{"id":553636,"date":"2021-11-02T07:49:20","date_gmt":"2021-11-02T07:49:20","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=553636"},"modified":"2021-11-03T05:40:57","modified_gmt":"2021-11-03T05:40:57","slug":"rs-aggarwal-solutions-for-class-6-maths-chapter-10-ratio-proportion-and-unitary-method","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-6-maths-chapter-10-ratio-proportion-and-unitary-method\/","title":{"rendered":"RS Aggarwal Solutions for Class 6 Maths Chapter 10\u2013Ratio, Proportion and Unitary Method"},"content":{"rendered":"\n

Class 6: Maths Chapter 10 solutions. Complete Class 6 Maths Chapter 10 Notes.<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 10\u2013Ratio, Proportion and Unitary Method<\/h2>\n\n\n\n

RS Aggarwal 6th Maths Chapter 10, Class 6 Maths Chapter 10 solutions<\/p>\n\n\n\n

Ex 10A Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
(i) 24 to 56
= 2456
= 24\u00f7856\u00f78
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
(i) 36 : 90
= 3690
= 36\u00f71890\u00f718
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
(i) The given ratio = Rs. 6.30 : Rs. 16.80
= Rs.6.30Rs.16.80
= 6301680
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
Earning of Sahai = Rs. 16800
and of his wife = Rs. 10500
Then total income = Rs. 16800 + 10500
= Rs. 27300
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
Rohit monthly earnings = Rs. 15300
and his savings = Rs. 1224
So, his expenditure = Rs. 15300 \u2013 1224
= Rs. 14076
Now,
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
Let the number of male and female workers in the mill be 5x and 3x respectively. Then,
5x = 115
=> 5×5 = 1155
(Dividing both sides by 5)
=> x = 23
Number of female workers in the mill
= 3x
= 3 x 23 = 69.<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
Let the number of boys and girls in the school be 9x and 5x respectively.
According to the question,
9x + 5x = 44
=> 14x = 448
=> 14×14 = 44814
(Dividing both sides by 14)
=> x = 32.
Number of girls =5x
= 5 x 32
= 160<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
Total amount = Rs. 1575
Ratio in Kamal and Madhu\u2019s share = 7 : 2
Sum of ratios = 7 + 2 = 9
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
Total amount = Rs. 3450
Ratio in A, B and C shares = 3 : 5 : 7
Sum of share = 3 + 5 + 7 = 15
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
Let the numbers be 11x and 12x.
Then. 11x + 12x = 460
=> 23x = 460
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
Length of line segment = 35 cm
Ratio = 4 : 3
Sum of ratio = 4 + 3 = 7
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
Total bulbs produced per day = 630
Out of every 10 bulbs, defective bulb = 1
Out of every 10 bulbs, lighting bulbs = 10 \u2013 1 = 9
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
Price of 20 pencils = Rs. 96
(1 score = 20 pencils)
Price of 1 pencil = Rs. (96 \u00f7 20)
= Rs. 4.80
Price of 12 ball pens = Rs. 50.40
(1 dozen = 12)
Price of 1 ball pen = Rs. (50.40 \u00f7 12)
= Rs. 4.20.
Ratio of the price of a pencil to that of a ball pen = Rs. 4.80 : Rs. 4.20
= 480 paise : 420 paise
= 480 : 420
= 48 : 42
= 8 : 7.
Required ratio = 8 : 7.<\/p>\n\n\n\n

Question 14.<\/strong>
Solution:<\/strong>
It is given that the ratio of the length of a field to its width is 5 : 3.
If the width of the field is 3 metres then length = 5 metres.
If the width of the field is 1 metres than length = 53 metres.
If the width of the field is 42 metres then length
= 53 x 42 metres
= 5 x 14 metres
= 70 metres.<\/p>\n\n\n\n

Question 15.<\/strong>
Solution:<\/strong>
Ratio in income and savings of a family = 11 : 2
But Total savings = Rs. 1520
Let income = x
11 : 2 = x : 1520
=> x = 11\u00d715202 = 11 x 760
= Rs 8360
Expenditure = total income \u2013 savings
= Rs 8360 \u2013 1520
= Rs 6840<\/p>\n\n\n\n

Question 16.<\/strong>
Solution:<\/strong>
Ratio in income and expenditure = 7 : 6
Total income = Rs. 14000
Let expenditure = x, then
7 : 6 :: 14000 : x
=>x = 6\u00d7140007 = Rs. 12000
Savings = Total income \u2013 Expenditure
= Rs. 14000 \u2013 12000
= Rs. 2000<\/p>\n\n\n\n

Question 17.<\/strong>
Solution:<\/strong>
It is given that the ratio of zinc and copper in an alloy is 7 : 9.
If the weight of zinc in the alloy is 7 kg then the weight of copper in the alloy is 9 kg.
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 18.<\/strong>
Solution:<\/strong>
A bus covers in 2 hours = 128 km
128 It will cover in 1 hour = 1282 = 64 km
A train cover in 3 hours = 240 km
It will cover in 1 hour = 2403
= 80 km
Ratio in their speeds = 64: 80
= 4 : 5
{Dividing by 16, the LCM of 64, 80}<\/p>\n\n\n\n

Question 19.<\/strong>
Solution:<\/strong>
(i) (3 : 4) or (9 : 16)
LCM of 4, 16 = 16
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"\"<\/figure>\n\n\n\n

Question 20.<\/strong>
Solution:<\/strong>
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Ex 10B Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
(i) 4, 6, 8, 12
If it is in proportion, then
If ad = bc if 4 x 12 = 6 x 8
If 48 = 48
Which is true
\u2234 4, 6, 8, 12 are in proportion
(ii) 7, 42, 13, 78
7 : 42 :: 13 : 78
If ad = bc if 7 x 78 = 42 x 13
If 546 = 546
Which is true
\u2234 7, 42, 13, 78 are in proportion
(iii) 33, 121, 9, 96 or 33 : 121 :: 9 : 96
are in proportion
If ad = bc
If 33 x 96 = 121 x 9
If 3168 = 1089
Which is not true
\u2234 33, 121,9, 96 are not in proportion
(iv) 22, 33, 42, 63 or 22 : 33 :: 42 : 63
are in proportion
If ad = bc
If 22 x 63 = 33 x 42
If 1386 = 1386
Which is true
\u2234 22, 33, 42, 63 are in proportion
(v) 32, 48, 70, 210 or 32 : 48 :: 70 : 210
are in proportion
If ad = bc
If 32 x 210 = 48 x 70
If 6720 = 3360
Which is not true
\u2234 32, 48, 70, 210 are not in proportion
(vi) 150, 200, 250, 300 or
150 : 200 :: 250 : 300 are in proportion
If ad = bc if 150 x 300 = 200 x 250
If 45000 = 50000
Which is not true
\u2234 150, 200,250, 300 are not in proportion<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
(i) We have 60 : 105 :: 84 : 147
Product of means = 105 x 84 = 8820
Product of extremes = 60 x 147 = 8820
\u2234 Product of means = Product of extremes
Hence 60 : 105 :: 84 : 147 is verified.
(ii) We have 91 : 104 :: 119 : 136
Product of means = 104 x 119 = 12376
Product of extremes = 91 x 136 = 12376
Product of means = Product of extremes
Hence 91 : 104 :: 119 : 136 is verified.
(iii) We have 108 : 72 :: 129 : 86
Product of means = 72 x 129 = 9288
Product of extremes = 108 x 86 = 9288
Product of means = Product of extremes
Hence 108 : 72 :: 129 : 86 is verified.
(iv) We have 39 : 65 :: 141 : 235
Product of means = 65 x 141 = 9165
Product of extremes = 39 x 235 = 9165
\u2234 Product of means = Product of extremes
Hence 39 : 65 :: 141 : 235 is verified.<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
(i) We have 55 : 11 :: x : 6
Product of means = 11 \u00d7 x = 11x
Product of extremes = 55 x 6 = 330
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
(i) We have, 51 : 68 = 5168
= 34
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
(i) 25 cm : 1 m and Rs. 40 : Rs. 160
= 25cm1000cm = 14,
Rs.40Rs.160 = 14
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
Let the third term be x.
Then 51 : 68 :: x : 108
Now, product of means = x \u00d7 68
And, product of extremes = 51 \u00d7 108
x \u00d7 68 = 51 \u00d7 108
=> x = 51\u00d710868
= 3 \u00d7 27 = 81
x = 81
Hence the third term of the given proportion is 81<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
1st term =12, third term = 8 and fourth term = 14
Let 2nd term = x, then
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
(i) The given numbers 48, 60, 75 are in
continued proportion if 48 : 60 :: 60 : 75.
Now, product of means = 60 x 60 = 3600
And, product of extremes = 48 x 75 = 3600
\u2234 Product of means = Product of extremes
So, 48 : 60 :: 60 : 75
Hence, the numbers 48, 60, 75 are in continued proportion.
(ii) The given numbers 36, 90, 225 are in
continued proportion of 36 : 90 :: 90 : 225
Now, product of means = 90 x 90 = 8100
And, product of extremes = 36 x 225 = 8100
\u2234 Product of means = Product of extremes
So, 36 : 90 :: 90 : 225
Hence, the numbers 36, 90, 225 are in continued proportion.
(iii)The given numbers 16, 84, 441 are in
continued proportion if 16 : 84 :: 84 : 441.
Now, product of means = 84 x 84 = 7056
And, product of extremes = 16 x 441 = 7056
Product of means = Product of extremes.
So, 16 : 845 :: 84 : 441
Hence 16, 84, 441 are in continued proportion.
(iv) The given numbers 27, 36, 48 are
in continued proportion if 27 : 36 :: 36 : 48
Now, product of means = 36 x 36 = 1296
And, product of extremes = 27 x 48 = 1296
\u2234 Product of means = Product of extremes.
So, 27 : 36 :: 36 : 48
Hence, the numbers 27, 36, 48 are in continued proportional.<\/p>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
It is given that 9, x, x, 49 are in proportion, that is, 9 : x :: x : 49
\u2234 Product of means = Product of extremes
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
Let the height of the pole be x metres.
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
5 : 3 :: x : 6
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\n

Ex 10C Solutions<\/h4>\n<\/div><\/div>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
Cost of 14 m of cloth = Rs. 1890
Cost of 1 m = Rs. 189014
and cost of 6 m = Rs. 1890\u00d7614
= Rs. 135 x 6
= Rs. 810<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
Cost of 1 dozen or 12 soaps = Rs. 285.60
Cost of 1 soap = Rs. 285.6012
Cost of 15 soaps = Rs. 285.60\u00d71512
= Rs. 357.00<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
Cost of 9 kg of rice = Rs. 327.60
Cost of 1 kg = Rs. 327.609
and cost of 50 kg = Rs. 327.60\u00d7509
= Rs. 36.40 x 50
= Rs. 1820<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
Weight of 22.5 metres of the iron rod: = 85.5 kg
Weight of 1 metre of the iron rod
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
Quantity of oil in 15 tins = 234 kg
Quantity of oil in 1 tin = 23415 kg
Quantity of oil in 10 tins
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
Distance covered by the car in 12 litres of diesel = 222 kms
Distance covered by the car in 1 litre of diesel = 22212 km
<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
Charges of 25 tonnes of weight = Rs. 540
charges of 1 ton = Rs.54025
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
Weight of copper in 4.5 g of alloy = 3.5g
Weight of copper in 1 g of alloy
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
In Rs. 87.50, the inland letter are purchased = 35
In Re. 1, letters can be purchased
= 3587.50
and in Rs. 315, letters can be purchased
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
4 dozen = 4 x 12 = 48 bananas
In Rs. 104, banana are purchased = 48
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
In Rs. 22770, chairs are purchased =18
In Re. 1, chairs will be purchased
= 1822770
and in Rs. 10120, chairs will be
purchased = 18\u00d71012022770
= 8<\/p>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
(i) A car travels 195 km distance in = 3 hours
It will travel 1 km distance in = 3195 hr.
and it will travel 520 km distance in
= 3\u00d7520195
= 8 hr
(ii) A car travels in 3hr = 195 km
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
(i) A laborer earn in 12 days = Rs. 1980
He will earn in 1 day = Rs. 198012
and he will earn in 7 days
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 14.<\/strong>
Solution:<\/strong>
(i) Weight of 65 books = 13 kg
Then weight of 1 book = 1365 kg
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 15.<\/strong>
Solution:<\/strong>
Number of boxes needed for 6000 pens = 48
Number of boxes needed for 1 pen 48 = 486000
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 16.<\/strong>
Solution:<\/strong>
Clearly, less workers will build the wall in more days.
And, more workers will build the wall in less days.
24 workers can build the wall in 15 days
1 worker can build the wall in (15 x 24) days
(less worker, more days)
9 workers will build the wall in
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 17.<\/strong>
Solution:<\/strong>
Men needed to finish a piece of work in 26 days = 40
Men needed to finish a piece of work in 1 day = 40 x 26 (less days, more men)
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 18.<\/strong>
Solution:<\/strong>
Clearly, less men will take more days to consume the food.
And, more men will take less days to consume the food.
550 men have provisions for 28 days
1 men has provisions for (28 x 550) days [less men, more days]
700 men will have provisions for
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 19.<\/strong>
Solution:<\/strong>
Clearly, less persons will consume the rice in more days.
And more persons will consume the rice in less days.
60 persons consume the bag of rice in 3 days.
1 person will consume the bag of rice in
(3 x 60) days (less persons, more days)
18 persons will consume the bag of rice
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Ex 10D Solutions<\/h4>\n\n\n\n

OBJECTIVE QUESTIONS<\/strong>
Mark against the correct answer in each of the following :<\/strong><\/p>\n\n\n\n

Question 1<\/strong>
Solution:<\/strong>
(d) 92115
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
(a) 57x
= 5185
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
(a) 2535
= 45x
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
(c) 45
= x35
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
(b) ab
= cd
=>ad = bc<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
(b) a : b :: b : c
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
(b) 58 < 34 => 4 x 5 < 3 x 8 => 20 < 24<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
Total amount = Rs 760
Ratio A : B = 8 : 11
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
(d) largest = 252\u00d775+7
= 252\u00d7712
= 21 x 7
= 147<\/p>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
(b) largest = 90\u00d751+3+5
= 90\u00d759
= 50 cm<\/p>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
(c) total strength of school
largest = 8405 x (12 + 5)
= 840\u00d7175
= 168 x 17
= 2856<\/p>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
(b) Cost of 12 pens = Rs 138
Cost of 1 pen = Rs 138\u00d71412
and cost of 14 pens = Rs 161<\/p>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
(b) 24\u00d7158
= 45 days<\/p>\n\n\n\n

Question 14.<\/strong>
Solution:<\/strong>
(a) 26\u00d74020
= 52 men<\/p>\n\n\n\n

Question 15.<\/strong>
Solution:<\/strong>
(b) In 6 L of petrol, a car covers = 111 km
In 1 L, it will cover = 1116 km
and in 10 L it will cover = 111\u00d7106 km
= 185 km<\/p>\n\n\n\n

Question 16.<\/strong>
Solution:<\/strong>
(a) 28\u00d7550700
= 22 days<\/p>\n\n\n\n

Question 17.<\/strong>
Solution:<\/strong>
Ratio in the angles of triangle
= 3 : 1 : 2
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 18.<\/strong>
Solution:<\/strong>
(b) Ratio in length and breadth of a rectangle = 5 : 4
Width = 36 m
Length = 54 x 36 m
= 45m<\/p>\n\n\n\n

Question 19.<\/strong>
Solution:<\/strong>
Bus covers in 3 hrs = 195 km
It will cover in 1 hr = 1953 = 65 km
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 20.<\/strong>
Solution:<\/strong>
1 dozen = 12 bars
Cost of 5 bars of soap = Rs.82.50
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 21.<\/strong>
Solution:<\/strong>
Total pencils in 30 packets of 8 pencils
= 30 x 8= 240
and total pencils of 25 packets of 12
pencils = 25 x 12 = 300
Now cost of 240 pencils = Rs. 600
Then cost of 1 percent = Rs. 60024
and cost of 300 pencils = Rs. 600\u00d7300240
= Rs 750 (b)<\/p>\n\n\n\n

Question 22.<\/strong>
Solution:<\/strong>
Journey of 75 km costs = Rs 215
Cost of 1 km = Rs 21575
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 23.<\/strong>
Solution:<\/strong>
1st term = 12
2nd term = 21
fourth term = 14
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 24.<\/strong>
Solution:<\/strong>
10 boys dig a patch in = 12 hrs
1 boy will dig it in = 12 x 10 hours
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 10: Download PDF<\/strong><\/h2>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 10\u2013Ratio, Proportion and Unitary Method<\/p>\n\n\n\n

Download PDF<\/strong>: RS Aggarwal Solutions for Class 6 Maths Chapter 10\u2013Ratio, Proportion and Unitary Method PDF<\/a><\/p>\n\n\n\n

Chapterwise RS Aggarwal Solutions for Class 6 Maths :<\/strong><\/h2>\n\n\n\n