{"id":602645,"date":"2022-05-14T10:46:26","date_gmt":"2022-05-14T10:46:26","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=602645"},"modified":"2022-05-17T10:25:20","modified_gmt":"2022-05-17T10:25:20","slug":"ml-aggarwal-solutions-for-class-6-maths-chapter-8-ratio-and-proportion","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-8-ratio-and-proportion\/","title":{"rendered":"ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion"},"content":{"rendered":"\n<p>Class 6: Maths Chapter 8 solutions. Complete Class 6 Maths Chapter 8 Notes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ml-aggarwal-solutions-for-class-6-maths-chapter-8-ratio-and-proportion\">ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion<\/h2>\n\n\n\n<p>ML Aggarwal 6th Maths Chapter 8, Class 6 Maths Chapter 8 solutions<\/p>\n\n\n\n<p>Exercise<strong><br>1. Express the following ratios in simplest form:<br>(i) 20 : 40<br>(ii)40 : 20<br>(iii) 81 : 108<br>(iv) 98 : 63<br>Solution:<\/strong><\/p>\n\n\n\n<p>(i) 20 : 40 = 20\/40 = \u00bd = 1 : 2<\/p>\n\n\n\n<p>(ii) 40 : 20 = 40\/20 = 2\/1 = 2 : 1<\/p>\n\n\n\n<p>(iii) 81 : 108 = 81\/108 = 9\/12 = \u00be = 3 : 4<\/p>\n\n\n\n<p>(iv) 98 : 63 = 98\/63 = 14\/9 = 14 : 9<\/p>\n\n\n\n<p><strong><br>2. Fill in the missing numbers in the following equivalent ratios::<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/05\/ml-aggarwal-solutions-for-class-6-chapter-8-1.png\" alt=\"ML Aggarwal Solutions for Class 6 Chapter 8 - 1\" title=\"ML Aggarwal Solutions Class 6 Maths Chapter 8\"\/><\/figure>\n\n\n\n<p>Solution<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/05\/ml-aggarwal-solutions-for-class-6-chapter-8-2.png\" alt=\"ML Aggarwal Solutions for Class 6 Chapter 8 - 2\" title=\"ML Aggarwal Solutions Class 6 Maths Chapter 8\"\/><\/figure>\n\n\n\n<p><strong><br>3. Find the ratio of each of the following in simplest form :<br>(i) 2.1 m to 1.2 m<br>(ii) 91 cm to 1.04m<br>(iii) 3.5 kg to 250gm<br>(iv) 60 paise to 4 rupees<br>(v) 1 minute to 15 seconds<br>(vi) 15 mm to 2 cm<br>Solution:<\/strong><\/p>\n\n\n\n<p><strong><br><\/strong><br>(i) 2.1 m : 1.2 m<\/p>\n\n\n\n<p>= 2.1\/ 1.2<\/p>\n\n\n\n<p>= 21\/12 \u00d7 10\/10<\/p>\n\n\n\n<p>= 7 : 4<\/p>\n\n\n\n<p>(ii) 91 cm : 1.04mm or (1.04 \u00d7 100) cm = 104 cm [As 1 m = 100 cm]<\/p>\n\n\n\n<p>= 91 cm : 104 cm<\/p>\n\n\n\n<p>= 91\/104<\/p>\n\n\n\n<p>= 7 : 8<\/p>\n\n\n\n<p>(iii) 3.5 kg : 250 gm or (3.5 \u00d7 1000) gm : 250 gm [As 1 kg = 1000 gm]<\/p>\n\n\n\n<p>=&nbsp;3500 gm : 250 gm<\/p>\n\n\n\n<p>= 3500\/250<\/p>\n\n\n\n<p>= 14\/1<\/p>\n\n\n\n<p>= 14 : 1<\/p>\n\n\n\n<p>(iv) 60 paise : 4 rupees or 60 paise : (4 \u00d7 100) paise [As 1 Rs = 100 paise]<\/p>\n\n\n\n<p>= 60 paise : 400 paise<\/p>\n\n\n\n<p>= 60\/400<\/p>\n\n\n\n<p>= 6\/40<\/p>\n\n\n\n<p>= 3\/20<\/p>\n\n\n\n<p>= 3 : 20<\/p>\n\n\n\n<p>(v) 1 minute : 15 seconds or 60 seconds : 15 seconds [As 1 minute = 60 seconds]<\/p>\n\n\n\n<p>= 60 : 15<\/p>\n\n\n\n<p>= 60\/15<\/p>\n\n\n\n<p>= 4\/1<\/p>\n\n\n\n<p>= 4 : 1<\/p>\n\n\n\n<p>(vi) 15 mm : 2 cm or 15 mm : (2 \u00d7 10) mm [As 1 cm = 10 mm]<\/p>\n\n\n\n<p>= 15 mm : 20 mm<\/p>\n\n\n\n<p>= 15\/20<\/p>\n\n\n\n<p>= 3\/4<\/p>\n\n\n\n<p>= 3 : 4<\/p>\n\n\n\n<p><strong><br>4. The length and the breadth of a rectangular park are 125 m and 60 m respectively. What is the ratio of the length to the breadth of the park?<br>Solution:<\/strong><\/p>\n\n\n\n<p><strong><br><\/strong><br>Given,<\/p>\n\n\n\n<p>Length of rectangular park = 125 m<\/p>\n\n\n\n<p>Breadth of rectangular park = 60 m<\/p>\n\n\n\n<p>Hence, the ratio of the length to the breadth of park is<\/p>\n\n\n\n<p>125\/60 = 25\/12 = 25 : 12<\/p>\n\n\n\n<p><strong><br>5. The population of village is 4800. If the numbers of females is 2160, find the ratio of males to that of females.<br>Solution:<\/strong><\/p>\n\n\n\n<p>Given,<\/p>\n\n\n\n<p>Population of village = 4800<\/p>\n\n\n\n<p>No. of females = 2160<\/p>\n\n\n\n<p>No. of males = 4800 \u2013 2160 = 2640<\/p>\n\n\n\n<p>No. of males : No. of females<\/p>\n\n\n\n<p>= 2640 : 2160<\/p>\n\n\n\n<p>= 2640\/2160<\/p>\n\n\n\n<p>= 264\/216<\/p>\n\n\n\n<p>= 11\/9<\/p>\n\n\n\n<p>= 11 : 9<\/p>\n\n\n\n<p><strong><br>6. In a class, there are 30 boys and 25 girls. Find the ratio of the numbers of<br>(i) boys to that of girls.<br>(ii) girls to that of total number of students.<br>(iii) boys to that of total number of students.<br>Solution:<\/strong><\/p>\n\n\n\n<p>Given,<\/p>\n\n\n\n<p>Boys = 30, girls = 25<\/p>\n\n\n\n<p>Total students = 30 + 25 = 55<\/p>\n\n\n\n<p>(i) boys : girls = 30 : 25<\/p>\n\n\n\n<p>= 30\/25 = 6\/5 = 6 : 5<\/p>\n\n\n\n<p>(ii) girls : Total no. of students = 25 : 55<\/p>\n\n\n\n<p>= 25\/55 = 5\/11 = 5 : 11<\/p>\n\n\n\n<p>(iii) Boys : Total no. of students = 30 : 55<\/p>\n\n\n\n<p>= 30\/55 = 6\/11 = 6 : 11<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-download-pdf\"><strong>Download PDF<\/strong><\/h2>\n\n\n\n<p>ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion<\/p>\n\n\n\n<p><a href=\"https:\/\/www.indcareer.com\/docs\/8edb06ad-efcb-4e73-922b-504837170f1c\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Download PDF<\/strong>: ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion PDF<\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Chapterwise ML Aggarwal Solutions for Class 6 Maths :<\/strong><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-1-knowing-our-numbers\/\">Chapter 1- Knowing Our Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-2-whole-numbers\/\">Chapter 2- Whole Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-3-integers\/\">Chapter 3- Integers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-4-playing-with-numbers\/\">Chapter 4- Playing with Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-5-sets\/\">Chapter 5- Sets<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-6-fractions\/\">Chapter 6- Fractions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-7-decimals\/\">Chapter 7- Decimals<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-8-ratio-and-proportion\/\">Chapter 8- Ratio and Proportion<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-9-algebra\/\">Chapter 9- Algebra<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-10-basic-geometrical-concept\/\">Chapter 10- Basic Geometrical Concept<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-11-understanding-symmetrical-shapes\/\">Chapter 11- Understanding Symmetrical Shapes<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-12-symmetry\/\">Chapter 12- Symmetry<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-13-practical-geometry\/\">Chapter 13- Practical Geometry<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-14-mensuration\/\">Chapter 14- Mensuration<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-15-data-handling\/\">Chapter 15- Data Handling<\/a><\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\">About ML Aggarwal<\/h2>\n\n\n\n<p>M. L. Aggarwal, is an Indian mechanical engineer, educator. His achievements include research in solutions of industrial problems related to fatigue design. Recipient Best Paper award, Manipal Institute of Technology, 2004. Member of TSTE.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Class 6: Maths Chapter 8 solutions. Complete Class 6 Maths Chapter 8 Notes. ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion ML Aggarwal 6th Maths Chapter 8, Class 6 Maths Chapter 8 solutions Exercise1. Express the following ratios in simplest form:(i) 20 : 40(ii)40 : 20(iii) 81 : 108(iv) 98 : [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":602648,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,876],"tags":[2265],"boards":[],"class_list":["post-602645","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-6","tag-ml-aggarwal-solutions","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>ML Aggarwal Solutions for Class 6, maths Chapter 8 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion | Browse all Class 6 Maths - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-8-ratio-and-proportion\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"ML Aggarwal Solutions for Class 6 Maths Chapter 8- Ratio and Proportion\" \/>\n<meta property=\"og:description\" content=\"Class 6: Maths Chapter 8 solutions. 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