{"id":585686,"date":"2022-03-16T11:09:45","date_gmt":"2022-03-16T11:09:45","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=585686"},"modified":"2022-03-19T04:21:47","modified_gmt":"2022-03-19T04:21:47","slug":"maharashtra-board-solutions-class-8-maths-practice-set-16-1-chapter-16-surface-area-and-volume","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/maharashtra-board-solutions-class-8-maths-practice-set-16-1-chapter-16-surface-area-and-volume\/","title":{"rendered":"Maharashtra Board Solutions Class 8-Maths (Practice Set 16.1): Chapter 16- Surface Area and Volume"},"content":{"rendered":"\n

Class 8: Maths Chapter 16 solutions. Complete Class 8 Maths Chapter 16 Notes.<\/p>\n\n\n\n

Maharashtra Board Solutions Class 8-Maths (Practice Set 16.1): Chapter 16- Surface Area and Volume<\/h2>\n\n\n\n

Maharashtra Board 8th Maths Chapter 16, Class 8 Maths Chapter 16 solutions<\/p>\n\n\n\n

Question 1.
Find the volume of a box if its length, breadth and height are 20 cm, 10.5 cm and 8 cm respectively.
Given: For cuboid shaped box,
length (l) = 20 cm, breadth (b) = 10.5 cm and height (h) = 8cm
To find: Volume of a box
Solution:<\/strong>
Volume of a box = l x b x h
= 20 x 10.5 x 8
= 1680 cc
\u2234 The volume of the box is 1680 cc.<\/p>\n\n\n\n

Question 2.
A cuboid shaped soap bar has volume 150 cc. Find its thickness if its length is 10 cm and breadth is 5 cm.<\/strong>
Given: For cuboid shaped soap bar,
length (l) = 10 cm, breadth (b) = 5 cm and volume = 150 cc
To find: Thickness of the soap bar (h)
Solution:
Volume of soap bar = l x b x h
\u2234 150 = 10 x 5 x h
\u2234 150 = 50h
\u2234 15050=h
\u2234 3 = h
i.e., h = 3 cm
\u2234 The thickness of the soap bar is 3 cm.<\/p>\n\n\n\n

Question 3.
How many bricks of length 25 cm, breadth 15 cm and height 10 cm are required to build a wall of length 6 m, height 2.5 m and breadth 0.5 m?<\/strong>
Given: For the cuboidal shape brick:
length (l1<\/sub>) = 25 cm,
breadth (b1<\/sub>) = 15 cm,
height (h1<\/sub>) = 10 cm
For the cuboidal shape wall:
length (l2<\/sub>) = 6 m,
height (h2<\/sub>) = 2.5 m,
breadth (b2<\/sub>) = 0.5 m
To find: Number of bricks required
Solution:
<\/strong>When all the bricks are arranged to build a wall, the volume of all the bricks is equal to volume of wall.
\u2234  Number of bricks = volume of the wall  volume of a brick <\/p>\n\n\n\n

i. Volume of a brick = l1<\/sub> x b1<\/sub> x h1<\/sub>
= 25 x 15 x 10 cc<\/p>\n\n\n\n

ii. l2<\/sub> = 6m = 6 x 100 \u2026[\u2235 1m = 100cm]
= 600 cm
h2<\/sub> = 2.5 m = 2.5 x 100 = 250 cm
b2<\/sub> = 0.5 m = 0.5 x 100 = 50 cm
Volume of the wall = l2<\/sub> x b2<\/sub> x h2<\/sub>
= 600 x 50 x 250 cc<\/p>\n\n\n\n

iii.  Number of bricks = volume of the wall  volume of a brick 
= 600\u00d750\u00d725025\u00d715\u00d710
= 40 x 2 x 25
= 2000 bricks
\u2234 2000 bricks are required to build the wall.<\/p>\n\n\n\n

Question 4.
For rain water harvesting a tank of length 10 m, breadth 6 m and depth 3 m is built. What is the capacity of the tank? How many litre of water can it hold?
Given: For a cuboidal tank,
Length (l) = 10 m, breadth (b) = 6 m, depth (h) = 3 m
To find: Capacity of the tank and litre of water tank can hold.
Solution:<\/strong>
i. l = 10m = 10 x 100 \u2026[\u2235 1m = 100cm]
= 1000 cm,
b = 6 m = 6 x 100 = 600 cm,
h = 3 m = 3 x 100 = 300 cm
Volume of the tank = l x b x h
= 1000 x 600 x 300
= 18,00,00,000 cc<\/p>\n\n\n\n

ii. Capacity of the tank = Volume of the tank
= 18,00,00,000 cc
= 18,00,00,0001000
\u2026[\u2235 1 litre =1000 cc]
= 1,80,000 litre
\u2234 The capacity of the tank is 18,00,00,000 cc and it can hold 1,80,000 litre of water.<\/p>\n\n\n\n

Download PDF<\/strong><\/h2>\n\n\n\n

Maharashtra Board Solutions Class 8-Maths (Practice Set 16.1): Chapter 16- Surface Area and Volume<\/p>\n\n\n\n

Download PDF<\/strong>: Maharashtra Board Solutions Class 8-Maths (Practice Set 16.1): Chapter 16- Surface Area and Volume PDF<\/a><\/p>\n\n\n\n

Chapterwise Maharashtra Board Solutions Class 8 Maths :<\/strong><\/h2>\n\n\n\n