NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n
Exercise 7.1<\/h2>\n\n\n\n
1. Write the fraction representing the shaded portion:<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (i)2\/4 <\/p>\n\n\n\n (ii) 8\/9 <\/p>\n\n\n\n (iii) 4\/8 <\/p>\n\n\n\n (iv)1\/4 <\/p>\n\n\n\n (v)3\/7<\/p>\n\n\n\n (vi)9\/12 <\/p>\n\n\n\n (vii)10\/10 <\/p>\n\n\n\n (viii)4\/9 <\/p>\n\n\n\n (ix)4\/8 <\/p>\n\n\n\n (x)1\/2<\/p>\n\n\n\n 2. Colour the part according to the given fraction:<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n 3. Identify the error, if any?<\/strong> Answer<\/strong> 4. What fraction of a day is 8 hours?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Since, 1 day = 24 hours.<\/p>\n\n\n\n Therefore, the fraction of 8 hours = 8\/24=1\/3<\/p>\n\n\n\n 5. What fraction of an hour is 40 minutes?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Since, 1 hour = 60 minutes.<\/p>\n\n\n\n Therefore, the fraction of 40 minutes = 40\/60=2\/3<\/p>\n\n\n\n 6. Arya, Abhimanyu and Vivek shared lunch. Arya has brought two sandwiches, one made of vegetable and one of jam. The other two boys forgot to bring their lunch. Arya agreed to share his sandwiches so that each person will have an equal share of each sandwich.<\/strong><\/p>\n\n\n\n (a)How can Arya divide his sandwiches so that each person has an equal share?<\/strong><\/p>\n\n\n\n (b)What part of a sandwich will each boy receive?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) Arya will divide each sandwich into three equal parts and give one part of each sandwich to each one of them.<\/p>\n\n\n\n (b) 1\u00d71\/3=1\/3<\/p>\n\n\n\n 7. Kanchan dyes dresses. She had to dye 30 dresses. She has so far finished 20 dresses. What fraction of dresses has she finished?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total number of dresses to dye= 30<\/p>\n\n\n\n Work completed = 20<\/p>\n\n\n\n Fraction of completed work = 20\/30=2\/3<\/p>\n\n\n\n 8. Write the natural numbers from 2 to 12. What fraction of them are prime numbers?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Natural numbers from 2 to 12: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12<\/p>\n\n\n\n Prime numbers from 2 to 12: 2, 3, 5, 7, 11<\/p>\n\n\n\n Hence, fraction of prime numbers = 5\/11<\/p>\n\n\n\n 9. Write the natural numbers from 102 to 113. What fraction of them are prime numbers?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Natural numbers from 102 to 113: 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113<\/p>\n\n\n\n Prime numbers from 102 to 113: 103, 107, 109, 113<\/p>\n\n\n\n Hence fraction of prime numbers = 4\/12=1\/3<\/p>\n\n\n\n 10. What fraction of these circles has \u2018X\u2019s in them?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total number of circles = 8 and number of circles having \u2018X\u2019 = 4<\/p>\n\n\n\n Hence, the fraction = 4\/8<\/p>\n\n\n\n 11. Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others as gifts. What fraction of her total CDs did she buy and what fraction did she receive as gifts?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total number of CDs = 3 + 5 = 8<\/p>\n\n\n\n Number of CDs purchased = 3<\/p>\n\n\n\n Fraction of CDs purchased = 3\/8<\/p>\n\n\n\n Fraction of CDs received as gifts = 5\/8<\/p>\n\n\n\n 1. Draw number lines and locate the points on them:<\/strong><\/p>\n\n\n\n (a)1\/2,1\/4,3\/4,4\/4<\/p>\n\n\n\n (b)1\/8,2\/8,3\/8,7\/8<\/p>\n\n\n\n (c)2\/5,3\/5,8\/5,4\/5<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n 2. Express the following fractions as mixed fractions:<\/strong><\/p>\n\n\n\n (a)20\/3 <\/p>\n\n\n\n (b)11\/5 <\/p>\n\n\n\n (c)17\/7 <\/p>\n\n\n\n (d)28\/5<\/p>\n\n\n\n (e)19\/6 <\/p>\n\n\n\n (f)35\/9<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a)<\/p>\n\n\n\n 20\/3= 6.2\/3<\/p>\n\n\n\n (b) <\/p>\n\n\n\n \u223411\/5= 2.1\/5<\/p>\n\n\n\n (c) <\/p>\n\n\n\n \u223417\/7= 2.3\/7<\/p>\n\n\n\n (d) <\/p>\n\n\n\n \u223428\/5=5.3\/5<\/p>\n\n\n\n (e) <\/p>\n\n\n\n 19\/6=3.1\/6<\/p>\n\n\n\n (f) <\/p>\n\n\n\n \u223435\/9=3.8\/9<\/p>\n\n\n\n 3. Express the following as improper fractions:<\/strong><\/p>\n\n\n\n (a)7.3\/4 <\/p>\n\n\n\n (b)5.6\/7 <\/p>\n\n\n\n (c)2.5\/6<\/p>\n\n\n\n (d)10.3\/5 <\/p>\n\n\n\n (e)9.3\/7 <\/p>\n\n\n\n (f)8.4\/9<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 7.3\/4 = {(7\u00d74)+3}\/4 = (28+3)\/4 = 31\/4<\/p>\n\n\n\n (b) 5.6\/7 = {(5\u00d77)+6}\/7 = (35+6)\/7 = 41\/7<\/p>\n\n\n\n (c) 2.5\/6 = {(2\u00d76)+5}\/6 = (12+5)\/6 =17\/6 <\/p>\n\n\n\n (d) 10.3\/5 = {(10\u00d75)+3}\/5 = (50+3)\/5 = 53\/5<\/p>\n\n\n\n (e) 9.3\/7 = {(9\u00d77)+3}\/7= (63+3)\/7 = 66\/7<\/p>\n\n\n\n (f) 8.4\/9 = {(8\u00d79)+4}\/9 = (72+4)\/9 = 76\/9<\/p>\n\n\n\n NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n 1. Write fractions. Are all these fractions equivalent: (b) <\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/2,2\/4,3\/6,4\/8<\/p>\n\n\n\n Yes, all of these fractions are equivalent.<\/p>\n\n\n\n (b) 4\/12,3\/9,2\/6,1\/3,6\/15<\/p>\n\n\n\n No, these fractions are not equivalent.<\/p>\n\n\n\n 2. Write the fraction and pair up the equivalent fractions to each row:<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/2 (b) 4\/6=2\/3 (c) 3\/9=1\/3 (d) 2\/8=1\/4 (e) 1\/4<\/p>\n\n\n\n (iii) 12\/16<\/p>\n\n\n\n 3. Replace __ in each of the following by the correct number: Answer<\/strong><\/p>\n\n\n\n (a) 2\/7 = 2\u00d74\/7\u00d74 = 8\/28 (e) 18\/24 = 18\u00f76\/24\u00f76 = 3\/4 Answer<\/strong><\/p>\n\n\n\n (a) 3\/5 =3\u00d74\/5\u00d74=12\/20 (d) 3\/5=3\u00d79\/5\u00d79=27\/45<\/p>\n\n\n\n 5. Find the equivalent fraction of 36\/48 with: Answer<\/strong><\/p>\n\n\n\n (a) 36\/48 = 36\u00f74\/48\u00f74 = 9\/12 6. Check whether the given fraction are equivalent: Answer<\/strong><\/p>\n\n\n\n (a) 5\/9,30\/54 = 5\u00d76\/9\u00d76,30\/54= 30\/54, 30\/54 (b) 3\/10,12\/50= 3\u00d75\/10\u00d75,12\/50= 15\/50,12\/50 (c) 7\/13,5\/11 = 7\u00d711\/13\u00d711,5\u00d713\/11\u00d713 = 77\/143,65\/143<\/p>\n\n\n\n Therefore, 7\/13,5\/11 are not equivalent fraction. Answer<\/strong><\/p>\n\n\n\n (a) 48\/60= (2\u00d72\u00d72\u00d72\u00d73)\/(2\u00d72\u00d73\u00d75) =4\/5 (e) 7\/28=7\/(2\u00d72\u00d77)= 1\/4<\/p>\n\n\n\n 8. Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check whether each has used an equal fraction of her\/his pencils?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Ramesh: Total pencils = 20 Since, all of them used half of their pencils, therefore each one of them used equal fraction of pencils.<\/p>\n\n\n\n 9. Match the equivalent fractions and write two more for each:<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (i) 250\/400=5\/8,10\/16,15\/24 (ii) 180\/200=9\/10,18\/20,27\/30 (iii) 660\/990=2\/3,4\/6,6\/96 (iv) 180\/360=1\/2,2\/4,3\/6 (v) 220\/550 = 2\/5, 4\/10, 6\/15 NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n 1. Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign \u2018<\u2019, \u2018>\u2019, \u2018=\u2019 between the fractions:<\/strong><\/p>\n\n\n\n (a) <\/p>\n\n\n\n (b) <\/p>\n\n\n\n (c) Show 2\/6,4\/6,8\/6 and 6\/6on the number line. Put appropriate signs between the fractions given:<\/p>\n\n\n\n 5\/6 – 2\/6, 3\/6 – 0<\/p>\n\n\n\n 1\/6 – 6\/6, 8\/6 – 5\/6<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 3\/8,6\/8,4\/8,1\/8<\/p>\n\n\n\n Ascending order: 1\/8<3\/8<4\/8<6\/8<\/p>\n\n\n\n Descending order: 6\/8>4\/8>3\/8>1\/8<\/p>\n\n\n\n (b) 8\/9,4\/9,3\/9,6\/9<\/p>\n\n\n\n Ascending order: 3\/9<4\/9<6\/9<8\/9<\/p>\n\n\n\n Descending order: 8\/9>6\/9>4\/9>3\/9<\/p>\n\n\n\n (c) Number line<\/p>\n\n\n\n 5\/6>2\/6 1\/6<6\/6<\/p>\n\n\n\n 3\/6>0\/6 8\/6>5\/6<\/p>\n\n\n\n 2. Compare the fractions and put an appropriate sign:<\/strong><\/p>\n\n\n\n (a) 3\/6 – 5\/6<\/p>\n\n\n\n (b) 1\/7 – 1\/4<\/p>\n\n\n\n (c) 4\/5 – 5\/5<\/p>\n\n\n\n (d) 3\/5 – 3\/7<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 3\/6<5\/6<\/p>\n\n\n\n (b) 1\/7<1\/4<\/p>\n\n\n\n (c) 4\/5<5\/5<\/p>\n\n\n\n (d) 3\/5>3\/7<\/p>\n\n\n\n 3. Make five more pairs and put appropriate signs.<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 9\/10>6\/10<\/p>\n\n\n\n (b) 1\/3>1\/6<\/p>\n\n\n\n (c) 1\/8<1\/5<\/p>\n\n\n\n (d) 7\/8<11\/8<\/p>\n\n\n\n (e) 11\/13>9\/13<\/p>\n\n\n\n 4. Look at the figures and write \u2018<\u2019 or \u2018>\u2019 between the given pairs of fractions:<\/strong><\/p>\n\n\n\n (a) 1\/6 _1\/3<\/p>\n\n\n\n (b) 3\/4 _ 2\/6<\/p>\n\n\n\n (c) 2\/3 _ 2\/4<\/p>\n\n\n\n (d) 6\/6 _ 3\/3<\/p>\n\n\n\n (e) 5\/6 _5\/5<\/p>\n\n\n\n Make five more such problems and solve them with your friends.<\/strong><\/p>\n\n\n\n Five more such problems:<\/strong><\/p>\n\n\n\n (a) 1\/2 _ 3\/6<\/p>\n\n\n\n (b) 2\/3 _ 3\/5<\/p>\n\n\n\n (c) 3\/4 _ 4\/6<\/p>\n\n\n\n (d) 5\/6 _ 2\/2<\/p>\n\n\n\n (e) 0\/1 _ 0\/6<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/6<1\/3<\/p>\n\n\n\n (b) 3\/4>2\/6<\/p>\n\n\n\n (c) 2\/3>2\/4<\/p>\n\n\n\n (d) 6\/6=3\/3<\/p>\n\n\n\n (e) 5\/6<5\/5<\/p>\n\n\n\n Five more such problems solution: <\/p>\n\n\n\n (a) 1\/2 = 3\/6<\/p>\n\n\n\n (b) 2\/3 > 3\/5<\/p>\n\n\n\n (c) 3\/4 > 4\/6<\/p>\n\n\n\n (d) 5\/6 < 2\/2<\/p>\n\n\n\n (e) 0\/1 = 0\/6<\/p>\n\n\n\n 5. How quickly can you do this? Fill the appropriate sign (<, =, >):<\/strong><\/p>\n\n\n\n (a) 1\/2 _ 1\/5<\/p>\n\n\n\n (b) 2\/4 _3\/6<\/p>\n\n\n\n (c) 3\/5 _ 2\/3<\/p>\n\n\n\n (d) 3\/4 _ 2\/8<\/p>\n\n\n\n (e) 3\/5 _ 6\/5<\/p>\n\n\n\n (f) 7\/9 _ 3\/9<\/p>\n\n\n\n (g) 1\/4 _ 2\/8<\/p>\n\n\n\n (h) 6\/10_ 4\/5<\/p>\n\n\n\n (i) 3\/4 _ 7\/8<\/p>\n\n\n\n (j) 6\/10 _ 4\/5<\/p>\n\n\n\n (k) 5\/7 _ 15\/21<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/2 > 1\/5<\/p>\n\n\n\n (b) 2\/4 = 3\/6<\/p>\n\n\n\n (c) 3\/5 < 2\/3<\/p>\n\n\n\n (d) 3\/4 > 2\/8<\/p>\n\n\n\n (e) 3\/5 < 6\/5<\/p>\n\n\n\n (f) 7\/9 > 3\/9<\/p>\n\n\n\n (g) 1\/4 = 2\/8<\/p>\n\n\n\n (h) 6\/10 < 4\/5<\/p>\n\n\n\n (i) 3\/4 < 7\/8<\/p>\n\n\n\n (j) 6\/10 < 4\/5<\/p>\n\n\n\n (k) 5\/7 = 15\/21<\/p>\n\n\n\n 6. The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form:<\/strong><\/p>\n\n\n\n (a) 2\/12<\/p>\n\n\n\n (b) 3\/15<\/p>\n\n\n\n (c) 8\/50<\/p>\n\n\n\n (d) 16\/100<\/p>\n\n\n\n (e) 10\/60<\/p>\n\n\n\n (f) 15\/75<\/p>\n\n\n\n (g) 12\/60<\/p>\n\n\n\n (h) 16\/96<\/p>\n\n\n\n (i) 12\/75<\/p>\n\n\n\n (j) 12\/72<\/p>\n\n\n\n (k) 3\/18<\/p>\n\n\n\n (l) 4\/25<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 2\/12=1\/6<\/p>\n\n\n\n (b) 3\/15=1\/5<\/p>\n\n\n\n (c) 8\/50=4\/25<\/p>\n\n\n\n (d) 16\/100=4\/25<\/p>\n\n\n\n (e) 10\/60=1\/6<\/p>\n\n\n\n (f) 15\/75=1\/5<\/p>\n\n\n\n (g) 12\/60=1\/5<\/p>\n\n\n\n (h) 16\/96=1\/6<\/p>\n\n\n\n (i) 12\/75=4\/25<\/p>\n\n\n\n (j) 12\/72=1\/6<\/p>\n\n\n\n (k) 3\/18=1\/6<\/p>\n\n\n\n (l) 4\/25=4\/25<\/p>\n\n\n\n Equivalent groups:<\/p>\n\n\n\n I group: 1\/5 [(b), (f), (g)]<\/p>\n\n\n\n II group: 1\/6 [(a), (e), (h), (j), (k)]<\/p>\n\n\n\n III group: 4\/25 [(c), (d), (i), (l)]<\/p>\n\n\n\n 7. Find answers to the following. Write and indicate how you solved them:<\/strong><\/p>\n\n\n\n (a) Is 5\/9 equal to 4\/5 ?<\/p>\n\n\n\n (b) Is 9\/16equal to 5\/9 ?<\/p>\n\n\n\n (c) Is 4\/5 equal to 16\/20 ?<\/p>\n\n\n\n (d) Is 1\/15 equal to 4\/30 ?<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a)5\/9 and 4\/5<\/p>\n\n\n\n \u21d2 5\u00d75\/9\u00d75 =25\/45 and 4\u00d79\/5\u00d79=36\/45 [\u2235 L.C.M. of 9 and 5 is 45]<\/p>\n\n\n\n Since, 25\/45\u226036\/45<\/p>\n\n\n\n Therefore, 5\/9\u22604\/5<\/p>\n\n\n\n (b) 9\/16 and 5\/9<\/p>\n\n\n\n \u21d2 9\u00d79\/16\u00d79= 81\/144 and 5\u00d716\/9\u00d716=80\/144 [\u2235 L.C.M. of 16 and 9 is 144]<\/p>\n\n\n\n Since, 81\/144\u226080\/144<\/p>\n\n\n\n Therefore, 9\/16\u22605\/9<\/p>\n\n\n\n (c) 4\/5 and 16\/20<\/p>\n\n\n\n \u21d2 4\u00d720\/ 5\u00d720=80\/100 and 16\u00d75\/20\u00d75=80\/100 [\u2235 L.C.M. of 5 and 20 is 100]<\/p>\n\n\n\n Since, 80\/100=80\/100<\/p>\n\n\n\n Therefore, 4\/5=16\/20<\/p>\n\n\n\n (d) 1\/15 and 4\/30<\/p>\n\n\n\n \u21d2 1\u00d721\/5\u00d72=2\/30 and 4\u00d71\/30\u00d71=4\/30 [\u2235 L.C.M. of 15 and 30 is 30]<\/p>\n\n\n\n Since, 2\/30\u22604\/30<\/p>\n\n\n\n Therefore,<\/p>\n\n\n\n 1\/15\u22604\/30<\/p>\n\n\n\n 8. Ila read 25 pages of a book containing 100 pages. Lalita read 2\/5 of the same book. Who read less?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Ila read 25 pages out of 100 pages.<\/p>\n\n\n\n Fraction of reading the pages = 25\/100=1\/4th part of book<\/p>\n\n\n\n Lalita read 2\/5th part of book = 40\/100 pages<\/p>\n\n\n\n Since 1\/4<2\/5<\/p>\n\n\n\n Therefore, Ila read less.<\/p>\n\n\n\n 9. Rafiq exercised for 3\/6 of an hour, while Rohit exercised for 3\/4 of an hour. Who exercised for a longer time?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Rafiq exercised 3\/6 of an hour.<\/p>\n\n\n\n Rohit exercised 3\/4 of an hour.<\/p>\n\n\n\n Since 3\/4>3\/6<\/p>\n\n\n\n Therefore, Rohit exercised for a longer time.<\/p>\n\n\n\n 10. In a class A of 25 students, 20 passed in first class; in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n In class A, 20 passed out of 25, i.e., 20\/25= 4\/5<\/p>\n\n\n\n In class B, 24 passed out of 30, i.e., 24\/30 = 4\/5<\/p>\n\n\n\n Hence, each class have same fraction of student getting first class.<\/p>\n\n\n\n NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n 1. Write the fractions appropriately as additions or subtractions<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/5+2\/5=(1+2)\/5= 3\/5<\/p>\n\n\n\n (b) 5\/5\u22123\/5=(5\u22123)\/5=2\/5<\/p>\n\n\n\n (c) 2\/6+3\/6=(2+3)\/6=5\/6<\/p>\n\n\n\n 2. Solve:<\/strong><\/p>\n\n\n\n (a) 1\/18+1\/18<\/p>\n\n\n\n (b) 8\/15+3\/15<\/p>\n\n\n\n (c) 7\/7\u22125\/7<\/p>\n\n\n\n (d) 1\/22+21\/22<\/p>\n\n\n\n (e) 12\/15\u22127\/15<\/p>\n\n\n\n (f) 5\/8+3\/8<\/p>\n\n\n\n (g) 1\u22122\/3(1=3\/3)<\/p>\n\n\n\n (h) 1\/4+0\/4<\/p>\n\n\n\n (i) 3\u221212\/5<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/18+1\/18=(1+1)\/18=2\/18=1\/9<\/p>\n\n\n\n (b) 8\/15+3\/15=(8+3)\/15=11\/15<\/p>\n\n\n\n (c) 7\/7\u22125\/7=(7\u22125)\/7=2\/7<\/p>\n\n\n\n (d) 1\/22+21\/22=(1+21)\/22=22\/22=1<\/p>\n\n\n\n (e) 12\/15\u22127\/15=(12\u22127)\/15=5\/15=1\/3<\/p>\n\n\n\n (f) 5\/8+3\/8=8\/8=1<\/p>\n\n\n\n (g) 1\u22122\/3=3\/3\u22122\/3=(3\u22122)\/2=1\/3<\/p>\n\n\n\n (h) 1\/4+0\/4=(1+0)\/4=1\/4<\/p>\n\n\n\n (i) 3\u221212\/5=15\/5\u221212\/5=(15\u221212)\/5=3\/5<\/p>\n\n\n\n 3. Shubham painted 2\/3 of the wall space in his room. His sister Madhavi helped and painted 1\/3 of the wall space. How much did they paint together?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Fraction of the wall painted by Shubham = 2\/3<\/p>\n\n\n\n Fraction of the wall painted by Madhavi = 1\/3<\/p>\n\n\n\n Total painting done by both of them = 2\/3+1\/3=(2+1)\/3= 3\/3=1<\/p>\n\n\n\n Therefore, they painted the wall completely. <\/p>\n\n\n\n 4. Fill in the missing fractions:<\/strong><\/p>\n\n\n\n (a) 7\/10\u2212 __ = 3\/10<\/p>\n\n\n\n (b) __ \u22123\/21 =5\/21 <\/p>\n\n\n\n (c) __ \u22123\/6=3\/6 <\/p>\n\n\n\n (d) __ +5\/27=12\/27<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 4\/10<\/p>\n\n\n\n (b) 8\/21<\/p>\n\n\n\n (c) 6\/6<\/p>\n\n\n\n (d) 7\/27<\/p>\n\n\n\n 5. Javed was given a basket of 7 oranges, He sold only 5 oranges. What fraction of oranges was left in the basket?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total = 1<\/p>\n\n\n\n Fraction of Orange left = 1\u22125\/7<\/p>\n\n\n\n = 7\/7\u22125\/7=7\u22125\/7=2\/7<\/p>\n\n\n\n Thus, 2\/7 oranges was left in the basket.<\/p>\n\n\n\n NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n 1. Solve:<\/strong><\/p>\n\n\n\n (a) 2\/3+1\/7<\/p>\n\n\n\n (b) 3\/10+7\/15<\/p>\n\n\n\n (c) 4\/9+2\/7<\/p>\n\n\n\n (d) 5\/7+1\/3<\/p>\n\n\n\n (e) 2\/5+1\/6<\/p>\n\n\n\n (f) 4\/5+2\/3<\/p>\n\n\n\n (g) 3\/4\u22121\/3<\/p>\n\n\n\n (h) 5\/6\u22121\/3<\/p>\n\n\n\n (i) 2\/3+3\/4+1\/2<\/p>\n\n\n\n (j) 1\/2+1\/3+1\/6<\/p>\n\n\n\n (k) 1.1\/3+3.2\/3<\/p>\n\n\n\n (l) 4.2\/3+3.1\/4<\/p>\n\n\n\n (m) 16\/5\u22127\/5<\/p>\n\n\n\n (n) 4\/3\u22121\/2<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) L.C.M. of 3 and 7 is 21<\/p>\n\n\n\n \u2234 2\/3+1\/7=(2\u00d77+1\u00d73)\/21=(14+3)\/21=17\/21<\/p>\n\n\n\n (b) L.C.M. of 10 and 15 is 30<\/p>\n\n\n\n \u2234 3\/10+7\/15=(3\u00d73+7\u00d72)\/30=(9+14)\/30=23\/30<\/p>\n\n\n\n (c) L.C.M. of 9 and 7 is 63<\/p>\n\n\n\n \u2234 4\/9+2\/7=(4\u00d77+2\u00d79)\/63=(28+18)\/63=46\/63<\/p>\n\n\n\n (d) L.C.M. of 7 and 3 is 21<\/p>\n\n\n\n \u2234 5\/7+1\/3=(5\u00d73+7\u00d71)\/21=(15+7)\/21=22\/21=1.1\/21<\/p>\n\n\n\n (e) L.C.M. of 5 and 6 is 30<\/p>\n\n\n\n \u2234 2\/5+1\/6=(2\u00d76+5\u00d71)\/30=(12+5)\/30=17\/30<\/p>\n\n\n\n (f) L.C.M. of 5 and 3 is 15<\/p>\n\n\n\n \u2234 4\/5+2\/345+23 = (4\u00d73+2\u00d75)\/15=(12+10)\/15=22\/15=1.7\/15<\/p>\n\n\n\n (g) L.C.M. of 4 and 3 is 12<\/p>\n\n\n\n \u2234 3\/4\u22121\/3=(3\u00d73\u22124\u00d71)\/12=(9\u22124)\/12=5\/12<\/p>\n\n\n\n (h) L.C.M. of 6 and 3 is 6<\/p>\n\n\n\n \u2234 5\/6\u22121\/3=(5\u00d71\u22122\u00d71)\/6=(5\u22122)\/6=3\/6=1\/2<\/p>\n\n\n\n (i) L.C.M. of 3, 4 and 2 is 12<\/p>\n\n\n\n \u2234 2\/3+3\/4+1\/2=(2\u00d74+3\u00d73+1\u00d76)\/12=(6+9+6)\/12=23\/12=1.11\/12<\/p>\n\n\n\n (j) L.C.M. of 2, 3, and 6 is 6<\/p>\n\n\n\n \u2234 1\/2+1\/3+1\/6=(1\u00d73+1\u00d72+1\u00d71)\/6= (3+2+1)\/6=6\/6=1<\/p>\n\n\n\n (k) L.C.M. of 3 and 3 is 3<\/p>\n\n\n\n \u2234 4\/3+11\/3=(4+11)\/3=15\/3=5<\/p>\n\n\n\n (l) L.C.M. of 3 and 4 is 12<\/p>\n\n\n\n \u2234 14\/3+13\/4=(14\u00d74+13\u00d73)\/12=(56+39)\/12=95\/12=7.11\/12<\/p>\n\n\n\n (m) L.C.M. of 5 and 5 is 5<\/p>\n\n\n\n \u2234 16\/5\u22127\/5=(16\u22127)\/5=9\/5=1.4\/5<\/p>\n\n\n\n (n) L.C.M. of 3 and 2 is 6<\/p>\n\n\n\n \u2234 4\/3\u22121\/2=(4\u00d72\u22121\u00d73)\/6= (8\u22123)\/6=5\/6<\/p>\n\n\n\n 2. Sarika bought 2\/5 meter of ribbon and Lalita 3\/4 meter of ribbon. What is the total length of the ribbon they bought?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Ribbon bought by Sarita = 2\/5 m and Ribbon bought by Lalita = 3\/4 m<\/p>\n\n\n\n Total length of the ribbon = 2\/5+3\/4= (2\u00d74+5\u00d73)\/20 [\u2235 L.C.M. of 5 and 4 is 20]<\/p>\n\n\n\n = (8+15)\/20=23\/20=1.3\/20 m<\/p>\n\n\n\n Therefore, they bought 1.3\/20 m of ribbon.<\/p>\n\n\n\n 3. Naina was given 1.1\/2piece of cake and Najma was given 1.1\/3piece of cake. Find the total amount of cake given to both of them.<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Cake taken by Naina = 1.1\/2 piece and Cake taken by Najma = 1.1\/3 piece<\/p>\n\n\n\n Total cake taken = 1.1\/2+ 1.1\/3= 3\/2+4\/3 = (3\u00d73+4\u00d72) [\u2235 L.C.M. of 2 and 3 is 6]<\/p>\n\n\n\n = (9+8)\/6=17\/6=25\/6<\/p>\n\n\n\n Therefore total consumption of cake is 25\/6.<\/p>\n\n\n\n 4. Fill in the boxes:<\/strong><\/p>\n\n\n\n (a) ___ \u22125\/8=1\/4 <\/p>\n\n\n\n (b)__ \u22121\/5=1\/2 <\/p>\n\n\n\n (c) 1\/2\u2212 __=1\/6<\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n (a) 1\/4+5\/8=(2+5)\/8=7\/8<\/p>\n\n\n\n (b) 1\/2+1\/5=(5+2)\/10=7\/10<\/p>\n\n\n\n (c) 1\/2\u22121\/6=(3\u22121)\/6=2\/6<\/p>\n\n\n\n 5. Complete the addition \u2013 subtraction box:<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n 6. A piece of wire 7\/8meter long broke into two pieces. One piece was 1\/4 meter long. How long is the other piece?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total length of wire = 7\/8 meter<\/p>\n\n\n\n Length of first part = 1\/4 meter<\/p>\n\n\n\n Remaining part = 7\/8\u22121\/4=(7\u00d71\u22122\u00d71)\/8 [\u2235 L.C.M. of 8 and 4 is 8]<\/p>\n\n\n\n = (7\u22122)\/8=5\/8meter<\/p>\n\n\n\n Therefore, the length of the remaining part is 5\/8 meter.<\/p>\n\n\n\n 7. Nandini house is 9\/10 km from her school. She walked some distance and then took a bus for 1\/2 km to reach the school. How far did she walk?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Total distance between the school and house = 9\/10 km<\/p>\n\n\n\n Distance covered by bus = 1\/2 km<\/p>\n\n\n\n Remaining distance = 9\/10\u22121\/2=(9\u00d71\u22121\u00d75)\/10 [\u2235 L.C.M. of 10 and 2 is 10]<\/p>\n\n\n\n = (9\u22125)\/10=4\/10=2\/5 km<\/p>\n\n\n\n Therefore, distance covered by walking us 2\/5 km.<\/p>\n\n\n\n 8. Asha and Samuel have bookshelves of the same size partly filled with books. Asha\u2019s shelf is 5\/6th full and Samuel\u2019s shelf is 2\/5th full. Whose bookshelf is more filled and by what fraction?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n 5\/6 and 2\/5<\/p>\n\n\n\n \u21d2 5\/6\u00d75\/5=25\/30 and 2\/5\u00d76\/6=12\/30 [\u2235 L.C.M. of 6 and 5 is 30]<\/p>\n\n\n\n \u2235 25\/30>12\/30 \u21d2 5\/6>2\/5<\/p>\n\n\n\n \u2234 Asha\u2019s bookshelf is more covered than Samuel.<\/p>\n\n\n\n Difference = 25\/30\u221212\/30=13\/30<\/p>\n\n\n\n 9. Jaidev takes 2.1\/5 minutes to walk across the school ground. Rahul takes 7\/4 minutes to do the same. Who takes less time and by what fraction?<\/strong><\/p>\n\n\n\n Answer<\/strong><\/p>\n\n\n\n Time taken by Jaidev = 2.1\/5 minutes = 11\/5minutes<\/p>\n\n\n\n Time taken by Rahul = 7\/4 minutes<\/p>\n\n\n\n Difference = 11\/5\u22127\/4= (11\u00d74\u22127\u00d75)\/20 [\u2235 L.C.M. of 5 and 4 is 20]<\/p>\n\n\n\n = (44\u221235)\/20=9\/20 minutes<\/p>\n\n\n\n Thus, Rahul takes less time, which is 9\/20 minutes.<\/p>\n\n\n\n NCERT 6th Maths Chapter 7, class 6 Maths Chapter 7 solutions<\/p>\n\n\n\n NCERT Solutions for 6th Class Maths: Chapter 7-Fractions<\/p>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_02.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_03.png\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_19.jpg\")
<\/figure>\n\n\n\n![](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_05.jpg\")
<\/p>\n\n\n\n
All the figures are not equally divided. For making fractions, it is necessary that figure is divided into equal parts.<\/p>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_06.jpg\")
<\/figure>\n\n\n\nExercise 7.2<\/h2>\n\n\n\n
![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_20.png\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_a.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_b.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_c.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_d.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_e.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/4370_2_f.jpg\")
<\/figure>\n\n\n\nExercise 6.3<\/h4>\n\n\n\n
<\/strong>(a) <\/p>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_07.png\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_08.png\")
<\/figure>\n\n\n\n
(ii) 4\/8=1\/2<\/p>\n\n\n\n
(iv) 8\/12=2\/3<\/p>\n\n\n\n
(i) 6\/18=1\/3<\/p>\n\n\n\n
(v) 4\/16=1\/4<\/p>\n\n\n\n
(a) 2\/7=8\/__
(b) 5\/8=10\/__
(c) 3\/5= __\/20
(d) 45\/60=15\/__
(e) 18\/24=__\/ 4<\/strong><\/p>\n\n\n\n
(b) 5\/8 = 5\u00d72\/8\u00d72 = 10\/16
(c) 3\/5 = 3\u00d74\/5\u00d74 = 12\/20
(d) 45\/60 = 45\u00f73\/60\u00f73=15\/20<\/p>\n\n\n\n
4. Find the equivalent fraction of 3\/5 having:
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27<\/strong><\/p>\n\n\n\n
(b) 3\/5=3\u00d73\/5\u00d73=9\/15
(c) 3\/5=3\u00d76\/5\u00d76=18\/30<\/p>\n\n\n\n
(a) numerator 9
(b) denominator 4<\/strong><\/p>\n\n\n\n
(b) 36\/48 = 36\u00f712\/48\u00f712 = 3\/4<\/p>\n\n\n\n
(a) 5\/9,30\/54
(b) 3\/10,12\/50
(c)7\/13,5\/11<\/strong><\/p>\n\n\n\n
Therefore, 5\/9,30\/54 are equivalent.<\/p>\n\n\n\n
Therefore, 3\/10,12\/50 are not equivalent.<\/p>\n\n\n\n
7. Reduce the following fractions to simplest form:
(a) 48\/60
(b) 150\/60
(c) 84\/98
(d) 12\/52
(e) 7\/28<\/strong><\/p>\n\n\n\n
(b) 150\/60= (3\u00d75\u00d710)\/(2\u00d73\u00d710)= 5\/2
(c) 84\/98= (2\u00d73\u00d714)\/(7\u00d714) = 6\/7
(d) 12\/52= (2\u00d72\u00d73)\/(2\u00d72\u00d713) =3\/13<\/p>\n\n\n\n
Pencils used = 10
Fraction = 10\/20 =1\/2
Sheelu: Total pencils = 50
Pencils used = 25
Fraction = 25\/50=1\/2
Jamaal: Total pencils = 80
Pencils used = 40
Fraction = 40\/80= 1\/2<\/p>\n\n\n\n(i)250\/400
<\/td>(a) 2\/3
<\/td><\/tr>(ii)180\/200
<\/td>(b) 2\/5
<\/td><\/tr>(iii)660\/990
<\/td>(c) 1\/2
<\/td><\/tr>(iv)180\/360
<\/td>(d) 5\/8
<\/td><\/tr>(v)220\/550
<\/td>(e) 9\/10
<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
(d) 5\/8<\/p>\n\n\n\n
(e) 9\/10<\/p>\n\n\n\n
(a) 2\/3<\/p>\n\n\n\n
(c)1\/2<\/p>\n\n\n\n
(b) 2\/5<\/p>\n\n\n\nExercise 7.4<\/h4>\n\n\n\n
![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_11.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_12.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_21.png\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_23.jpg\")
<\/figure>\n\n\n\nExercise 7.5<\/h4>\n\n\n\n
![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_24.jpg\")
<\/figure>\n\n\n\nExercise 7.6<\/h4>\n\n\n\n
![\"\"\/](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_18.jpg\")
<\/figure>\n\n\n\n![\"NCERT](\"https:\/\/www.indcareer.com\/schools\/wp-content\/uploads\/2021\/02\/06_math_ncert_ch07_22.jpg\")
<\/figure>\n\n\n\nNCERT Solutions for 6th Class Maths: Chapter 7: Download PDF<\/strong><\/h2>\n\n\n\n