Question 12: Convert 72 cm into metre.<\/p>\n\n\n\n
Answer : 1 meter = 10 cm<\/p>\n\n\n\n
- 72 cm = 72\/100<\/li>
- 0.72 m ans.<\/li><\/ul>\n\n\n\n
Question 13: Find the sum:<\/p>\n\n\n\n
27.076 + 0.55 + 0.004<\/p>\n\n\n\n
Answer :<\/p>\n\n\n\n
- 27.076 + 0.55 + 0.004<\/li>
- 27,630 ans.<\/li><\/ul>\n\n\n\n
Question 14: Mr. Bansal spends Rs. X daily and saves Rs. Y per week what is his income for two weeks?<\/p>\n\n\n\n
Answer : Income for 1 week = Rs. (y + 7x)<\/p>\n\n\n\n
- Income for 2 week = Rs. 2(y + 7x)<\/li>
- Rs.(2y + 14x) ans.<\/li><\/ul>\n\n\n\n
Question 15: Arrange the following decimals in ascending order:<\/p>\n\n\n\n
0.8, 8.8, 8.08, 88.8, 0.08<\/p>\n\n\n\n
Answer : Decimals arranged in ascending order are:<\/p>\n\n\n\n
- 0.08, 0.8, 8.08, 8.8, 88.8<\/li><\/ul>\n\n\n\n
Question 16: Subtract 17\/6 from 33\/4<\/p>\n\n\n\n
Answer : 33\/4 \u2013 17\/6<\/p>\n\n\n\n
- (99 \u2013 34)\/12<\/li>
- 65\/12 ans.<\/li><\/ul>\n\n\n\n
Question 17: The side of a square is 14 cm, find its area.<\/p>\n\n\n\n
Answer : Side of a square = 14 cm<\/p>\n\n\n\n
- Area of square = (side)2<\/sup><\/li>
- (14 *14) = 196 cm2<\/sup> ans.<\/li><\/ul>\n\n\n\n
Question 18: Find the value of 12\/15 = 7\/15<\/p>\n\n\n\n
Answer : 12\/15 = 7\/15<\/p>\n\n\n\n
- (12 -7)\/15<\/li>
- 5\/15<\/li>
- 1\/3 ans.<\/li><\/ul>\n\n\n\n
Section \u2013 C<\/h3>\n\n\n\n
Question 19: These are 20 girls and 45 boys 1n a class<\/p>\n\n\n\n
- (a) What is the ratio of number of girls to the number of boys?<\/li>
- (b) What is the ratio of number of girls to total number of students in the class?<\/li><\/ul>\n\n\n\n
Answer : Number of girls = 20<\/p>\n\n\n\n
- Number of boys = 45<\/li>
- (a) ratio of number of girls to no. of boys = 20:45
4:9<\/li> - (b) Total no. of students in the class = 20 + 45 =85
Ratio of no. of girls to total no. of students = 20:85
4:17<\/li><\/ul>\n\n\n\nQuestion 20: The length and breadth of a rectangular field arc in the ratio 3:2 the cost of covering the field at Rs. 6.50 per meter is Rs. 520. Find the dimension of the field,<\/p>\n\n\n\n
Answer : Let the length =(3x)n<\/p>\n\n\n\n
- The breadth =(2x)m<\/li>
- Perimeter of the field = 2(3x + 2x)<\/li>
- (10x)m<\/li>
- According to question<\/li>
- Perimeter of the field = (Total cost)\/(Rate per meter)<\/li>
- 520\/6.5<\/li>
- 80m<\/li>
- Therefore, 10x = 80<\/li>
- X = 80\/10<\/li>
- 8<\/li>
- Dimension of the field will (3 *8)m and (2 * 8)m or 24m and 16m.<\/li><\/ul>\n\n\n\n
Question 21: A wire of length 7\/8 m is broken into two piece. If the length of 1 piece is 1\/4 m what is the length of other piece?<\/p>\n\n\n\n
Answer : Total length of wire = 7\/8 m<\/p>\n\n\n\n
- Length of one piece = 1\/4 m<\/li>
- Length of other piece =(7\/8 \u2013 1\/4)m<\/li>
- (7 \u2013 2)\/8<\/li>
- 5\/8 m<\/li><\/ul>\n\n\n\n
Question 22: Find the perimeter of the adjacent figure.<\/p>\n\n\n\n
![\"CBSE](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/66.png\" "\\"CBSE")
<\/figure>\n\n\n\nAnswer : Perimeter of figure =sum of all sides<\/p>\n\n\n\n
- (5 + 6.5 + 9 + 6) cm<\/li>
- 26.5 cm<\/li><\/ul>\n\n\n\n
Question 23: Solve (-2) + (8) + (-4) on the number line,<\/p>\n\n\n\n
Answer :\u00a0<\/p>\n\n\n\n
![\"\"](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/555.png\")
<\/figure>\n\n\n\nQuestion 24: Write coefficients of:<\/p>\n\n\n\n
(a) a in 5ab2<\/sup>c<\/p>\n\n\n\n
(b) ab in -5abc<\/p>\n\n\n\n
(c) y in -3xy<\/p>\n\n\n\n
Answer :<\/p>\n\n\n\n
(a) Coefficient of a in 5ab2<\/sup>c is 5b2<\/sup>c<\/p>\n\n\n\n
(b) Coefficient of ab in -5abc is -5c<\/p>\n\n\n\n
(c) Coefficient of y in -3xy is -3x<\/p>\n\n\n\n
Question 25: Draw the line symmetry for the following English alphabets:<\/p>\n\n\n\n
![\"CBSE](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/333.png\" "\\"CBSE")
<\/figure>\n\n\n\nAnswer :<\/p>\n\n\n\n
![\"CBSE](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/444.png\" "\\"CBSE")
<\/figure>\n\n\n\nQuestion 26: The cost of a pen is Rs. 19\/3 and that of a pencil is Rs. 21\/5, which costs more and by now much?<\/p>\n\n\n\n
Answer : The cost of a pen = Rs. 19\/3<\/p>\n\n\n\n
- The cost of a pencil = Rs. 21\/5<\/li>
- The cost of a pen is more = Rs. (19\/3 \u2013 21\/5)<\/li>
- (95 \u2013 63)\/15<\/li>
- 32\/15 ans.<\/li><\/ul>\n\n\n\n
Question 27: Urmila\u2019s school at a distance of 5 km 350m from her home, she travels 1 km 70 m on foot and rest by bus, How much distance does she travel by bus?<\/p>\n\n\n\n
Answer : Distance of school from home = 5 km 350 m<\/p>\n\n\n\n
- Distance covered on foot = 1km 70 m<\/li>
- Distance travelled by bus = (5 km 350 m \u2013 1 km 70 m)<\/li>
- 3 km 280 m ans.<\/li><\/ul>\n\n\n\n
Question 28: Express the following as an using decimals :<\/p>\n\n\n\n
(a) 2 mm
(b) 30 mm
(c) 4 cm 2 mm<\/p>\n\n\n\nAnswer :<\/p>\n\n\n\n
(a) 2\/10 cm = 0.2 cm
(b) 30\/10 = 3 cm
(c) 4 + 2\/10 = 4.2 cm<\/p>\n\n\n\nSection \u2013 D<\/h3>\n\n\n\n
Question 29: Dram any line segment . Mark any point M on it. Through M draw a perpendicular to . (Use ruler and compass)<\/p>\n\n\n\n
Answer :<\/p>\n\n\n\n
- \u00a0Step 1: Given a point M on the line \u2013 segment .<\/li>
- Step 2: with M as center and a convenient radius, construct part of cicrcle(arc) intersecting the line \u2013 segment at P and Q<\/li><\/ul>\n\n\n\n
![\"\"](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2020\/04\/12.png\")
<\/figure>\n\n\n\n- \u00a0Step 3: with pand Q as center and radius greater than pm construct two arcs.<\/li>
- Step 4: Join MN. Then MN is perpendicular to .<\/li><\/ul>\n\n\n\n
Question 30: Add the following<\/p>\n\n\n\n
(a) 25\/8 + 17\/12
(b) 11\/3 + 11\/6 + 2<\/p>\n\n\n\nAnswer :<\/p>\n\n\n\n
(a) 25\/8 + 7\/12<\/p>\n\n\n\n
- (75 + 34)\/24<\/li>
- 109\/24 ans.<\/li><\/ul>\n\n\n\n
(b) 11\/3 + 11\/6 + 2<\/p>\n\n\n\n
- (22 + 11 + 12)\/6<\/li>
- 45\/6<\/li>
- 5\/12 ans.<\/li><\/ul>\n\n\n\n
Question 31: A marble file measures 25 cm by 15 cm. how many tiles will he required to cover floor of dimensions of 10 m and 3 m?<\/p>\n\n\n\n
Answer : Area of floor 10m * 3m<\/p>\n\n\n\n
- 30m2<\/sup><\/li>
- Area of tile = 25 cm * 15 cm<\/li>
- 375 cm2<\/sup><\/li>
- No. of tiles = (Area of floor) \/(Area of tile)<\/li>
- (30 * 100 * 100)\/375 cm2<\/sup><\/li>
- 800 tiles ans.<\/li><\/ul>\n\n\n\n
Question 32: Cost of 4 dozens bananas is Rs. 60. How many bananas can be purchased for Rs.12.50?<\/p>\n\n\n\n
Answer : In Rs. 60 no. of bananas purchased = 48<\/p>\n\n\n\n
- In Rs. 1 no. of bananas purchased 48\/60<\/li>
- In Rs. 12.50 no. of bananas purchased = 40\/60 *12.50<\/li>
- 4\/5 * 1250\/100<\/li>
- 2*5<\/li>
- 10 bananas<\/li><\/ul>\n\n\n\n
Question 33: Find the cost of fencing a rectangular pack of length 175m and breadth 125m at the rate of Rs. 12 per meter.<\/p>\n\n\n\n
Answer : Length of the rectangular park = 175m<\/p>\n\n\n\n
- Breadth of the rectangular park = 125m<\/li>
- Perimeter of park = 2(l + b)<\/li>
- 2(175 + 125)m<\/li>
- 2 * 300<\/li>
- 600m<\/li>
- Cost of one meter of wire = Rs. 12<\/li>
- Cost of fencing the rectangular park = Rs. 12 * 600m<\/li>
- Rs. 7200 ans.<\/li><\/ul>\n\n\n\n
Question 34: Give expressions in the following cases:<\/p>\n\n\n\n
(a) 11 added to 2m
(b) 5 times y to which 5 is added
(c) 3 times y from which 3 is subtracted
(d) 11 subtracted from 2m<\/p>\n\n\n\nAnswer :<\/p>\n\n\n\n
(a) 2m + 11
(b) 5y + 5
(c) 3y \u2013 3
(d) 2m \u2013 11<\/p>\n\n\n\n<\/p>\n","protected":false},"excerpt":{"rendered":"
CBSE Solved Sample Papers for Class 6 for Maths CBSE Solved Sample Papers for Class 6 for Maths Subject is given below.\u00a0The solved sample papers are created as per the latest CBSE syllabus and curriculum keeping in mind the latest marking schemes. Section \u2013 A Question 1 : 2\/5 + 3\/5 + 11\/20 is equal […]<\/p>\n","protected":false},"author":295,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[876,16],"tags":[],"boards":[1181],"class_list":["post-45011","post","type-post","status-publish","format-standard","hentry","category-class-6","category-sample-papers","boards-cbse","entry"],"yoast_head":"\n
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- 30m2<\/sup><\/li>
- (14 *14) = 196 cm2<\/sup> ans.<\/li><\/ul>\n\n\n\n
- Area of square = (side)2<\/sup><\/li>
- 0.08, 0.8, 8.08, 8.8, 88.8<\/li><\/ul>\n\n\n\n