{"id":45053,"date":"2020-04-28T08:10:34","date_gmt":"2020-04-28T08:10:34","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=45053"},"modified":"2020-04-28T08:12:55","modified_gmt":"2020-04-28T08:12:55","slug":"cbse-solved-sample-papers-for-class-8-maths","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/cbse-solved-sample-papers-for-class-8-maths\/","title":{"rendered":"CBSE Solved Sample Papers for Class 8 \u2013 Maths"},"content":{"rendered":"\n<h2 class=\"wp-block-heading\">CBSE Solved Sample Papers for Class 8 for Maths&nbsp;\u2013 Second Term<\/h2>\n\n\n\n<p>CBSE&nbsp;Solved&nbsp;Sample Papers for Class 8 for Maths&nbsp;Subject (Term 2) &nbsp;is given below.&nbsp;The solved sample papers are created as per the latest CBSE syllabus and curriculum keeping in mind the latest marking scheme.<\/p>\n\n\n\n<p class=\"has-text-align-center\"><strong>SECTION \u2013 A<\/strong><\/p>\n\n\n\n<p>Q 1 The value of (5\u02da + 7<sup>-1<\/sup>)<sup>&nbsp;*<\/sup>&nbsp;7 are:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 35<br>(b)&nbsp;&nbsp; 36<br>(c)&nbsp;&nbsp;&nbsp; 8<br>(d)&nbsp;&nbsp; 84<\/p>\n\n\n\n<p>Ans (c)<\/p>\n\n\n\n<p>Q 2 Factories x<sup>2 +<\/sup>&nbsp;5x + 6:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; (x+3) (x+2)<br>(b)&nbsp;&nbsp; (x-3) (x+2)<br>(c)&nbsp;&nbsp;&nbsp; (x+3) (x- 2)<br>(d)&nbsp;&nbsp; All of above<\/p>\n\n\n\n<p>Ans (a)<\/p>\n\n\n\n<p>Q 3 A train is moving at a uniform speed of 80 km\/hr. How for it will travel in 15 minutes.<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 85 km<br>(b)&nbsp;&nbsp; 120km<br>(c)&nbsp;&nbsp;&nbsp; 20km<br>(d)&nbsp;&nbsp; 30km<\/p>\n\n\n\n<p>Ans (c)<\/p>\n\n\n\n<p>Q 4 (1.02)<sup>2<\/sup>&nbsp;\u2013 (0.98)<sup>2<\/sup>&nbsp;are equal to:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 0.04<br>(b)&nbsp;&nbsp; 0.08<br>(c)&nbsp;&nbsp;&nbsp; 0.8<br>(d)&nbsp;&nbsp; 2<\/p>\n\n\n\n<p>Ans (b)<\/p>\n\n\n\n<p>Q 5 what is the coordinate of point P on the graph:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 7<\/p>\n\n\n\n<p>(b)&nbsp;&nbsp; (7,0)<br>(c)&nbsp;&nbsp;&nbsp; (1,5)<br>(d)&nbsp;&nbsp; (0,7)<\/p>\n\n\n\n<p>Ans (d)<\/p>\n\n\n\n<p>Q 6 the cost of 5 pens is Rs. 25.50. What is the cost of 8 pens?<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 40.80<br>(b)&nbsp;&nbsp; 40<br>(c)&nbsp;&nbsp;&nbsp; 50<br>(d)&nbsp;&nbsp; 45.20<\/p>\n\n\n\n<p>Ans (a)<\/p>\n\n\n\n<p>Q 7 Which one of the following pair forms like terms:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 7x \u2013 5y<br>(b)&nbsp;&nbsp; 2x \u2013 3x<sup>2<\/sup><br>(c)&nbsp;&nbsp;&nbsp; 2\/3x \u2013 5\/7x<br>(d)&nbsp;&nbsp; 2\/5x \u2013 3xy<\/p>\n\n\n\n<p>Ans (c)<\/p>\n\n\n\n<p>Q 8 The relation between F,V and E are represented by Euler\u2019s formula as follows:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; F \u2013 V + E = 0<br>(b)&nbsp;&nbsp; F + E + V = 1<br>(c)&nbsp;&nbsp;&nbsp; F \u2013 V + E = 2<br>(d)&nbsp;&nbsp; F + V \u2013 E = 2<\/p>\n\n\n\n<p>Ans (d)<\/p>\n\n\n\n<p>Q 9 which one is binomial:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 4l + 5m<br>(b)&nbsp;&nbsp; 3x<sup>2<\/sup>\u2013 5x + 2<br>(c)&nbsp;&nbsp;&nbsp; 4 + 3\/x<br>(d)&nbsp;&nbsp; X + 1\/y<\/p>\n\n\n\n<p>Ans (a)<\/p>\n\n\n\n<p>Q 10 if the longer side of a trapezium is 10 cm and the distance between the parallel sides is 8 cm. The area is 50 cm<sup>2.&nbsp;<\/sup>What is the smaller parallel side?<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 10 cm<br>(b)&nbsp;&nbsp; 2 cm<br>(c)&nbsp;&nbsp;&nbsp; 2.5 cm<br>(d)&nbsp;&nbsp; 3.5 cm<\/p>\n\n\n\n<p>Ans (c)<\/p>\n\n\n\n<p><strong>SECTION \u2013 B<\/strong><\/p>\n\n\n\n<p>Q 11 How many sides of the following have?<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; Nonagon<br>(b)&nbsp;&nbsp; Octagon<\/p>\n\n\n\n<p>Ans<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; Nonagon: Nonagon has 9 sides.<br>(b)&nbsp;&nbsp; Octagon: octagon has 8 sides.<\/p>\n\n\n\n<p>Q 12 What is the volume of a cube with side 6 cm?<\/p>\n\n\n\n<p>Ans side of cube = 6 cm<\/p>\n\n\n\n<p>Volume of cube= side * side * side<\/p>\n\n\n\n<p>= (6 * 6 * 6) cm<\/p>\n\n\n\n<p>= 216 cm<sup>3&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<\/sup><\/p>\n\n\n\n<p>Q 13 Simplify (-5)<sup>-2<\/sup><\/p>\n\n\n\n<p>Ans (-5)<sup>-2<\/sup>&nbsp;= 1 \/ (-5)<sup>-2<\/sup>&nbsp;= 1\/-5 * -5<\/p>\n\n\n\n<p>=1 \/ 25<\/p>\n\n\n\n<p>Q 14 Find the value of:&nbsp;(2<sup>-1<\/sup>&nbsp;+ 4<sup>-1<\/sup>) \/ 2)<sup>-2<\/sup><\/p>\n\n\n\n<p>Ans (2<sup>-1<\/sup>&nbsp;+ 4<sup>-1<\/sup>) \/ 2)<sup>-2<\/sup><\/p>\n\n\n\n<p>= [1\/2+ \u00bc] \/ 1\/2<sup>2<\/sup><\/p>\n\n\n\n<p>= (2 + 1 \/ 4) \/ (1\/4)<\/p>\n\n\n\n<p>= (\u00be) \/ (1\/4)<\/p>\n\n\n\n<p>= \u00be * 4 = 3<\/p>\n\n\n\n<p>Q 15 Write 2 \u2013 dimensional or 3 \u2013 dimensional for the following shapes:<\/p>\n\n\n\n<p>Square, cone, circle, cylinder<\/p>\n\n\n\n<p>AnsSquare, circle = 2 \u2013 dimensional<\/p>\n\n\n\n<p>Cone, cylinder = 3 \u2013 dimensional<\/p>\n\n\n\n<p>Q 16 What formula would you use to calculate the area of a rectangle?<\/p>\n\n\n\n<p>AnsArea of a rectangle = length * breadth<\/p>\n\n\n\n<p>Q 17 what is range of the data?<\/p>\n\n\n\n<p>Ans The difference between the highest and the lowest values of the observation in a data is called the range of the data.<\/p>\n\n\n\n<p>Q 18 Evaluate (2\/3)<sup>-3<\/sup><\/p>\n\n\n\n<p>Ans(2\/3)<sup>-3 =<\/sup>&nbsp;(3\/2)<sup>3<\/sup><\/p>\n\n\n\n<p>= 3\/2 * 3\/2 * 3\/2<\/p>\n\n\n\n<p>= 27\/8<\/p>\n\n\n\n<p>SECTION \u2013 C<\/p>\n\n\n\n<p>Q 19 The lateral surface area of a hollow cylinder is 4224 cm<sup>2.&nbsp;<\/sup>It is cut along its height and formed a rectangle sheet of width 33 cm. Find the perimeter of the rectangle sheet.<\/p>\n\n\n\n<p>Ans lateral surface area of cylinder = 4224 cm<sup>2<\/sup><\/p>\n\n\n\n<p>Width of sheet (b) = 33 cm<\/p>\n\n\n\n<p>Length of sheet (l) = area\/width<\/p>\n\n\n\n<p>L = 4224\/33 = 128 cm<\/p>\n\n\n\n<p>Perimeter of sheet = 2(l + b)<\/p>\n\n\n\n<p>= 2 (128 + 33)<\/p>\n\n\n\n<p>= 2(161)<\/p>\n\n\n\n<p>= 322 cm<\/p>\n\n\n\n<p>Q 20 Factories 16x<sup>5<\/sup>&nbsp;\u2013 121x<sup>3<\/sup><\/p>\n\n\n\n<p>Ans&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 16x<sup>5<\/sup>&nbsp;\u2013 121x<sup>3<\/sup><\/p>\n\n\n\n<p>= x<sup>3<\/sup>(16x<sup>2<\/sup>\u2013 121)<\/p>\n\n\n\n<p>= x<sup>3<\/sup>[(4x)<sup>&nbsp;2<\/sup>\u2013 (11)<sup>2<\/sup>]<\/p>\n\n\n\n<p>= [(a<sup>&nbsp;2<\/sup>\u2013 b<sup>&nbsp;2)<\/sup>&nbsp;= (a +b) (a \u2013 b)]<\/p>\n\n\n\n<p>= x<sup>3<\/sup>[(4x + 11)\u2013 (4x \u2013 11)]<\/p>\n\n\n\n<p>Q 21 Find the value of 9<sup>-1<\/sup>&nbsp;* 5<sup>-3&nbsp;<\/sup>\/ 3<sup>-4<\/sup><\/p>\n\n\n\n<p>Ans 9<sup>-1<\/sup>&nbsp;* 5<sup>-3&nbsp;<\/sup>\/ 3<sup>-4<\/sup>= 3<sup>4<\/sup>&nbsp;* 5<sup>3<\/sup>&nbsp;\/ 9<\/p>\n\n\n\n<p>= 3<sup>4<\/sup>&nbsp;* 5<sup>3<\/sup>&nbsp;\/ 3<sup>2<\/sup><\/p>\n\n\n\n<p>= 3<sup>4 \u2013 2&nbsp;<\/sup>* 5<sup>3<\/sup><\/p>\n\n\n\n<p>= 3<sup>2<\/sup>&nbsp;* 5<sup>3<\/sup><\/p>\n\n\n\n<p>= (3 * 3) (5 * 5 * 5)<\/p>\n\n\n\n<p>= 9 * 125<\/p>\n\n\n\n<p>= 1125<\/p>\n\n\n\n<p>Q 22 A loaded truck travels 14 km in 25 minute. If the speed remains the same. How far can it ravel in 5 hours?<\/p>\n\n\n\n<p>AnsDistance covered in 25 minute = 14 km<\/p>\n\n\n\n<p>Distance covered in 1 minute = 14 \/ 25 km<\/p>\n\n\n\n<p>Distance covered in 5 hours = (5 hours = 5 * 60 = 300 minute)<\/p>\n\n\n\n<p>= 14 \/ 25 * 300<\/p>\n\n\n\n<p>= 14 * 12 = 168 km<\/p>\n\n\n\n<p>He can travel 168 km in 5 hours.<\/p>\n\n\n\n<p>Q 23 In a model of a ship, the mast is 9 cm high, while the mast of the actual ship is 12 m high. If the length of the ship is 28 m. How long is the mast on the ship?<\/p>\n\n\n\n<p>Ans The height of the mast and the length of the model ship are indirect proportion.<\/p>\n\n\n\n<p>Let x =length of model<\/p>\n\n\n\n<p>Y= length of ship<\/p>\n\n\n\n<p>X = 9 cm&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; , &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; y =12 cm<\/p>\n\n\n\n<p>X =?&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; ,&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; y = 28 cm<\/p>\n\n\n\n<p>X<sub>1<\/sub>\/y<sub>1&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<\/sub>= &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x<sub>2<\/sub>\/y<sub>2<\/sub><\/p>\n\n\n\n<p>9 \/ 12&nbsp;&nbsp;&nbsp;&nbsp; = &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; x<sub>2<\/sub>\/28<\/p>\n\n\n\n<p><sub>X2<\/sub>&nbsp;= 9 * 28 \/12<\/p>\n\n\n\n<p><sub>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; X2<\/sub>= 3 * 7s<\/p>\n\n\n\n<p><sub>X2<\/sub>&nbsp;= 21 cm<\/p>\n\n\n\n<p>Thus Model ship is 21 cm long.<\/p>\n\n\n\n<p>Q 24 Find the height of a cuboid whose base area is 180 cm<sup>2<\/sup>&nbsp;and volume is 900 cm<sup>3<\/sup>.<\/p>\n\n\n\n<p>Ans Base area of a cuboid = 180 cm<sup>2<\/sup><\/p>\n\n\n\n<p>Volume of a cuboid = 900 cm<sup>3<\/sup><\/p>\n\n\n\n<p>Height of a cuboid = volume\/base area<\/p>\n\n\n\n<p>= 900 \/ 180<\/p>\n\n\n\n<p>Thus height of a cuboid = 5 cm.<\/p>\n\n\n\n<p>Q 25 Using suitable identity, evaluate:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 1.05 * 0.95<\/p>\n\n\n\n<p>(b)&nbsp;&nbsp; 9.7 * 9.8<\/p>\n\n\n\n<p>Ans<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 1.05 * 0.95<\/p>\n\n\n\n<p>= (1 + 0.05)(1-0.05)<\/p>\n\n\n\n<p>= 1 \u2013 0.0025 = .9975<\/p>\n\n\n\n<p>(b)&nbsp;&nbsp; 9.7 * 9.8<\/p>\n\n\n\n<p>= (9 + .7) (9 + .8)<\/p>\n\n\n\n<p>= (9)<sup>2<\/sup>&nbsp;+ (.7 + .8) * 9 + (.7 * .8)<\/p>\n\n\n\n<p>=81 + (1.5) * 9 + (.56)<\/p>\n\n\n\n<p>= 95.06<\/p>\n\n\n\n<p>Q 26 multiply (2 \/ 3 xy) * (-9 \/ 10 x<sup>2<\/sup>y<sup>2<\/sup>)<\/p>\n\n\n\n<p>Ans (2 \/ 3 xy) * (-9 \/ 10 x<sup>2<\/sup>y<sup>2<\/sup>)<\/p>\n\n\n\n<p>= (2 \/ 3 * -9 \/ 10) xy * x<sup>2<\/sup>y<sup>2<\/sup><\/p>\n\n\n\n<p>= -3 \/ 5 x<sup>3<\/sup>y<sup>3<\/sup><\/p>\n\n\n\n<p>Q 27 Using identity solve 99<sup>2<\/sup><\/p>\n\n\n\n<p>Ans&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 99<sup>2<\/sup>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; = (100 \u2013 1)<sup>2<\/sup><\/p>\n\n\n\n<p>(a \u2013 b)<sup>&nbsp;2<\/sup>&nbsp; = a<sup>2<\/sup>&nbsp;+b<sup>2<\/sup>&nbsp;-2ab<\/p>\n\n\n\n<p>= (100)<sup>&nbsp;2<\/sup>&nbsp;+ (1)<sup>&nbsp;2<\/sup>&nbsp;\u2013 2(100) (1)<\/p>\n\n\n\n<p>= 10000 + 1 -200<\/p>\n\n\n\n<p>= 10001 \u2013 200<\/p>\n\n\n\n<p>= 9801<\/p>\n\n\n\n<p>Q 28 Subtract 3xy \u2013 5yz- 7zx from 5xy \u2013 2yz -2zx + 10xyz<\/p>\n\n\n\n<p>Ans (5xy \u2013 2yz -2zx + 10xyz) \u2013 (3xy \u2013 5yz- 7zx)<\/p>\n\n\n\n<p>= 5xy \u2013 2yz -2zx + 10xyz \u2013 3xy + 5yz + 7zx<\/p>\n\n\n\n<p>= 5xy \u2013 3xy \u2013 2yz + 5yz -2zx + 7zx + 10xyz<\/p>\n\n\n\n<p>= 2xy +3yz + 5zx +10xyz<\/p>\n\n\n\n<p>Q 29 A field is 60 m long and 24 m broad. In one corner of the filed, a pit which is 8 m long 6.5m broad and 4 m deep has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. Find the rise in the level of the filed.<\/p>\n\n\n\n<p>Ans area of the filed = (60 * 24) m<\/p>\n\n\n\n<p>= 1440 m<sup>2<\/sup><\/p>\n\n\n\n<p>Area of th pit = (8 * 6.5) m<\/p>\n\n\n\n<p>= 52m<sup>2<\/sup><\/p>\n\n\n\n<p>Area over the remaining part of the filed = (1440 \u2013 52) m<sup>2<\/sup><\/p>\n\n\n\n<p>= 1388 m<sup>2<\/sup><\/p>\n\n\n\n<p>Volume of earth dug out = 8 * 6.5 * 4<\/p>\n\n\n\n<p>= 208 m<sup>2<\/sup><\/p>\n\n\n\n<p>Rise in level = Volume of earth dug out\/area over the remaining part of filed<\/p>\n\n\n\n<p>=208\/1388 m<\/p>\n\n\n\n<p>= 208 * 100\/1388 cm<\/p>\n\n\n\n<p>= 10.4 cm<\/p>\n\n\n\n<p>Q 30 If x \u2013 1\/x = 6 find (x<sup>2<\/sup>&nbsp;+ 1 \/ x<sup>2<\/sup>) and x<sup>4<\/sup>&nbsp;+ 1 \/ x<sup>4<\/sup><\/p>\n\n\n\n<p>Ans x \u2013 1 \/ x = 6 = (x \u2013 1 \/ x)<sup>&nbsp;2<\/sup>&nbsp;= (6)2<\/p>\n\n\n\n<p>= x<sup>2<\/sup>&nbsp;+ 1 \/ x<sup>2<\/sup>\u2013 2 = 36<\/p>\n\n\n\n<p>= x<sup>2<\/sup>&nbsp;+ 1 \/ x<sup>2<\/sup>= 38<\/p>\n\n\n\n<p>=(x2 + 1 \/ x<sup>2)2<\/sup>= (38)<sup>2<\/sup><\/p>\n\n\n\n<p>= x<sup>4<\/sup>&nbsp;+ 1 \/ x<sup>4<\/sup>+ 2 = 1444<\/p>\n\n\n\n<p>= x<sup>4<\/sup>&nbsp;+ 1 \/ x<sup>4<\/sup>= 1444<\/p>\n\n\n\n<p>Q 31 A square park has been each side of 100 m. At each corner there is a flower bed in the form of a quadrant of radius 14m as shown in fig. Find the area of the remaining part of the park. (Take\u03c0 =22 \/ 7)<\/p>\n\n\n\n<p>AnsArea of each quadrant of radius = 14 cm<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"203\" height=\"187\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/28.png\" alt=\"\" class=\"wp-image-45054\"\/><\/figure>\n\n\n\n<p>= 1 \/ 4 (\u03c0r<sup>2<\/sup>)<\/p>\n\n\n\n<p>=1 \/ 4 \u03c0 * 14<sup>2<\/sup><\/p>\n\n\n\n<p>= 1 \/ 4 * 22 \/ 7 * 14 *14<\/p>\n\n\n\n<p>= 154 m<sup>2<\/sup><\/p>\n\n\n\n<p>Area of 4 quadrants = (4 * 154) m<sup>2<\/sup>&nbsp;= 616 m<sup>2<\/sup><\/p>\n\n\n\n<p>Side of square = 100 m<\/p>\n\n\n\n<p>Area of square = (100 * 100) m<sup>2<\/sup><\/p>\n\n\n\n<p>= 10000 m<sup>2<\/sup><\/p>\n\n\n\n<p>Area of the remaining part of the park<\/p>\n\n\n\n<p>= (1000 \u2013 616) m<sup>2<\/sup><\/p>\n\n\n\n<p>= 9384 m<sup>2<\/sup><\/p>\n\n\n\n<p>Q 32 Factories:<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 8x<sup>3<\/sup>&nbsp;\u2013 18 xy<sup>2<\/sup><\/p>\n\n\n\n<p>(b)&nbsp;&nbsp; 3x<sup>2<\/sup>&nbsp;+ 12x \u2013 36<\/p>\n\n\n\n<p>(c)&nbsp;&nbsp;&nbsp; X<sup>2<\/sup>&nbsp;+ 4xy +4y<sup>2<\/sup>&nbsp;\u2013 9z<sup>2<\/sup><\/p>\n\n\n\n<p>Ans<\/p>\n\n\n\n<p>(a)&nbsp;&nbsp;&nbsp; 8x<sup>3<\/sup>&nbsp;\u2013 18 xy<sup>2<\/sup><\/p>\n\n\n\n<p>= 2x (4x<sup>2<\/sup>&nbsp;\u2013 9y<sup>2<\/sup>)<\/p>\n\n\n\n<p>= 2x (2x + 3y) (2x \u2013 3y)&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; [By using a<sup>2<\/sup>&nbsp;\u2013 b<sup>2<\/sup>&nbsp;= (a + b) (a \u2013 b)]<\/p>\n\n\n\n<p>= 2x (2x + 3y) (2x \u2013 3y)<\/p>\n\n\n\n<p>(b)&nbsp;&nbsp; 3x<sup>2<\/sup>&nbsp;+ 12x \u2013 36<\/p>\n\n\n\n<p>= 3 (x<sup>2<\/sup>&nbsp;+ 4x \u2013 12)<\/p>\n\n\n\n<p>= 3 (x<sup>2<\/sup>&nbsp;+ 6x -2x \u2013 12)<\/p>\n\n\n\n<p>= 3 [x (x + 6) \u2013 2 (x + 6)]<\/p>\n\n\n\n<p>= 3 [(x \u2013 2) (x +6)]<\/p>\n\n\n\n<p>(c)&nbsp;&nbsp;&nbsp; &nbsp;X<sup>2<\/sup>&nbsp;+ 4xy +4y<sup>2<\/sup>&nbsp;\u2013 9z<sup>2<\/sup><\/p>\n\n\n\n<p>= (x<sup>2<\/sup>&nbsp;+ 4xy + 4y<sup>2<\/sup>) \u2013 9z<sup>2<\/sup><\/p>\n\n\n\n<p>= (x + 2y)<sup>&nbsp;2<\/sup>&nbsp;\u2013 (9z<sup>2<\/sup>)<\/p>\n\n\n\n<p>=(x +2y + 3z) (x + 2y -3z)<\/p>\n\n\n\n<p>= (x + 2y + 3z) (x + 2y \u2013 3z)<\/p>\n\n\n\n<p>Q 33 Subtract: 3a (a + b + c) -2b (a \u2013 b + c) from 4c (- a + b + c)<\/p>\n\n\n\n<p>Ans : <\/p>\n\n\n\n<p>3a (a + b + c) -2b (a \u2013 b + c) from 4c (- a + b + c)<\/p>\n\n\n\n<p>= 4c (- a + b + c) \u2013 [3a (a + b + c) -2b (a \u2013 b + c)]<\/p>\n\n\n\n<p>= \u2013 4ca + 4bc +4c<sup>2<\/sup>&nbsp;\u2013 [(3a<sup>2<\/sup>&nbsp;+ 3ab + 3ac) \u2013 2ba +2b<sup>2<\/sup>&nbsp;\u2013 2bc)]<\/p>\n\n\n\n<p>= \u2013 4ca + 4bc +4c<sup>2<\/sup>&nbsp;\u2013 [3a<sup>2<\/sup>&nbsp;+ 3ab + 3ac \u2013 2ba +2b<sup>2<\/sup>&nbsp;\u2013 2bc]<\/p>\n\n\n\n<p>= \u2013 4ca +4bc +4c<sup>2<\/sup>&nbsp;\u2013 [+ 3ac -2bc + 3a<sup>2<\/sup>&nbsp;+ 2b<sup>2<\/sup>&nbsp;+ 3ab]<\/p>\n\n\n\n<p>= \u2013 4ca +4bc +4c<sup>2<\/sup>&nbsp;\u2013 3ac +2bc \u2013 3a<sup>2<\/sup>&nbsp;\u2013 2b<sup>2<\/sup>&nbsp;\u2013 3ab<\/p>\n\n\n\n<p>= \u2013 7ac + 6bc \u2013 3a<sup>2<\/sup>&nbsp;\u2013 2b<sup>2<\/sup>&nbsp;+4c<sup>2<\/sup>&nbsp;\u2013 3ab<\/p>\n\n\n\n<p>= \u2013 7ac + 6bc \u2013 3ab \u2013 3a<sup>2<\/sup>&nbsp;\u2013 2b<sup>2<\/sup>&nbsp;+4c<sup>2<\/sup><\/p>\n\n\n\n<p>Q 34 Plot the graph from the following table. Is the graph linear?<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table><tbody><tr><td>Side of square (in cm)<\/td><td>2<\/td><td>3<\/td><td>3.5<\/td><td>5<\/td><td>6<\/td><\/tr><tr><td>Perimeter (in cm)<\/td><td>8<\/td><td>12<\/td><td>14<\/td><td>20<\/td><td>24<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>Ans<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"622\" height=\"513\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/29.png\" alt=\"\" class=\"wp-image-45057\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/29.png 622w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/29-300x247.png 300w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/29-327x270.png 327w\" sizes=\"auto, (max-width: 622px) 100vw, 622px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>CBSE Solved Sample Papers for Class 8 for Maths&nbsp;\u2013 Second Term CBSE&nbsp;Solved&nbsp;Sample Papers for Class 8 for Maths&nbsp;Subject (Term 2) &nbsp;is given below.&nbsp;The solved sample papers are created as per the latest CBSE syllabus and curriculum keeping in mind the latest marking scheme. SECTION \u2013 A Q 1 The value of (5\u02da + 7-1)&nbsp;*&nbsp;7 are: [&hellip;]<\/p>\n","protected":false},"author":295,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[58,16],"tags":[],"boards":[1181],"class_list":["post-45053","post","type-post","status-publish","format-standard","hentry","category-class-8","category-sample-papers","boards-cbse","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>CBSE Solved Sample Papers for Class 8 \u2013 Maths - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"CBSE Solved Sample Papers for 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