{"id":177174,"date":"2021-02-26T11:42:25","date_gmt":"2021-02-26T11:42:25","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=177174"},"modified":"2023-09-21T08:57:47","modified_gmt":"2023-09-21T08:57:47","slug":"ncert-solutions-for-12th-class-chemistry-chapter-3-electrochemistry","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-3-electrochemistry\/","title":{"rendered":"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry"},"content":{"rendered":"\n<p>Class 12: Chemistry Chapter 3 solutions. Complete Class 12 Chemistry Chapter 3 Notes.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ncert-solutions-for-12th-class-chemistry-chapter-3-electrochemistry\"><strong>NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry<\/strong><\/h2>\n\n\n\n<p>NCERT 12th Chemistry Chapter 3, class 12 Chemistry chapter 3 solutions<\/p>\n\n\n\n<p><strong>3.1. Arrange the following metals in the order in which they displace each other from their salts.<\/strong><br>Al, Cu, Fe, Mg and Zn<br><strong>Sol:<\/strong>&nbsp;Mg, Al, Zn, Fe, Cu.<\/p>\n\n\n\n<p><strong>3.2. Given the standard electrode potentials, K<sup>+<\/sup>\/K=-2. 93 V, Ag<sup>+<\/sup>\/Ag = 0.80 V, Hg<sup>2+<\/sup>\/Hg =0.79V, Mg<sup>2+<\/sup>\/Mg=-2.37V, Cr<sup>3+<\/sup>\/Cr=0.74V.<\/strong><br><strong>Arrange these metals in their increasing order of reducing power.<\/strong><br><strong>Sol:<\/strong>&nbsp;Higher the oxidation potential more easily it is oxidized and hence greater is the reducing power. Thus, increasing order of reducing power will be Ag&lt;Hg&lt;Cr&lt;Mg&lt;K.<\/p>\n\n\n\n<p><strong>3.3. Depict the galvanic cell in which the reaction<\/strong><br><strong>Zn(s) + 2Ag<sup>+<\/sup>(aq) \u2014-&gt; 7M<sup>2+<\/sup>(aq) + 2Ag (s) takes place. Further show:<\/strong><br><strong>(i) Which of the electrode is negatively charged?<\/strong><br><strong>(ii) The carriers of the current in the cell.<\/strong><br><strong>(iii) Individual reaction at each electrode.<\/strong><br><strong>Sol.<\/strong>&nbsp;The set-up will be similar to as shown below,<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"364\" height=\"239\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q3-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.3\" class=\"wp-image-527335\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q3-1.png 364w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q3-1-300x197.png 300w\" sizes=\"auto, (max-width: 364px) 100vw, 364px\" \/><\/figure>\n\n\n\n<p><br>(i) Anode, i. e, zinc electrode will be negatively charged.<br>(ii) The current will flow from silver to copper in the external circuit.<br>(iii) At anode: Zn(s) \u2014\u2014\u2013&gt; Zn<sup>2+<\/sup>(aq) + 2e<sup>\u2013<\/sup><br>At cathode: 2Ag<sup>+<\/sup>(aq) + 2e<sup>\u2013<\/sup>&nbsp;\u2014\u2014\u2013&gt; 2Ag(s)<\/p>\n\n\n\n<p><strong>3.4. Calculate the standard cell potentials of the galvanic cells in which the following reactions take place.<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"452\" height=\"143\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.4\" class=\"wp-image-527336\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-1.png 452w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-1-300x95.png 300w\" sizes=\"auto, (max-width: 452px) 100vw, 452px\" \/><\/figure>\n\n\n\n<p><br>Also calculate \u2206G\u00b0 and equilibrium constant for the reaction. (C.B.S.E. Outside Delhi 2008)<br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"452\" height=\"143\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-2.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.4\" class=\"wp-image-527338\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-2.png 452w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4-2-300x95.png 300w\" sizes=\"auto, (max-width: 452px) 100vw, 452px\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q4.1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.4\" class=\"wp-image-114503\"\/><\/figure>\n\n\n\n<p><strong>3.5. Write the Nernst equation and emf of the following cells at 298 K:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"328\" height=\"131\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.5\" class=\"wp-image-527339\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5-1.png 328w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5-1-300x120.png 300w\" sizes=\"auto, (max-width: 328px) 100vw, 328px\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"321\" height=\"422\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.5\" class=\"wp-image-527340\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-1.png 321w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-1-228x300.png 228w\" sizes=\"auto, (max-width: 321px) 100vw, 321px\" \/><\/figure>\n\n\n\n<p><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"321\" height=\"422\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-2.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.5\" class=\"wp-image-527341\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-2.png 321w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.1-2-228x300.png 228w\" sizes=\"auto, (max-width: 321px) 100vw, 321px\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.3.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.5\" class=\"wp-image-114507\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q5.4.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.5\" class=\"wp-image-114508\"\/><\/figure>\n\n\n\n<h5 class=\"wp-block-heading\" id=\"h-ncert-12th-chemistry-chapter-3-class-12-chemistry-chapter-3-solutions\">NCERT 12th Chemistry Chapter 3, class 12 Chemistry chapter 3 solutions<\/h5>\n\n\n\n<p><strong>3.6. In the button cells widely used in watches and other devices the following reaction takes place:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"324\" height=\"135\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.6\" class=\"wp-image-527342\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6-1.png 324w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6-1-300x125.png 300w\" sizes=\"auto, (max-width: 324px) 100vw, 324px\" \/><\/figure>\n\n\n\n<p><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"311\" height=\"134\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6.1-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.6\" class=\"wp-image-527343\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6.1-1.png 311w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q6.1-1-300x129.png 300w\" sizes=\"auto, (max-width: 311px) 100vw, 311px\" \/><\/figure>\n\n\n\n<p><strong>3.7. Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration.<\/strong><br><strong>Sol:&nbsp;<\/strong>The reciprocal of resistivity is known as specific conductance or simply conductivity. It is denoted by K (kappa). Thus, if K is the specific conductance and G is the conductance of the solution, then<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"340\" height=\"52\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.7\" class=\"wp-image-527344\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7-1.png 340w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7-1-300x46.png 300w\" sizes=\"auto, (max-width: 340px) 100vw, 340px\" \/><\/figure>\n\n\n\n<p><br>Now, if I = 1 cm and A = 1 sq.cm, then K = G.<\/p>\n\n\n\n<p>Hence, conductivity of a solution is defined as the conductance of a solution of 1 cm length and having 1 sq. cm as the area of cross-section. Alternatively, it may be defined as conductance of one centimetre cube of the solution of the electrolyte.<\/p>\n\n\n\n<p>Molar conductivity of a solution at a dilution V is the conductance of all the ions produced from 1 mole of the electrolyte dissolved in V cm<sup>3<\/sup>&nbsp;of the solution when the electrodes are one cm apart and the area of the electrodes is so large that the whole of the solution is contained between them. It is represented by \u2206<sub>m<\/sub>.<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"354\" height=\"129\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7.1-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.7\" class=\"wp-image-527345\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7.1-1.png 354w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q7.1-1-300x109.png 300w\" sizes=\"auto, (max-width: 354px) 100vw, 354px\" \/><\/figure>\n\n\n\n<p><br>Variation of conductivity and molar conductivity with concentration: Conductivity always decreases with decrease in concentration, for both weak and strong electrolytes. This is because the number of ions per unit volume that carry the current in a solution decreases on dilution.<\/p>\n\n\n\n<p>Molar conductivity increases with decrease in concentration. This is because that total volume, V, of solution containing one mole of electrolyte also increases. It has been found that decrease in K on dilution of a solution is more than compensated by increase in its volume.<\/p>\n\n\n\n<p><strong>3.8. The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm<sup>-1<\/sup>. Calculate its molar conductivity.<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"275\" height=\"86\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q8-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.8\" class=\"wp-image-527346\"\/><\/figure>\n\n\n\n<p><strong>3.9. The resistance of a conductivity cell containing 0.001 M KCI solution at 298 K is 1500 \u03a9 What is the cell constant if conductivity of 0.001 M KCI solution at 298 K is 0.146 x 10<sup>-3<\/sup>&nbsp;S cm<sup>-1<\/sup>?<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"323\" height=\"116\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q9-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.9\" class=\"wp-image-527347\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q9-1.png 323w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q9-1-300x108.png 300w\" sizes=\"auto, (max-width: 323px) 100vw, 323px\" \/><\/figure>\n\n\n\n<p><strong>3.10. The conductivity of NaCl at 298 K has been determined at different concentrations and the results are given below:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"710\" height=\"98\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.10\" class=\"wp-image-527348\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10-1.png 710w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10-1-300x41.png 300w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10-1-706x97.png 706w\" sizes=\"auto, (max-width: 710px) 100vw, 710px\" \/><\/figure>\n\n\n\n<p><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"266\" height=\"54\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10.1-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.10\" class=\"wp-image-527349\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q10.2.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.10\" class=\"wp-image-114517\"\/><\/figure>\n\n\n\n<p><strong>3.11. Conductivity of 0.00241 M acetic acid is 7.896 x 10<sup>-5<\/sup>&nbsp;S cm<sup>-1<\/sup>. Calculate its molar conductivity.&nbsp;If \u039b<sub>m0<\/sub>, for acetic acid is 390.5 S cm<sup>2<\/sup>&nbsp;mol<sup>-1<\/sup>, what is its dissociation constant?<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"312\" height=\"211\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q11-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.11\" class=\"wp-image-527350\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q11-1.png 312w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q11-1-300x203.png 300w\" sizes=\"auto, (max-width: 312px) 100vw, 312px\" \/><\/figure>\n\n\n\n<p><strong>3.12. How much charge is required for the following reductions:<\/strong><br><strong>(i) 1 mol of Al<sup>3+<\/sup>&nbsp;to Al?<\/strong><br><strong>(ii) 1 mol of Cu<sup>2+<\/sup>&nbsp;to Cu ?<\/strong><br><strong>(iii) 1 mol of Mn04- to Mn<sup>2+<\/sup>?<\/strong><br><strong>Sol:<\/strong>&nbsp;(i) The electrode reaction is Al<sup>3+<\/sup>&nbsp;+ 3e \u2014\u2014&gt; Al<br>\u2234 Quantity of charge required for reduction of 1 mol of Al<sup>3+<\/sup>=3F=3 x 96500C=289500C.<br>(ii) The electrode reaction is Cu<sup>2+<\/sup>&nbsp;+ 2e<sup>\u2013<\/sup>&nbsp;\u2014\u2014\u2013&gt; Cu<br>\u2234 Quantity of charge required for reduction of 1 mol of Cu<sup>2+<\/sup>=2F=2 x 96500=193000 C.<br>(iii) The electrode reaction is Mn04- \u2014\u2014\u2014-&gt; Mn<sup>2+<\/sup>.<br>i.e., Mn<sup>7+<\/sup>&nbsp;+ 5e<sup>\u2013<\/sup>\u2014\u2014-&gt; Mn<sup>2+<\/sup>.<br>\u2234 Quantity of charge required = 5F<br>=5 x 96500 C=4825000.<\/p>\n\n\n\n<p><strong>3.13. How much electricity in terms of Faraday is required to produce :<\/strong><br><strong>(i) 20\u00b70 g of Ca from molten CaCl<sub>2<\/sub><\/strong><br><strong>(ii) 40\u00b70 g of Al from molten Al<sub>2<\/sub>O<sub>3<\/sub>&nbsp;?<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"289\" height=\"53\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q13-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.13\" class=\"wp-image-527351\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q13.1-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.13\" class=\"wp-image-114520\"\/><\/figure>\n\n\n\n<p><strong>3.14. How much electricity is required in coulomb for the oxidation of (i) 1 mol of H<sub>2<\/sub>O to 0<sub>2<\/sub>&nbsp;(ii) 1 mol of FeO to Fe<sub>2<\/sub>0<sub>3<\/sub><\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"330\" height=\"283\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q14-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.14\" class=\"wp-image-527352\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q14-1.png 330w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q14-1-300x257.png 300w\" sizes=\"auto, (max-width: 330px) 100vw, 330px\" \/><\/figure>\n\n\n\n<p><strong>3.15. A solution of Ni(N0<sub>3<\/sub>)<sub>2<\/sub>&nbsp;is electrolyzed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"293\" height=\"198\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q15-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.15\" class=\"wp-image-527353\"\/><\/figure>\n\n\n\n<p><strong>3.16. Three electrolytic cells A, B, C containing solutions of ZnS0<sub>4<\/sub>, AgNO<sub>3<\/sub>&nbsp;and CuS0<sub>4<\/sub>, respectively are connected in series. A steady current of 1.5 amperes was passed through them until 45 g of silver deposited at the cathode of call B. How long did the current flow? What mass of copper and zinc were deposited?<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"339\" height=\"594\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q16-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.16\" class=\"wp-image-527354\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q16-1.png 339w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q16-1-171x300.png 171w\" sizes=\"auto, (max-width: 339px) 100vw, 339px\" \/><\/figure>\n\n\n\n<p><strong>3.17. Using the standard electrode potentials given in the table, predict if the reaction between the following is feasible.<\/strong><br><strong>(a) Fe<sup>3+<\/sup>(aq) and I<sup>\u2013<\/sup>(aq)<\/strong><br><strong>(b) Ag<sup>+<\/sup>(aq) and Cu(s)<\/strong><br><strong>(c) Fe<sup>3+<\/sup>(aq) and Br<sup>\u2013<\/sup>(aq)<\/strong><br><strong>(d) Ag(s) and Fe<sup>3+<\/sup>(aq)<\/strong><br><strong>(e) Br<sub>2<\/sub>(aq) and Fe<sup>2+<\/sup>(aq).<\/strong><br><strong>Sol:<\/strong><br>A particular reaction can be feasible if e.m.f. of the cell based on the E\u00b0 values is positive. Keeping this in mind, let us predict the feasibility of the reactions.<br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"534\" height=\"276\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q17-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.17\" class=\"wp-image-527355\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q17-1.png 534w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q17-1-300x155.png 300w\" sizes=\"auto, (max-width: 534px) 100vw, 534px\" \/><\/figure>\n\n\n\n<p><strong>3.18. Predict the products of electrolysis in each of the following.<\/strong><br><strong>(i) An aqueous solution of AgNO<sub>3<\/sub>&nbsp;with silver electrodes.<\/strong><br><strong>(ii) An aqueous solution of AgNO<sub>3<\/sub>&nbsp;with platinum electrodes.<\/strong><br><strong>(iii) A dilute solution of H<sub>2<\/sub>S0<sub>4<\/sub>&nbsp;with platinum electrodes.<\/strong><br><strong>(iv) An aqueous solution of CuCl<sub>2<\/sub>&nbsp;with platinum electrodes.<\/strong><br><strong>Sol:<\/strong><br><\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"325\" height=\"52\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q18-1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.18\" class=\"wp-image-527356\" srcset=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q18-1.png 325w, https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/07\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q18-1-300x48.png 300w\" sizes=\"auto, (max-width: 325px) 100vw, 325px\" \/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q18.1.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.18\" class=\"wp-image-114526\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/03\/NCERT-Solutions-For-Class-12-Chemistry-Chapter-3-Electrochemistry-Exercises-Q18.2.png\" alt=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry Ex.3.18\" class=\"wp-image-114527\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ncert-solutions-for-12th-class-chemistry-chapter-3-nbsp-download-pdf\">NCERT Solutions for 12th Class Chemistry: Chapter 3:&nbsp;<strong>Download PDF<\/strong><\/h2>\n\n\n\n<p>NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry<\/p>\n\n\n\n<p><a href=\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/08\/NCERT-Solutions-for-12th-Class-Chemistry_-Chapter-3-Electrochemistry.pdf\"><strong>Download PDF<\/strong>: NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry PDF<\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-chapterwise-ncert-solutions-for-class-12-chemistry\"><strong>Chapterwise NCERT Solutions for Class 12 Chemistry<\/strong>:<\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-1-the-solid-state\/\">Chapter 1 : The Solid State<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-2-solutions\/\">Chapter 2 : Solutions<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-3-electrochemistry\/\">Chapter 3 Electrochemistry<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-4-chemical-kinetics\/\">Chapter 4 : Chemical Kinetics<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-5-surface-chemistry\/\">Chapter 5 : Surface chemistry<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-6-general-principles-and-processes-of-isolation-of-elements\/\">Chapter 6 : General Principles and Processes of Isolation of Elements<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-7-the-p-block-elements\/\">Chapter 7 : The p Block Elements<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-8-the-d-and-f-block-elements\/\">Chapter 8 : The d and f Block Elements<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-9-coordination-compounds\/\">Chapter 9 : Coordination Compounds<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-10-haloalkanes-and-haloarenes\/\">Chapter 10 : Haloalkanes and Haloarenes<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-11-alcohols-phenols-and-ether\/\">Chapter 11 : Alcohols Phenols and Ether<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-12-aldehydes-ketones-and-carboxylic-acids\/\">Chapter 12 : Aldehydes Ketones and Carboxylic Acids<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistrychapter-13-amines\/\">Chapter 13 : Amines<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistrychapter-14-biomolecules\/\">Chapter 14 : Biomolecules<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistrychapter-15-polymers\/\">Chapter 15 : Polymers<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistrychapter-16-chemistry-in-everyday-life\/\">Chapter 16 : Chemistry in Everyday Life<\/a><\/li>\n<\/ul>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-about-ncert\">About NCERT<\/h2>\n\n\n\n<p>The National Council of Educational Research and Training is an autonomous organization of the Government of India which was established in 1961 as a literary, scientific, and charitable Society under the Societies Registration Act. Its headquarters are located at Sri Aurbindo Marg in New Delhi. <a href=\"https:\/\/ncert.nic.in\/\" target=\"_blank\" rel=\"noreferrer noopener\">Visit the Official NCERT website<\/a> to learn more. <\/p>\n\n\n\n<div class=\"wp-block-buttons is-layout-flex wp-block-buttons-is-layout-flex\">\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions\/\">NCERT Solutions<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-class-xii\/\">NCERT Solutions for Class 12<\/a><\/div>\n\n\n\n<div class=\"wp-block-button\"><a class=\"wp-block-button__link has-primary-background-color has-background wp-element-button\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-class-12-chemistry\/\">NCERT Solutions for Class 12 <strong>Chemistry<\/strong><\/a><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Class 12: Chemistry Chapter 3 solutions. Complete Class 12 Chemistry Chapter 3 Notes. NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry NCERT 12th Chemistry Chapter 3, class 12 Chemistry chapter 3 solutions 3.1. Arrange the following metals in the order in which they displace each other from their salts.Al, Cu, Fe, Mg and ZnSol:&nbsp;Mg, Al, [&hellip;]<\/p>\n","protected":false},"author":302,"featured_media":628554,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"newspack_featured_image_position":"","newspack_post_subtitle":"","newspack_article_summary_title":"Overview:","newspack_article_summary":"","newspack_hide_updated_date":false,"newspack_show_updated_date":false,"footnotes":""},"categories":[1411,25],"tags":[1560],"boards":[1180],"class_list":["post-177174","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-book-solutions","category-class-12","tag-ncert-chemistry-class-12","boards-ncert","entry"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.0 (Yoast SEO v27.1.1) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Solutions for Class 12, Chemistry Chapter 3 - IndCareer Schools<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry | Browse all Class 12 Chemistry Chapters NCERT book - IndCareer Schools\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-12th-class-chemistry-chapter-3-electrochemistry\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for 12th Class Chemistry: Chapter 3-Electrochemistry\" \/>\n<meta property=\"og:description\" content=\"Class 12: Chemistry Chapter 3 solutions. 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