{"id":551887,"date":"2021-10-25T10:59:37","date_gmt":"2021-10-25T10:59:37","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=551887"},"modified":"2021-10-30T07:46:02","modified_gmt":"2021-10-30T07:46:02","slug":"rs-aggarwal-solutions-for-class-7-maths-chapter-9-unitary-method","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-7-maths-chapter-9-unitary-method\/","title":{"rendered":"RS Aggarwal Solutions for Class 7 Maths Chapter 9\u2013Unitary Method"},"content":{"rendered":"\n

Class 7: Maths Chapter 9 solutions. Complete Class 7 Maths Chapter 9 Notes.<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 7 Maths Chapter 9\u2013Unitary Method<\/h2>\n\n\n\n

RS Aggarwal 7th Maths Chapter 9, Class 7 Maths Chapter 9 solutions<\/p>\n\n\n\n

Ex 9A Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
Cost of 15 oranges = Rs. 110
Cost of 1 orange = Rs. 11015
and cost of 39 oranges = Rs. 11015 x 39
= Rs. 22 x 13 = Rs. 286<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
In Rs. 260, the sugar is bought = 8 kg
and in Re. 1, the sugar is bought = 8260 kg
Then in Rs. 877.50, the sugar will be bought = 8260 x 877.50 kg
= 8260 x 87750100
= 27 kg<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
In Rs. 6290, silk is purchased = 37 m
and in Re. 1, silk is purchased = 376290 m
and in Rs. 4420, silk will be purchased 37
= 376290 x 4420 m = 26 m<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
Rs. 1110 is wages for = 6 days.
Re. 1 will be wages for = 61110 days
and Rs. 4625 will be wages for
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
In 42 litres of petrol, a car covers = 357 km
and in 1 litre, car will cover = 35742 km
and in 12 litres, car will cover = 35742 x 12 = 102 km<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
Cost of travelling 900 km is = Rs. 2520
and cost of 1 km will be = Rs. 2520900
andcostof360kmwillbe = Rs. 2520900 x 360 = Rs. 1008<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
To cover a distance of 51 km, time is taken = 45 minutes
<\/p>\n\n\n\n

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Question 8.<\/strong>
Solution:<\/strong>
If weight is 85.5 kg, then length of iron rod = 22.5 m
If weight is 1 kg, then length of rod will be
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
In 162 grams, sheets are = 6
<\/p>\n\n\n\n

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Question 10.<\/strong>
Solution:<\/strong>
1152 bars of soap can be packed in 8 cartons
1 bar of soap coil be packed in
<\/p>\n\n\n\n

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Question 11.<\/strong>
Solution:<\/strong>
In 44 mm of thickness, cardboards are = 16
In 1 mm of thickness, cardboards will be
<\/p>\n\n\n\n

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Question 12.<\/strong>
Solution:<\/strong>
If length of shadow is 8.2 m, then
height of flag staff is = 7 m
If length of shadow is 1 m, then height will
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
16.25 m long wall is build by = 15 men
<\/p>\n\n\n\n

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Question 14.<\/strong>
Solution:<\/strong>
1350 litres of milk cm be consumed by = 60 patients
1 litres of milk can be consumed by = 601350 patients
and 1710 litres of milk can be consumed
<\/p>\n\n\n\n

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Question 15.<\/strong>
Solution:<\/strong>
2.8 cm extension is produced by = 150 g.
1 cm extension will be produced by = 1502.8 g
and 19.6 cm extension will be produced by
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Ex 9B Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
48 men can dig a trench in = 14 days
1 man will dig the trench in = 14 x 48 days (less men more days)
28 men will dig the trench m = 14×4828 (more men less days)
= 24 days<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
In 30 days, a field is reaped by = 16 men
In 1 day, it will be reaped by = 16 x 30 (less days, more men)
and in 24 days, it will be reaped by = 16×3024 men (more days, less men)
= 48024
= 20 men<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
In 13 days, a field is grazed by = 45 cows.
In 1 day, the field will be grazed by = 45 x 13 cows (less days, more cows)
and in 9 days the field will be grazed by = 45×139 cows (more days, less cows)
= 5 x 13 = 65 cows<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
16 horses can consume corn in = 25 days
1 horse will consume it in = 25 x 16 days (Less horse, more days)
and 40 horses will consume it in = 25×1640 days (more horses, less days)
= 10 days<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
By reading 18 pages a day, a book is finished in = 25 days
By reading 1 page a day, it will be finished = 25 x 18 days (Less page, more days)
and by reading 15 pages a day, it will be finished in = 25×1815 days (more pages, less days)
= 5 x 6 = 30 days<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
Reeta types a document by typing 40 words a minute in = 24 minutes
She will type it by typing 1 word a minute in = 24 x 40 minutes (Less speed, more time)
Her friend will type it by typing 48 words 24 x 40 a minute in = 24×4048 minutes
(more speed, less time)
= 20 minutes<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
With a speed of 45 km\/h, a bus covers a distance in = 3 hours 20 minutes
= 313 = 103 hours
With a speed of 1 km\/h it will cover the distance m = 10×453 h
(Less speed, more time)
and with a speed of 36 km\/h, it will cover the distance in
= 10x453x36 hr (more speed, less time)
= 256 h
= 416 h
= 4 hr 10 minutes<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
To make 240 tonnes of steel, material is sufficient in = 1 month or 30 days
To make 1 tonne of steel, it will be sufficient in = 30 x 240 days (Less steel, more days)
To make 240 + 60 = 300 tonnes of steel it will be sufficient in = 30×240300 days
= 24 days (more steel, less days)<\/p>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
In the beginning, number of men = 210
After 12 days, more men employed = 70
Total men = 210 + 70 = 280
Total period = 60 days.
After 12 days, remaining period = 60 \u2013 12 = 48 days
Now 210 men can build the house in = 48 days
and 1 man can build the house in = 48 x 210 days (less men, more days) .
280 men can build the house in = 48×210280 days
(more men, less days)
= 36 days<\/p>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
In 25 days, the food is sufficient for = 630 men
In 1 day, the food will be sufficient for = 630 x 25 men (less days, more men)
and in 30 days, the food will be sufficient for = 630×2530 hr
(more days less men)
= 525 men
Number of men to be transfered = 630 \u2013 525 = 105 men<\/p>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
Number of men in the beginning = 120
Number of men died = 30
Remaining = 120 \u2013 30 = 90 men
Total period = 200 days
No. of days passed = 5
Remaining period = 200 \u2013 5 = 195
Now, The food lasts for 120 men for = 195 days
The food will last for 1 man for = 195 x 120 days (Less men, more days)
The food will last for 90 men for = 195×12090
(more men less days)
= 65 x 4 = 260 days<\/p>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
Period in the beginning = 28 days
No. of days passed = 4 days.
Remaining period = 28 \u2013 4 = 24 days
The food is sufficient for 24 days for = 1200 soldiers
The food will be sufficient for 1 day for = 1200 x 24 soldiers (Less days, more men)
and the food will be sufficient for 32 days = 1200×2432
= 900 soldiers (more days, less men)
No. of soldiers who left the fort = 1200 \u2013 900 = 300 soldiers<\/p>\n\n\n\n

Ex 9C Solutions<\/h4>\n\n\n\n

Objective Questions.<\/strong>
Marks (\u2713) against the correct answer in each of the following :<\/strong>
Question 1.<\/strong>
Solution:<\/strong>
(c)
Weight of 4.5 m rod = 17.1 kg
<\/p>\n\n\n\n

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Question 2.<\/strong>
Solution:<\/strong>
(d) None of these 0.8 cm represent the map = 8.8 km
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
(c) In 20 minutes, Raghu covers = 5 km
in 1 minutes, he will cover = 520 km
and in 50 minutes, he will cover
<\/p>\n\n\n\n

\"RS<\/figure>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
(d)
No. of men in the beginning = 500
More men arrived = 300
No. of total men = 500 + 300 = 800
For 500 men, provision are for = 24 days
For 1 man, provision will be = 24 x 500 days (less men, more days)
and for 800 men, provision will be = 24800 x 500 days
(more men less days)
= 15 days<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
(b) Total cistern = 1
Filled in 1 minute = 45
Unfilled = 1 \u2013 45 = 15
45 of cistern is filled in = 1 minutes = 60 seconds
1 full cistern can be filled in = 60×54 = 75 seconds
More time = 75 \u2013 60 = 15 seconds<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
(a)
15 buffaloes can eat as much as = 21 cows
1 buffalo will eat as much as = 2115 cows
35 buffaloes will eat as much as
= 21×3515 cm = 49 cows<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
(b) 4 m long shadow is of a tree of height = 6 m
1 m long shadow of flagpole will of height = 64 m
50 m long shadow, the height of pole 6 will be = 64 x 50 = 75 m<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
(b) 8 men can finish the work in = 40 days
1 man will finish it in=40 x 8 days (less men, more days)
8 + 2 = 10 men will finish it in = 40×810 days
(more men, less days)
= 32 days<\/p>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
(b)
16 men can reap a field in = 30 days
1 man will reap the field in = 30 x 16 days
and 20 men will reap the field in = 30×1620 = 24 days<\/p>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
(c) 10 pipe can fill tank in = 24 minutes
1 pipe will fill it in = 24 x 10 minutes (less pipe, more time)
and 10 \u2013 2 = 8 pipes will fill the tank in
= 24×108 = 30 minutes<\/p>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
(d) 6 dozen or 6 x 12 = 72 eggs
Cost of 72 eggs is = Rs. 108
Cost of 1 egg will be = Rs. 10872
and cost of 132 eggs will be 108
= Rs. 10872 x 132 = Rs. 198<\/p>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
(b) 12 workers take to complete the work = 4 hrs.
1 worker will take = 4 x 12 hrs. (less worker, more time)
15 workers will take = 4×1215 hrs. (more workers, less time)
= 165 hr. = 3 hrs. 12 min<\/p>\n\n\n\n

Question 13.<\/strong>
Solution:<\/strong>
(a) 27 days \u2013 3 days = 24 days
Men = 500 + 300 = 800
For 500 men, provision is sufficient = 24 days
For 1 man, provision will be = 24 x 500 (less man, more days)
and for 500 + 300 = 800 men provision
will be sufficient = 24×500800 = 15 days
(more men, less days)<\/p>\n\n\n\n

Question 14.<\/strong>
Solution:<\/strong>
(c) No. of rounds of rope = 140
Radius of base of cylinder = 14 cm
Radius of second cylinder of cylinder = 20 cm
If radius is 14 cm, then rounds of rope are = 140
If radius is 1 cm, then round = 140 x 14 (less radius more rounds)
and if radius is 20 cm, then rounds will
be = 140×1420 = 98 (more radius less rounds)<\/p>\n\n\n\n

Question 15.<\/strong>
Solution:<\/strong>
(d) A worker makes toy in 23 hr= 1
He will make toys in 1 hr = 1 x 32
and will make toys in 223 hrs. = 1 x 32 x 223
= 11 (more time more toys)<\/p>\n\n\n\n

Question 16.<\/strong>
Solution:<\/strong>
(d) A wall is constructed in 8 days by = 10 men
It will be constructed in 1 day by = 10 x 8 men (less time, more men)
10 x 8
<\/p>\n\n\n\n

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More men required = 160 \u2013 10 = 150<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 7 Maths Chapter 9: Download PDF<\/strong><\/h2>\n\n\n\n

RS Aggarwal Solutions for Class 7 Maths Chapter 9\u2013Unitary Method<\/p>\n\n\n\n

Download PDF<\/strong>: RS Aggarwal Solutions for Class 7 Maths Chapter 9\u2013Unitary Method PDF<\/a><\/p>\n\n\n\n

Chapterwise RS Aggarwal Solutions for Class 7 Maths :<\/strong><\/h2>\n\n\n\n