{"id":551195,"date":"2021-10-23T07:47:43","date_gmt":"2021-10-23T07:47:43","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=551195"},"modified":"2021-10-29T10:59:11","modified_gmt":"2021-10-29T10:59:11","slug":"rs-aggarwal-solutions-for-class-8-maths-chapter-24-probability","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rs-aggarwal-solutions-for-class-8-maths-chapter-24-probability\/","title":{"rendered":"RS Aggarwal Solutions for Class 8 Maths Chapter 24\u2013Probability"},"content":{"rendered":"\n

Class 8: Maths Chapter 24 solutions. Complete Class 8 Maths Chapter 24 Notes.<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 8 Maths Chapter 24\u2013Probability<\/h2>\n\n\n\n

RS Aggarwal 8th Maths Chapter 24, Class 8 Maths Chapter 24 solutions<\/p>\n\n\n\n

Ex 24A Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
(i) When a coin is tossed, we get outcomes 2 as H or T (Head or Tail)
(ii) When two coins are tossed together, we get possible four outcomes as HH, HT, TH, TT
(iii) A die is thrown, we get possible outcomes as 1,2, 3, 4, 5, 6
(iv) From a well \u2013 shuffled deck of 52 cards, 0ne card is at random drawn, we get the possible outcomes is 52<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
Possible outcomes = 2
In a single throw of a coin, we get
probability of getting a tail = 12<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
In a single throw of two coins, possible outcomes = 4
(i) Probability of getting both tails = 14
(ii) Probability of getting at least one tail = 34
(iii) Probability of getting at the most one tail = 24 = 12<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
In a bag, there are 4 white and 5 blue balls ,
Possible outcomes = 4 + 5 = 9
One ball is drawn at random, then
(i) the probability of a white ball = 49
(ii) the probability of a blue ball = 59<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
In a bag, there are 5 white, 6 red and 4 green balls
Possible outcome is 5 + 6 + 4 = 15
One ball is drawn at random, then
(i) Probability of a green ball = 415
(ii) Probability of a white ball = 515 = 13
(iii) Probability of a non-red ball = 5+415
= 915
= 35
(5 white and 4 green balls are non-red balls)<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
In a lottery, there are 10 prizes and 20 blanks
Possible outcomes = 10 + 20 = 30
A ticket is chosen at random, then
probability of getting a prize = 1030 = 13<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
In a ,box of 100 electric bulb, 8 are defective
Then non-defective bulbs = 100 \u2013 8 = 92
Now possible outcomes = 100
(i) Probability of a drawn bulb, which is defective = 8100 = 225
(ii) Probability of a drawn bulb which is non defective = 92100 = 2325<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
A die is thrown, then
Possible outcomes = 6
(i) Now probability of getting 2 = 16
(ii) Probability of a number less than 3 (which are 1 and 2) = 26 = 13
(iii) Probability of a composite number (a composite number is a number which is not a prime number which are 4, 6) = 26 = 13
(iv) Probability of a number not less than 4 (which are 5, 6) = 26 = 13<\/p>\n\n\n\n

Question 9.<\/strong>
Solution:<\/strong>
Total number of ladies = 200
Those who like coffee = 82
Those who dislike coffee = 118
Possible number of outcomes = 200
One lady is chosen at random, then
(i) Probability of a lady who dislikes coffee = 118200
= 59100<\/p>\n\n\n\n

Question 10.<\/strong>
Solution:<\/strong>
19 ball bearing numbers, 1, 2, 3,\u202619
possible outcomes = 19
A ball is drawn at random from the box, then
(i) Probability of a ball which bears a prime numbers which are 2, 3, 5, 7, 11, 13, 17 and 19 = 8 = 819
(ii) Probability of a ball which bears an even number which are 2, 4, 6, 8, 10, 12, 14, 16, 18 = 9 = 919
(iii) Probability of a number which bears a number divisible by 3 which are 3, 6, 9, 12, 15, 18 = 6 = 619<\/p>\n\n\n\n

Question 11.<\/strong>
Solution:<\/strong>
A card\u2019s drawn at random from a deck
of well-shuffled deck of 52 cards Probability = 52
(i) Probability of a card being a king = 452 = 113
(ii) Probability of a card being spade = 1352 = 14
(iii) Probability of a card being a red queen = 252 = 126
(iv) Probability of a card being a black 8 = 252 = 126<\/p>\n\n\n\n

Question 12.<\/strong>
Solution:<\/strong>
One card is drawn at random from a deck of well shuffled deck of 52 cards
Possible outcomes = 52
(i) Probability of a card being a 4 = 452 = 113
(ii) Probability of a card being a queen = 452 = 113
(iii) Probability of a card being a black card = 2652 = 12<\/p>\n\n\n\n

Ex 24B Solutions<\/h4>\n\n\n\n

Question 1.<\/strong>
Solution:<\/strong>
A spinning wheel has 3 white and 5 green sectors
Possible out come = 3 + 5 = 8
It is spinners, then
Probability of getting a green sector = 58 (b)<\/p>\n\n\n\n

Question 2.<\/strong>
Solution:<\/strong>
8 cards are numbered 1, 2, 3, 4, 5, 6, 7, 8
They are mixed and kept in a box One card is chosen at random, then Probability of card having 9 number less than 4 = 38 (c)<\/p>\n\n\n\n

Question 3.<\/strong>
Solution:<\/strong>
Two coins are tossed simultaneously, then Possible outcomes = 4
Now probability of getting one head and one tail = 24 = 12 (b)<\/p>\n\n\n\n

Question 4.<\/strong>
Solution:<\/strong>
. In a bag, there are 3 white and 2 red balls
Possible outcomes = 3 + 2 = 5
Now probability of a red ball drawn
= 25 (d)<\/p>\n\n\n\n

Question 5.<\/strong>
Solution:<\/strong>
A die is thrown then
Possible outcomes = 6
Now probability of getting 6 is 16 (b)<\/p>\n\n\n\n

Question 6.<\/strong>
Solution:<\/strong>
A die is thrown
Possible outcomes = 6
Now probability of getting an even number
which are 2, 4, 6 = 36 = 12 (a)<\/p>\n\n\n\n

Question 7.<\/strong>
Solution:<\/strong>
One card is drawn from a well shuffled deck of 52 cards, possible out comes = 52
The probability of card which is a queen = 452
= 113 (c)<\/p>\n\n\n\n

Question 8.<\/strong>
Solution:<\/strong>
One card is drawn from a well-shuffled deck of 52 card, possible out comes = 52 Probability of a card being a black 6
(which are two) = 252 = 126 (b)<\/p>\n\n\n\n

RS Aggarwal Solutions for Class 8 Maths Chapter 24: Download PDF<\/strong><\/h2>\n\n\n\n

RS Aggarwal Solutions for Class 8 Maths Chapter 24\u2013Probability<\/p>\n\n\n\n

Download PDF<\/strong>: RS Aggarwal Solutions for Class 8 Maths Chapter 24\u2013Probability PDF<\/a><\/p>\n\n\n\n

Chapterwise RS Aggarwal Solutions for Class 8 Maths :<\/strong><\/h2>\n\n\n\n