{"id":552087,"date":"2021-10-26T05:40:16","date_gmt":"2021-10-26T05:40:16","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=552087"},"modified":"2021-10-30T08:57:07","modified_gmt":"2021-10-30T08:57:07","slug":"rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/","title":{"rendered":"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles"},"content":{"rendered":"\n<p>Class 7: Maths Chapter 13 solutions. Complete Class 7 Maths Chapter 13 Notes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\">RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles<\/h2>\n\n\n\n<p>RS Aggarwal 7th Maths Chapter 13, Class 7 Maths Chapter 13 solutions<\/p>\n\n\n\n<p><strong>Question 1.<\/strong><br><strong>Solution:<\/strong><br>(i) The given angle = 35\u00b0<br>Let x be its complementary, then<br>x + 35\u00b0 = 90\u00b0<br>\u21d2 x = 90\u00b0 \u2013 35\u00b0 = 55\u00b0<br>Complement angle = 55\u00b0<br>(ii) The given angle = 47\u00b0<br>Let x be its complement, then<br>x + 47\u00b0 = 90 \u21d2 x = 90\u00b0 \u2013 47\u00b0 = 43\u00b0<br>Complement angle = 43\u00b0<br>(iii) The given angles = 60\u00b0<br>Let x be its complement angle<br>x + 60\u00b0 = 90\u00b0 \u21d2 x = 90\u00b0 \u2013 60\u00b0 = 30\u00b0<br>Complement angle = 30\u00b0<br>(iv) The given angle = 73\u00b0<br>Let x be its complement angle<br>x + 73\u00b0 = 90\u00b0<br>\u21d2 x = 90\u00b0 \u2013 73\u00b0 = 17\u00b0<br>Complement angle = 17\u00b0<\/p>\n\n\n\n<p><strong>Question 2.<\/strong><br><strong>Solution:<\/strong><br>(i) Given angle = 80\u00b0<br>Let x be its supplement angle, then<br>x + 80\u00b0 = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 80\u00b0 = 100\u00b0<br>Supplement angle = 100\u00b0<br>(ii) Given angle = 54\u00b0<br>Let x be its supplement angle, then<br>x + 54\u00b0 = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 54\u00b0 = 126\u00b0<br>Supplement angle = 126\u00b0<br>(iii) Given angle = 105\u00b0<br>let x be its supplement angle, then<br>x + 105\u00b0 = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 105\u00b0 = 75\u00b0<br>Supplement angle = 75\u00b0<br>(iv) Given angle = 123\u00b0<br>Let x be its supplement angle, then<br>x + 123\u00b0 = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 123\u00b0 = 57\u00b0<br>\u21d2 Supplement angle = 57\u00b0<\/p>\n\n\n\n<p><strong>Question 3.<\/strong><br><strong>Solution:<\/strong><br>Let smaller angle =x<br>Then larger angle = x + 36\u00b0<br>But x + x + 36\u00b0 = 180\u00b0 (Angles are supplementary)<br>2x = 180\u00b0 \u2013 36\u00b0= 144\u00b0<br>x = 72\u00b0<br>Smaller angle = 72\u00b0<br>and larger angle = 72\u00b0 + 36\u00b0 = 108\u00b0<\/p>\n\n\n\n<p><strong>Question 4.<\/strong><br><strong>Solution:<\/strong><br>Let angle be = x<br>Then other supplement angle = 180\u00b0- x<br>x = 180\u00b0 \u2013 x<br>\u21d2 x + x = 180\u00b0<br>\u21d2 2x = 180\u00b0<br>\u21d2 x = 90\u00b0<br>Hence angles are 90\u00b0, and 90\u00b0<\/p>\n\n\n\n<p><strong>Question 5.<\/strong><br><strong>Solution:<\/strong><br>Sum of two supplementary angles is 180\u00b0<br>If one is acute, then second will be obtuse or both angles will be equal<br>Hence both angles can not be acute or obtuse<br>Both can be right angles only<\/p>\n\n\n\n<p><strong>Question 6.<\/strong><br><strong>Solution:<\/strong><br>In the given figure,<br>AOB is a straight line and the ray OC stands on it.<br>\u2220AOC = 64\u00b0 and \u2220BOC = x\u00b0<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"236\" height=\"150\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-1.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 6\" class=\"wp-image-552091\"\/><\/figure>\n\n\n\n<p><br>\u2220AOC + \u2220BOC = 180\u00b0 (Linear pair)<br>\u21d2 64\u00b0 + x = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 64\u00b0 = 116\u00b0<br>Hence x = 116\u00b0<\/p>\n\n\n\n<p><strong>Question 7.<\/strong><br><strong>Solution:<\/strong><br>AOB is a straight line and ray OC stands on it \u2220AOC = (2x \u2013 10)\u00b0, \u2220BOC = (3x + 20)\u00b0<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"243\" height=\"153\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-2.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question7\" class=\"wp-image-552092\"\/><\/figure>\n\n\n\n<p><br>\u2220AOC + \u2220BOC = 180\u00b0 (Linear pair)<br>\u21d2 2x \u2013 10\u00b0 + 3x + 20\u00b0 = 180\u00b0<br>\u21d2 5x + 10\u00b0 = 180\u00b0<br>\u21d2 5x = 170\u00b0<br>\u21d2 x = 34\u00b0<br>\u2220AOC = (2x \u2013 10)\u00b0 = 2 x 34\u00b0 \u2013 10 = 68\u00b0 \u2013 10\u00b0 = 58\u00b0<br>\u2220BOC = (3x + 20)\u00b0 = 3 x 34\u00b0 + 20\u00b0 \u2013 102\u00b0 + 20\u00b0 = 122\u00b0<\/p>\n\n\n\n<p><strong>Question 8.<\/strong><br><strong>Solution:<\/strong><br>AOB is a straight line and rays OC and OD stands on it \u2220AOC = 65\u00b0, \u2220BOD = 70\u00b0 and \u2220COD = x<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"245\" height=\"141\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-3.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 8\" class=\"wp-image-552093\"\/><\/figure>\n\n\n\n<p>But \u2220AOC + \u2220COD + \u2220BOD = 180\u00b0 (Angles on one side of the straight line)<br>\u21d2 65\u00b0 + x + 70\u00b0 = 180\u00b0<br>\u21d2 135\u00b0 + x = 180\u00b0<br>\u21d2 x = 180\u00b0 \u2013 135\u00b0<br>\u21d2 x = 45\u00b0<br>Hence x = 45\u00b0<\/p>\n\n\n\n<p><strong>Question 9.<\/strong><br><strong>Solution:<\/strong><br>Two straight lines AB and CD intersect each other at O.<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"243\" height=\"121\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-4.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 9\" class=\"wp-image-552094\"\/><\/figure>\n\n\n\n<p><br>\u2220AOC = 42\u00b0<br>AB and CD intersect each other at O.<br>\u2220AOC = \u2220BOD (Vertically opposite angles)<br>and \u2220AOD = \u2220BOC<br>But \u2220AOC = 42\u00b0<br>\u2220BOD = 42\u00b0<br>AOB is a straight line and OC stands on it<br>\u2220AOC + \u2220BOC = 180\u00b0<br>\u21d2 42\u00b0 = \u2220BOC = 180\u00b0<br>\u21d2 \u2220BOC = 180\u00b0 \u2013 42\u00b0 = 138\u00b0<br>But \u2220AOD = \u2220BOC (vertically opposite angles)<br>\u2220AOD = 138\u00b0<br>Hence \u2220AOD = 138\u00b0, \u2220BOD = 42\u00b0 and \u2220COB =138\u00b0<\/p>\n\n\n\n<p><strong>Question 10.<\/strong><br><strong>Solution:<\/strong><br>Two straight lines PQ and RS intersect at O.<br>\u2220POS = 114\u00b0<br>Straight lines,<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"246\" height=\"192\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-5.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 10\" class=\"wp-image-552095\"\/><\/figure>\n\n\n\n<p>PQ and RS intersect each other at O<br>\u2220POS = \u2220QOR (Vertically opposite angles)<br>But \u2220POS = 114\u00b0<br>\u2220QOR = 114\u00b0 or \u2220ROQ = 114\u00b0<br>But \u2220POS + \u2220POR = 180\u00b0 (Linear pair)<br>\u21d2 114\u00b0 + \u2220POR = 180\u00b0<br>\u21d2 \u2220POR = 180\u00b0 \u2013 114\u00b0 = 66\u00b0<br>But \u2220QOS = \u2220POR (vertically opposite angles)<br>\u2220QOS = 66\u00b0<br>Hence \u2220POR = 66\u00b0, \u2220ROQ =114\u00b0 and \u2220QOS = 66\u00b0<\/p>\n\n\n\n<p><strong>Question 11.<\/strong><br><strong>Solution:<\/strong><br>In the given figure, rays OA, OB, OC and OD meet at O and ZAOB \u2013 56\u00b0,<br>\u2220BOC = 100\u00b0, \u2220COD = x and \u2220DOA = 74\u00b0<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"231\" height=\"231\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png\" alt=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles Question 11\" class=\"wp-image-552096\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6.png 231w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6-150x150.png 150w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Class-7-Solutions-Chapter-13-Lines-and-Angles-Ex-13-6-200x200.png 200w\" sizes=\"auto, (max-width: 231px) 100vw, 231px\" \/><\/figure>\n\n\n\n<p><br>But \u2220AOB + \u2220BOC + \u2220COD + \u2220DOA = 360\u00b0 (Angles at a point)<br>56\u00b0 + 100\u00b0 + x\u00b0 + 74\u00b0 = 360\u00b0<br>\u21d2 230\u00b0 + x\u00b0 = 360\u00b0<br>\u21d2 x\u00b0 = 360\u00b0 \u2013 230\u00b0 = 130\u00b0<br>\u21d2 x = 130\u00b0<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-rs-aggarwal-solutions-for-class-7-maths-chapter-13-download-pdf\">RS Aggarwal Solutions for Class 7 Maths Chapter 13:&nbsp;<strong>Download PDF<\/strong><\/h2>\n\n\n\n<p>RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles<\/p>\n\n\n\n<p><a href=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RS-Aggarwal-Solutions-for-Class-7-Maths-Chapter-13\u2013Lines-and-Angles-1.pdf\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Download PDF<\/strong>: RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles PDF<\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Chapterwise RS Aggarwal Solutions for Class 7&nbsp;Maths :<\/strong><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-1-integers\/\">Chapter 1\u2013Integers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-2-fractions\/\">Chapter 2\u2013Fractions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-3-decimals\/\">Chapter 3\u2013Decimals<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-4-rational-numbers\/\">Chapter 4\u2013Rational Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-5-exponents\/\">Chapter 5\u2013Exponents<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-6-algebraic-expressions\/\">Chapter 6\u2013Algebraic Expressions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-7-linear-equations-in-one-variable\/\">Chapter 7\u2013Linear Equations in One Variable<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-8-ratio-and-proportion\/\">Chapter 8\u2013Ratio and Proportion<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-9-unitary-method\/\">Chapter 9\u2013Unitary Method<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-10-percentage\/\">Chapter 10\u2013Percentage<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-11-profit-and-loss\/\">Chapter 11\u2013Profit and Loss<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-12-simple-interest\/\">Chapter 12\u2013Simple Interest<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/\">Chapter 13\u2013Lines and Angles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-14-properties-of-parallel-lines\/\">Chapter 14\u2013Properties of Parallel Lines<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-15-properties-of-triangles\/\">Chapter 15\u2013Properties of Triangles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-16-congruence\/\">Chapter 16\u2013Congruence<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-17-constructions\/\">Chapter 17\u2013Constructions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-18-reflection-and-rotational-symmetry\/\">Chapter 18\u2013Reflection and Rotational Symmetry<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-19-three-dimensional-shapes\/\">Chapter 19\u2013Three-Dimensional Shapes<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-20-mensuration\/\">Chapter 20\u2013Mensuration<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-21-collection-and-organisation-of-data-mean-median-and-mode\/\">Chapter 21\u2013Collection and Organisation of Data (Mean, Median and Mode)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-22-bar-graphs\/\">Chapter 22\u2013Bar Graphs<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-23-probability\/\">Chapter 23\u2013Probability<\/a><\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"block-154547f6-c927-4f93-83d4-1d0b8ad551b9\">About RS Aggarwal Class 7 Book<\/h2>\n\n\n\n<p id=\"block-d1969927-3cdd-4d79-b3f2-e1f6de36124a\">Investing in an R.S. Aggarwal book will never be of waste since you can use the book to prepare for various competitive exams as well. RS Aggarwal is one of the most prominent books with an endless number of problems. R.S. Aggarwal&#8217;s book very neatly explains every derivation, formula, and question in a very consolidated manner. It has tonnes of examples, practice questions, and solutions even for the NCERT questions.<\/p>\n\n\n\n<p id=\"block-42249921-3e3c-4ebc-8a22-32dcf019c4cf\">He was born on January 2, 1946 in a village of Delhi. He graduated from Kirori Mal College, University of Delhi. After completing his M.Sc. in Mathematics in 1969, he joined N.A.S. College, Meerut, as a lecturer. In 1976, he was awarded a fellowship for 3 years and joined the University of Delhi for his Ph.D. Thereafter, he was promoted as a reader in N.A.S. College, Meerut. In 1999, he joined M.M.H. College, Ghaziabad, as a reader and took voluntary retirement in 2003. He has authored more than 75 titles ranging from Nursery to M. Sc. He has also written books for competitive examinations right from the clerical grade to the I.A.S. level.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"block-b5926142-f365-44d7-938d-958337adb5d2\">FAQs<\/h2>\n\n\n\n<p id=\"block-97c79607-88e9-4eb8-8f73-d3203ec01f96\"><strong>Why must I refer to the RS Aggarwal textbook?<br><\/strong>RS Aggarwal is one of the most important reference books for high school grades and is recommended to every high school student. The book covers every single topic in detail. It goes in-depth and covers every single aspect of all the mathematics topics and covers both theory and problem-solving. The book is true of great help for every high school student. Solving a majority of the questions from the book can help a lot in understanding topics in detail and in a manner that is very simple to understand. Hence, as a high school student, you must definitely dwell your hands on RS Aggarwal!<\/p>\n\n\n\n<p id=\"block-0fe58d7c-722a-4ef6-a6bf-77ff1b1330f2\"><strong>Why should you refer to RS Aggarwal textbook solutions on Indcareer?<br><\/strong>RS Aggarwal is a book that contains a few of the hardest questions of high school mathematics. Solving them and teaching students how to solve questions of such high difficulty is not the job of any neophyte. For solving such difficult questions and more importantly, teaching the problem-solving methodology to students, an expert teacher is mandatory!<\/p>\n\n\n\n<p id=\"block-eed77e3c-a4dc-483a-a406-921e2242c7bf\"><strong>Does IndCareer cover RS Aggarwal Textbook solutions for Class 6-12?<br><\/strong>RS Aggarwal is available for grades 6 to 12 and hence our expert teachers have formulated detailed solutions for all the questions of each edition of the textbook. On our website, you&#8217;ll be able to find solutions to the RS Aggarwal textbook right from Class 6 to Class 12. You can head to the website and download these solutions for free. All the solutions are available in PDF format and are free to download!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Read More<\/h2>\n\n\n\n<ul class=\"wp-block-yoast-seo-related-links\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-9-maths-chapter-4-lines-and-triangles\/\">RS Aggarwal Solutions for Class 9 Maths Chapter 4\u2013Lines and Triangles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-9-maths-chapter-8-lines-and-angles\/\">RD Sharma Solutions for Class 9 Maths Chapter 8\u2013Lines and Angles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-9th-class-maths-chapter-6-lines-and-angles\/\">NCERT Solutions for 9th Class Maths : Chapter 6 Lines and Angles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-7th-class-science-chapter-13-motion-and-time\/\">NCERT Solutions for 7th Class Science: Chapter 13-Motion and Time<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-9-maths-chapter-11-co-ordinate-geometry\/\">RD Sharma Solutions for Class 9 Maths Chapter 11\u2013Co-ordinate Geometry<\/a><\/li><\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Class 7: Maths Chapter 13 solutions. Complete Class 7 Maths Chapter 13 Notes. RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles RS Aggarwal 7th Maths Chapter 13, Class 7 Maths Chapter 13 solutions Question 1.Solution:(i) The given angle = 35\u00b0Let x be its complementary, thenx + 35\u00b0 = 90\u00b0\u21d2 x = 90\u00b0 [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":552090,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,907],"tags":[1963],"boards":[],"class_list":["post-552087","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-7","tag-rs-aggarwal-solutions","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>RS Aggarwal Solutions for Class 7, maths Chapter 13 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles | Browse all Class 7 Maths Chapters RS Aggarwal books - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-13-lines-and-angles\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"RS Aggarwal Solutions for Class 7 Maths Chapter 13\u2013Lines and Angles\" \/>\n<meta property=\"og:description\" content=\"Class 7: Maths Chapter 13 solutions. 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