{"id":546622,"date":"2021-10-07T09:26:43","date_gmt":"2021-10-07T09:26:43","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=546622"},"modified":"2021-10-09T06:10:57","modified_gmt":"2021-10-09T06:10:57","slug":"rd-sharma-solutions-for-class-7-maths-chapter-3-decimals","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/","title":{"rendered":"RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals"},"content":{"rendered":"\n<p><meta http-equiv=\"content-type\" content=\"text\/html; charset=utf-8\">Class 7: Maths Chapter 3 solutions. Complete Class 7 Maths Chapter 3 Notes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\">RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals<\/h2>\n\n\n\n<p><meta http-equiv=\"content-type\" content=\"text\/html; charset=utf-8\">RD Sharma 7th Maths Chapter 3, Class 7 Maths Chapter 3 solutions<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Exercise 3.1 Page No: 3.4<\/h4>\n\n\n\n<p><strong>1. Write each of the following as decimals:<\/strong><\/p>\n\n\n\n<p><strong>(i) (8\/100)<\/strong><\/p>\n\n\n\n<p><strong>(ii) 20 + (9\/10) + (4\/100)<\/strong><\/p>\n\n\n\n<p><strong>(iii) 23 + (2\/10) + (6\/1000)<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given (8\/100)<\/p>\n\n\n\n<p>Mark the decimal point two places from right to left<\/p>\n\n\n\n<p>(8\/100) = 0.08<\/p>\n\n\n\n<p>(ii) Given 20 + (9\/10) + (4\/100)<\/p>\n\n\n\n<p>First convert the fractions (9\/10) and (4\/100) to decimals<\/p>\n\n\n\n<p>Consider (9\/10)<\/p>\n\n\n\n<p>Mark the decimal point one place from right to left<\/p>\n\n\n\n<p>(9\/10) = 0.9<\/p>\n\n\n\n<p>Now consider (4\/100)<\/p>\n\n\n\n<p>Mark the decimal point two places from right to left<\/p>\n\n\n\n<p>(4\/100) = 0.04<\/p>\n\n\n\n<p>20 + (9\/10) + (4\/100) = 20 + 0.9 + 0.04<\/p>\n\n\n\n<p>= 20.94<\/p>\n\n\n\n<p>(iii) Given 23 + (2\/10) + (6\/1000)<\/p>\n\n\n\n<p>First convert the fractions (2\/10) and (6\/1000) to decimals<\/p>\n\n\n\n<p>Consider (2\/10)<\/p>\n\n\n\n<p>Mark the decimal point one place from right to left<\/p>\n\n\n\n<p>(2\/10) = 0.2<\/p>\n\n\n\n<p>Now consider (6\/1000)<\/p>\n\n\n\n<p>Mark the decimal point three places from right to left<\/p>\n\n\n\n<p>(6\/1000) = 0.006<\/p>\n\n\n\n<p>23 + (2\/10) + (6\/1000) = 23 + 0.2 + 0.006<\/p>\n\n\n\n<p>= 23.206<\/p>\n\n\n\n<p><strong>2. Convert each of the following decimals as fractions:<\/strong><\/p>\n\n\n\n<p><strong>(i) 0.04<\/strong><\/p>\n\n\n\n<p><strong>(ii) 2.34<\/strong><\/p>\n\n\n\n<p><strong>(iii) 0.342<\/strong><\/p>\n\n\n\n<p><strong>(iv) 17.38<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 0.04<\/p>\n\n\n\n<p>Here we have to convert given decimals into fractions<\/p>\n\n\n\n<p>0.04 can be written as (0.04\/1)<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 100 then we get<\/p>\n\n\n\n<p>(0.04\/1) = (0.04 \u00d7 100 \/1 \u00d7 100)<\/p>\n\n\n\n<p>= (4\/100)<\/p>\n\n\n\n<p>= (1\/25)<\/p>\n\n\n\n<p>(ii) Given 2.34<\/p>\n\n\n\n<p>Here we have to convert given decimals into fractions<\/p>\n\n\n\n<p>2.34 can be written as (2.34\/1)<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 100 then we get<\/p>\n\n\n\n<p>(2.34\/1) = (2.34 \u00d7 100 \/1 \u00d7 100)<\/p>\n\n\n\n<p>= (234\/100)<\/p>\n\n\n\n<p>= (117\/50)<\/p>\n\n\n\n<p>(iii) Given 0.342<\/p>\n\n\n\n<p>Here we have to convert given decimals into fractions<\/p>\n\n\n\n<p>0.342 can be written as (0.342\/1)<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 1000 then we get<\/p>\n\n\n\n<p>(0.342\/1) = (0.342 \u00d7 1000 \/1 \u00d7 1000)<\/p>\n\n\n\n<p>= (342\/1000)<\/p>\n\n\n\n<p>= (171\/500)<\/p>\n\n\n\n<p>(iv) Given 17.38<\/p>\n\n\n\n<p>Here we have to convert given decimals into fractions<\/p>\n\n\n\n<p>17.38 can be written as (17.38\/1)<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 100 then we get<\/p>\n\n\n\n<p>(17.38\/1) = (17.38 \u00d7 100 \/1 \u00d7 100)<\/p>\n\n\n\n<p>= (1738\/100)<\/p>\n\n\n\n<p>= (869\/50)<\/p>\n\n\n\n<p><strong>3. Express the following fractions as decimals:<\/strong><\/p>\n\n\n\n<p><strong>(i) (23\/10)<\/strong><\/p>\n\n\n\n<p><strong>(ii)&nbsp;25182518<\/strong><\/p>\n\n\n\n<p><strong>(iii)&nbsp;3973539735<\/strong><\/p>\n\n\n\n<p><strong>(iv)&nbsp;1512515125<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given (23\/10)<\/p>\n\n\n\n<p>Divide 23 by 10 we get<\/p>\n\n\n\n<p>(23\/10) = 2.3<\/p>\n\n\n\n<p>(ii) Given&nbsp;2518251825182518&nbsp;can be written as25182518&nbsp;= 25 + (1\/8)<\/p>\n\n\n\n<p>Consider (1\/8),<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 125 to get 1000 as denominator25182518&nbsp;= 25 + (1\/8) = 25 + (1 \u00d7 125 \/8 \u00d7 125)<\/p>\n\n\n\n<p>= 25 + (125\/1000)<\/p>\n\n\n\n<p>= 25 + 0.125<\/p>\n\n\n\n<p>= 25.125<\/p>\n\n\n\n<p>(iii) Given&nbsp;3973539735<\/p>\n\n\n\n<p>First convert given mixed fraction&nbsp;3973539735&nbsp;into improper fraction3973539735&nbsp;= 1372\/35<\/p>\n\n\n\n<p>By dividing we get3973539735&nbsp;= 39.2<\/p>\n\n\n\n<p>(iv) Given&nbsp;15125151251512515125&nbsp;can be written as1512515125&nbsp;= 15 + (1\/25)<\/p>\n\n\n\n<p>Consider (1\/25),<\/p>\n\n\n\n<p>Now multiply both numerator and denominator by 4 to get 100 as denominator1512515125&nbsp;= 15 + (1\/25) = 15 + (1 \u00d7 4 \/25 \u00d7 4)<\/p>\n\n\n\n<p>= 15 + (4\/100)<\/p>\n\n\n\n<p>= 15 + 0.04<\/p>\n\n\n\n<p>= 15.04<\/p>\n\n\n\n<p><strong>4. Add the following:<\/strong><\/p>\n\n\n\n<p><strong>(i) 41.8, 39.24, 5.01 and 62.6<\/strong><\/p>\n\n\n\n<p><strong>(ii) 18.03, 146.3, .829 and 5.324<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 41.8, 39.24, 5.01 and 62.6<\/p>\n\n\n\n<p>41.8<\/p>\n\n\n\n<p>39.24<\/p>\n\n\n\n<p>5.01<\/p>\n\n\n\n<p>+ 62.6<\/p>\n\n\n\n<p>148.65<\/p>\n\n\n\n<p>(ii) Given 18.03, 146.3, 0.829 and 5.324<\/p>\n\n\n\n<p>18.03<\/p>\n\n\n\n<p>146.3<\/p>\n\n\n\n<p>0.829<\/p>\n\n\n\n<p>+ 5.324<\/p>\n\n\n\n<p>170.483<\/p>\n\n\n\n<p><strong>5. Find the value of:<\/strong><\/p>\n\n\n\n<p><strong>(i) 9.756 \u2013 6.28<\/strong><\/p>\n\n\n\n<p><strong>(ii) 48.1 \u2013 0.37<\/strong><\/p>\n\n\n\n<p><strong>(iii) 108.032 \u2013 86.8<\/strong><\/p>\n\n\n\n<p><strong>(iv) 100 \u2013 26.32<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 9.756 \u2013 6.28<\/p>\n\n\n\n<p>9.756<\/p>\n\n\n\n<p>\u2013 6.28<\/p>\n\n\n\n<p>3.476<\/p>\n\n\n\n<p>(ii) Given 48.1 \u2013 0.37<\/p>\n\n\n\n<p>48.1<\/p>\n\n\n\n<p>\u2013 0.37<\/p>\n\n\n\n<p>47.73<\/p>\n\n\n\n<p>(iii) Given 108.032 \u2013 86.8<\/p>\n\n\n\n<p>108.032<\/p>\n\n\n\n<p>\u2013 86.8<\/p>\n\n\n\n<p>21.232<\/p>\n\n\n\n<p>(iv) Given 100 \u2013 26.32<\/p>\n\n\n\n<p>100.00<\/p>\n\n\n\n<p>\u2013 26.32<\/p>\n\n\n\n<p>73.68<\/p>\n\n\n\n<p><strong>6. Take out of 3.547 from 7.2<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given 3.547 from 7.2<\/p>\n\n\n\n<p>7.2<\/p>\n\n\n\n<p>\u2013 3.547<\/p>\n\n\n\n<p>3.653<\/p>\n\n\n\n<p><strong>7. What is to be added to 36.85 to get 59.41?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given 36.85 and 59.41<\/p>\n\n\n\n<p>Let the unknown number be x<\/p>\n\n\n\n<p>x + 36.85 = 59.41<\/p>\n\n\n\n<p>x = 59.41 \u2013 36.85<\/p>\n\n\n\n<p>x = 22.56<\/p>\n\n\n\n<p>Hence 22.56 is to be added to 36.85 to get 59.41<\/p>\n\n\n\n<p><strong>8. What is to be subtracted from 17.1 to get 2.051?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Let the unknown number be x<\/p>\n\n\n\n<p>Given that x is to be subtracted from 17.1 to get 2.051<\/p>\n\n\n\n<p>17.1 \u2013 x = 2.051<\/p>\n\n\n\n<p>17.1 \u2013 2.051 = x<\/p>\n\n\n\n<p>x = 17.1 \u2013 2.051<\/p>\n\n\n\n<p>x = 15.049<\/p>\n\n\n\n<p><strong>9. By how much should 34.79 be increased to get 70.15?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Let x be the unknown number<\/p>\n\n\n\n<p>x + 34.79 = 70.15<\/p>\n\n\n\n<p>x = 70.15 \u2013 34.79<\/p>\n\n\n\n<p>x = 35.36<\/p>\n\n\n\n<p>35.36 should be increased to 34.79 to get 70.15<\/p>\n\n\n\n<p><strong>10. By how much should 59.71 be decreased to get 34.58?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Let x be the unknown number<\/p>\n\n\n\n<p>59.71 \u2013 x =34.58<\/p>\n\n\n\n<p>59.71 \u2013 34.58 = x<\/p>\n\n\n\n<p>x = 59.71 \u2013 34.58<\/p>\n\n\n\n<p>x = 25.13<\/p>\n\n\n\n<p>25.13 should be decreased by 59.71 to get 34.58<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Exercise 3.2 Page No: 3.8<\/h4>\n\n\n\n<p><strong>1. Find the product:<\/strong><\/p>\n\n\n\n<p><strong>(i) 4.74 \u00d7 10<\/strong><\/p>\n\n\n\n<p><strong>(ii) 0.45 \u00d7 10<\/strong><\/p>\n\n\n\n<p><strong>(iii) 0.0215 \u00d7 10<\/strong><\/p>\n\n\n\n<p><strong>(iv) 0.0054 \u00d7 10<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 4.74 \u00d7 10<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by one place to the right<\/p>\n\n\n\n<p>Therefore 4.74 \u00d7 10 = 47.4<\/p>\n\n\n\n<p>(ii) Given 0.45 \u00d7 10<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by one place to the right<\/p>\n\n\n\n<p>Therefore 0.45 \u00d7 10 = 4.5<\/p>\n\n\n\n<p>(iii) Given 0.0215 \u00d7 10<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by one place to the right<\/p>\n\n\n\n<p>Therefore 0.0215 \u00d7 10 = 0.215<\/p>\n\n\n\n<p>(iv) Given 0.0054 \u00d7 10<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by one place to the right<\/p>\n\n\n\n<p>Therefore 0.0054 \u00d7 10 = 0.054<\/p>\n\n\n\n<p><strong>2. Find the product:<\/strong><\/p>\n\n\n\n<p><strong>(i) 35.853 \u00d7 100<\/strong><\/p>\n\n\n\n<p><strong>(ii) 42.5 \u00d7 100<\/strong><\/p>\n\n\n\n<p><strong>(iii) 12.075 \u00d7 100<\/strong><\/p>\n\n\n\n<p><strong>(iv) 100 \u00d7 0.005<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 35.853 \u00d7 100<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by two places to the right<\/p>\n\n\n\n<p>Therefore 35.853 \u00d7 100 = 3585.3<\/p>\n\n\n\n<p>(ii) Given 42.5 \u00d7 100<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by two places to the right<\/p>\n\n\n\n<p>Therefore 42.5 \u00d7 100 = 4250<\/p>\n\n\n\n<p>(iii) Given 12.075 \u00d7 100<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by two places to the right<\/p>\n\n\n\n<p>Therefore 12.075 \u00d7 100 = 1207.50<\/p>\n\n\n\n<p>(iv) Given 100 \u00d7 0.005<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by two places to the right<\/p>\n\n\n\n<p>Therefore 100 \u00d7 0.005 = 0.5<\/p>\n\n\n\n<p><strong>3. Find the product:<\/strong><\/p>\n\n\n\n<p><strong>(i) 2.506 \u00d7 1000<\/strong><\/p>\n\n\n\n<p><strong>(ii) 20.708 \u00d7 1000<\/strong><\/p>\n\n\n\n<p><strong>(iii) 0.0529 \u00d7 1000<\/strong><\/p>\n\n\n\n<p><strong>(iv) 1000 \u00d7 0.1<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 2.506 \u00d7 1000<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by three places to the right<\/p>\n\n\n\n<p>Therefore 2.506 \u00d7 1000 = 2506<\/p>\n\n\n\n<p>(ii) Given 20.708 \u00d7 1000<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by three places to the right<\/p>\n\n\n\n<p>Therefore 20.708 \u00d7 1000 = 20708<\/p>\n\n\n\n<p>(iii) Given 0.0529 \u00d7 1000<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by three places to the right<\/p>\n\n\n\n<p>Therefore 0.0529 \u00d7 1000 = 52.9<\/p>\n\n\n\n<p>(iv) Given 1000 \u00d7 0.1<\/p>\n\n\n\n<p>Here we have to do normal multiplication with shifting the decimal point by three places to the right<\/p>\n\n\n\n<p>Therefore 1000 \u00d7 0.1 = 100<\/p>\n\n\n\n<p><strong>4. Find the product:<\/strong><\/p>\n\n\n\n<p><strong>(i) 3.14 \u00d7 17<\/strong><\/p>\n\n\n\n<p><strong>(ii) 0.745 \u00d7 12<\/strong><\/p>\n\n\n\n<p><strong>(iii) 28.73 \u00d7 47<\/strong><\/p>\n\n\n\n<p><strong>(iv) 0.0415 \u00d7 59<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 3.14 \u00d7 17<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>3.14 \u00d7 17 = 578<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have one place of decimal as there in the given decimal<\/p>\n\n\n\n<p>3.14 \u00d7 17 = 57.8<\/p>\n\n\n\n<p>(ii) Given 0.745 \u00d7 12<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>0.745 \u00d7 12 = 894<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have three places of decimal as there in the given decimal<\/p>\n\n\n\n<p>0.745 \u00d7 12 = 8.94<\/p>\n\n\n\n<p>(iii) Given 28.73 \u00d7 47<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>28.73 \u00d7 47 = 135031<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have two places of decimal as there in the given decimal<\/p>\n\n\n\n<p>28.73 \u00d7 47 = 1350.31<\/p>\n\n\n\n<p>(iv) Given 0.0415 \u00d7 59<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>0.0415 \u00d7 59 = 24485<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have four places of decimal as there in the given decimal<\/p>\n\n\n\n<p>0.0415 \u00d7 59 = 2.4485<\/p>\n\n\n\n<p><strong>5. Find:<\/strong><\/p>\n\n\n\n<p><strong>(i) 1.07 \u00d7 0.02<\/strong><\/p>\n\n\n\n<p><strong>(ii) 211.9 \u00d7 1.13<\/strong><\/p>\n\n\n\n<p><strong>(iii) 10.05 \u00d7 1.05<\/strong><\/p>\n\n\n\n<p><strong>(iv) 13.01 \u00d7 5.01<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 1.07 \u00d7 0.02<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>1.07 \u00d7 0.02 = 00214<\/p>\n\n\n\n<p>Sum of the decimals is 4<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have four places of decimal as there in the given decimal<\/p>\n\n\n\n<p>1.07 \u00d7 0.02 = 0.0214<\/p>\n\n\n\n<p>(ii) Given 211.9 \u00d7 1.13<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>211.9 \u00d7 1.13 = 239447<\/p>\n\n\n\n<p>Sum of the decimals is 3<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have three places of decimal as there in the given decimal<\/p>\n\n\n\n<p>211.9 \u00d7 1.13 = 239.447<\/p>\n\n\n\n<p>(iii) Given 10.05 \u00d7 1.05<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>10.05 \u00d7 1.05 = 105525<\/p>\n\n\n\n<p>Sum of the decimals is 4<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have four places of decimal as there in the given decimal<\/p>\n\n\n\n<p>10.05 \u00d7 1.05 = 10.5525<\/p>\n\n\n\n<p>(iv) Given 13.01 \u00d7 5.01<\/p>\n\n\n\n<p>First multiply as usual without looking at the decimal point<\/p>\n\n\n\n<p>13.01 \u00d7 5.01 = 651801<\/p>\n\n\n\n<p>Sum of the decimals is 4<\/p>\n\n\n\n<p>Now mark the decimal point in the product to have four places of decimal as there in the given decimal<\/p>\n\n\n\n<p>13.01 \u00d7 5.01 = 65.1801<\/p>\n\n\n\n<p><strong>6. Find the area of a rectangle whose length is 5.5m and breadth is 3.4m.<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given length of rectangle = 5.5m<\/p>\n\n\n\n<p>Breadth of rectangle = 3.4 m<\/p>\n\n\n\n<p>Area of rectangle = length \u00d7 breadth<\/p>\n\n\n\n<p>= 5.5 \u00d7 3.4<\/p>\n\n\n\n<p>= 18.7 m<sup>2<\/sup><\/p>\n\n\n\n<p><strong>7. If the cost of a book is Rs 25.57, find the cost 0f 24 such books.<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given cost of a book is Rs 25.57<\/p>\n\n\n\n<p>Cost of 24 books = 25.57 \u00d7 24<\/p>\n\n\n\n<p>= Rs 618.00<\/p>\n\n\n\n<p><strong>8. A car covers a distance of 14.75km in one liter of petrol. How much distance it will cover in 15.5 liters of petrol?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that distance covered by car in 1 liter of petrol = 14.75 km<\/p>\n\n\n\n<p>Distance covered by car in 15.5 liters of petrol = 14.75 \u00d7 15.5<\/p>\n\n\n\n<p>= 228.625 km<\/p>\n\n\n\n<p><strong>9. One kg of rice costs Rs 42.65. What will be the cost of 18.25 kg of rice?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given cost of 1kg of rice = 42.65<\/p>\n\n\n\n<p>Cost of 18.25kg of rice = 42.65 \u00d7 18.25<\/p>\n\n\n\n<p>= Rs 778.3625<\/p>\n\n\n\n<p><strong>10. One meter of cloth costs Rs 152.50. What is the cost of 10.75 meters of cloth?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that cost of 1m cloth = Rs 152.50<\/p>\n\n\n\n<p>Cost of 10.75 m of cloth = 152.50 \u00d7 10.75<\/p>\n\n\n\n<p>= Rs 1639.375<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Exercise 3.3 Page No: 3.16<\/h4>\n\n\n\n<p><strong>1. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 142.45 by 10<\/strong><\/p>\n\n\n\n<p><strong>(ii) 54.25 by 10<\/strong><\/p>\n\n\n\n<p><strong>(iii) 3.45 by 10<\/strong><\/p>\n\n\n\n<p><strong>(iv) 0.57 by 10<\/strong><\/p>\n\n\n\n<p><strong>(v) 0.0043 by 10<\/strong><\/p>\n\n\n\n<p><strong>(vi) 0.004 by 10<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 142.45 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>142.45\/10 = 14.245<\/p>\n\n\n\n<p>(ii) Given 54.25 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>54.25\/10 = 5.425<\/p>\n\n\n\n<p>(iii) Given 3.45 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>3.45\/10 = 0.345<\/p>\n\n\n\n<p>(iv) Given 0.57 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>0.57\/10 = 0.057<\/p>\n\n\n\n<p>(v) Given 0.0043 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>0.0043\/10 = 0.0043<\/p>\n\n\n\n<p>(vi) Given 0.004 by 10<\/p>\n\n\n\n<p>Now shifting the decimal point by one place to the left we can get the result<\/p>\n\n\n\n<p>0.004\/10 = 0.0004<\/p>\n\n\n\n<p><strong>2. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 459.5 by 100<\/strong><\/p>\n\n\n\n<p><strong>(ii) 74.3 by 100<\/strong><\/p>\n\n\n\n<p><strong>(iii) 5.8 by 100<\/strong><\/p>\n\n\n\n<p><strong>(iv) 0.7 by 100<\/strong><\/p>\n\n\n\n<p><strong>(v) 0.48 by 100<\/strong><\/p>\n\n\n\n<p><strong>(vi) 0.03 by 100<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 459.5 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>459.5\/100 = 4.595<\/p>\n\n\n\n<p>(ii) Given 74.3 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>74.3\/100 = 0.743<\/p>\n\n\n\n<p>(iii) Given 5.8 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>5.8\/100 = 0.058<\/p>\n\n\n\n<p>(iv) Given 0.7 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>0.7\/100 = 0.007<\/p>\n\n\n\n<p>(v) Given 0.48 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>0.48\/100 = 0.0048<\/p>\n\n\n\n<p>(vi) Given 0.03 by 100<\/p>\n\n\n\n<p>Now shifting the decimal point by two places to the left we can get the result<\/p>\n\n\n\n<p>0.03 \/ 100 = 0.0003<\/p>\n\n\n\n<p><strong>3. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 235. 41 by 1000<\/strong><\/p>\n\n\n\n<p><strong>(ii) 29.5 by 1000<\/strong><\/p>\n\n\n\n<p><strong>(iii) 3.8 by 1000<\/strong><\/p>\n\n\n\n<p><strong>(iv) 0.7 by 1000<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 235. 41 by 1000<\/p>\n\n\n\n<p>Now shifting the decimal point by three places to the left we can get the result<\/p>\n\n\n\n<p>235. 41\/1000 = 0.23541<\/p>\n\n\n\n<p>(ii) Given 29.5 by 1000<\/p>\n\n\n\n<p>Now shifting the decimal point by three places to the left we can get the result<\/p>\n\n\n\n<p>29.5\/1000 = 0.0295<\/p>\n\n\n\n<p>(iii) Given 3.8 by 1000<\/p>\n\n\n\n<p>Now shifting the decimal point by three places to the left we can get the result<\/p>\n\n\n\n<p>3.8 \/1000 = 0.0038<\/p>\n\n\n\n<p>(iv) Given 0.7 by 1000<\/p>\n\n\n\n<p>Now shifting the decimal point by three places to the left we can get the result<\/p>\n\n\n\n<p>0.7 \/1000 = 0.0007<\/p>\n\n\n\n<p><strong>4. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 0.45 by 9<\/strong><\/p>\n\n\n\n<p><strong>(ii) 217.44 by 18<\/strong><\/p>\n\n\n\n<p><strong>(iii) 319.2 by 2.28<\/strong><\/p>\n\n\n\n<p><strong>(iv) 40.32 by 9.6<\/strong><\/p>\n\n\n\n<p><strong>(v) 0.765 by 0.9<\/strong><\/p>\n\n\n\n<p><strong>(vi) 0.768 by 1.6<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 0.45 by 9<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"99\" height=\"221\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de.png\" alt=\"\" class=\"wp-image-546625\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 1\"\/><\/figure>\n\n\n\n<p>0.45 by 9 = 0.05<\/p>\n\n\n\n<p>(ii) Given 217.44 by 18<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"166\" height=\"336\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-1.png\" alt=\"\" class=\"wp-image-546626\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 2\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-1.png 166w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-1-148x300.png 148w\" sizes=\"auto, (max-width: 166px) 100vw, 166px\" \/><\/figure>\n\n\n\n<p>217.44 by 18 = 12.08<\/p>\n\n\n\n<p>3. Given 319.2 by 2.28<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"185\" height=\"340\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-2.png\" alt=\"\" class=\"wp-image-546627\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 3\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-2.png 185w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-2-163x300.png 163w\" sizes=\"auto, (max-width: 185px) 100vw, 185px\" \/><\/figure>\n\n\n\n<p>319.2 by 2.28 = 140<\/p>\n\n\n\n<p>(iv) Given 40.32 by 9.6<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"150\" height=\"283\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-3.png\" alt=\"\" class=\"wp-image-546628\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 4\"\/><\/figure>\n\n\n\n<p>40.32 by 9.6 = 4.2<\/p>\n\n\n\n<p>(v) Given 0.765 by 0.9<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"105\" height=\"226\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-4.png\" alt=\"\" class=\"wp-image-546629\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 5\"\/><\/figure>\n\n\n\n<p>0.765 by 0.9 = 0.85<\/p>\n\n\n\n<p>(vi) Given 0.768 by 1.6<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"117\" height=\"235\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-5.png\" alt=\"\" class=\"wp-image-546630\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 6\"\/><\/figure>\n\n\n\n<p>0.768 by 1.6 = 0.48<\/p>\n\n\n\n<p><strong>5. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 16.64 by 20<\/strong><\/p>\n\n\n\n<p><strong>(ii) 0.192 by 12<\/strong><\/p>\n\n\n\n<p><strong>(iii) 163.44 by 24<\/strong><\/p>\n\n\n\n<p><strong>(iv) 403.2 by 96<\/strong><\/p>\n\n\n\n<p><strong>(v) 16.344 by 12<\/strong><\/p>\n\n\n\n<p><strong>(vi) 31.92 by 228<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 16.64 by 20<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"163\" height=\"340\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-6.png\" alt=\"\" class=\"wp-image-546631\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 7\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-6.png 163w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-6-144x300.png 144w\" sizes=\"auto, (max-width: 163px) 100vw, 163px\" \/><\/figure>\n\n\n\n<p>16.64 by 20 = 0.832<\/p>\n\n\n\n<p>(ii) Given 0.192 by 12<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"134\" height=\"280\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-7.png\" alt=\"\" class=\"wp-image-546632\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 8\"\/><\/figure>\n\n\n\n<p>0.192 by 12 = 0.016<\/p>\n\n\n\n<p>(iii) Given 163.44 by 24<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"161\" height=\"338\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-8.png\" alt=\"\" class=\"wp-image-546633\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 9\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-8.png 161w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-8-143x300.png 143w\" sizes=\"auto, (max-width: 161px) 100vw, 161px\" \/><\/figure>\n\n\n\n<p>163.44 by 24 = 6.81<\/p>\n\n\n\n<p>(iv) Given 403.2 by 96<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"137\" height=\"285\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-9.png\" alt=\"\" class=\"wp-image-546634\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 10\"\/><\/figure>\n\n\n\n<p>403.2 by 96 = 4.2<\/p>\n\n\n\n<p>(v) Given 16.344 by 12<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"157\" height=\"340\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-10.png\" alt=\"\" class=\"wp-image-546635\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 11\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-10.png 157w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-10-139x300.png 139w\" sizes=\"auto, (max-width: 157px) 100vw, 157px\" \/><\/figure>\n\n\n\n<p>16.344 by 12 = 1.362<\/p>\n\n\n\n<p>(vi) Given 31.92 by 228<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"162\" height=\"292\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-11.png\" alt=\"\" class=\"wp-image-546636\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 12\"\/><\/figure>\n\n\n\n<p>31.92 by 228 = 0.14<\/p>\n\n\n\n<p><strong>6. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 15.68 by 20<\/strong><\/p>\n\n\n\n<p><strong>(ii) 164.6 by 200<\/strong><\/p>\n\n\n\n<p><strong>(iii) 403.80 by 30<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 15.68 by 20<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"166\" height=\"338\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-12.png\" alt=\"\" class=\"wp-image-546637\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 13\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-12.png 166w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-12-147x300.png 147w\" sizes=\"auto, (max-width: 166px) 100vw, 166px\" \/><\/figure>\n\n\n\n<p>15.68 by 20 = 0.784<\/p>\n\n\n\n<p>(ii) Given 164.6 by 200<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"211\" height=\"390\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-13.png\" alt=\"\" class=\"wp-image-546638\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 14\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-13.png 211w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-13-162x300.png 162w\" sizes=\"auto, (max-width: 211px) 100vw, 211px\" \/><\/figure>\n\n\n\n<p>164.6 by 200 = 0.823<\/p>\n\n\n\n<p>(iii) Given 403.80 by 30<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"167\" height=\"343\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-14.png\" alt=\"\" class=\"wp-image-546639\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 15\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-14.png 167w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-14-146x300.png 146w\" sizes=\"auto, (max-width: 167px) 100vw, 167px\" \/><\/figure>\n\n\n\n<p>403.80 by 30 = 13.46<\/p>\n\n\n\n<p><strong>7. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 76 by 0.019<\/strong><\/p>\n\n\n\n<p><strong>(ii) 88 by 0.08<\/strong><\/p>\n\n\n\n<p><strong>(iii) 148 by 0.074<\/strong><\/p>\n\n\n\n<p><strong>(iv) 7 by 0.014<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 76 by 0.019<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 1000 then divide<\/p>\n\n\n\n<p>= 76000\/19<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"155\" height=\"334\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-15.png\" alt=\"\" class=\"wp-image-546640\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 16\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-15.png 155w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-15-139x300.png 139w\" sizes=\"auto, (max-width: 155px) 100vw, 155px\" \/><\/figure>\n\n\n\n<p>76 by 0.019 = 4000<\/p>\n\n\n\n<p>(ii) Given 88 by 0.08<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 100 then divide<\/p>\n\n\n\n<p>= 8800\/8<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"116\" height=\"280\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-16.png\" alt=\"\" class=\"wp-image-546641\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 17\"\/><\/figure>\n\n\n\n<p>88 by 0.08 = 1100<\/p>\n\n\n\n<p>(iii) Given 148 by 0.074<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 1000 then divide<\/p>\n\n\n\n<p>= 14800\/74<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"184\" height=\"391\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-17.png\" alt=\"\" class=\"wp-image-546642\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 18\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-17.png 184w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-17-141x300.png 141w\" sizes=\"auto, (max-width: 184px) 100vw, 184px\" \/><\/figure>\n\n\n\n<p>148 by 0.074 = 2000<\/p>\n\n\n\n<p>(iv) Given 7 by 0.014<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 1000 then divide<\/p>\n\n\n\n<p>= 7000\/14<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"139\" height=\"281\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-18.png\" alt=\"\" class=\"wp-image-546643\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 19\"\/><\/figure>\n\n\n\n<p>7 by 0.014 = 500<\/p>\n\n\n\n<p><strong>8. Divide:<\/strong><\/p>\n\n\n\n<p><strong>(i) 20 by 50<\/strong><\/p>\n\n\n\n<p><strong>(ii) 8 by 100<\/strong><\/p>\n\n\n\n<p><strong>(iii) 72 by 576<\/strong><\/p>\n\n\n\n<p><strong>(iv) 144 by 15<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>(i) Given 20 by 50<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"117\" height=\"221\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-19.png\" alt=\"\" class=\"wp-image-546644\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 20\"\/><\/figure>\n\n\n\n<p>20 by 50 = 0.4<\/p>\n\n\n\n<p>(ii) Given 8 by 100<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"138\" height=\"232\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-20.png\" alt=\"\" class=\"wp-image-546645\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 21\"\/><\/figure>\n\n\n\n<p>8 by 100 = 0.08<\/p>\n\n\n\n<p>(iii) Given 72 by 576<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"186\" height=\"341\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-21.png\" alt=\"\" class=\"wp-image-546646\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 22\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-21.png 186w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-21-164x300.png 164w\" sizes=\"auto, (max-width: 186px) 100vw, 186px\" \/><\/figure>\n\n\n\n<p>72 by 576 = 0.125<\/p>\n\n\n\n<p>(iv) Given 144 by 15<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"142\" height=\"285\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-22.png\" alt=\"\" class=\"wp-image-546647\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 23\"\/><\/figure>\n\n\n\n<p>144 by 15 = 9.6<\/p>\n\n\n\n<p><strong>9. A vehicle covers a distance 0f 43.2 km in 2.4 litres of petrol. How much distance will travel in 1 litre of petrol?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given distance covered by vehicle in 2.4 litres of petrol is = 43.2 km<\/p>\n\n\n\n<p>Distance travel by vehicle in 1 litre of petrol = 43.2\/2.4<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 10 then we get 432\/24<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"115\" height=\"224\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-23.png\" alt=\"\" class=\"wp-image-546648\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 24\"\/><\/figure>\n\n\n\n<p>Therefore 18km can travel in 1litre of petrol.<\/p>\n\n\n\n<p><strong>10. The total weight of some bags of wheat is 1743 kg. If each bag weighs 49.8 kg, how many bags are there?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given total weight of total bags = 1743 kg<\/p>\n\n\n\n<p>Each bag weighs = 49.8 kg<\/p>\n\n\n\n<p>Number of bags = 1743\/49.8<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 10 then we get 17430\/498<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"176\" height=\"335\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-24.png\" alt=\"\" class=\"wp-image-546649\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 25\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-24.png 176w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-24-158x300.png 158w\" sizes=\"auto, (max-width: 176px) 100vw, 176px\" \/><\/figure>\n\n\n\n<p>Therefore number of bags are 35<\/p>\n\n\n\n<p><strong>11. Shikha cuts 50 m of cloth into pieces 0f 1.25 m each. How many pieces does she get?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that total length of cloth = 50 m<\/p>\n\n\n\n<p>Length of each piece = 1.25 m<\/p>\n\n\n\n<p>Number of cloth piece = 50\/1.25<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 100 then we get 5000\/125<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"158\" height=\"280\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-25.png\" alt=\"\" class=\"wp-image-546650\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 26\"\/><\/figure>\n\n\n\n<p>Number of cloth piece = 40<\/p>\n\n\n\n<p><strong>12. Each side of a rectangular polygon is 2.5cm in length. The perimeter of the polygon is 12.5 cm. How many sides does the polygon have?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that length of each side of polygon is = 2.5 cm<\/p>\n\n\n\n<p>Perimeter of polygon = 12.5 cm<\/p>\n\n\n\n<p>Number of sides = 12.5\/2.5<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 10 then we get 125\/25<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"118\" height=\"223\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-26.png\" alt=\"\" class=\"wp-image-546651\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 27\"\/><\/figure>\n\n\n\n<p>Number of sides of polygon is 5<\/p>\n\n\n\n<p><strong>13. The product of two decimals is 42.987. If one of them is 12.46, find the other.<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that product of two decimals = 42.987<\/p>\n\n\n\n<p>One of the number is = 12.46<\/p>\n\n\n\n<p>Another number is = 42.987\/12.46<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 1000 then we get 42987\/12460<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"222\" height=\"385\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-27.png\" alt=\"\" class=\"wp-image-546652\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 28\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-27.png 222w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-27-173x300.png 173w\" sizes=\"auto, (max-width: 222px) 100vw, 222px\" \/><\/figure>\n\n\n\n<p>Another number is 3.45<\/p>\n\n\n\n<p><strong>14. The weight of 34 bags of sugar is 3483.3 kg. If all bags weigh equally, find the weight of each bag.<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that weight of 34 bags of sugar is = 3483.3 kg<\/p>\n\n\n\n<p>Weight of each bag = 3483.3\/34<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 10 then we get 34833\/34<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"189\" height=\"386\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-28.png\" alt=\"\" class=\"wp-image-546653\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 29\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-28.png 189w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-28-147x300.png 147w\" sizes=\"auto, (max-width: 189px) 100vw, 189px\" \/><\/figure>\n\n\n\n<p>Weight of each bag = 102.45 kg<\/p>\n\n\n\n<p><strong>15. How many buckets of equal capacity can be filled from 586.5 litres of water, if each has capacity of 8.5 litres?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Given that capacity of each bucket = 8.5 litres<\/p>\n\n\n\n<p>Total water available = 586.5 litres<\/p>\n\n\n\n<p>Number of buckets = 586.5\/8.5<\/p>\n\n\n\n<p>Multiply both numerator and denominator by 10 then we get 5865\/85<\/p>\n\n\n\n<p>On dividing<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"138\" height=\"279\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/rd-sharma-solutions-for-class-7-maths-chapter-3-de-29.png\" alt=\"\" class=\"wp-image-546654\" title=\"RD Sharma Solutions for Class 7 Maths Chapter 3 Decimals image 30\"\/><\/figure>\n\n\n\n<p>Number of buckets = 69<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-rd-sharma-solutions-for-class-7-maths-chapter-3-download-pdf\">RD Sharma Solutions for Class 7 Maths Chapter 3:&nbsp;<strong>Download PDF<\/strong><\/h2>\n\n\n\n<p>RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals<\/p>\n\n\n\n<p><a href=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/RD-Sharma-Solutions-for-Class-7-Maths-Chapter-3\u2013Decimals.pdf\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Download PDF<\/strong>: RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals PDF<\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Chapterwise RD Sharma Solutions for Class 7&nbsp;Maths :<\/strong><\/h2>\n\n\n\n<ul class=\"wp-block-list\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-1-integers\/\">Chapter 1\u2013Integers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-2-fractions\/\">Chapter 2\u2013Fractions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\">Chapter 3\u2013Decimals<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-4-rational-numbers\/\">Chapter 4\u2013Rational Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-5-operations-on-rational-numbers\/\">Chapter 5\u2013Operations On Rational Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-6-exponents\/\">Chapter 6\u2013Exponents<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-7-algebraic-expressions\/\">Chapter 7\u2013Algebraic Expressions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-8-linear-equations-in-one-variable\/\">Chapter 8\u2013Linear Equations in One Variable<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-9-ratio-and-proportion\/\">Chapter 9\u2013Ratio And Proportion<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-10-unitary-method\/\">Chapter 10\u2013Unitary Method<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-11-percentage\/\">Chapter 11\u2013Percentage<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-12-profit-and-loss\/\">Chapter 12\u2013Profit And Loss<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-13-simple-interest\/\">Chapter 13\u2013Simple Interest<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-14-lines-and-angles\/\">Chapter 14\u2013Lines And Angles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-15-properties-of-triangles\/\">Chapter 15\u2013Properties of Triangles<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-16-congruence\/\">Chapter 16\u2013Congruence<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-17-constructions\/\">Chapter 17\u2013Constructions<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-18-symmetry\/\">Chapter 18\u2013Symmetry<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-19-visualising-solid-shapes\/\">Chapter 19\u2013Visualising Solid Shapes<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-20-mensuration-i-perimeter-and-area-of-rectilinear-figures\/\">Chapter 20\u2013Mensuration \u2013 I (Perimeter and area of rectilinear figures)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-21-mensuration-ii-area-of-circle\/\">Chapter 21\u2013Mensuration \u2013 II (Area of Circle)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-22-data-handling-i-collection-and-organisation-of-data\/\">Chapter 22\u2013Data Handling \u2013 I (Collection and Organisation of Data)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-23-data-handling-ii-central-values\/\">Chapter 23\u2013Data Handling \u2013 II Central Values<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-24-data-handling-iii-constructions-of-bar-graphs\/\">Chapter 24\u2013Data Handling \u2013 III (Constructions of Bar Graphs)<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-25-data-handling-iv-probability\/\">Chapter 25\u2013Data Handling \u2013 IV (Probability)<\/a><\/li><\/ul>\n\n\n\n<h2 class=\"wp-block-heading\">About RD Sharma<\/h2>\n\n\n\n<p>RD Sharma i<em>sn&#8217;t the kind of author you&#8217;d bump into at lit fests. But his bestselling books have helped many&nbsp;<\/em>CBSE<em>&nbsp;students lose their dread of&nbsp;<\/em>maths<em>. Sunday Times profiles the tutor turned internet star<\/em><br>He dreams of algorithms that would give most people nightmares. And, spends every waking hour thinking of ways to explain concepts like &#8216;series solution of linear differential equations&#8217;. Meet Dr&nbsp;Ravi Dutt Sharma&nbsp;\u2014&nbsp;mathematics&nbsp;teacher and author of 25 reference books \u2014 whose name evokes as much awe as the subject he teaches. And though students have used his thick tomes for the last 31 years to ace the dreaded maths exam, it&#8217;s only recently that a spoof video turned the tutor into a YouTube star.<\/p>\n\n\n\n<p>R D Sharma had a good laugh but said he shared little with his on-screen persona except for the love for maths. &#8220;I like to spend all my time thinking and writing about maths problems. I find it relaxing,&#8221; he says. When he is not writing books explaining mathematical concepts for classes 6 to 12 and engineering students, Sharma is busy dispensing his duty as vice-principal and head of department of science and humanities at Delhi government&#8217;s Guru Nanak Dev Institute of Technology.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">Read More<\/h2>\n\n\n\n<ul class=\"wp-block-yoast-seo-related-links\"><li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-9th-class-maths-chapter-1-number-systems\/\">NCERT Solutions for 9th Class Maths :Chapter 1 Number Systems<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-9-maths-chapter-1-number-system\/\">RD Sharma Solutions for Class 9 Maths Chapter 1\u2013Number System<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-9-maths-chapter-3-rationalisation\/\">RD Sharma Solutions for Class 9 Maths Chapter 3\u2013Rationalisation<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-class-10th-mathematics-chapter-1-real-numbers\/\">NCERT Solutions for Class 10th Mathematics: Chapter 1 Real Numbers<\/a><\/li><li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-5th-class-maths-chapter-13-ways-to-multiply-and-divide\/\">NCERT Solutions for 5th Class Maths Chapter 13- Ways To Multiply And Divide<\/a><\/li><\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Class 7: Maths Chapter 3 solutions. Complete Class 7 Maths Chapter 3 Notes. RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals RD Sharma 7th Maths Chapter 3, Class 7 Maths Chapter 3 solutions Exercise 3.1 Page No: 3.4 1. Write each of the following as decimals: (i) (8\/100) (ii) 20 + (9\/10) + (4\/100) [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":546655,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,907],"tags":[1962],"boards":[],"class_list":["post-546622","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-7","tag-rd-sharma-solutions","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>RD Sharma Solutions for Class 7, maths Chapter 3 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals | Browse all Class 7 Maths Chapters RD Sharma books - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals\" \/>\n<meta property=\"og:description\" content=\"Class 7: Maths Chapter 3 solutions. Complete Class 7 Maths Chapter 3 Notes. RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals RD Sharma 7th Maths\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\" \/>\n<meta property=\"og:site_name\" content=\"IndCareer Schools\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/indcareer\" \/>\n<meta property=\"article:published_time\" content=\"2021-10-07T09:26:43+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2021-10-09T06:10:57+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/i0.wp.com\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/class7m3.png?fit=1200%2C675&ssl=1\" \/>\n\t<meta property=\"og:image:width\" content=\"1200\" \/>\n\t<meta property=\"og:image:height\" content=\"675\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"Pooja\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@indcareer\" \/>\n<meta name=\"twitter:site\" content=\"@indcareer\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Pooja\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"21 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\"},\"author\":{\"name\":\"Pooja\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/#\/schema\/person\/d6945cf059726f162259ba738092301e\"},\"headline\":\"RD Sharma Solutions for Class 7 Maths Chapter 3\u2013Decimals\",\"datePublished\":\"2021-10-07T09:26:43+00:00\",\"dateModified\":\"2021-10-09T06:10:57+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\"},\"wordCount\":2471,\"publisher\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/#organization\"},\"image\":{\"@id\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/10\/class7m3.png\",\"keywords\":[\"RD Sharma Solutions\"],\"articleSection\":[\"Book Solutions\",\"Class 7\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\",\"url\":\"https:\/\/www.indcareer.com\/schools\/rd-sharma-solutions-for-class-7-maths-chapter-3-decimals\/\",\"name\":\"RD Sharma Solutions for Class 7, maths Chapter 3 - 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