{"id":623860,"date":"2023-08-31T11:50:42","date_gmt":"2023-08-31T11:50:42","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=623860"},"modified":"2023-08-31T11:51:33","modified_gmt":"2023-08-31T11:51:33","slug":"kc-sinha-exercise-8-2-mathematics-solution-class-9-chapter-8-lines-and-angles","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/kc-sinha-exercise-8-2-mathematics-solution-class-9-chapter-8-lines-and-angles\/","title":{"rendered":"KC Sinha: Exercise 8.2 &#8211; Mathematics Solution Class 9 Chapter 8 Lines and Angles"},"content":{"rendered":"\n\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-exercise-8-2\">Exercise 8.2<\/h3>\n\n\n\n<p>Type 1<\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-1-nbsp\">Question 1&nbsp;<\/h4>\n\n\n\n<p><strong>Answer the following questions :<\/strong><br><strong>(i) If any transversal intersects two parallel lines in such a way that the ratio of interior angles on the same side is 2 : 7 , then f\u200cind the measure of the bigger angle in degrees.<\/strong><br><strong>(ii) If two parallel lines are intersected by a transversal, what relation will exist between alternate angles ?<\/strong><br><strong>(iii) If each of the two lines is parallel to a third line, what relation exists between them ?<\/strong><br><strong>(iv) At what angle, in degree measure, all perpendiculars drawn to a line segment&nbsp;are inclined to one another ?<\/strong><br><strong>(v) If P be a point not lying on line &#8216;l&#8217; then how many lines parallel to &#8216;l&#8217; through the point P, can be drawn ?<\/strong><br><strong>(vi) If a transversal intersects two parallel lines, then write two conditions for these two lines to be parallel.<\/strong><br><strong>(vii) If arms of any two angles are parallel, what relation exists between these angles ?<\/strong><br><strong>Sol :<\/strong><br>(i) 2:7<br>2x+7x=180\u00b0<br>9x=180\u00b0<br>x=\\frac{180^{\\circ}}{9}<br>x=20\u00b0<\/p>\n\n\n\n<p>bigger angle-<br>7x=7\u00d720\u00b0<br>=140\u00b0<\/p>\n\n\n\n<p>(ii) will be equal<\/p>\n\n\n\n<p>(iii) they will be Parallel<\/p>\n\n\n\n<p>(iv) 0\u00b0 or 180\u00b0<\/p>\n\n\n\n<p>(v) only one<\/p>\n\n\n\n<p>(vi) Pair of alternate interior angles are equal; pair of corresponding angles are equal<\/p>\n\n\n\n<p>(vii) will be parallel<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-2\">Question 2<\/h4>\n\n\n\n<p><strong>Fill up the blanks :<\/strong><br><strong>(i) All perpendiculars drawn on a line segment are __<\/strong><br><strong>(ii) If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are __<\/strong><br><strong>(iii) A transversal intersects two parallel lines and one pair of alternate angles x and y are formed , then x and y are __<\/strong><br>Sol :<br>(i) Parallel<br>(ii) Parallel<br>(iii) Equal<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-3\">Question 3<\/h4>\n\n\n\n<p><strong>P is a point between two parallel lines AB and CD. If \u2220ABP=30\u00b0 , \u2220CDP=45\u00b0 , then find the value of \u2220DPB.<\/strong><br>Sol :<br>Diagram<br>Construction: Draw a line RS through P parallel to the AB and CD line.<\/p>\n\n\n\n<p>Given: AB||CD<br>\u2220ABP=30\u00b0,\u2220CDP=45\u00b0<\/p>\n\n\n\n<p>To prove: \u2220DPB=?<\/p>\n\n\n\n<p>PS||AB(from construction)<\/p>\n\n\n\n<p>\u2220SPB=\u2220ABP(alternate interior angle)<\/p>\n\n\n\n<p>\u2235RS||AB<br>AB||CD(given)<\/p>\n\n\n\n<p>\u2234RS||CD<br>\u2220SPD=\u2220CDP(alternate interior angles)<br>\u2220SPD=45\u00b0<\/p>\n\n\n\n<p>\u2220DPB=\u2220SPB+\u2220SPD<br>=30\u00b0+45\u00b0<br>=75\u00b0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Type 2<\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-4\">Question 4<\/h4>\n\n\n\n<p><strong>In the given f\u200cigure, if AB||DE, then find the value of \u2220BCD<\/strong><br>&lt;figure to be added&gt;<br>[Hint: Draw a line PCQ through C parallel to AB and DE ]<\/p>\n\n\n\n<p>Sol:<br>Diagram<br>Given: AB||DE<\/p>\n\n\n\n<p>\u2220ABC=100\u00b0,\u2220CDE=120\u00b0<br>\u2220BCD=?<\/p>\n\n\n\n<p>Construction: We can extend the line AB towards the line CD.<\/p>\n\n\n\n<p>Now,<br>\u2220ABC+\u2220CBP=180\u00b0(Linear pair)<br>100\u00b0+\u2220CBP=180\u00b0<br>\u2220CBP=80\u00b0<\/p>\n\n\n\n<p>\u2220CBP+\u2220BCP=\u2220CDE(exterior angle is equal to the sum of opposite interior angles)<br>80\u00b0+\u2220BCD=120\u00b0 (\u2235\u2220CPT=\u2220PDE or \u2220CPT=\u2220CDE)<br>\u2220BCD=40\u00b0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-5\">Question 5<\/h4>\n\n\n\n<p><strong>In the given figure, if \u22201=130\u00b0 and \u22206=60\u00b0 , is AB||CD ?<\/strong><br>&lt;figure to be added&gt;<br>Sol :<br>Diagram<br>\u22205+\u22206=180\u00b0(linear pair)<br>\u22205+60\u00b0=180\u00b0<\/p>\n\n\n\n<p>\u22205=120\u00b0<\/p>\n\n\n\n<p>\u22201\u22605<\/p>\n\n\n\n<p>\u2234AB\u2226CD<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Page 8.30<\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-6\">Question 6<\/h4>\n\n\n\n<p><strong>In the given figure , m||n and \u22202:\u22203=2:3, then find the values of angles denoted by 1,2,&#8230;..7,8.<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/h1u8A3UAP8-C7tyDvlH4oBIHeXKMD8wvvEAqMwn_JK2R4tNy91-MbYDMy4Qk1nPTInDoUWPbR7Zki7JUbbt7ZahqdRMHki0WgFks8D8t79r3xSm90cepJc7goN1x3wVzit6VeuIiVk9x44fb3E41mp8ohzVKkHXKb9NtDc3rDnSS2TT6MYhEBQSUkaoV2Fm63jhBDtvkg_3GBO13AbUWtZD720wRZmvX-hUiACFw4N7uUCjx30jkjpE5u9QSxFEkC3BXC37vXlB0FaHbKnmH-dcKju_f21o7gcMp4UbWeggePH18NsclDGgfjVnVyjsoM3Y-Hc7yR_J6YnTb3mA_5MGv6pUW1WjLSnHBr8GxRLUQ_Oh_Ty0MK2yaf6RIvyvmNQe20dNoBa5UPmWmHzWLW4ZZLVOGIx0h0lsPA0Cazr4b3M5XR81jsiPNZqJh-NC5KfbDAkJG0JRNJ00IwG8l_vCQ4fSu9lOU451TwXxuqvJ534j6skOptTtfk_AVhcBawqzcTLwQtUCQ6PDx--vOzlELTMOCp962yPNaCtWEGh-WHyz0CWLqDt11ud7GmSSpbL3qRNhTKvFf7B7GPlzWZ5wisGS-G8_oe-Yj2ChmVGOCUaVK6iz1zEEQRaaqDfL73Jeh9-0C8j2IcQE1yn394KO9irlKv-h2ei9CVrZ13-bQA-dA8I80YQ=w177-h136-no\"><br>Sol:<br>Let&nbsp;\u22202=2x<br>\u22203=3x<\/p>\n\n\n\n<p>\u22202+\u22203=180\u00b0(linear pair)<br>2x+3x=180\u00b0<br>5x=180\u00b0<br>x=\\frac{180^{\\circ}}{5}<br>x=36\u00b0<\/p>\n\n\n\n<p>\u22202=2x<br>=2\u00d736\u00b0<br>=72\u00b0<\/p>\n\n\n\n<p>\u22203=3x<br>=3\u00d736\u00b0<br>=108\u00b0<\/p>\n\n\n\n<p>\u22204=\u22202(V.OA)<br>\u22204=72\u00b0<br>\u22201=\u22203(V.O.A)<br>\u22201=108\u00b0<\/p>\n\n\n\n<p>\u22205=\u22201(corresponding angles)<br>\u22205=108\u00b0<\/p>\n\n\n\n<p>\u22207=\u22205(V.O.A)<br>\u22207=108\u00b0<\/p>\n\n\n\n<p>\u22206=\u22202(corresponding angles)<br>\u22206=72\u00b0<\/p>\n\n\n\n<p>\u22208=\u22206(V.O.A)<br>\u22208=72\u00b0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-7\">Question 7<\/h4>\n\n\n\n<p><strong>In figures (i) , (ii) , (iii) , (iv) if AB||CD , then find the value of x and y in each of the following cases:<\/strong><br><strong>(i)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/XKaaaa9vHelcdk9ViRWkYdjT6ZoKB9TR6J00DIsbKe_m_HPhHhSqdeXZgeojce6VYMbX3hHpqiFLlEjYCxCTNO__wRYwN3pforYtg2XaxHq1-uNuarE7yF4yT3TY27ZvG9l6A1O9rPWpuyMpskwsiAQtVDskRlXQ0gKhteoE9DXrnrboXNoMTIxd6LHfMjw49viNdC-kUShcPHs2zRe94-QqakOAEGVuLaldSoZddYet3Xy59qvze3OimNIOGWlDGN1YfVBq66mAH8DfDCO5LvNF54CJqWUsyiSD4qRw1m2-szXI3csb0ajqpJSaIi6Ra269J7o1mfIMyPxu18zLFAwbyPf6KF3m555q2gPaE_RpDEz8RJvCvkCMWPnu8E5cJ10t2pwvLd9-GnbI5LbuHu2yoOMDf2WqaF8nxsSTp-0kCD76xnlUwIN8TwUYeoAJFwrJ83ZpT6URsOgUU2R4bDT0ImLX8pCT5pX7wMNXu75KKsh4HxVeIrL3ns24uVe27bv0OyCcClFDrH3DMm7eXNkuanQtkQq1--Dj5NtRcDAlZOcaNktfupC_KLw_Uoxnw4jWjNRoWM-vGbvp9o8BDl4lguJ7hsPGRv6x5-D97XG8lvYtl8uXhthZbXsvX1gPLSZlHgr-g8NjsnyApVaK6thhfFG3_VgA4kqyHKk6Rc71HHccSg0ygQ=w175-h137-no\"><br>Sol :<br>\u2220SRB=\u2220ARP(V.O.A)<br>x=65\u00b0<\/p>\n\n\n\n<p>\u2220SRB+\u2220RSD=180\u00b0(Interior angles on same side of transversal are supplementary)<br>65\u00b0+y=180\u00b0<br>y=180\u00b0-65\u00b0<br>y=115\u00b0<\/p>\n\n\n\n<p><strong>(ii)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/KEwBI4gvnqT1-Lxmq8sWXUcMK5ZrQLZeNRRPjPNlNz3zqhopXQGcqsIcF_2mx9VkeDknUrkFvelY7OCH__5nFYSDJOUeYh1voj8T6KSXiMlgq3xndAKih4Xa4xGy2r5o9_0bvhZCvkXqNEMfLRvjxlkMBWjEcZBSLuFaX4w0taJKYmqChmysRj8EnOQ27pFS2cJAkIXdNVhtu8z-zUrScktmgYRlXL_JYtIaWKoTC8TCAncmb63Jpn4eEqviIHyGXvcRevusVpvGM-Sp4pUEeHtgn9XW7LB0bU7IsP4ujz2EKmxEX0L8OHtAOiboWohfbwt_TkuePJJkgWKpvVetZU85ZTdVraJcANXvPdp2WOuGEMg0X_O9J1KgL_IgenMg8jlhQf_lO8hhXIJn87roumXVnmDQj1s35U3_7uB3MjZz1dnt1QRUVIJZ_bmAWaU328MtI7gr1qcdJrrQePVx04DnWoQ-KLKUoeak2pzBc1Anm2M9n-dHSMeXBb-QRjDvfY8FyeSGB-Ma-7iqoxFf2xSUkagHWEXQh1yt7OXXDmyCTgpV7hsChaR-kHUwDT6TdGdKYNDspzjcASC4CStMspnrXwVUfvyDRxK5wS7qfdGgx2MRYOXAFaXpQ2CEgcLv9t_46ybNj5M05uct4nfU5vigIFZrt1byfRPbUemfETmiztxSbj_-Xg=w191-h133-no\"><br>Sol :<br>\u2220CSR=\u2220SRB(Alternate interior angle)<br>x=105\u00b0<\/p>\n\n\n\n<p>\u2220CSR+\u2220CSQ=180\u00b0<br>105\u00b0+y=180\u00b0<br>y=75\u00b0<\/p>\n\n\n\n<p><strong>(iii)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/MHS0HOU2BfjbaNgRdabJy3OeYLnfvUf9Bl7TesgIKHwBWJs_r3KI3xhdkSIWR29xw--BSpWZZbvBDGVWexYuvfCtRt5bfQRrF3fEmCiDiNxdGxLDNk11imrYTS1Fe89AVjNECfz1fmzrcTiUluRmGW2WlZUS5G2lWcd7qwq3h4L5nESG9uGj3Fy2qNOysZk_3K7ZaU10lonlm7HYxJDKW1TrkiiLdrAceD3ez6W9rovC1bPMFV0g1FhQtihfdbgTR7UiNEmIkbPUkCMJBsZl_1yck7xvxN0RH0-vxSnW0RwJqyBAwkd4-FxaNVOWqU1FS3rxKcBbjx13PuGgMZUhh-M9i9152Vd4Bg5j9PQn40tmtTQtFbOXDdswzV0-hnngmAmSf74qX8p9EUjfeUvhPC16xXrHgAeBO4jaPJ2dpMddioHLjfb0vcP11Bg2mutsxq7Mt8npIGFUU2gdHxelGOnSZj8hEFmFunuRaI_ApZp53xW-ec3n07F5jaozTg28H3AHgrXv-RbyWBdSbCM4OeK-E_DupgZdLJzJRUHt3baTUw1Quj2CMtrJhWUnL4MOK2Mn_WTmH7H_Qrk7W27thIzGieGeKyvo649RjqeduHq4Xqv8iyeNy-snFcO1hAnL7hvu81wc2mHowNXGCjwr_QY3hld2jOSqgX2d6uVcK6HrwpeKnDM97A=w197-h139-no\"><\/p>\n\n\n\n<p><strong>(iv)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/MHS0HOU2BfjbaNgRdabJy3OeYLnfvUf9Bl7TesgIKHwBWJs_r3KI3xhdkSIWR29xw--BSpWZZbvBDGVWexYuvfCtRt5bfQRrF3fEmCiDiNxdGxLDNk11imrYTS1Fe89AVjNECfz1fmzrcTiUluRmGW2WlZUS5G2lWcd7qwq3h4L5nESG9uGj3Fy2qNOysZk_3K7ZaU10lonlm7HYxJDKW1TrkiiLdrAceD3ez6W9rovC1bPMFV0g1FhQtihfdbgTR7UiNEmIkbPUkCMJBsZl_1yck7xvxN0RH0-vxSnW0RwJqyBAwkd4-FxaNVOWqU1FS3rxKcBbjx13PuGgMZUhh-M9i9152Vd4Bg5j9PQn40tmtTQtFbOXDdswzV0-hnngmAmSf74qX8p9EUjfeUvhPC16xXrHgAeBO4jaPJ2dpMddioHLjfb0vcP11Bg2mutsxq7Mt8npIGFUU2gdHxelGOnSZj8hEFmFunuRaI_ApZp53xW-ec3n07F5jaozTg28H3AHgrXv-RbyWBdSbCM4OeK-E_DupgZdLJzJRUHt3baTUw1Quj2CMtrJhWUnL4MOK2Mn_WTmH7H_Qrk7W27thIzGieGeKyvo649RjqeduHq4Xqv8iyeNy-snFcO1hAnL7hvu81wc2mHowNXGCjwr_QY3hld2jOSqgX2d6uVcK6HrwpeKnDM97A=w197-h139-no\"><br>Sol :<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-8\">Question 8<\/h4>\n\n\n\n<p><strong>Write the pair of parallel lines in each of the following cases shown in figures below:<\/strong><br><strong>(i)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/47UoIu6ZRfI0QFkz5h4xgc0qgzj4RSk6Qs0UAR6ZmFz13oIoyokwb8-Xmm32GIVi89bSxsOwpVtwE_MDmpYUA6eQJg7PUQYpW3fsAd9Bld8713GCo-OhZmg44GLh_3EmspZxVej1J7FB2pX3qvQgGGnKJW4onb3tTmtTX6k_yHPhdTsDWII_oxbfBLhMKUnOFUlEfef3WIYp7as-gFTF9ZEZhp9yobnIhLvdew_rzi-1KyfzYxY7NgJ_Gp08-XNrjEvZZbHunZgPeevoy3j2vM37DkQS_9hpsBoBinad2iClCBFBXkEWQmY20Lm7VrwMCFXDGNYqK_C8m5ywnVqKRia_weBGI82wnyuUxwD0F8ifaUM_rNznO9K4vN8VQLH1C_0PKunTkdmObIHnnAMaNQbcvloAuRLYKHSHvWY3Dd63JJKR9ObzEE-HsUk0Nyc7ZG0Q1YFJRHbJrKc6DD3zbvl2_2xXcj8UL0wfy-8iC_KsRbPQYItEDJcrsm8N0SBHHdj5bHkyT6VjkSjLkWcYnctr-wHw0BTfV79B7aOQ8MswBfRanxu4mDcI5V_1jj3aR6bzJ13ecgZwgLdObz8vpH-Eb9Hq6UZ50kHf1wFHFXe3xogAzxXF8IfzgS0XZZ4O8WbLxbQRssm_9dWkhltAirwLLYly0-jFsxdvwVpkgPjx3XlQaPEjpQ=w188-h140-no\"><br>Sol :<br>x+60\u00b0=180\u00b0<br>x=120\u00b0<\/p>\n\n\n\n<p>y=60\u00b0(alternate angle)<\/p>\n\n\n\n<p><strong>(ii)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/qt7H-CmZAW1fv5UgfNj7Lhnx60Wchk57lIW2Z-wVKMGCdhkRNWWkVfZKqLKjK6ILj0orF06A7OKGDb5b0QXV2NxacuiS-bHhHkcAnO8ljwBvPImDaj5HNYo7zP6Ub-dK0NyWic3rb00iQINKmPE8aVKHkCMEBPC3LgjdnQrSoPirrPOrtpxV5dPkMBtZNx9Rs2oImf5uSHhpQjQAGlnqVnE9mbpuHuGIvdeEAuJPichUyYGkWPJKT4y8bkVPW1iK9waxj_IgzyXmwJJ-9VQ1shwipn0dM9Mc-Fda-C4hapUM3ySRJp2d0LF5GfFplX5w3cjig3Y7LFLUHl_-kqiB3CDLLC90bzx9cpI7L9y-bWB1MT_J5MZgLqGIPsxGGcN2Jqf1W03nXDzgWqP35lxBLWtGaKpJzNaU9WkwF8GzcL7Dg7apW4giZiwHfxlAOmoISNfGUjPOVGSQUGs6H6vpfQ8TYsBMhSHKluK2r9WguC4bCnXJgiQ3ueGyv-5ACemhCx7dIbmE-6QgjJ-SstmY-Ttsgd0ni8I_tXwlpEmwb_Uf-y5E3z14MSrYXeb9EuY-4Nx-R2LSjKfCh-64b-LPZ93VgYNn5C6Bj4OjqNYhRyeDNAQJ_SBtyj37Y_xkXMiUdZLxsM2BzGP1JISL44Pcw91edgI-DDsK8bJ9iYc--g4Hf5pIyQld6g=w199-h160-no\"><br>Sol :<br>x=100\u00b0(alternate angle)<\/p>\n\n\n\n<p>y=80\u00b0(corresponding angle)<\/p>\n\n\n\n<p><strong>(iii)<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/jlZb5389ySI1LbWcp_x_L1nDWHFdD4PQiZrYxxRCiZIR6tzjbEPJrtExDyDoETfzxqMW9ubvJJAGU_2KVpd-1LPGtEBIrcPVxeCuCfpeifvLKlyGj2JBUlzMITDLxJjZPTRTjfR3Nw09XNQpXlUppF96is_2x0q_-56ZiQgS_OA_3WUj8Gx-ltgFmerQfJNftYOPS7CK7AytnCnWhLzp-e5JMdzmu1VZhCbhkYb-okVJtgZP2Q9WCuW1XG3_K4kpaJ46VorTdiNBOvXHE496DH27Iubsqx6W-cNLeBG-o3xeYjUEqsfsqR-bX_eoVbep0CqH8DCKGBfxnTEKewt7WTRAIWQ6eomZg7lpP2ySbLBJOtkRLwrgMb8pBu8ej8xCvCtBnm8fIaTChLOj_xeJDRumFYF3GysF-0WIUNnTT01EBK_PzMbfvLIIoZ79-sJBupipXZfw_3FvhQtduAHqP5OuezMvKQUJ2XYqMq3gDLltZ9B-kxl1LbDHl6rrcCha0aFrXvaOFZph6ooKGov5UxV7wgbb4fjt5RIKhA_Wo-IOMysEnDmi9p_rNSTxX0bmkIaPtgfajNAYWkisEBZtW5loL-t6AIqFTKeyxc40w4fLkdYyEzI3RI1CYiWSbYvSMEldbaLm2k57aNHdPqC2Pd9f44bcfMHqPY3uJvUo_-doP52vGKOJKg=w181-h108-no\"><br>Sol :<br>\u2220D+\u2220A<br>=115\u00b0+65\u00b0<br>=180\u00b0<\/p>\n\n\n\n<p>\u2220A+\u2220B<br>=115\u00b0+65\u00b0<br>=180\u00b0<\/p>\n\n\n\n<p>AD||BC<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Type 3<\/p>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-9\">Question 9<\/h4>\n\n\n\n<p><strong>In the given figure , p is a transversal of the lines m and n and \u22201=60\u00b0 and \\angle 2=\\dfrac{2}{3} of a right angle. Prove that m||n.<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/QClD5VXvbmCU3ClBoARxznXvNfC5WMseN0ku2vx0059Ddpevh3UkD2A0C8Ck_aBECcENzn0uhRo6APMPmWbYzruTm3SOF38tdNkBoFqavLPFn1NNM9ckSsaqIJe6O-tdD4y223U8IV_nsNlzuYVkA48R6m4xgEZGEX06WtluKcknGTxlJ2XDOgQp4OMnCpIZJu2YZ9KdwIK_AO66xvNq1wyW-jlbWZUnhx_K9YhgAPe8AOm1KgXaDEcvIq1urIB1LyVaidobcJ5U8HYIpKK1crCuC8E5y8OVgY2R_Y6F2dPdIPSMB-aPYJjkBZrgLyKUyOURA2gG7EllPOIy8b6kOpVjwYM2FVV4eav3F4JarPl_ohr9oqC49jEWOphDIdEhdP2FpiUEGhxu6PpsYv94GtBSeLNeCHAk-uc2w-asL6vDyF-U-W_OgQ_azzMIpMrgS9oeHH4qD8PvDUdTW1Lm_VGgpqe1UydHj_kXL6T-_rhFUOK4MSXfDcPzoUjBCBgYdITepH3Dquqzz_Go1Rhm4leIb41ARVGV7OQyPmhuyJPJLmq8bEPIpzdtYionNfJ-84WfCtgwCuYtAwUmfjLCKjO7RzQaBX7MiIgeoSbbsRQnvW0dYKqDCf_20oVN4bf-Qm1F5QHQHbs-cPZ6345ATQtfl8RMmkuqT6QOJcq3YEot7zppKyvvEQ=w179-h114-no\"><br>Sol :<br>Diagram<br>Given: P is a transversal of the lines m and n<br>\u22201=60\u00b0 ,\\angle=\\frac{2}{3} of right angle<\/p>\n\n\n\n<p>To prove: m\u2225n<\/p>\n\n\n\n<p>Proof: \\angle 2=\\frac{2}{3} of right angle<\/p>\n\n\n\n<p>\\angle 2=90^{\\circ} \\times \\frac{2}{3}<\/p>\n\n\n\n<p>\u22202=60\u00b0<\/p>\n\n\n\n<p>\u22203=\u22202(V.O.A)<\/p>\n\n\n\n<p>\u22203=60\u00b0<\/p>\n\n\n\n<p>\u2235\u22201=60\u00b0(\u22201 and \u22203 are pair of corresponding angle)<\/p>\n\n\n\n<p>If pair of corresponding angles are equal then the lines are parallel<\/p>\n\n\n\n<p>\u2234 m\u2225n<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-10\">Question 10<\/h4>\n\n\n\n<p><strong>In the given figure , m||n and p||q. If \u22201=75\u00b0 , then prove that \\angle 2=\\angle 1+\\dfrac{1}{3} of right angles<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/CA9TwlFna2psDmfDa_vcdh-bGHMGl9LoAjKY53EfbhkMzVUUHpUWygw7nrzRI7PBzLCiNGrYhimJ7phbSMw8pfG0iU498WlkeGUzpMgsN7BfmMuaO7xvLR2ypXI6587puBOHk2rW1fpUKimxqBgRcFvVOeNeec3__Il4o22OFlHaIzHLVum2bkb2mfi4-mcjSShA4lwv80Dc8z3typm1QuQTjDIlfY6xmXNr5i2Aaz0xh91zOYfVZibuGqcm6EWMIjKtb2zt3JSJ6SiTduxjjzWpogtZKU5Q2idpwviEdErIxZ5lbVg695Kfpv3QE8oKNtmc7RE1Fph-3cCTzMQSrIVV1F6e1dmOQXPxksTfomPEF3nFrBTGoEOqlXXjq2HryTRp1IhQq9UsWjmR-33QKdOs2nv-sj1ScF75qHzuRL5v2jrL_BZG14pvZ6rJ1FE-cIzUtplmSfTBK_aKbwkovP8_RKbu0TaaZzhBCsztpQVZfc0OR9MtBtPP0rJT1qDJSsY6fHph0H9qp3WW-8KJrPQZkEBv1IAlUaUAu34moISxIbRfrKcH5JcARMI7uK28q-vqAKyV8ITfHBHMLKcOXjp4Wu_3-8-i77cTYahJmxHmfOcM2czyPlCOFeXTCaSI1kjrG6NeyGc9ejWfejTyeZPxUr7SEuDKjc376PO9u4PxgHBq5UIt5A=w115-h97-no\"><br>Sol :<br>[Hint: \u2220BAC=\u22201=75\u00b0 [alternate angles]<br>Now , \u22202+\u2220BAC=180\u00b0&nbsp; [sum of the interior angle son the same side of transversal n]<br>\u2234 \u22202=180\u00b0-\u2220BAC<br>=180\u00b0-75\u00b0<br>=105\u00b0=75\u00b0+30\u00b0=\\angle 1+\\dfrac{1}{3} of right angle ]<\/p>\n\n\n\n<p>Sol :<br>Given: m||n and p|q , \u22201=75\u00b0<\/p>\n\n\n\n<p>To prove: \u22202=\u22201+\\frac{1}{3} of right angles<\/p>\n\n\n\n<p>Proof: \u2235p||q (given)<br>\u2220CDB=\u22201(corresponding angle)<br>\u2220CDB=75\u00b0<br>\u2235 m|n (given)<\/p>\n\n\n\n<p>\u2220CDB+\u22202=180\u00b0<br>75\u00b0+\u22202=180\u00b0<\/p>\n\n\n\n<p>\u22202=180\u00b0-75\u00b0<br>\u22202=105\u00b0<\/p>\n\n\n\n<p>\u22202=75\u00b0+30\u00b0<\/p>\n\n\n\n<p>\\angle 2=\\angle 1+\\frac{1}{3} of right angle<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-11\">Question 11<\/h4>\n\n\n\n<p><strong>In the given figure , if x=y and a=b , prove that r||n<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/Mr_z4XCDVduyHunFeRqTg6MDZqswKB7lO1MCKWIOnxxOmXz2e65sPjmAna7uBYXmDCMhLKXiep9TyaUsthBa76cbT8uIRExO4pQQDiP_k338lD9Dv5XNux_znNDUMCbJqJ8Yq6fVV_M7egT9IorDC8Yb7Detq7L36Dplqx4s5jRPCaO-C75dNsOGSuglkCOb2CyoYefokS_R2equuGgLxUjEsQX_XxRBBBhKmffZGDsoES-f0GFrEIcJ16_1-Ix3IbSow2qCBwlm9mE9Q0vUCGRDIzxGDY7VbFuJTlWOj572OORo9qsXb61lPd-3ITuYpPyUhNEz55gyRLAmezLC4AZkekBDyR-fQFbZ7DV_dSwECXBqeT77HpDeRM-FLa0g350o0AKo2Swjn52P-_mRyR9cp71_l24tPXl6_FWygVoEY4OVG0T8hp7rOxhXacXk_w26dGn3OGXffKCB6w-Lzv2dQQ_JyQokw-W0BlTy-S_XZ4yqyvrO2_IK5CeKSRwaLOVlpbY9s47zRxgDVl1ne4PRuujNJ7MCBbv8bE8IE7GD1xLy1NihQ14NUHDHnqoGfLCqfG1Am135fgg2SV1fp-jP7DFVBgcRX5p70GkxZedENZiA9Bp0XMK4TRXSane6fefSgfe5jTZehyOUjwEjQNaUTFlk5hswZWcTG6SHoiZd5CaBMffFwA=w143-h134-no\"><br>Sol :<br>Given:x=y or a=b<\/p>\n\n\n\n<p>To prove:r||n<\/p>\n\n\n\n<p>Proof:<br>x=y(given)<\/p>\n\n\n\n<p>r||m (\u2235 if corresponding angle of transversal are equal then the given lines is are parallel)<\/p>\n\n\n\n<p>a=b (given)<\/p>\n\n\n\n<p>m||n (\u2235 if corresponding angle of transversal are equal then the given lines is are parallel)<\/p>\n\n\n\n<p>\u2235r||m and m||n<\/p>\n\n\n\n<p>\u2234r||n<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-12\">Question 12<\/h4>\n\n\n\n<p><strong>lf m,n, p are three lines such that p||m and n\u22a5p, prove that n\u22a5m&nbsp;<\/strong><br>Sol :<br>Diagram<br>Given: P||m or n\u27c2p<\/p>\n\n\n\n<p>To prove: n\u27c2m<\/p>\n\n\n\n<p>Proof: n\u27c2p (given)<\/p>\n\n\n\n<p>\u22201=90\u00b0<\/p>\n\n\n\n<p>p||m<\/p>\n\n\n\n<p>\u22202=\u22201 (alternate interior angle)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-13\">Question 13<\/h4>\n\n\n\n<p><strong>What are the conditions for two lines to be parallel ?<\/strong><br>Sol :<br>Alternate angles are equal or corresponding angles are equal or , the co-interior angels are supplementary<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-14\">Question 14<\/h4>\n\n\n\n<p><strong>In the given f\u200cigure, l and m are two intersecting lines and p||l and q||m. Prove that p and q are also intersecting lines .<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/I_tmlt-wUqkulayrSVFGHeqoZ34YZr_kaWXZ5rI52HKPPMyphir3SCE3DKlqKNyRku1Zcatl2LCQHafWu_agTokEzBOMi4QsfFqcci2YsnTfdRYMadS2dY94mGyLvaZhG2tT2ETm3bemo_Fmq2BuJUMTIWmw0BR9v9J-h2BzKGszJ5r2spBRjfleXSySyLNoSArR4VcQZxNOPOpHub0KpOg7HN2W5oOxO-QKa-Tn6M63TbzdVcFL8DFGbb0AR4zMMPxfjG-S3Eay7Wy3QrM6XpLk-5x_stmF4maZpKwsaMyHuq3rmJQLUbZS08OSysCT5ZwUliBZTncE1cU80x_UtXhej70ehC78BxJmnmajgRs3OyYcVQp4aZ079MDEZETuAKXwut5QHovbs4uWzMDEaP51gXWbzlNgSLT9aPqzvijRebcLeKTYu53qbjfiCXe7gTGLCH2NNmBKYaE1jqVCqgKD-QBjyzqwStihLhPN_HUuLIabBKAUG40t0GU8h0-EEH6e3UX7q8iH7f9kra2INgGLx4Umzm2CYYFtNcSQXc6VMpKZPvlWYNH83rWvGROj2vF4ZKymeF1evZa0LftRbHIemNlYX-i8HnbPHKbKJRi43mY9lLi8y4I9kyu1UEfXzmtI92lRge-Xm72kGXL49qD8csghczjysh3tIGe-KNYhksr7osTY1Q=w184-h114-no\"><br>Sol:<br>Given: l and m are intersecting lines p||l and q||m<\/p>\n\n\n\n<p>Let us assume that p and q are not intersecting lines, which means p||q.<\/p>\n\n\n\n<p>We know ,<\/p>\n\n\n\n<p>p||l and q||m<\/p>\n\n\n\n<p>\u2234It implies that q||p, q||l , l||m [\u2235p||l] [\u2235q||m]<\/p>\n\n\n\n<p>But , we are given that l and m intersect each other.<\/p>\n\n\n\n<p>Therefore , our assumption is wrong.<\/p>\n\n\n\n<p>Hence , p and q are intersecting lines.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-15\">Question 15<\/h4>\n\n\n\n<p><strong>If a line is perpendicular to any one of the two parallel lines , prove that this line will also be perpendicular to the other parallel line<\/strong><br>Sol :<br>Diagram<br>Given: p||q and r\u27c2p<\/p>\n\n\n\n<p>To prove: r\u27c2q<\/p>\n\n\n\n<p>Proof: p||q (given)<\/p>\n\n\n\n<p>\u22202=\u22201 (alternate interior angle)<\/p>\n\n\n\n<p>\u22202=90\u00b0<\/p>\n\n\n\n<p>\u2234r\u27c2q<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-16\">Question 16<\/h4>\n\n\n\n<p><strong>In the given f\u200cigure, AB||CD and AD||BC, prove that \u2220DAB=\u2220DCB.<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/Acjb_ovEGQDLpaRCe6PktAP-XGvwRBT5LVRlJUmxU4NhFGxuaxU7SltkedeZ9r1c4Cm7tGckKV9g7PyM-gojXirEwx63szBxnWourQmRgWQ7NyF9Hv3AOzsnu3nebCn3RIBNdBUIXhen3x4eRZWMVjPEoYiRoTlQmsNHwTVtLoaMsFEaAb879mERQjcwjWXgmrOfCeMA2yEKH7N9OKeeY5hzgdm_gpIS6Fi5p-m1fkx7rGuTqd0Ll53nQo-JhaoLw17JnbAlUn-HA_whLXX8garPOBj00iYayyn5-hfi4vu0uxwBcdUe4-vY7fdEzpc_YiDP-CunDpljPLzFYZx19BRP1z-rztFYIJPnRLIwV_GZZpTpu0oB2C8v187n9Btlk_1lRq044qql32YmHKGxCyXrrH2TLd2MC_hZ6495Kg7PR1s61BBM8we5T6am9Fjn4fgz717vDegMQX83UOoKOLkV1DE5nIYr3RuwexMVcGbIFH79R6WKSh-D7HYdVG_jfXhDJpi7wyiISwwEn96dVIdh3mWegXd0sMA8v8mQj1C7QVKBY4NWcgxOoQ5eQH7Ga-5zHr0wC2vFiicLz4t5tUY5EZam9suA4mBtisoTki0jUw_3RKu6MC14DxeMXl-XbBVCV2YfeuxXEpsWsgjxzQP6bhyAfCVGKbq3lCkka_IVjbpBJ9Ffmg=w204-h165-no\"><br>Sol :<br>[Hint: AB||DC and transversal BC meets them]<br>\u2234 \u2220ABC+\u2220BCD=180\u00b0..(i)<br>Again AD||BC<br>\u2234 \u2220DAB+\u2220ABC=180\u00b0..(ii)<br>From (i) and (ii) , \u2220ABC+\u2220BCD=\u2220DAB+\u2220ABC=180\u00b0<br>or \u2220DAB=\u2220BCD=\u2220DAB ]<br>Sol :<br>Given: AB||CD and AD||BC<\/p>\n\n\n\n<p>To prove: \u2220DAB=\u2220DCB<\/p>\n\n\n\n<p>Proof: AB||CD (given)<\/p>\n\n\n\n<p>\u2220ABC+\u2220DCB=180\u00b0..(i)<\/p>\n\n\n\n<p>AD||BC(given)<\/p>\n\n\n\n<p>\u2220DAB+\u2220ABC=180\u00b0..(ii)<\/p>\n\n\n\n<p>From equation (i) and (ii)<\/p>\n\n\n\n<p>\u2220DAB+\u2220ABC=\u2220ABC+\u2220DCB<\/p>\n\n\n\n<p>\u2220DAB=\u2220DCB<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-17\">Question 17<\/h4>\n\n\n\n<p><strong>A transversal intersects two given lines m and n in such a way that interior angles on the same side of the transversal are equal , then it is always true that the given lines are parallel ? If not , state the condition under which the two lines will be parallel.<\/strong><br>[Hint: m||n only when transversal line is perpendicular to both m and n]<br>Sol :<br>Diagram<br>\u2220AOC+\u2220BOC=180\u00b0<br>6x+30\u00b0+4x=180\u00b0<br>10x+30\u00b0=180\u00b0<br>10x=180\u00b0-30\u00b0<br>10x=150\u00b0<br>x=\\frac{150^{\\circ}}{10}<br>x=15\u00b0<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-18\">Question 18<\/h4>\n\n\n\n<p><strong>Prove that the two lines that are respectively perpendicular to two intersecting lines intersect each other .<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/BsuA2KiHyRJ0a8cVASA5ycWBh6LBV6lSBw7Vx96hPxwVLf-MtTTg2NwPBP1Az6QTl-Pt0T4Mxls-Tku3iI7D4wOexvDpV-BrTD-vVJ4a6gJK2Rv4A9HDcq5tc4S0bM9qQUK2zjHEkt3l5qlkKL7PymvnCd393jjowqxyHY2Uq4ccQ2_sWfZBslGxr4l-j2_mS3jz6ZiOPqPvn4rkvwN8jSk288b7-wNpzmUUs7bMm9H1KH1m-Zd2EGtmOPbrJf3YJ3ghPsSSnfJ_sVm-E-oweJZ9-2gN3nLes8I1rShsN1M8FZ7HIJUameb-BNmF9tN_hsSuGeEOKugugs_H3AtCjQYqlAaUxVeT0rMA7ftP2v3BnoiMNPEhrukLRYojr6ZvTpNK8ClxkyykSPpsqxP81Ij7YhDvzmC9Y9W-ihLgdMSC2P2L6jZ_XPcowqqBoVnsvHAHLmq6kCL0hUZ3BTaG1t7fu9iI0ueJnixU47kib-wt_IfRP_Qe9DCNgCcFZUi0c-MH6tsj-31WTskeTRWZlT3_F7rDYeq1Mh2Q7FFqQJihKKMpGjxihlclmF1ryoJM-zGbLLfNoN9CsTkmfiCcRfFQxzx9C3O5Cf1kRo-jIc1Y7ug49dZLvgI_GrBy7-S87NlID7xgj5J3_Icl1h49do7cJhu0nf2SgJpoUy3pmlyJd022_DgrbQ=w137-h119-no\"><br>[Hint: As shown in the given figure , lines MN and PQ are perpendicular to intersecting lines AB and CD respectively. If possible , suppose lines MN and PQ do not intersect , then definitely MN||PQ.<br>But we know that two parallel lines cannot be simultaneously perpendicular to two intersecting lines. So , it is wrong to assume that MN||PQ. Hence MN and PQ are intersecting lines&nbsp;]<br>Sol :<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/scontent.fdel11-1.fna.fbcdn.net\/v\/t1.15752-9\/p1080x2048\/96939830_535474527163241_7166520762965164032_n.jpg?_nc_cat=105&amp;_nc_sid=b96e70&amp;_nc_ohc=GGVqaSv4ZHkAX94iwuP&amp;_nc_ht=scontent.fdel11-1.fna&amp;_nc_tp=6&amp;oh=1b0a609668d52523cf59e53613927f77&amp;oe=5EE2D755\"><img decoding=\"async\" src=\"https:\/\/scontent.fdel11-1.fna.fbcdn.net\/v\/t1.15752-9\/p1080x2048\/96939830_535474527163241_7166520762965164032_n.jpg?_nc_cat=105&amp;_nc_sid=b96e70&amp;_nc_ohc=GGVqaSv4ZHkAX94iwuP&amp;_nc_ht=scontent.fdel11-1.fna&amp;_nc_tp=6&amp;oh=1b0a609668d52523cf59e53613927f77&amp;oe=5EE2D755\" alt=\"\"\/><\/a><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-19\">Question 19<\/h4>\n\n\n\n<p><strong>In the given f\u200cigure, lines AB and CD are parallel and any point P lies between these lines . Prove that \u2220ABP+\u2220CDO=\u2220DPB<\/strong><br><img decoding=\"async\" alt=\"\" src=\"https:\/\/lh3.googleusercontent.com\/ljo3XVbJyCKCbGEWWOmRqgMCPJGbUyQ30_TfJ01Oc6Ilr_qVWrhJBNzRCjtevVkhPlBwDHJIDHF93X-YK-hM09FdCHseFXyF0c31Q_ug2lLmCJa6-zDpafk2MgYYiRS6g9w4PU9AOLdf39koS7knURqLaELAO98l6NhLMmeSWr3tfEMrE2MPyG5sczy0K6qCp1XVJB-f1P2c--UhjM6w8l67ApMPhyLM2C_0ih-6b6AF-Gceu3B9yIPneKhZH-fk8RFVcfco9DjllIeMwULc6cmlLiWU-R6R_N0HcykcnMLwIkYsXnO3vBgmHMPUfkGFXkQzzLUmsQ-Myk8b5y6Dpzzf8Q07bnxQGzGTusBvwNSvPVWMCj84NR1ifnAG3pKW_ZGKS0Ay_co0TxPKkiIiS0eBTtARJO-t_Qq7sLOBYETN0mqbhsfGu77xqwAhWSfxBCRxDb0KhdVZ5f7u6Byf2BoC2e0ogj1rQETMuHkVcJ9Vdfb0QXEZa-q82-wbhP32JVUuGAHCoyFpyRhf1GPAPj3O0bX3fPQDYFTKYxeuF2sQkPXoa5MHjN2LasC7Adyjz2QizQQ7UBgrgHW0HIqQifhEsm6sKgQ1Y7FBrYhui7r8VI3oJBFUjEZHl5rbIFfZq_fu3PGYCtyozOlg1vmLJ1sVvM94Eibvybs8jVIssDfzUsmj-9rVkA=w203-h135-no\"><br>[Hint: Through point P , draw a line PM||AB and proceed.]<br>Sol :<\/p>\n\n\n\n<figure class=\"wp-block-image\"><a href=\"https:\/\/scontent.fdel11-1.fna.fbcdn.net\/v\/t1.15752-9\/96833271_333062537670352_8175124022032334848_n.jpg?_nc_cat=109&amp;_nc_sid=b96e70&amp;_nc_ohc=tmZcEZL7-M8AX9Euy9W&amp;_nc_ht=scontent.fdel11-1.fna&amp;oh=cf88254516d15cb36e074b7d5838c197&amp;oe=5EE1B7B7\"><img decoding=\"async\" src=\"https:\/\/scontent.fdel11-1.fna.fbcdn.net\/v\/t1.15752-9\/96833271_333062537670352_8175124022032334848_n.jpg?_nc_cat=109&amp;_nc_sid=b96e70&amp;_nc_ohc=tmZcEZL7-M8AX9Euy9W&amp;_nc_ht=scontent.fdel11-1.fna&amp;oh=cf88254516d15cb36e074b7d5838c197&amp;oe=5EE1B7B7\" alt=\"\"\/><\/a><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\" id=\"h-question-20\">Question 20<\/h4>\n\n\n\n<p><strong>If a transversal intersects two lines such that the bisectors of a pair of alternate angles are parallel, then prove that the two lines are parallel<\/strong><br>Sol :<br>[Hint: Proceed as in solved example 20 page 8.27]<br>Diagram<br>Given: \u2220AOB=\u2220COD..(i)<br>\u2220BOC=\u2220DOA..(ii)<\/p>\n\n\n\n<p>from diagram<br>\u2220AOB+\u2220BOC+\u2220COD+\u2220DOA=360\u00b0<br>\u21d22\u2220COD+2\u2220DOA=360\u00b0<br>\u21d2\u2220COD+\u2220DOA=\\frac{360^{\\circ}}{2}<br>\u21d2\u2220AOC=180\u00b0<\/p>\n\n\n\n<p>Similarly \u2220BOD=180\u00b0<\/p>\n\n\n\n<p>Sum of all angle at a point on a straight line is 180\u00b0<\/p>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solutions\/\">KC Sinha Solutions<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/kc-sinha-solution-for-class-9\/\">KC Sinha Class 9 Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Exercise 8.2 Type 1 Question 1&nbsp; Answer the following questions :(i) If any transversal intersects two parallel lines in such a way that the ratio of interior angles on the same side is 2 : 7 , then f\u200cind the measure of the bigger angle in degrees.(ii) If two parallel lines are intersected by a [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":623859,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[921],"tags":[],"boards":[],"class_list":["post-623860","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-class-9","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>KC Sinha: Exercise 8.2 - Mathematics Solution Class 9 Chapter 8 Lines and Angles - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Exercise 8.2 Type 1 Question 1&nbsp; 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