically:<\/strong><\/p>\n\n\n\n<p><strong>A shopkeeper buys a number of books for Rs. 80. If he had bought four more books for the same amount, the book would have cost Re. 1 less.<\/strong><br>Sol :<br>Let \u2018x\u2019 be the number of books bought by the shopkeeper.<br>\u2234&nbsp;Cost of one book = Rs. 80 \u00f7 x.<br>[\u2235&nbsp;the total cost of books is Rs. 80]<br>\u2234&nbsp;Cost of one book when he buys 4 more books for same rate = Rs. 80 \u00f7 (x + 4).<br>When he buys four more books for the same amount; it will cost Re. 1 per book less than the previous.<br>\u2234&nbsp;80 \u00f7 (x + 4) = (80 \u00f7 x) \u2212 1<br>\u21d2&nbsp;80x+4=80x\u22121<br>\u21d2&nbsp;80x = (x + 4) (80 \u2212 x)<br>\u21d2&nbsp;80x = 80x \u2212 x<sup>2<\/sup>&nbsp;+ 320 \u2212 4x<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ 4x + 320 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-c-nbsp\">Question 3 C&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations mathematically:<\/strong><\/p>\n\n\n\n<p><strong>A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs. 750. We would like to find out the number of toys produced on that day.<\/strong><br>Sol :<br>Let \u2018x\u2019 be the number of toys produced on that day.<br>\u2234&nbsp;Cost of production of each toy that day= Rs. 55 \u2212 x.<\/p>\n\n\n\n<p>[\u2235&nbsp;The cost of production of each toy (in rupees) is 55 minus the number of toys produced in a day]<br>\u2234&nbsp;Cost of production of x toys = Rs. x (55 \u2212 x)<br>[\u2235&nbsp;On a particular day, the total cost of production was Rs. 750.]<br>\u2234&nbsp;x (55 \u2212 x) = 750<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 55x + 750 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3-d-nbsp\">Question 3 D&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations mathematically:<\/strong><\/p>\n\n\n\n<p><strong>The sum of the squares of two positive integers is 117. If the square of the smaller number equals four times the larger number, we need to find the integers.<\/strong><br>Sol :<br>Let \u2018x\u2019 and \u2018y\u2019 be the smaller and larger integer respectively.<br>\u2234&nbsp;x<sup>2<\/sup>&nbsp;+ y<sup>2<\/sup>&nbsp;= 117.<br>[\u2235&nbsp;The sum of the squares of two positive integers is 117]<br>\u2234&nbsp;x<sup>2<\/sup>&nbsp;= 4y<br>[\u2235&nbsp;the square of the smaller number equals four times the larger number.]<br>\u2234&nbsp;y<sup>2<\/sup>&nbsp;+ 4y \u2013 117 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4-a-nbsp\">Question 4 A&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations in the form of the quadratic equation.<\/strong><\/p>\n\n\n\n<p><strong>Divide 16 into two parts such that twice of the square of larger part exceeds the square of the smaller part by 164.<\/strong><br>Sol :<br>Let \u2018x\u2019 be the one part and the other part will be 16 \u2212 x.<br>[\u2235&nbsp;16 is being divided]<br>\u2235&nbsp;Twice of the square of larger part exceeds the square of the smaller part by 164.<br>\u2234&nbsp;2x<sup>2<\/sup>&nbsp;= (16 \u2013 x)<sup>2<\/sup>&nbsp;+ 164<br>\u2234&nbsp;2x<sup>2<\/sup>&nbsp;= 256 \u2013 32x + x<sup>2<\/sup>&nbsp;+ 164<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;+ 32x \u2212 420 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4-b-nbsp\">Question 4 B&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations in the form of the quadratic equation.<\/strong><\/p>\n\n\n\n<p><strong>One year ago, a man was eight times as old as his son. Now, his age is equal to the square of his son&#8217;s age.<\/strong><br>Sol :<br>Let \u2018y\u2019 and \u2018x\u2019 be the present age of the man and son.<br>\u2235&nbsp;One year ago the man was eight times as old as his son.<br>\u2234&nbsp;y \u2013 1 = 8 (x \u2212 1)<br>\u2235&nbsp;Now, his age is equal to the square of his son&#8217;s age.<br>\u2234&nbsp;y = x<sup>2<\/sup><br>\u2234&nbsp;x<sup>2<\/sup>&nbsp;\u2212 1 = 8 (x \u2212 1)<br>\u21d2&nbsp;x<sup>2<\/sup>&nbsp;\u2212 8x + 7 = 0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4-c-nbsp\">Question 4 C&nbsp;<\/h4>\n\n\n\n<p><strong>Represent the following situations in the form of the quadratic equation.<\/strong><\/p>\n\n\n\n<p><strong>A train travels a distance of 300 km at a constant speed. If the speed of the train &#8216;is increased by 5 km an hour. The journey would have taken two hours less.<\/strong><br>Sol :<br>Let \u2018x\u2019 be the speed of the train in km per hour.<br>\u2234&nbsp;Time taken to cover 300 km =&nbsp;300x<br>[\u2235&nbsp;Time =&nbsp;Distance&nbsp;&nbsp;speed&nbsp;.]<br>\u2234&nbsp;Time taken when speed is increased by 5 =&nbsp;\\frac{300}{x+5}<\/p>\n\n\n\n<p>300x+5<br>\u2235&nbsp;The&nbsp;journey would have taken two hours less when speed is decreased.<\/p>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solutions\/\">KC Sinha Solutions<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solution-for-class-10\/\">KC Sinha Class 10 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Question 1 A&nbsp; Check whether the following are quadratic equations:(x \u2212 2) (x + 1) = (x \u2212 1) (x + 3) Sol :Given; (x \u2212 2) (x + 1) = (x \u2212 1) (x + 3)\u21d2&nbsp;x2&nbsp;+ x \u2212 2x \u2212 2 = x2&nbsp;+ 3x \u2212 x \u2212 3\u21d2&nbsp;x2&nbsp;\u2212 x \u2212 2 \u2212 x2&nbsp;\u2212 2x [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":624299,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[24],"tags":[],"boards":[],"class_list":["post-624298","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-10","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>KC Sinha: Exercise 7.2 - Mathematics Solution Class 10 Chapter 7 Quadratic Equations - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Question 1 A&nbsp; 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