{"id":592314,"date":"2022-04-25T05:22:37","date_gmt":"2022-04-25T05:22:37","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=592314"},"modified":"2022-04-25T10:44:22","modified_gmt":"2022-04-25T10:44:22","slug":"selina-class-10-icse-solutions-mathematics-chapter-17-circles","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/","title":{"rendered":"Selina Class 10 ICSE Solutions Mathematics : Chapter 17-\u00a0Circles"},"content":{"rendered":"\n<p>Class 10: Maths Chapter 17 solutions. Complete Class 10 Maths Chapter 17 Notes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-selina-class-10-icse-solutions-mathematics-chapter-17-circles\">Selina Class 10 ICSE Solutions Mathematics : Chapter 17-&nbsp;Circles<\/h2>\n\n\n\n<p>Selina 10th Maths Chapter 17, Class 10 Maths Chapter 17 solutions<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Exercise 17A<\/h3>\n\n\n\n<p><strong>Question 1.<br>In the given figure, O is the centre of the circle. \u2220OAB and \u2220OCB are 30\u00b0 and 40\u00b0 respectively. Find \u2220AOC. Show your steps of working.<br><img loading=\"lazy\" decoding=\"async\" width=\"204\" height=\"198\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-1.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 1\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"554\" height=\"568\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-2.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 2\"><\/p>\n\n\n\n<p><strong>Question 2.<br>In the given figure, \u2220BAD = 65\u00b0, \u2220ABD = 70\u00b0, \u2220BDC = 45\u00b0<\/strong><br>(i) Prove that AC is a diameter of the circle.<br>(ii) Find \u2220ACB.<br><img loading=\"lazy\" decoding=\"async\" width=\"176\" height=\"172\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-3.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 3\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"571\" height=\"232\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-4.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 4\"><\/p>\n\n\n\n<p><strong>Question 3.<br>Given O is the centre of the circle and \u2220AOB = 70\u00b0. Calculate the value of:<\/strong><br>(i) \u2220 OCA,<br>(ii) \u2220OAC.<br><img loading=\"lazy\" decoding=\"async\" width=\"189\" height=\"193\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-5.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 5\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"543\" height=\"358\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-6.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 6\"><\/p>\n\n\n\n<p><strong>Question 4.<br>In each of the following figures, O is the centre of the circle. Find the values of a, b, and c.<br><img loading=\"lazy\" decoding=\"async\" width=\"400\" height=\"203\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-7.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 7\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"436\" height=\"504\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-8.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 8\"><\/p>\n\n\n\n<p><strong>Question 5.<br>In each of the following figures, O is the centre of the circle. Find the value of a, b, c and d.<br><img loading=\"lazy\" decoding=\"async\" width=\"437\" height=\"388\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-9.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 9\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"442\" height=\"385\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-10.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 10\"><br><img loading=\"lazy\" decoding=\"async\" width=\"415\" height=\"559\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-11.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 11\"><\/p>\n\n\n\n<p><strong>Question 6.<br>In the figure, AB is common chord of the two circles. If AC and AD are diameters; prove that D, B and C are in a straight line. O<sub>1<\/sub> and O<sub>2<\/sub> are the centres of two circles.<br><img loading=\"lazy\" decoding=\"async\" width=\"306\" height=\"191\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-12.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 12\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"602\" height=\"308\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-13.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 13\"><\/p>\n\n\n\n<p><strong>Question 7.<br>In the figure given beow, find :<\/strong><br>(i) \u2220 BCD,<br>(ii) \u2220 ADC,<br>(iii) \u2220 ABC.<br><img loading=\"lazy\" decoding=\"async\" width=\"202\" height=\"185\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-14.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 14\"><br><strong>Show steps of your workng.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"545\" height=\"464\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-15.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 15\"><\/p>\n\n\n\n<p><strong>Question 8.<br>In the given figure, O is centre of the circle. If \u2220 AOB = 140\u00b0 and \u2220 OAC = 50\u00b0; find :<\/strong><br>(i) \u2220 ACB,<br>(ii) \u2220 OBC,<br>(iii) \u2220 OAB,<br>(iv) \u2220CBA<br><img loading=\"lazy\" decoding=\"async\" width=\"161\" height=\"152\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-16.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 16\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"538\" height=\"393\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-17.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 17\"><\/p>\n\n\n\n<p><strong>Question 9.<br>Calculate :<\/strong><br>(i) \u2220 CDB,<br>(ii) \u2220 ABC,<br>(iii) \u2220 ACB.<br><img loading=\"lazy\" decoding=\"async\" width=\"241\" height=\"243\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-18.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 18\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"574\" height=\"393\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-19.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 19\"><\/p>\n\n\n\n<p><strong>Question 10.<br>In the figure given below, ABCD is a eyclic quadrilateral in which \u2220 BAD = 75\u00b0; \u2220 ABD = 58\u00b0 and \u2220ADC = 77\u00b0. Find:<\/strong><br>(i) \u2220 BDC,<br>(ii) \u2220 BCD,<br>(iii) \u2220 BCA.<br><img loading=\"lazy\" decoding=\"async\" width=\"235\" height=\"237\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-20.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 20\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"570\" height=\"463\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-21.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 21\"><\/p>\n\n\n\n<p><strong>Question 11.<br>In the following figure, O is centre of the circle and \u2206 ABC is equilateral. Find :<\/strong><br>(i) \u2220 ADB<br>(ii) \u2220 AEB<br><img loading=\"lazy\" decoding=\"async\" width=\"222\" height=\"265\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-22.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 22\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"559\" height=\"433\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-23.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 23\"><\/p>\n\n\n\n<p><strong>Question 12.<br>Given\u2014\u2220 CAB = 75\u00b0 and \u2220 CBA = 50\u00b0. Find the value of \u2220 DAB + \u2220 ABD<br><img loading=\"lazy\" decoding=\"async\" width=\"214\" height=\"209\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-24.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 24\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"558\" height=\"535\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-25.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 25\"><\/p>\n\n\n\n<p><strong>Question 13.<br>ABCD is a cyclic quadrilateral in a circle with centre O.<br>If \u2220 ADC = 130\u00b0; find \u2220 BAC.<br><img loading=\"lazy\" decoding=\"async\" width=\"214\" height=\"187\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-26.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 26\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"547\" height=\"357\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-27.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 27\"><\/p>\n\n\n\n<p><strong>Question 14.<br>In the figure given below, AOB is a diameter of the circle and \u2220 AOC = 110\u00b0. Find \u2220 BDC.<br><img loading=\"lazy\" decoding=\"async\" width=\"182\" height=\"188\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-28.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 28\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"541\" height=\"367\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-29.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 29\"><\/p>\n\n\n\n<p><strong>Question 15.<br>In the following figure, O is centre of the circle,<br>\u2220 AOB = 60\u00b0 and \u2220 BDC = 100\u00b0.<br>Find \u2220 OBC.<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"175\" height=\"163\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-30.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 30\"><\/p>\n\n\n\n<p><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"542\" height=\"340\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-31.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 31\"><\/p>\n\n\n\n<p><strong>Question 16.<br>ABCD is a cyclic quadrilateral in which \u2220 DAC = 27\u00b0; \u2220 DBA = 50\u00b0 and \u2220 ADB = 33\u00b0.<br>Calculate :<\/strong><br>(i) \u2220 DBC,<br>(ii) \u2220 DCB,<br>(iii) \u2220 CAB.<br><img loading=\"lazy\" decoding=\"async\" width=\"168\" height=\"170\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-32.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 32\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"490\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-33.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 33\"><\/p>\n\n\n\n<p><strong>Question 17.<br>In the figure given alongside, AB and CD are straight lines through the centre O of a circle. If \u2220AOC = 80\u00b0 and \u2220CDE = 40\u00b0. Find the number of degrees in:<\/strong><br>(i) \u2220DCE;<br>(ii) \u2220ABC.<br><img loading=\"lazy\" decoding=\"async\" width=\"234\" height=\"192\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-34.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 34\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"574\" height=\"439\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-35.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 35\"><\/p>\n\n\n\n<p><strong>Question 17 (old).<br>In the figure given below, AB is diameter of the circle whose centre is O. Given that:<br>\u2220 ECD = \u2220 EDC = 32\u00b0.<br><img loading=\"lazy\" decoding=\"async\" width=\"183\" height=\"156\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-36.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 36\"><br>Show that \u2220 COF = \u2220 CEF.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"541\" height=\"362\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-37.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 37\"><\/p>\n\n\n\n<p><strong>Question 18.<br>In the figure given below, AC is a diameter of a circle, whose centre is O. A circle is described on AO as diameter. AE, a chord of the larger circle, intersects the smaller circle at B. Prove that AB = BE.<br><img loading=\"lazy\" decoding=\"async\" width=\"192\" height=\"154\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-38.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 38\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"564\" height=\"305\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-39.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 39\"><\/p>\n\n\n\n<p><strong>Question 19.<br>In the following figure,<\/strong><br>(i) if \u2220BAD = 96\u00b0, find BCD and<br>(ii) Prove that AD is parallel to FE.<br><img loading=\"lazy\" decoding=\"async\" width=\"299\" height=\"166\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-40.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 40\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"602\" height=\"510\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-41.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 41\"><\/p>\n\n\n\n<p><strong>Question 20.<br>Prove that:<\/strong><br>(i) the parallelogram, inscribed in a circle, is a rectangle.<br>(ii) the rhombus, inscribed in a circle, is a square.<br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"536\" height=\"408\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-42.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 42\"><br><img loading=\"lazy\" decoding=\"async\" width=\"539\" height=\"392\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-43.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 43\"><\/p>\n\n\n\n<p><strong>Question 21.<br>In the following figure, AB = AC. Prove that DECB is an isosceles trapezium.<br><img loading=\"lazy\" decoding=\"async\" width=\"163\" height=\"198\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-44.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 44\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"530\" height=\"591\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-45.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 45\"><\/p>\n\n\n\n<p><strong>Question 22.<br>Two circles intersect at P and Q. Through P diameters PA and PB of the two circles are drawn. Show that the points A, Q and B are collinear.<br>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"570\" height=\"345\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-46.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 46\"><\/p>\n\n\n\n<p><strong>Question 23.<br>The figure given below, shows a circle with centre O. Given: \u2220 AOC = a and \u2220 ABC = b.<\/strong><br>(i) Find the relationship between a and b<br>(ii) Find the measure of angle OAB, if OABC is a parallelogram.<br><img loading=\"lazy\" decoding=\"async\" width=\"186\" height=\"180\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-47.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 47\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"543\" height=\"531\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-48.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 48\"><\/p>\n\n\n\n<p><strong>Question 24.<br>Two chords AB and CD intersect at P inside the circle. Prove that the sum of the angles subtended by the arcs AC and BD as the centre O is equal to twice the angle APC.<br>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"606\" height=\"715\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-49.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 49\"><\/p>\n\n\n\n<p><strong>Question 24 (old).<br>ABCD is a quadrilateral inscribed in a circle having \u2220A = 60\u00b0; O is the centre of the circle. Show that: \u2220OBD + \u2220ODB = \u2220CBD + \u2220CDB<br>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"390\" height=\"511\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-50.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 50\"><\/p>\n\n\n\n<p><strong>Question 25.<br>In the figure given RS is a diameter of the circle. NM is parallel to RS and \u2220MRS = 29\u00b0<br>Calculate:<\/strong><br>(i) \u2220RNM;<br>(ii) \u2220NRM.<br><img loading=\"lazy\" decoding=\"async\" width=\"190\" height=\"166\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-51.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 51\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"543\" height=\"579\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-52.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 52\"><\/p>\n\n\n\n<p><strong>Question 26.<br>In the figure given alongside, AB || CD and O is the centre of the circle. If \u2220 ADC = 25\u00b0; find the angle AEB. Give reasons in support of your answer.<br><img loading=\"lazy\" decoding=\"async\" width=\"185\" height=\"166\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-53.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 53\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"540\" height=\"455\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-54.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 54\"><\/p>\n\n\n\n<p><strong>Question 27.<br>Two circles intersect at P and Q. Through P, a straight line APB is drawn to meet the circles in A and B. Through Q, a straight line is drawn to meet the circles at Cand D. Prove that AC is parallel to BD.<br><img loading=\"lazy\" decoding=\"async\" width=\"213\" height=\"128\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-55.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 55\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"555\" height=\"535\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-56.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 56\"><\/p>\n\n\n\n<p><strong>Question 28.<br>ABCD is a cyclic quadrilateral in which AB and DC on being produced, meet at P such that PA = PD. Prove that AD is parallel to BC.<br>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"539\" height=\"483\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-57.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 57\"><\/p>\n\n\n\n<p><strong>Question 29.<br>AB is a diameter of the circle APBR as shown in the figure. APQ and RBQ are straight lines. Find:<\/strong><br>(i) \u2220PRB<br>(ii) \u2220PBR<br>(iii) \u2220BPR.<br><img loading=\"lazy\" decoding=\"async\" width=\"297\" height=\"158\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-58.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 58\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"599\" height=\"523\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-59.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 59\"><\/p>\n\n\n\n<p><strong>Question 30.<br>In the given figure, SP is the bisector of angle RPT and PQRS is a cyclic quadrilateral. Prove that: SQ = SR.<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"238\" height=\"163\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-60.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 60\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"571\" height=\"514\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-61.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 61\"><\/p>\n\n\n\n<p><strong>Question 31.<br>In the figure, O is the centre of the circle, \u2220AOE = 150\u00b0, DAO = 51\u00b0. Calculate the sizes of the angles CEB and OCE.<br><img loading=\"lazy\" decoding=\"async\" width=\"299\" height=\"166\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-62.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 62\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"601\" height=\"445\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-63.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 63\"><\/p>\n\n\n\n<p><strong>Question 32.<br>In the figure, P and Q are the centres of two circles intersecting at B and C. ACD is a straight line. Calculate the numerical value of x.<br><img loading=\"lazy\" decoding=\"async\" width=\"287\" height=\"162\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-64.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 64\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"596\" height=\"462\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-65.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 65\"><\/p>\n\n\n\n<p><strong>Question 33.<br>The figure shows two circles which intersect at A and B. The centre of the smaller circle is O and lies on the circumference of the larger circle. Given that \u2220APB = a\u00b0. Calculate, in terms of a\u00b0, the value of:<\/strong><br>(i) obtuse \u2220AOB<br>(ii) \u2220ACB<br>(iii) \u2220ADB.<br>Give reasons for your answers clearly.<br><img loading=\"lazy\" decoding=\"async\" width=\"221\" height=\"186\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-66.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 66\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"562\" height=\"468\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-67.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 67\"><\/p>\n\n\n\n<p><strong>Question 34.<br>In the given figure, O is the centre of the circle and \u2220 ABC = 55\u00b0. Calculate the values of x and y.<br><img loading=\"lazy\" decoding=\"async\" width=\"173\" height=\"170\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-68.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 68\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"373\" height=\"386\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-69.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 69\"><\/p>\n\n\n\n<p><strong>Question 35.<br>In the given figure, A is the centre of the circle, ABCD is a parallelogram and CDE is a straight line. Prove that \u2220BCD = 2\u2220ABE<br><img loading=\"lazy\" decoding=\"async\" width=\"244\" height=\"164\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-70.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 70\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"570\" height=\"405\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-71.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 71\"><\/p>\n\n\n\n<p><strong>Question 36.<br>ABCD is a cyclic quadrilateral in which AB is parallel to DC and AB is a diameter of the circle. Given \u2220BED = 65\u00b0; calculate:<\/strong><br>(i) \u2220 DAB,<br>(ii) \u2220BDC.<br><img loading=\"lazy\" decoding=\"async\" width=\"181\" height=\"159\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-72.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 72\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"537\" height=\"363\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-73.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 73\"><\/p>\n\n\n\n<p><strong>Question 37.<br>\u2220 In the given figure, AB is a diameter of the circle. Chord ED is parallel to AB and \u2220 EAB = 63\u00b0; calculate:<\/strong><br>(i) \u2220EBA,<br>(ii) BCD.<br><img loading=\"lazy\" decoding=\"async\" width=\"166\" height=\"163\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-74.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 74\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"534\" height=\"591\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-75.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 75\"><\/p>\n\n\n\n<p><strong>Question 38.<br>In the given figure, AB is a diameter of the circle with centre O. DO is parallel to CB and \u2220DCB = 120\u00b0; calculate:<\/strong><br>(i) \u2220 DAB,<br>(ii) \u2220 DBA,<br>(iii) \u2220 DBC,<br>(iv) \u2220 ADC.<br>Also, show that the \u2206AOD is an equilateral triangle.<br><img loading=\"lazy\" decoding=\"async\" width=\"168\" height=\"159\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-76.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 76\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"532\" height=\"765\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-77.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 77\"><\/p>\n\n\n\n<p><strong>Question 39.<br>In the given figure, I is the incentre of the \u2206 ABC. Bl when produced meets the circumcirle of \u2206 ABC at D. Given \u2220BAC = 55\u00b0 and \u2220 ACB = 65\u00b0, calculate:<\/strong><br>(i) \u2220DCA,<br>(ii) \u2220 DAC,<br>(iii) \u2220DCI,<br>(iv) \u2220AIC.<br><img loading=\"lazy\" decoding=\"async\" width=\"144\" height=\"138\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-78.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 78\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"514\" height=\"501\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-79.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 79\"><\/p>\n\n\n\n<p><strong>Question 40.<br>A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that:<\/strong><br>(i) \u2220ABC = 2 \u2220APQ<br>(ii) \u2220ACB = 2 \u2220APR<br>(iii) \u2220QPR = 90\u00b0 \u2013 12BAC<br><img loading=\"lazy\" decoding=\"async\" width=\"163\" height=\"171\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-80.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 80\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"524\" height=\"576\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-81.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 81\"><\/p>\n\n\n\n<p><strong>Question 40 (old).<br>The sides AB and DC of a cyclic quadrilateral ABCD are produced to meet at E; the sides DA and CB are produced to meet at F. If \u2220BEC = 42\u00b0 and \u2220BAD = 98\u00b0; calculate:<\/strong><br>(i) \u2220AFB,<br>(ii) \u2220ADC.<br><img loading=\"lazy\" decoding=\"async\" width=\"261\" height=\"204\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-82.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 82\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"573\" height=\"486\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-83.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 83\"><\/p>\n\n\n\n<p><strong>Question 41.<br>Calculate the angles x, y and z if: x3=y4=z5<br><img loading=\"lazy\" decoding=\"async\" width=\"303\" height=\"244\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-84.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 84\"><\/strong><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"603\" height=\"559\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-85.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 85\"><\/p>\n\n\n\n<p><strong>Question 42.<br>In the given figure, AB = AC = CD and \u2220ADC = 38\u00b0. Calculate:<\/strong><br>(i) Angle ABC<br>(ii) Angle BEC.<br><img loading=\"lazy\" decoding=\"async\" width=\"265\" height=\"158\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-86.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 86\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"581\" height=\"406\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-87.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 87\"><\/p>\n\n\n\n<p><strong>Question 43.<br>In the given figure, AC is the diameter of circle, centre O. Chord BD is perpendicular to AC. Write down the angles p, and r in terms of x.<br><img loading=\"lazy\" decoding=\"async\" width=\"174\" height=\"179\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-88.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 88\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"534\" height=\"540\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-89.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 89\"><\/p>\n\n\n\n<p><strong>Question 44.<br>In the given figure, AC is the diameter of circle, centre O. CD and BE are parallel. Angle AOB = 80\u00b0 and angle ACE = 10\u00b0. Calculate:<\/strong><br>(i) Angle BEC;<br>(ii) Angle BCD;<br>(iii) Angle CED.<br><img loading=\"lazy\" decoding=\"async\" width=\"160\" height=\"158\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-90.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 90\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"535\" height=\"613\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-91.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 91\"><\/p>\n\n\n\n<p><strong>Question 45.<br>In the given figure, AE is the diameter of circle. Write down the numerical value of \u2220ABC + \u2220CDE. Give reasons for your answer.<br><img loading=\"lazy\" decoding=\"async\" width=\"188\" height=\"174\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-92.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 92\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"545\" height=\"503\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-93.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 93\"><\/p>\n\n\n\n<p><strong>Question 46.<br>In the given figure, AOC is a diameter and AC is parallel to ED. If \u2220CBE = 64\u00b0, calculate \u2220DEC.<br><img loading=\"lazy\" decoding=\"async\" width=\"194\" height=\"178\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-94.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 94\"><br>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"544\" height=\"369\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-95.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 95\"><\/p>\n\n\n\n<p><strong>Question 47.<br>Use the given figure to find<\/strong><br>(i) \u2220BAD<br>(ii) \u2220DQB.<br><img loading=\"lazy\" decoding=\"async\" width=\"339\" height=\"188\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-96.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 96\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"628\" height=\"380\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-97.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 97\"><\/p>\n\n\n\n<p><strong>Question 48.<br>In the given figure, AOB is a diameter and DC is parallel to AB. If \u2220 CAB = x\u00b0; find (in terms of x) the values of:<\/strong><br>(i) \u2220COB<br>(ii) \u2220DOC<br>(iii) \u2220DAC<br>(iv) \u2220ADC.<br><img loading=\"lazy\" decoding=\"async\" width=\"215\" height=\"134\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-98.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 98\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"450\" height=\"498\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-99.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 99\"><\/p>\n\n\n\n<p><strong>Question 49.<br>In the given figure, AB is the diameter of a circle with centre O. \u2220BCD = 130\u00b0. Find:<\/strong><br>(i) \u2220DAB<br>(ii) \u2220DBA<br><img loading=\"lazy\" decoding=\"async\" width=\"189\" height=\"149\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-100.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 100\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"232\" height=\"249\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-101.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 101\"><\/p>\n\n\n\n<p><strong>Question 50.<br>In the given figure, PQ is the diameter of the circle whose centre is O. Given \u2220ROS = 42\u00b0; calculate \u2220RTS.<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"227\" height=\"175\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-102.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 102\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"567\" height=\"426\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-103.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 103\"><\/p>\n\n\n\n<p><strong>Question 51.<br>In the given figure, PQ is a diameter. Chord SR is parallel to PQ. Given that \u2220PQR = 58\u00b0; calcula<\/strong>te<br>(i) \u2220RPQ<br>(ii) \u2220STP.<br><img loading=\"lazy\" decoding=\"async\" width=\"196\" height=\"168\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-104.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 104\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"553\" height=\"428\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-105.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 105\"><\/p>\n\n\n\n<p><strong>Question 52.<br>AOD = 60\u00b0; calculate the numerical values of:<br>AB is the diameter of the circle with centre O. OD is parallel to BC and \u2220AOD = 60\u00b0; calculate the numerical values of:<\/strong><br>(i) \u2220ABD,<br>(ii) \u2220DBC,<br>(iii) \u2220ADC.<br><img loading=\"lazy\" decoding=\"async\" width=\"202\" height=\"207\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-106.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 106\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"579\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-107.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 107\"><\/p>\n\n\n\n<p><strong>Question 53.<br>In the given figure, the centre of the small circle lies on the circumference of the bigger circle. If \u2220APB = 75\u00b0 and \u2220BCD = 40\u2033; find:<\/strong><br>(i) \u2220AOB,<br>(ii) \u2220ACB,<br>(iii) \u2220ABD,<br>(iv) \u2220ADB.<br><img loading=\"lazy\" decoding=\"async\" width=\"241\" height=\"187\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-108.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 108\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"569\" height=\"562\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-109.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 109\"><\/p>\n\n\n\n<p><strong>Question 54.<br>In the given figure, \u2220BAD = 65\u00b0, \u2220ABD = 70\u00b0 and \u2220BDC = 45\u00b0; find:<\/strong><br>(i) \u2220BCD,<br>(ii) \u2220ACB.<br>Hence, show that AC is a diameter.<br><img loading=\"lazy\" decoding=\"async\" width=\"161\" height=\"181\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-110.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 110\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"525\" height=\"439\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-111.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 111\"><\/p>\n\n\n\n<p><strong>Question 55.<br>In a cyclic quadrilateral ABCD, \u2220A : \u2220C = 3 : 1 and \u2220B : \u2220D = 1 : 5; find each angle of the quadrilateral.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"408\" height=\"403\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-112.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 112\"><\/p>\n\n\n\n<p><strong>Question 56.<br>The given figure shows a circle with centre O and \u2220ABP = 42\u00b0. Calculate the measure of<\/strong><br>(i) \u2220PQB<br>(ii) \u2220QPB + \u2220PBQ<br><img loading=\"lazy\" decoding=\"async\" width=\"159\" height=\"143\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-195.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 195\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"522\" height=\"332\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-196.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 196\"><\/p>\n\n\n\n<p><strong>Question 57.<br>In the given figure, M is the centre of the circle. Chords AB and CD are perpendicular to each other. If \u2220 MAD =x and \u2220BAC = y.<\/strong><br>(i) express \u2220AMD in terms of x.<br>(ii) express \u2220ABD in terms of y.<br>(iii) prove that : x = y<br><img loading=\"lazy\" decoding=\"async\" width=\"175\" height=\"171\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-197.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 197\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"435\" height=\"741\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-198.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 198\"><\/p>\n\n\n\n<p><strong>Question 61 (old).<br>In a circle, with centre O, a cyclic quadrilateral ABCD is drawn with AB as a diameter of the circle and CD equal to radius of the circle. If AD and BC produced meet at point P; show that \u2220APB = 60\u00b0.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"537\" height=\"516\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-199.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 199\"><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Exercise 17B<\/h3>\n\n\n\n<p><strong>Question 1.<br>In a cyclic-trapezium, the non-parallel sides are equal and the diagonals are also equal.<br>Prove it.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"554\" height=\"601\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-200.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 200\"><\/p>\n\n\n\n<p><strong>Question 2.<br>In the following figure, AD is the diameter of the circle with centre 0. chords AB, BC and CD are equal. If \u2220DEF = 110\u00b0, calculate:<\/strong><br>(i) \u2220 AFE,<br>(ii) \u2220FAB.<br><img loading=\"lazy\" decoding=\"async\" width=\"182\" height=\"160\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-201.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 201\"><\/p>\n\n\n\n<p><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"558\" height=\"701\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-202.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 202\"><\/p>\n\n\n\n<p><strong>Question 3.<br>If two sides of a cycli-quadrilateral are parallel; prove thet:<\/strong><br>(i) its other two side are equal.<br>(ii) its diagonals are equal.<br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"566\" height=\"639\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-203.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 203\"><\/p>\n\n\n\n<p><strong>Question 4.<br>The given figure show a circle with centre O. also, PQ = QR = RS and \u2220PTS = 75\u00b0. Calculate:<\/strong><br>(i) \u2220POS,<br>(ii) \u2220 QOR,<br>(iii) \u2220PQR.<br><img loading=\"lazy\" decoding=\"async\" width=\"193\" height=\"195\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-204.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 204\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"590\" height=\"719\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-205.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 205\"><\/p>\n\n\n\n<p><strong>Question 5.<br>In the given figure, AB is a side of a regular six-sided polygon and AC is a side of a regular eight-sided polygon inscribed in the circle with centre O. calculate the sizes of:<\/strong><br>(i) \u2220 AOB,<br>(ii) \u2220 ACB,<br>(iii) \u2220ABC.<br><img loading=\"lazy\" decoding=\"async\" width=\"225\" height=\"226\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-206.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 206\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"350\" height=\"351\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-207.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 207\"><\/p>\n\n\n\n<p><strong>Question 6.<br>In a regular pentagon ABCDE, inscribed in a circle; find ratio between angle EDA and angel ADC.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"557\" height=\"422\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-208.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 208\"><\/p>\n\n\n\n<p><strong>Question 7.<br>In the given figure. AB = BC = CD and \u2220ABC = 132\u00b0, calculate:<\/strong><br>(i) \u2220AEB,<br>(ii) \u2220 AED,<br>(iii) \u2220COD.<br><img loading=\"lazy\" decoding=\"async\" width=\"211\" height=\"210\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-209.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 209\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"552\" height=\"671\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-210.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 210\"><\/p>\n\n\n\n<p><strong>Question 8.<br>In the figure, O is the centre of the circle and the length of arc AB is twice the length of arc BC. If angle AOB = 108\u00b0, find:<\/strong><br>(i) \u2220 CAB,<br>(ii) \u2220ADB.<br><img loading=\"lazy\" decoding=\"async\" width=\"203\" height=\"197\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-211.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 211\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"534\" height=\"704\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-212.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 212\"><\/p>\n\n\n\n<p><strong>Question 9.<br>The figure shows a circle with centre O. AB is the side of regular pentagon and AC is the side of regular hexagon. Find the angles of triangle ABC.<br><img loading=\"lazy\" decoding=\"async\" width=\"201\" height=\"201\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-213.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 213\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"777\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-214.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 214\"><\/p>\n\n\n\n<p><strong>Question 10.<br>In the given figire, BD is a side of a regularhexagon, DC is a side of a regular pentagon and AD is adiameter. Calculate:<\/strong><br>(i) \u2220 ADC<br>(ii) \u2220BAD,<br>(iii) \u2220ABC<br>(iv) \u2220 AEC.<br><img loading=\"lazy\" decoding=\"async\" width=\"218\" height=\"197\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-215.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 215\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"265\" height=\"212\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-216.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 216\"><br><img loading=\"lazy\" decoding=\"async\" width=\"446\" height=\"679\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-217.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 217\"><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Exercise 17C<\/h3>\n\n\n\n<p><strong>Question 1.<br>In the given circle with diametre AB, find the value of x.<\/strong><\/p>\n\n\n\n<p><img loading=\"lazy\" decoding=\"async\" width=\"206\" height=\"187\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-218.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 218\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"167\" height=\"165\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-219.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 219\"><br>\u2220ABD = \u2220ACD = 30\u00b0 (Angle in the same segment)<br>Now in \u2206 ADB,<br>\u2220BAD + \u2220ADB + \u2220DBA = 180\u00b0&nbsp;(Angles of a A)<br>But \u2220ADB = 90\u00b0 (Angle in a semi-circle)<br>\u2234 x + 90\u00b0 + 30\u00b0 = 180\u00b0 \u21d2 x + 120\u00b0 = 180\u00b0<br>\u2234 x= 180\u00b0 \u2013 120\u00b0 = 60\u00b0 Ans.<\/p>\n\n\n\n<p><strong>Question 1.<br>In the given figure, O is the centre of the circle with radius 5 cm, OP and OQ are perpendiculars to AB and CD respectively. AB = 8cm and CD = 6cm. Determine the length of PQ.<br><img loading=\"lazy\" decoding=\"async\" width=\"165\" height=\"148\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-220.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 220\"><br>Solution:<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-221.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 221\"\/><\/figure>\n\n\n\n<p><strong>Question 2.<br>In the given figure, ABC is a triangle in which \u2220 BAC = 30\u00b0 Show that BC is equal to the radius of the circum-circle of the triangle ABC, whose centre is O.<br><img loading=\"lazy\" decoding=\"async\" width=\"206\" height=\"191\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-222.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 222\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"544\" height=\"730\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-223.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 223\"><\/p>\n\n\n\n<p><strong>Question 3.<br>Prove that the circle drawn on any one a the equalside of an isoscele triangle as diameter bisects the base.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"597\" height=\"598\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-224.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 224\"><\/p>\n\n\n\n<p><strong>Question 3 (old).<br>The given figure show two circles with centres A and B; and radii 5 cm and 3cm respectively, touching each other internally. If the perpendicular bisector of AB meets the bigger circle in P and Q, find the length of PQ.<br><img loading=\"lazy\" decoding=\"async\" width=\"191\" height=\"201\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-225.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 225\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"551\" height=\"641\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-226.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 226\"><\/p>\n\n\n\n<p><strong>Question 4.<br>In the given figure, chord ED is parallel to diameter AC of the circle. Given \u2220 CBE = 65\u00b0, calculate \u2220DEC.<br><img loading=\"lazy\" decoding=\"async\" width=\"223\" height=\"200\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-227.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 227\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"548\" height=\"665\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-228.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 228\"><\/p>\n\n\n\n<p><strong>Question 5.<br>The quadrilateral formed by angle bisectors of a cyclic quadrilateral is also cyclic. Prove it.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"553\" height=\"676\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-229.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 229\"><\/p>\n\n\n\n<p><strong>Question 6.<br>In the figure, \u2220DBC = 58\u00b0. BD is a diameter of the circle. Calculate:<\/strong><br>(i) \u2220BDC<br>(ii) \u2220BEC<br>(iii) \u2220BAC<br><img loading=\"lazy\" decoding=\"async\" width=\"188\" height=\"203\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-230.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 230\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"499\" height=\"536\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-231.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 231\"><\/p>\n\n\n\n<p><strong>Question 7.<br>D and E are points on equal sides AB and AC of an isosceles triangle ABC such that AD = AE. Provet that the points B, C, E and D are concyclic.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"580\" height=\"598\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-232.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 232\"><\/p>\n\n\n\n<p><strong>Question 7 (old).<br>Chords AB and CD of a circle intersect each other at point P such that AP = CP.<br>Show that: AB = CD.<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"186\" height=\"198\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-233.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 233\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"546\" height=\"591\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-234.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 234\"><\/p>\n\n\n\n<p><strong>Question 8.<br>In the given rigure, ABCD is a cyclic eqadrilateral. AF is drawn parallel to CB and DA is produced to point E. If \u2220 ADC = 92\u00b0, \u2220 FAE = 20\u00b0; determine \u2220 BCD. Given reason in support of your answer.<br><img loading=\"lazy\" decoding=\"async\" width=\"210\" height=\"149\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-235.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 235\"><\/strong><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"566\" height=\"520\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-236.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 236\"><\/p>\n\n\n\n<p><strong>Question 9.<br>If I is the incentre of triangle ABC and Al when produced meets the cicrumcircle of triangle ABC in points D. if \u2220 BAC = 66\u00b0 and \u2220 = 80o.calculate:<\/strong><br>(i) \u2220 DBC<br>(ii) \u2220 IBC<br>(iii) \u2220 BIC.<br><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"192\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-237.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 237\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"217\" height=\"208\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-238.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 238\"><br><img loading=\"lazy\" decoding=\"async\" width=\"443\" height=\"585\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-239.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 239\"><\/p>\n\n\n\n<p><strong>Question 10.<br>In the given figure, AB = AD = DC = PB and \u2220 DBC = x\u00b0. Determine, in terms of x:<\/strong><br>(i) \u2220 ABD,<br>(ii) \u2220 APB.<br>Hence or otherwise, prove thet AP is parallel to DB.<br><img loading=\"lazy\" decoding=\"async\" width=\"155\" height=\"237\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-240.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 240\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"546\" height=\"598\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-241.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 241\"><\/p>\n\n\n\n<p><strong>Question 11.<br>In the given figure; ABC, AEQ and CEP are straight lines. Show that \u2220APE and \u2220 CQE are supplementary.<br><img loading=\"lazy\" decoding=\"async\" width=\"237\" height=\"148\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-242.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 242\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"571\" height=\"553\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-243.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 243\"><\/p>\n\n\n\n<p><strong>Question 12.<br>In the given, AB is the diameter of the circle with centre O.<br><img loading=\"lazy\" decoding=\"async\" width=\"179\" height=\"187\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-244.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 244\"><br>If \u2220 ADC = 32\u00b0, find angle BOC.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"574\" height=\"472\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-245.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 245\"><\/p>\n\n\n\n<p><strong>Question 13.<br>In a cyclic-quadrilateral PQRS, angle PQR = 135\u00b0. Sides SP and RQ prouduced meet at point A: whereas sides PQ and SR produced meet at point B.<br>If \u2220A: \u2220B = 2 : 1;find angles A and B.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"264\" height=\"232\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-246.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 246\"><br><img loading=\"lazy\" decoding=\"async\" width=\"590\" height=\"556\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-247.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 247\"><\/p>\n\n\n\n<p><strong>Question 17 (old).<br>If the following figure, AB is the diameter of a circle with centre O and CD is the chord with lengh equal radius OA.<br>If AC produced and BD produed meet at point p; show that \u2220APB = 60\u00b0<br><img loading=\"lazy\" decoding=\"async\" width=\"212\" height=\"179\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-248.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 248\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"253\" height=\"214\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-249.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 249\"><br><img loading=\"lazy\" decoding=\"async\" width=\"596\" height=\"604\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-250.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 250\"><\/p>\n\n\n\n<p><strong>Question 14.<br>In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC.<br><img loading=\"lazy\" decoding=\"async\" width=\"158\" height=\"153\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-251.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 251\"><br>If the bisector of angle A meet BC at point E and the given circle at point F, prove that:<\/strong><br>(i) EF = FC<br>(ii) BF =DF<br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"540\" height=\"718\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-252.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 252\"><\/p>\n\n\n\n<p><strong>Question 15.<br>ABCD is a cyclic quadrilateral. Sides AB and DC produced meet at point e; whereas sides BC and AD produced meet at point F. I f \u2220 DCF : \u2220F : \u2220E = 3 : 5 : 4, find the angles of the cyclic quadrilateral ABCD.<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"269\" height=\"266\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-253.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 253\"><br><img loading=\"lazy\" decoding=\"async\" width=\"622\" height=\"583\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-254.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 254\"><\/p>\n\n\n\n<p><strong>Question 16.<br>The following figure shows a cicrcle with PR as its diameter. If PQ = 7 cm and QR = 3RS = 6 cm, Find the perimetre of the cyclic quadrilateral PORS.<br><img loading=\"lazy\" decoding=\"async\" width=\"196\" height=\"182\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-255.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 255\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"467\" height=\"458\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-256.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 256\"><\/p>\n\n\n\n<p><strong>Question 17.<br>In the following figure, AB is the diameter of a circle with centre O. If chord AC = chord AD.prove that:<\/strong><br>(i) arc BC = arc DB<br>(ii) AB is bisector of \u2220 CAD.<br>Further if the lenghof arc AC is twice the lengthof arc BC find :<br>(a) \u2220 BAC<br>(b) \u2220 ABC<br><img loading=\"lazy\" decoding=\"async\" width=\"208\" height=\"188\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-257.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 257\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"260\" height=\"209\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-258.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 258\"><br><img loading=\"lazy\" decoding=\"async\" width=\"556\" height=\"602\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-259.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 259\"><\/p>\n\n\n\n<p><strong>Question 18.<br>In cyclic quadrilateral ABCD; AD = BC, \u2220 = 30\u00b0 and \u2220 = 70\u00b0; find;<\/strong><br>(i) \u2220 BCD<br>(ii) \u2220BCA<br>(iii) \u2220ABC<br>(iv) \u2220 ADC<br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"234\" height=\"201\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-260.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 260\"><br><img loading=\"lazy\" decoding=\"async\" width=\"617\" height=\"603\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-261.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 261\"><\/p>\n\n\n\n<p><strong>Question 19.<br>In the given figure, \u2220ACE = 43\u00b0 and \u2220 = 62\u00b0; find the values of a, b and c.<br><img loading=\"lazy\" decoding=\"async\" width=\"289\" height=\"190\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-262.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 262\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"604\" height=\"608\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-263.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 263\"><\/p>\n\n\n\n<p><strong>Question 20.<br>In the given figure, AB is parallel to DC, \u2220BCE = 80\u00b0 and \u2220 BAC = 25\u00b0<br>Find<\/strong><br>(i) \u2220 CAD<br>(ii) \u2220 CBD<br>(iii) \u2220 ADC<br><img loading=\"lazy\" decoding=\"async\" width=\"310\" height=\"163\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-264.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 264\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"597\" height=\"558\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-265.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 265\"><\/p>\n\n\n\n<p><strong>Question 21.<br>ABCD is a cyclic quadrilateral of a circle with centre o such that AB is a diameter of this circle and the length of the chord CD is equal to the radius of the circle..if AD and BC produced meet at P, show that APB =60\u00b0<br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"570\" height=\"767\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-266.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 266\"><\/p>\n\n\n\n<p><strong>Question 22.<br>In the figure, given alongside, CP bisects angle ACB. Show that DP bisects angle ADB.<br><img loading=\"lazy\" decoding=\"async\" width=\"186\" height=\"206\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-267.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 267\"><br>Solution:<\/strong><br><img loading=\"lazy\" decoding=\"async\" width=\"523\" height=\"196\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-268.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 268\"><\/p>\n\n\n\n<p><strong>Question 23.<br>In the figure, given below, AD = BC, \u2220 BAC = 30\u00b0 and \u2220 = 70\u00b0 find:<\/strong><br>(i) \u2220 BCD<br>(ii) \u2220 BCA<br>(iii) \u2220 ABC<br>(iv) \u2220ADC<br><img loading=\"lazy\" decoding=\"async\" width=\"195\" height=\"181\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-269.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 269\"><br><strong>Solution:<br><\/strong><img loading=\"lazy\" decoding=\"async\" width=\"574\" height=\"542\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-270.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 270\"><\/p>\n\n\n\n<p><strong>Question 24.<br>In the figure given below, AD is a diameter. O is the centre of the circle. AD is parallel to BC and \u2220CBD = 32\u00b0. Find :<\/strong><br>(i) \u2220OBD<br>(ii) \u2220AOB<br>(iii) \u2220BED (2016)<br><strong>Solution:<br><\/strong>i. AD is parallel to BC, i.e., OD is parallel to BC and BD is transversal.<br><img loading=\"lazy\" decoding=\"async\" width=\"340\" height=\"89\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-271.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 271\"><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-272.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 272\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-273.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 273\"\/><\/figure>\n\n\n\n<p><strong>Question 25.<br>In the figure given, O is the centre of the circle.&nbsp;\u2220DAE = 70\u00b0. Find giving suitable reasons, the measure of<\/strong><br>i. \u2220BCD<br>ii. \u2220BOD<br>iii.&nbsp;\u2220OBD<br><img loading=\"lazy\" decoding=\"async\" width=\"423\" height=\"264\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/Selina-Concise-Mathematics-Class-10-ICSE-Solutions-Circles-274.png\" alt=\"Selina Concise Mathematics Class 10 ICSE Solutions Circles - 274\"><br><strong>Solution:<br><\/strong>\u2220DAE and&nbsp;\u2220DAB are linear pair<br>So,<br>\u2220DAE +&nbsp;\u2220DAB = 180\u00b0<br>\u2234\u2220DAB = 110\u00b0<\/p>\n\n\n\n<p>Also,<br>\u2220BCD +&nbsp;\u2220DAB = 180\u00b0\u2026\u2026Opp. Angles of cyclic quadrilateral BADC<br>\u2234\u2220BCD = 70\u00b0<br>\u2220BCD = 12 \u2220BOD\u2026angles subtended by an arc on the centre and on the circle<br>\u2234\u2220BOD = 140\u00b0<\/p>\n\n\n\n<p>In&nbsp;\u0394BOD,<br>OB = OD\u2026\u2026radii of same circle<br>So,<br>\u2220OBD =\u2220ODB\u2026\u2026isosceles triangle theorem<br>\u2220OBD +&nbsp;\u2220ODB +&nbsp;\u2220BOD = 180\u00b0\u2026\u2026sum of angles of triangle<br>2\u2220OBD = 40\u00b0<br>\u2220OBD = 20\u00b0<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-download-pdf\"><strong>Download PDF<\/strong><\/h2>\n\n\n\n<p>Selina Class 10 ICSE Solutions Mathematics : Chapter 17-&nbsp;Circles<\/p>\n\n\n\n<p><a href=\"https:\/\/www.indcareer.com\/docs\/7e703a02-516a-4d07-911c-06f5c5a38e6b\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Download PDF<\/strong>: Selina Class 10 ICSE Solutions Mathematics : Chapter 17-\u00a0Circles PDF<\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"block-04f27dcc-02cb-4232-9335-36633ffeee10\"><strong>Chapterwise Selina Publishers&nbsp;ICSE Solutions for Class 10&nbsp;Maths :<\/strong><\/h2>\n\n\n\n<ul class=\"wp-block-list\" id=\"block-a1c25f8c-f868-4bf5-9eb7-11af143c4614\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-1-gst-goods-and-services-tax\/\">Chapter 1 &#8211; GST (Goods and Services Tax)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-2-banking-recurring-deposit-accounts\/\">Chapter 2 &#8211; Banking (Recurring Deposit Accounts)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-3-shares-and-dividends\/\">Chapter 3 -Shares and Dividends<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-4-linear-inequations-in-one-variable\/\">Chapter 4 &#8211; Linear Inequations (in one variable)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-5-quadratic-equations\/\">Chapter 5 &#8211; Quadratic Equations<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-6-solving-simple-problems-based-on-quadratic-equations\/\">Chapter 6 &#8211; Solving Simple Problems (Based on Quadratic Equations)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-7-ratio-and-proportion-including-properties-and-uses\/\">Chapter 7 &#8211; Ratio and Proportion (Including Properties and Uses)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-8-remainder-and-factor-theorems\/\">Chapter 8 &#8211; Remainder and Factor Theorems<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-9-matrices\/\">Chapter 9 &#8211; Matrices<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-10-arithmetic-progression\/\">Chapter 10- Arithmetic Progression<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-11-geometric-progression\/\">Chapter 11- Geometric Progression<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-12-reflection\/\">Chapter 12- Reflection<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-13-section-and-mid-point-formula\/\">Chapter 13 &#8211; Section and Mid-Point Formula<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-14-equation-of-a-line\/\">Chapter 14- Equation of a Line<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-15-similarity\/\">Chapter 15- Similarity<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-16-loci-locus-and-its-constructions\/\">Chapter 16- Loci (Locus and Its Constructions)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\">Chapter 17- Circles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-18-tangents-and-intersecting-chords\/\">Chapter 18- Tangents and Intersecting Chords<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-19-constructions-circles\/\">Chapter 19- Constructions (Circles)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-20-cylinder-cone-and-sphere\/\">Chapter 20- Cylinder, Cone and Sphere<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-21-trigonometrical-identities\/\">Chapter 21- Trigonometrical Identities<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-22-heights-and-distances\/\">Chapter 22- Heights and Distances<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-23-graphical-representation\/\">Chapter 23- Graphical Representation<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-24-measures-of-central-tendency\/\">Chapter 24- Measures of Central Tendency<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-25-probability\/\">Chapter 25- Probability<\/a><\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\">About Selina Publishers&nbsp;ICSE<\/h2>\n\n\n\n<p>Selina Publishers has been serving the students since 1976 and is one of the quality ICSE school textbooks publication houses. Mathematics and Science books for classes 6-10 form the core of our business, apart from certain English and Hindi literature as well as a few primary books. All these books are based upon the syllabus published by the Council for the I.C.S.E. Examinations, New Delhi. The textbooks are composed by a panel of subject experts and vetted by teachers practising in ICSE schools all over the country. Continuous efforts are made in complying with the standards and ensuring lucidity and clarity in content, which makes them stand tall in the industry.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Class 10: Maths Chapter 17 solutions. Complete Class 10 Maths Chapter 17 Notes. Selina Class 10 ICSE Solutions Mathematics : Chapter 17-&nbsp;Circles Selina 10th Maths Chapter 17, Class 10 Maths Chapter 17 solutions Exercise 17A Question 1.In the given figure, O is the centre of the circle. \u2220OAB and \u2220OCB are 30\u00b0 and 40\u00b0 respectively. [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":594029,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,24],"tags":[2261],"boards":[],"class_list":["post-592314","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-10","tag-icse-solutions","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Selina Solutions for Class 10, maths Ch 17 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"Selina Class 10 ICSE Solutions Mathematics : Chapter 17-\u00a0Circles | Browse all Class 10 Maths - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Selina Class 10 ICSE Solutions Mathematics : Chapter 17-\u00a0Circles\" \/>\n<meta property=\"og:description\" content=\"Class 10: Maths Chapter 17 solutions. 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Selina Class 10 ICSE Solutions Mathematics : Chapter 17-&nbsp;Circles\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2022-04-25T05:22:37+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2022-04-25T10:44:22+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/NCERT-Solutions-14-5.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1920\" \/>\n\t<meta property=\"og:image:height\" content=\"1080\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"55 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"Selina Class 10 ICSE Solutions Mathematics : Chapter 17-\u00a0Circles\",\"datePublished\":\"2022-04-25T05:22:37+00:00\",\"dateModified\":\"2022-04-25T10:44:22+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\"},\"wordCount\":3196,\"publisher\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#organization\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2022\/04\/NCERT-Solutions-14-5.jpg\",\"keywords\":[\"ICSE Solutions\"],\"articleSection\":[\"Book Solutions\",\"Class 10\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\",\"url\":\"https:\/\/www.indcareer.com\/schools\/selina-class-10-icse-solutions-mathematics-chapter-17-circles\/\",\"name\":\"Selina Solutions for Class 10, maths Ch 17 - 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