{"id":597676,"date":"2022-04-30T09:34:46","date_gmt":"2022-04-30T09:34:46","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=597676"},"modified":"2022-05-09T05:21:42","modified_gmt":"2022-05-09T05:21:42","slug":"selina-class-8-icse-solutions-mathematics-chapter-18-constructions","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/selina-class-8-icse-solutions-mathematics-chapter-18-constructions\/","title":{"rendered":"Selina Class 8 ICSE Solutions Mathematics : Chapter 18-\u00a0Constructions"},"content":{"rendered":"\n

Class 8: Maths Chapter 18 solutions. Complete Class 8 Maths Chapter 18 Notes.<\/p>\n\n\n\n

Selina Class 8 ICSE Solutions Mathematics : Chapter 18- Constructions<\/h2>\n\n\n\n

Selina 8th Maths Chapter 18, Class 8 Maths Chapter 18 solutions<\/p>\n\n\n\n

Exercise 18A<\/h3>\n\n\n\n

Question 1.
<\/strong>Given below are the angles x and y.
\"Selina
Without measuring these angles, construct :
(i) \u2220ABC = x + y
(ii) \u2220ABC = 2x + y
(iii) \u2220ABC = x + 2y
Solution:
<\/strong>\"Selina
\"Selina
\"Selina<\/p>\n\n\n\n

Question 2.
<\/strong>Given below are the angles x, y and z.
Without measuring these angles construct :
(i) \u2220ABC = x + y + z
(ii) \u2220ABC = 2x + y + z
(iii) \u2220ABC = x + 2y + z
\"Selina
Solution:
<\/strong>\"Selina
\"Selina
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Question 3.
<\/strong>Draw a line segment BC = 4 cm. Construct angle ABC = 60\u00b0.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 4.
<\/strong>Construct angle ABC = 45\u00b0 in which BC = 5 cm and AB = 4.6 cm.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 5.
<\/strong>Construct angle ABC = 90\u00b0. Draw BP, the bisector of angle ABC. State the measure of angle PBC.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 6.
<\/strong>6. Draw angle ABC of any suitable measure.
(i) Draw BP, the bisector of angle ABC.
(ii) Draw BR, the bisector of angle PBC and draw BQ, the bisector of angle ABP.
(iii) Are the angles ABQ, QBP, PBR and RBC equal?
(iv) Are the angles ABR and QBC equal ?
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Exercise 18B<\/h3>\n\n\n\n

Question 1.
<\/strong>Draw a line segment AB of length 5.3 cm. Using two different methods bisect AB.
Solution:
<\/strong>\"Selina
\"Selina<\/p>\n\n\n\n

Question 2.
<\/strong>Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 3.
<\/strong>In each of the following, draw perpendicular through point P to the line segment AB :
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Solution:
<\/strong>\"Selina
\"Selina
\"Selina<\/p>\n\n\n\n

Question 4.
<\/strong>Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From the point P, draw a perpendicular to AB.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 5.
<\/strong>Draw a line segment AB = 6.2 cm. Mark a point P in AB such that BP = 4 cm. Through point P draw perpendicular to AB.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Exercise 18C<\/h3>\n\n\n\n

Question 1.
<\/strong>Draw a line AB = 6 cm. Mark a point P any where outside the line AB. Through the point P, construct a line parallel to AB.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 2.
<\/strong>Draw a line MN = 5.8 cm. Locate a point A which is 4.5 cm from M and 5 cm from N. Through A draw a line parallel to line MN.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 3.
<\/strong>Draw a straight line AB = 6.5 cm. Draw another line which is parallel to AB at a distance of 2.8 cm from it.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 4.
<\/strong>Construct an angle PQR = 80\u00b0. Draw a line parallel to PQ at a distance of 3 cm from it and another line parallel to QR at a distance of 3.5 cm from it. Mark the point of intersection of these parallel lines as A.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 5.
<\/strong>Draw an angle ABC = 60\u00b0. Draw the bisector of it. Also draw a line parallel to BC a distance of 2.5 cm from it.
Let this parallel line meet AB at point P and angle bisector at point Q. Measure the length of BP and PQ. Is BP = PQ?
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 6.
<\/strong>Construct an angle ABC = 90\u00b0. Locate a point P which is 2.5 cm from AB and 3.2 cm from BC.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Exercise 18D<\/h3>\n\n\n\n

Question 1.
<\/strong>Construct a quadrilateral ABCD; if:
(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and angle ABC = 75\u00b0.
(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and \u2220BCD = 60\u00b0.
(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, \u2220A = 60\u00b0 and \u2220B = 75\u00b0.
(iv) AB = 5 cm, BC = 6.5 cm, CD =4.8 cm, \u2220B = 75\u00b0 and \u2220C = 120\u00b0.
(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.
(vi) AB = AD = 5cm, BD = 7 cm and BC = DC = 5.5 cm
Solution:
<\/strong>\"Selina
\"Selina<\/p>\n\n\n\n

\"Selina<\/figure>\n\n\n\n
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\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n

Question 2.
<\/strong>Construct a parallelogram ABCD, if :
(i) AB = 3.6 cm, BC = 4.5 cm and \u2220ABC = 120\u00b0.
(ii) BC = 4.5 cm, CD = 5.2 cm and \u2220ADC = 75\u00b0.
(iii) AD = 4 cm, DC = 5 cm and diagonal BD = 7 cm.
(iv) AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
(v) diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75\u00b0.
(vi) lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45\u00b0.
(vii) lengths of diagonals AC and BD are 5.4 cm and 6.7 cm respectively and the angle between them is 60\u00b0.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n
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\"Selina<\/figure>\n\n\n\n
\"Selina<\/figure>\n\n\n\n

Question 3.
<\/strong>Construct a rectangle ABCD ; if :
(i) AB = 4.5 cm and BC = 5.5 cm.
(ii) BC = 61 cm and CD = 6.8 cm.
(iii) AB = 5.0 cm and diagonal AC = 6.7 cm.
(iv) AD = 4.8 cm and diagonal AC = 6.4 cm.
(v) each diagonal is 6 cm and the angle between them is 45\u00b0.
(vi) each diagonal is 5.5 cm and the angle between them is 60\u00b0.
Solution:
<\/strong>\"Selina
\"Selina
\"Selina
\"Selina
\"Selina
\"Selina<\/p>\n\n\n\n

Question 4.
<\/strong>Construct a rhombus ABCD, if ;
(i) AB = 4 cm and \u2220B = 120\u00b0.
(ii) BC = 4.7 cm and \u2220B = 75\u00b0.
(iii) CD = 5 cm and diagonal BD = 8.5 cm.
(iv) BC = 4.8cm, and diagonal AC = 7cm.
(v) diagonal AC = 6 cm and diagonal BD = 5.8 cm.
(vi) diagonal AC = 4.9 cm and diagonal BD = 6 cm.
(vii) diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.
Solution:
<\/strong>\"Selina
\"Selina
\"Selina
\"Selina
\"Selina
\"Selina
\"Selina<\/p>\n\n\n\n

Question 5.
<\/strong>Construct a square, if :
(i) its one side is 3.8 cm.
(ii) its each side is 4.3 cm.
(iii) one diagonal is 6.2 cm.
(iv) each diagonal is 5.7 cm.
Solution:
<\/strong>\"Selina
\"Selina
\"Selina
\"Selina<\/p>\n\n\n\n

Question 6.
<\/strong>Construct a quadrilateral ABCD in which ; \u2220A = 120\u00b0, \u2220B = 60\u00b0, AB = 4 cm, BC = 4.5 cm and CD = 5 cm.
Solution:
<\/strong>\"Selina
\"Selina<\/p>\n\n\n\n

Question 7.
<\/strong>Construct a quadrilateral ABCD, such that AB = BC = CD = 4.4 cm, \u2220B = 90\u00b0 and \u2220C = 120\u00b0.
Solution:
<\/strong>\"Selina
\"Selina<\/p>\n\n\n\n

Question 8.
<\/strong>Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and \u2220DAB = 60\u00b0. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Question 9.
<\/strong>Draw a parallelogram ABCD, with AB = 6 cm, AD = 4.8 cm and \u2220DAB = 45\u00b0. Draw the perpendicular bisector of side AD and let it meet AD at point P. Also draw the diagonals AC and BD ; and let they intersect at point O. Join O and P. Measure OP.
Solution:
\"Selina<\/p>\n\n\n\n

Question 10.
<\/strong>Using ruler and compasses only, construct a rhombus whose diagonals are 8 cm and 6 cm. Measure the length of its one side.
Solution:
<\/strong>\"Selina<\/p>\n\n\n\n

Download PDF<\/strong><\/h2>\n\n\n\n

Selina Class 8 ICSE Solutions Mathematics : Chapter 18- Constructions<\/p>\n\n\n\n

Download PDF<\/strong>: Selina Class 8 ICSE Solutions Mathematics : Chapter 18-\u00a0Constructions PDF<\/a><\/p>\n\n\n\n

Chapterwise Selina Publishers ICSE Solutions for Class 8 Mathematics :<\/strong><\/h2>\n\n\n\n