{"id":553461,"date":"2021-11-01T10:49:30","date_gmt":"2021-11-01T10:49:30","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=553461"},"modified":"2021-11-03T05:15:22","modified_gmt":"2021-11-03T05:15:22","slug":"rs-aggarwal-solutions-for-class-6-maths-chapter-6-simplification","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-6-maths-chapter-6-simplification\/","title":{"rendered":"RS Aggarwal Solutions for Class 6 Maths Chapter 6\u2013Simplification"},"content":{"rendered":"\n

Class 6: Maths Chapter 6 solutions. Complete Class 6 Maths Chapter 6 Notes.<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 6\u2013Simplification<\/h2>\n\n\n\n

RS Aggarwal 6th Maths Chapter 6, Class 6 Maths Chapter 6 solutions<\/p>\n\n\n\n

Ex 6A Solutions<\/h4>\n\n\n\n

Simplify<\/strong><\/p>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
21 \u2013 12 \u00f7 3 x 2
= 21 \u2013 4 x 2
= 21 \u2013 8
= 13. Ans<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
16 + 8 \u00f7 4 \u2013 2 x 3
= 16 + 2 \u2013 2 x 3
= 16 + 2 \u2013 6
= 18 \u2013 6
= 12. Ans.<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
13 \u2013 (12 \u2013 6 \u00f7 3)
= 13 \u2013 (12 \u2013 2)
= 13 \u2013 (10)
= 13 \u2013 10
= 3 Ans.<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
19 \u2013 [4 + {16 \u2013 (12 \u2013 2)}]
= 19 \u2013 [4 + {16 \u2013 10}]
= 19 \u2013 [4 + 6]
= 19 \u2013 10
= 9. Ans<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
36 \u2013 [18 \u2013 {14 \u2013 (15 \u2013 4 \u00f7 2 x 2)}]
= 36 \u2013 [18 \u2013 {14 \u2013 (15 \u2013 2 x 2)}]
= 36 \u2013 [18 \u2013 {14 \u2013 (15 \u2013 4)}]
= 36 \u2013 [18 \u2013 {14 \u2013 11}]
= 36 \u2013 [18 \u2013 3]
= 36 \u2013 15
= 21. Ans.<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
27\u2212[18\u2212{16\u2212(5\u22124\u22121\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af)}]
= 27 \u2013 [18 \u2013 {16 \u2013 (5 \u2013 3)}]
= 27 \u2013 [18 \u2013 {16 \u2013 2}]
= 27 \u2013 [18 \u2013 14]
= 27 \u2013 4
= 23. Ans.<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
443\u00f735of5+45\u00d7310\u221215
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
(23+49)of35\u00f7123\u00d7114\u221213
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
713\u00f723of215+138\u00f7234\u2212112
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
517\u2212{3310\u00f7(245\u2212710)}
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
934\u00f7[216+{413\u2212(112+134)}]
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n
\"RS<\/figure>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
4110\u2212[212\u2212{56\u2212(25+310\u2212415)}]
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
156+[223\u2212{334(345\u00f7912)}]
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 14.<\/strong>
Solution:<\/strong>
445\u00f7{215\u221212(114\u221214\u221215\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af)}
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 15.<\/strong>
Solution:<\/strong>
712\u2212[214\u00f7{114\u221212(32\u221213\u221216\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af)}]
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Ex 6B Solutions<\/h4>\n\n\n\n

OBJECTIVE QUESTIONS<\/strong>
Mark against the correct answer in each of the following :<\/strong><\/p>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
(c) 8 + 4 \u00f7 2 x 5
= 8 + 4 x 12 x 5
= 8 + 10
= 18.<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
(b) 54 \u00f7 3 of 6 + 9 = 54 \u00f7 18 + 9
= 54 x 118 + 9
= 3 + 9
= 12.<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
(b) 13 \u2013 (12 \u2013 6 \u00f7 3)
= 13 \u2013 (12 \u2013 2)
= 13 \u2013 10
= 3<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
(a) 1001 \u00f7 11 of 13
= 1001 \u00f7 143
= 1001 x 1143
= 7.<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
(b) 133 + 28 \u00f7 7 \u2013 8 x 2
= 133 + 4 \u2013 16
= 137 \u2013 16
= 121.<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
(a) 3640 \u2013 14 \u00f7 7 x 2
= 3640 \u2013 2 x 2
= 3640 \u2013 4
= 3636.<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
(b) 100 x 10 \u2013 100 + 2000 \u00f7 100
= 1000 \u2013 100 + 20
= 920.<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
(b) 27\u2212[18\u2212{16\u2212(5\u22124\u22121\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af)}]
= 27 \u2013 [18 \u2013 {16 \u2013 (5 \u2013 4 + 1)}]
= 27 \u2013 [18 \u2013 {16 \u2013 5 + 4 \u2013 1}]
= 27 \u2013 [18 \u2013 16 + 5 \u2013 4 + 1]
= 27 \u2013 18 + 16 \u2013 5 + 4 \u2013 1
= 23<\/p>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
32\u2212[48\u00f7{36\u2212(27\u221216\u22129\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af\u00af)}]
= 32 \u2013 [48 \u00f7 {36 \u2013 (27 \u2013 16 + 9)}]
= 32 \u2013 [48 \u00f7 {36 \u2013 27 + 16 \u2013 9}]
= 32 \u2013 [48 \u00f7 16]
= 32 \u2013 3
= 29<\/p>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
(a) 8 \u2013 [28 \u00f7 {34 \u2013 (36 \u2013 18 \u00f7 9 x 8)}]
8\u2212[28\u00f7{34\u2212(36\u221218\u00d719\u00d78)}]
= 8 \u2013 [28 \u00f7 {34 \u2013 (36 \u2013 16)}]
= 8 \u2013 [28 \u00f7 {34 \u2013 20}]
= 8 \u2013 {28 \u00f7 14}
= 8 \u2013 2
= 6.<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 6: Download PDF<\/strong><\/h2>\n\n\n\n

RS Aggarwal Solutions for Class 6 Maths Chapter 6\u2013Simplification<\/p>\n\n\n\n

Download PDF<\/strong>: RS Aggarwal Solutions for Class 6 Maths Chapter 6\u2013Simplification PDF<\/a><\/p>\n\n\n\n

Chapterwise RS Aggarwal Solutions for Class 6 Maths :<\/strong><\/h2>\n\n\n\n