{"id":602600,"date":"2022-05-14T10:20:33","date_gmt":"2022-05-14T10:20:33","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=602600"},"modified":"2022-05-17T10:11:08","modified_gmt":"2022-05-17T10:11:08","slug":"ml-aggarwal-solutions-for-class-6-maths-chapter-2-whole-numbers","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/ml-aggarwal-solutions-for-class-6-maths-chapter-2-whole-numbers\/","title":{"rendered":"ML Aggarwal Solutions for Class 6 Maths Chapter 2- Whole Numbers"},"content":{"rendered":"\n

Class 6: Maths Chapter 2 solutions. Complete Class 6 Maths Chapter 2 Notes.<\/p>\n\n\n\n

ML Aggarwal Solutions for Class 6 Maths Chapter 2- Whole Numbers<\/h2>\n\n\n\n

ML Aggarwal 6th Maths Chapter 2, Class 6 Maths Chapter 2 solutions<\/p>\n\n\n\n

1. Write the smallest whole number. Can you write the largest whole number?
Solution:<\/strong><\/p>\n\n\n\n

The smallest whole number is 0.<\/p>\n\n\n\n

No, we cannot write the largest whole number.<\/p>\n\n\n\n

2. Write the successor of each of the following numbers:
(i) 3999
(ii) 378915
(iii) 5001299
Solution:<\/strong><\/p>\n\n\n\n

(i)<\/strong> 3999<\/p>\n\n\n\n

The successor of 3999 is<\/p>\n\n\n\n

3999 + 1 = 4000<\/p>\n\n\n\n

(ii)<\/strong> 378915<\/p>\n\n\n\n

The successor of 378915 is<\/p>\n\n\n\n

378915 + 1 = 378916<\/p>\n\n\n\n

(iii)<\/strong> 5001299<\/p>\n\n\n\n

The successor of 5001299 is<\/p>\n\n\n\n

5001299 + 1 = 5001300<\/p>\n\n\n\n

3. Write the predecessor of each of the following numbers:
(i) 500
(ii) 38794
(iii) 54789011
Solution:<\/strong><\/p>\n\n\n\n

(i)<\/strong> 500<\/p>\n\n\n\n

Predecessor of 500 is<\/p>\n\n\n\n

500 \u2013 1 = 499<\/p>\n\n\n\n

(ii)<\/strong> 38794<\/p>\n\n\n\n

Predecessor of 38794 is<\/p>\n\n\n\n

38794 \u2013 1 = 38793<\/p>\n\n\n\n

(iii)<\/strong> 54789011<\/p>\n\n\n\n

Predecessor of 54789011 is<\/p>\n\n\n\n

54789011 \u2013 1 = 54789010<\/p>\n\n\n\n

4. Write the whole number (in each of the following) whose successor is:
(i) 50795
(ii) 720300
(iii) 8300000
Solution:<\/strong><\/p>\n\n\n\n

(i)<\/strong> 50795<\/p>\n\n\n\n

The required whole number = Predecessor of given number<\/p>\n\n\n\n

50795 \u2013 1 = 50794<\/p>\n\n\n\n

(ii)<\/strong> 720300<\/p>\n\n\n\n

The required whole number = Predecessor of given number<\/p>\n\n\n\n

720300 \u2013 1 = 720299<\/p>\n\n\n\n

(iii)<\/strong> 8300000<\/p>\n\n\n\n

The required whole number = Predecessor of given number<\/p>\n\n\n\n

8300000 \u2013 1 = 8299999<\/p>\n\n\n\n

5. Write the whole number (in each of the following) whose predecessor is:
(i) 5347
(ii) 72399
(iii) 3012999
Solution:<\/strong><\/p>\n\n\n\n

(i)<\/strong> 5347<\/p>\n\n\n\n

The required whole number = Successor of given number<\/p>\n\n\n\n

5347 + 1 = 5348<\/p>\n\n\n\n

(ii)<\/strong> 72399<\/p>\n\n\n\n

The required whole number = Successor of given number<\/p>\n\n\n\n

72399 + 1 = 72400<\/p>\n\n\n\n

(iii)<\/strong> 3012999<\/p>\n\n\n\n

The required whole number = Successor of given number<\/p>\n\n\n\n

3012999 + 1 = 3013000<\/p>\n\n\n\n

6. Write next three consecutive whole numbers of the following numbers:
(i) 79
(ii) 598
(iii) 35669
Solution:<\/strong><\/p>\n\n\n\n

(i)<\/strong> 79<\/p>\n\n\n\n

The next three consecutive whole numbers are 80, 81, 82.<\/p>\n\n\n\n

(ii)<\/strong> 598<\/p>\n\n\n\n

The next three consecutive whole numbers are 599, 600, 601.<\/p>\n\n\n\n

(iii)<\/strong> 35669<\/p>\n\n\n\n

The next three consecutive whole numbers are 35670, 35671, 35672.<\/p>\n\n\n\n

Download PDF<\/strong><\/h2>\n\n\n\n

ML Aggarwal Solutions for Class 6 Maths Chapter 2- Whole Numbers<\/p>\n\n\n\n

Download PDF<\/strong>: ML Aggarwal Solutions for Class 6 Maths Chapter 2- Whole Numbers PDF<\/a><\/p>\n\n\n\n

Chapterwise ML Aggarwal Solutions for Class 6 Maths :<\/strong><\/h2>\n\n\n\n