{"id":618567,"date":"2023-03-03T05:48:37","date_gmt":"2023-03-03T05:48:37","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=618567"},"modified":"2024-05-02T09:07:00","modified_gmt":"2024-05-02T09:07:00","slug":"ncert-exemplar-class-11-physics-chapter-11-thermodynamics","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/ncert-exemplar-class-11-physics-chapter-11-thermodynamics\/","title":{"rendered":"NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics"},"content":{"rendered":"\n<p>NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics. NCERT Exemplar Solutions for Class 11 Physics Chapter 11 Thermodynamics prepare students for their Class 11 exams thoroughly. <\/p>\n\n\n\n<p>Physics problems and solutions for the Class 11 pdf are provided here which are similar to the questions being asked in the previous year&#8217;s board. <\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ncert-exemplar-class-11-physics-chapter-11-thermodynamics\"><strong>NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics<\/strong><\/h2>\n\n\n\n<p>Class 11: Physics Chapter 11 solutions. Complete Class 11 Physics Chapter 11 Notes.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-multiple-choice-questions-mcq-i\"><strong>Multiple Choice Questions (MCQ I)<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>An ideal gas undergoes four different processes from the same initial state (Fig. 12.1). Four processes are adiabatic, isothermal, isobaric and isochoric. Out of 1, 2, 3 and 4 which one is adiabatic.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15793697546_60bc6f91f9_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) 4<\/li>\n\n\n\n<li>(b) 3<\/li>\n\n\n\n<li>(c) 2<\/li>\n\n\n\n<li>(d) 1<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>If an average person jogs, hse produces 14.5 \u00d7 10<sup>3<\/sup> cal\/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming 1 kg requires 580 \u00d7 10<sup>3<\/sup> cal for evaporation) is\n<ul class=\"wp-block-list\">\n<li>(a) 0.25 kg<\/li>\n\n\n\n<li>(b) 2.25 kg<\/li>\n\n\n\n<li>(c) 0.05 kg<\/li>\n\n\n\n<li>(d) 0.20 kg<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Consider P-V diagram for an ideal gas shown in Fig 12.2.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15817373155_97f5fa351f_o.jpg\" alt=\"\"><\/li>\n\n\n\n<li>Out of the following diagrams (Fig. 12.3), which represents the T-P diagram?<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15631543809_d13be03cff_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) (iv)<\/li>\n\n\n\n<li>(b) (ii)<\/li>\n\n\n\n<li>(c) (iii)<\/li>\n\n\n\n<li>(d) (i)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram (Fig. 12.4).<br>The amount of work done by the gas is<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15818923022_9feb93c413_o.jpg\" alt=\"\"><\/li>\n\n\n\n<li>Consider two containers A and B containing identical gases at the same pressure, volume and temperature. The gas in container A is compressed to half of its original volume isothermally while the gas in container B is compressed to half of its original value adiabatically. The ratio of final pressure of gas in B to that of gas in A is<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15815480361_a99393414b_o.jpg\" alt=\"\"><\/li>\n\n\n\n<li>Three copper blocks of masses M<sub>1<\/sub>, M<sub>2<\/sub> and M<sub>3<\/sub> kg respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at T<sub>1<\/sub>, T<sub>2<\/sub>, T<sub>3<\/sub> (T<sub>1<\/sub> &gt; T<sub>2<\/sub> &gt; T<sub>3<\/sub> ). Assuming there is no heat loss to the surroundings, the equilibrium temperature T is (s is specific heat of copper)<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15632507420_72f541d7b6_o.jpg\" alt=\"\"><\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-multiple-choice-questions-mcq-ii\"><strong>Multiple Choice Questions (MCQ II)<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Which of the processes described below are irreversible?\n<ul class=\"wp-block-list\">\n<li>(a) The increase in temperature of an iron rod by hammering it.<\/li>\n\n\n\n<li>(b) A gas in a small container at a temperature T<sub>1<\/sub> is brought in contact with a big reservoir at a higher temperature T<sub>2<\/sub> which increases the temperature of the gas.<\/li>\n\n\n\n<li>(c) A quasi-static isothermal expansion of an ideal gas in cylinder fitted with a frictionless piston.<\/li>\n\n\n\n<li>(d) An ideal gas is enclosed in a piston cylinder arrangement with adiabatic walls. A weight W is added to the piston, resulting in compression of gas.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>An ideal gas undergoes isothermal process from some initial state i to final state f. Choose the correct alternatives.\n<ul class=\"wp-block-list\">\n<li>(a) dU = 0<\/li>\n\n\n\n<li>(b) dQ= 0<\/li>\n\n\n\n<li>(c) dQ = dU<\/li>\n\n\n\n<li>(d) dQ = dW<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Figure 12.5 shows the P-V diagram of an ideal gas undergoing a change of state from A to B. Four different parts I, II, III and IV as shown in the figure may lead to the same change of state.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15631543729_daec3f5cd3_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) Change in internal energy is same in IV and III cases, but not in I and II.<\/li>\n\n\n\n<li>(b) Change in internal energy is same in all the four cases.<\/li>\n\n\n\n<li>(c) Work done is maximum in case I<\/li>\n\n\n\n<li>(d) Work done is minimum in case II.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Consider a cycle followed by an engine (Fig. 12.6)\n<ul class=\"wp-block-list\">\n<li>1 to 2 is isothermal<\/li>\n\n\n\n<li>2 to 3 is adiabatic<\/li>\n\n\n\n<li>3 to 1 is adiabatic<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15632507370_a83019d644_o.jpg\" alt=\"\"><br>Such a process does not exist because<\/li>\n\n\n\n<li>(a) heat is completely converted to mechanical energy in such a process, which is not possible.<\/li>\n\n\n\n<li>(b) mechanical energy is completely converted to heat in this process,which is not possible.<\/li>\n\n\n\n<li>(c) curves representing two adiabatic processes don\u2019t intersect.<\/li>\n\n\n\n<li>(d) curves representing an adiabatic process and an isothermal process don\u2019t intersect.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Consider a heat engine as shown in Fig. 12.7. Q<sub>1<\/sub> and Q<sub>2<\/sub> are heat added to heat bath T<sub>1<\/sub> and heat taken from T<sub>2<\/sub> in one cycle of engine. W is the mechanical work done on the engine.<br>If W &gt; 0, then possibilities are:<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15631543649_b2e2910387_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) Q<sub>1<\/sub> &gt; Q<sub>2<\/sub> &gt; 0<\/li>\n\n\n\n<li>(b) Q<sub>2<\/sub> &gt; Q<sub>1<\/sub> &gt; 0<\/li>\n\n\n\n<li>(c) Q<sub>2<\/sub> &lt; Q<sub>1<\/sub> &lt; 0<\/li>\n\n\n\n<li>(d) Q<sub>1<\/sub> &lt; 0, Q<sub>2<\/sub> &gt; 0<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-very-short-answer-type-questions\"><strong>Very Short Answer Type Questions<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Can a system be heated and its temperature remains constant?<\/li>\n\n\n\n<li>A system goes from P to Q by two different paths in the P-V diagram as shown in Fig. 12.8. Heat given to the system in path 1 is 1000 J. The work done by the system along path 1 is more than path 2 by 100 J. What is the heat exchanged by the system in path 2?<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15631543579_ef34486d35_o.jpg\" alt=\"\"><\/li>\n\n\n\n<li>If a refrigerator\u2019s door is kept open, will the room become cool or hot? Explain.<\/li>\n\n\n\n<li>Is it possible to increase the temperature of a gas without adding heat to it? Explain.<\/li>\n\n\n\n<li>Air pressure in a car tyre increases during driving. Explain.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-short-answer-type-questions\"><strong>Short Answer Type Questions<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Consider a Carnot\u2019s cycle operating between T<sub>1<\/sub> = 500K and T<sub>2<\/sub> = 300K producing 1 k J of mechanical work per cycle. Find the heat transferred to the engine by the reservoirs.<\/li>\n\n\n\n<li>A person of mass 60 kg wants to lose 5kg by going up and down a 10m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt on expending 7000 kilo calories, how many times must he go up and down to reduce his weight by 5 kg?<\/li>\n\n\n\n<li>Consider a cycle tyre being filled with air by a pump. Let V be the volume of the tyre (fixed) and at each stroke of the pump \u0394V\u2264V)<br>of air is transferred to the tube adiabatically. What is the work done when the pressure in the tube is increased from P<sub>1<\/sub> to P<sub>2<\/sub>?<\/li>\n\n\n\n<li>In a refrigerator one removes heat from a lower temperature and deposits to the surroundings at a higher temperature. In this process, mechanical work has to be done, which is provided by an electric motor. If the motor is of 1kW power, and heat is transferred from \u20133\u00b0C to 27\u00b0C, find the heat taken out of the refrigerator per second assuming its efficiency is 50% of a perfect engine.<\/li>\n\n\n\n<li>If the co-efficient of performance of a refrigerator is 5 and operates at the room temperature (27 \u00b0C), find the temperature inside the refrigerator.<\/li>\n\n\n\n<li>The initial state of a certain gas is (P<sub>i<\/sub>, V<sub>i<\/sub>, T<sub>i<\/sub>). It undergoes expansion till its volume becomes Vf . Consider the following two cases:\n<ul class=\"wp-block-list\">\n<li>(a) the expansion takes place at constant temperature.<\/li>\n\n\n\n<li>(b) the expansion takes place at constant pressure.<br>Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more?<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-long-answer-type-questions\"><strong>Long Answer Type Questions<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Consider a P-V diagram in which the path followed by one mole of perfect gas in a cylindrical container is shown in Fig. 12.9.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15632181557_530bf6e97b_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) Find the work done when the gas is taken from state 1 to state 2.<\/li>\n\n\n\n<li>(b) What is the ratio of temperature T<sub>1<\/sub>\/T<sub>2<\/sub>, if V<sub>2<\/sub> = 2V<sub>1<\/sub>?<\/li>\n\n\n\n<li>(c) Given the internal energy for one mole of gas at temperature T is (3\/2) RT, find the heat supplied to the gas when it is taken from state 1 to 2, with V<sub>2<\/sub> = 2V<sub>1<\/sub>.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>A cycle followed by an engine (made of one mole of perfect gas in a cylinder with a piston) is shown in Fig. 12.10.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15197401604_18db29992c_o.jpg\" alt=\"\"><br>A to B : volume constant<br>B to C : adiabatic<br>C to D : volume constant<br>D to A : adiabatic<br>V<sub>C<\/sub> = V<sub>D<\/sub> = 2V<sub>A<\/sub> = 2V<sub>B<\/sub>\n<ul class=\"wp-block-list\">\n<li>(a) In which part of the cycle heat is supplied to the engine from outside?<\/li>\n\n\n\n<li>(b) In which part of the cycle heat is being given to the surrounding by the engine?<\/li>\n\n\n\n<li>(c) What is the work done by the engine in one cycle? Write your answer in term of P<sub>A<\/sub>, P<sub>B<\/sub>, V<sub>A<\/sub>.<\/li>\n\n\n\n<li>(d) What is the efficiency of the engine?<br>[ 5 \u03b3 = 5 \/ 3 for the gas], (C<sub>V<\/sub> = 3 \/ 2 R for one mole)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>A cycle followed by an engine (made of one mole of an ideal gas in a cylinder with a piston) is shown in Fig. 12.11. Find heat exchanged by the engine, with the surroundings for each section of the cycle. (C<sub>v<\/sub> = (3\/2) R)<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15197401554_e6e6b20a3e_o.jpg\" alt=\"\"><br>AB : constant volume<br>BC : constant pressure<br>CD : adiabatic<br>DA : constant pressure<\/li>\n\n\n\n<li>Consider that an ideal gas (n moles) is expanding in a process given by P = f ( V ), which passes through a point (V<sub>o<\/sub>, P<sub>o<\/sub>). Show that the gas is absorbing heat at (P<sub>o<\/sub>, V<sub>o<\/sub>) if the slope of the curve P = f (V ) is larger than the slope of the adiabat passing through (P<sub>o<\/sub>, V<sub>o<\/sub>).<\/li>\n\n\n\n<li>Consider one mole of perfect gas in a cylinder of unit cross section with a piston attached (Fig. 12.12). A spring (spring constant k) is attached (unstretched length L ) to the piston and to the bottom of the cylinder. Initially the spring is unstretched and the gas is in equilibrium. A certain amount of heat Q is supplied to the gas causing an increase of volume from V<sub>o<\/sub> to V<sub>1<\/sub>.<br><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2023\/03\/15817372865_0b5a870bb4_o.jpg\" alt=\"\">\n<ul class=\"wp-block-list\">\n<li>(a) What is the initial pressure of the system?<\/li>\n\n\n\n<li>(b) What is the final pressure of the system?<\/li>\n\n\n\n<li>(c) Using the first law of thermodynamics, write down a relation between Q, P<sub>a<\/sub>, V, V<sub>o<\/sub> and k.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h2 class=\"wp-block-heading\">Answers to Multiple Choice Questions<\/h2>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49036956458_bdf013bea0_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037679417_8c595f2de7_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037465111_9c6e728134_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037468771_1dfb6b6893_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49036969933_7cd0178444_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49036974318_5b594753ff_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037481451_57e9f25025_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49036982738_314c7c1352_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037487441_aa9b614036_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49036987823_77f9141c3e_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037710052_05e8cddd61_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037713447_251aa9a8fa_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2024\/05\/49037498571_f781779e53_o.png\" alt=\"\"\/><\/figure>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-exemplar-problems-solutions\/\" style=\"background-color:#f06d6d\" target=\"_blank\" rel=\"noreferrer noopener\">NCERT Exemplar Solutions<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-exemplar-class-11-physics-solutions\/\" style=\"background-color:#f06d6d\" target=\"_blank\" rel=\"noreferrer noopener\">NCERT Class 11 Exemplar Solutions<\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics. NCERT Exemplar Solutions for Class 11 Physics Chapter 11 Thermodynamics prepare students for their Class 11 exams thoroughly. Physics problems and solutions for the Class 11 pdf are provided here which are similar to the questions being asked in the previous year&#8217;s board. NCERT Exemplar Class 11 [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":618603,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,919],"tags":[],"boards":[],"class_list":["post-618567","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-11","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Exemplar for Class 11, Physics Chapter 11 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics | Browse all Class 11 Physics Chapters NCERT Exemplar books - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-exemplar-class-11-physics-chapter-11-thermodynamics\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics\" \/>\n<meta property=\"og:description\" content=\"NCERT Exemplar Class 11 Physics Chapter 11: Thermodynamics. 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