{"id":158950,"date":"2021-02-23T11:35:45","date_gmt":"2021-02-23T11:35:45","guid":{"rendered":"https:\/\/www.indcareer.com\/schools\/?p=158950"},"modified":"2023-09-14T05:33:53","modified_gmt":"2023-09-14T05:33:53","slug":"ncert-solutions-for-6th-class-maths-chapter-2-whole-numbers","status":"publish","type":"post","link":"https:\/\/www.indcareer.com\/schools\/ncert-solutions-for-6th-class-maths-chapter-2-whole-numbers\/","title":{"rendered":"NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers"},"content":{"rendered":"\n

Class 6: Maths Chapter 2 solutions. Complete Class 6 Maths Chapter 2 Notes.<\/p>\n\n\n\n

NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers<\/strong><\/h2>\n\n\n\n

NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions<\/p>\n\n\n\n

Page No: 31<\/p>\n\n\n\n

Exercise 2.1<\/h4>\n\n\n\n

1. Write the next three natural numbers after 10999.<\/strong><\/p>\n\n\n\n


Answer<\/strong><\/p>\n\n\n\n

11000 , 11001, 11002<\/p>\n\n\n\n

2. Write the three whole numbers occurring just before 10001.<\/strong><\/p>\n\n\n\n


Answer<\/strong><\/p>\n\n\n\n

10000, 9999,9998<\/p>\n\n\n\n

3. Which is the smallest whole number?<\/strong><\/p>\n\n\n\n


Answer<\/strong><\/p>\n\n\n\n

0 is the smallest whole number.<\/p>\n\n\n\n

4. How many whole numbers are there between 32 and 53?<\/strong><\/p>\n\n\n\n

(33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52)<\/p>\n\n\n\n

There are 20 whole numbers lie between 32 and 53.<\/p>\n\n\n\n

5. Write the successor of :
(a) 2440701
(b) 100199
(c) 1099999
(d) 2345670<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

a) 2440701 = 2440701 + 1 = 2440702.<\/p>\n\n\n\n

b) 100199 = 100199 + 1 = 100200<\/p>\n\n\n\n

c) 1099999 = 1099999 + 1 = 1100000<\/p>\n\n\n\n

d) 2345670 = 2345670 + 1 = 2345671<\/p>\n\n\n\n

6. Write the predecessor of :
(a) 94
(b) 10000
(c) 208090
(d) 7654321<\/strong>

Answer<\/strong><\/p>\n\n\n\n

(a) 94 = 94 \u2013 1 = 93<\/p>\n\n\n\n

(b) 10000 = 10000 \u2013 1= 9999<\/p>\n\n\n\n

(c) 208090 = 208090 \u2013 1 = 208089<\/p>\n\n\n\n

(d) 7654321 = 7654321 \u2013 1 = 76543210<\/p>\n\n\n\n

7. In each of the following pairs of numbers, state which whole number is on the left of the other number on the number line. Also write them with the appropriate sign (>,< ) between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 530 > 503
530 is on the left side of number line.<\/p>\n\n\n\n

(b) 370 > 307
370 is on the left side of number line.<\/p>\n\n\n\n

(c) 98765 > 56789
98765 is on the left side of the number line<\/p>\n\n\n\n

(d) 9830415 < 10023001
10023001 is the left side of the number line.<\/p>\n\n\n\n

8. Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor of 399.
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.<\/strong>
Answer<\/strong><\/p>\n\n\n\n

(a) 0 is not a natural number (false)<\/p>\n\n\n\n

(b) Predecessor of 399 is 398 (false)<\/p>\n\n\n\n

(c) True<\/p>\n\n\n\n

(d) 599 + 1 = 600 (true)<\/p>\n\n\n\n

(e) True<\/p>\n\n\n\n

(f) 0 is whole number but not natural numbers.(false)<\/p>\n\n\n\n

(g) False<\/p>\n\n\n\n

(h) 0 is the smallest whole number (false)<\/p>\n\n\n\n

(i) True<\/p>\n\n\n\n

(j) False<\/p>\n\n\n\n

(k) False<\/p>\n\n\n\n

(l) True<\/p>\n\n\n\n

(m) False<\/p>\n\n\n\n

Page No: 40

Exercise 2.2<\/strong>

1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n


(a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408<\/p>\n\n\n\n

(b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (647 + 453)
= 3500 + 1100 = 4600

2. Find the product by suitable rearrangement:
(a) 2 \u00d7 1768 \u00d7 50
(b) 4 \u00d7 166 \u00d7 25
(c) 8 \u00d7 291 \u00d7 125
(d) 625 \u00d7 279 \u00d7 16
(e) 285 \u00d7 5 \u00d7 60
(f) 125 \u00d7 40 \u00d7 8 \u00d7 25<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 2 \u00d7 50 \u00d7 1768 = 176,800<\/p>\n\n\n\n

(b) 166 \u00d7 25 \u00d7 4 = 16600<\/p>\n\n\n\n

(c) 291 \u00d7 125 \u00d7 8 = 291000<\/p>\n\n\n\n

(d) 285 \u00d7 60 \u00d7 5 = 2790000<\/p>\n\n\n\n

(e) 285 \u00d7 60 \u00d7 3 = 85500<\/p>\n\n\n\n

(f) 125 \u00d7 40 \u00d7 25 \u00d7 8 = 1000000<\/p>\n\n\n\n

3. Find the value of the following:
(a) 297 \u00d7 17 + 297 \u00d7 3
(b) 54279 \u00d7 92 + 8 \u00d7 54279
(c) 81265 \u00d7 169 \u2013 81265 \u00d7 69
(d) 3845 \u00d7 5 \u00d7 782 + 769 \u00d7 25 \u00d7 218<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 297 \u00d7 (17 + 3 ) = 297 \u00d7 20 = 5940.<\/p>\n\n\n\n

(b) 54279 \u00d7 (92 + 8)
= 54279 \u00d7 100 = 5427900.<\/p>\n\n\n\n

(c) 81265 \u00d7 (169 \u2013 69)
81265 \u00d7 100 = 8126500<\/p>\n\n\n\n

(d) 3845 \u00d7 5 \u00d7 782 + 769 \u00d7 5 \u00d7 5 \u00d7 218
= 3845 \u00d7 5 \u00d7 (782 + 218)
= 19225 \u00d7 1000 = 19225000.<\/p>\n\n\n\n

4. Find the product using suitable properties.
(a) 738 \u00d7 103
(b) 854 \u00d7 102
(c) 258 \u00d7 1008
(d) 1005 \u00d7 168<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 738 \u00d7 103
= (738 \u00d7 100) + (738 \u00d7 3)
= 73800 + 2214 = 76014<\/p>\n\n\n\n

(b) 854 \u00d7 102
= (854 \u00d7 100) + (854 \u00d7 2)
= 85400 + 1708 = 87108<\/p>\n\n\n\n

(c) 258 \u00d7 1008
= (258 \u00d7 1000) + (258 \u00d7 8)
= 258000 + 2064 = 260064<\/p>\n\n\n\n

(d) 1005 \u00d7 168 = (1000 + 5) \u00d7 168
= (1000 \u00d7 168) + (5 \u00d7 168)
= 168000 + 840 = 168840<\/p>\n\n\n\n

5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?
<\/strong>
Answer<\/strong><\/p>\n\n\n\n

Petrol filled on Monday = 40 litres
Petrol next day filled = 50 litres
Total quantity of petrol filled = (40 +50) litres
Cost of petrol per litres = 44<\/p>\n\n\n\n

Total amount of money spent on petrol = 44 \u00d7 (40 + 50)
= 44 \u00d7 90 = Rs 3960<\/p>\n\n\n\n

Page No: 41<\/p>\n\n\n\n

6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day?<\/strong><\/p>\n\n\n\n

Answer <\/strong><\/p>\n\n\n\n

In the morning vendor supplies = 32 litres.
In the evening vendor supplies = 68 litres.
Cost of milk per litre = Rs 15
Total cost of per day = 15 \u00d7 ( 32 + 68)
= 15 \u00d7 100 = Rs 1500<\/p>\n\n\n\n

7. Match the following:<\/strong><\/p>\n\n\n\n

\"\"\/<\/figure>\n\n\n\n

Answer<\/strong>
(i) \u279d C
(ii) \u279d A<\/p>\n\n\n\n

(iii) \u279d B<\/p>\n\n\n\n

Page No: 43<\/p>\n\n\n\n

Exercise  2.3<\/strong><\/p>\n\n\n\n

1. Which of the following will not represent zero: <\/strong><\/p>\n\n\n\n

(a) 1 + 0<\/strong><\/p>\n\n\n\n

(b) 0 \u00d7 0 <\/strong><\/p>\n\n\n\n

(c) 0 \/ 2<\/strong><\/p>\n\n\n\n

(d) (10 – 10)\/2<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 1 + 0 =  1 (not represent zero)<\/p>\n\n\n\n

(b) 0 \u00d7 0 = 0 (it represent  zero)<\/p>\n\n\n\n

(c) 0 \/ 2 = 0 (it represent zero)<\/p>\n\n\n\n

(d) (10 \u2013 10)\/ 2 = 0 (it represent zero)<\/p>\n\n\n\n

2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

Product of two whole number is zero then both of them may be zero  <\/p>\n\n\n\n

0 \u00d7 3 =0<\/p>\n\n\n\n

1 \u00d7 3 = 3<\/p>\n\n\n\n

3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

Product of two whole number is 1 , both number is equal to 1.<\/p>\n\n\n\n

For example , 1 \u00d7 1 = 1 , 1 \u00d7 6 = 6<\/p>\n\n\n\n

In both example, number is multiplied by 1.<\/p>\n\n\n\n

4. Find using distributive property : <\/strong><\/p>\n\n\n\n

(a) 728 \u00d7 101 <\/strong><\/p>\n\n\n\n

(b) 5437 \u00d7 1001<\/strong><\/p>\n\n\n\n

(c) 824 \u00d7 25 <\/strong><\/p>\n\n\n\n

(d) 4275 \u00d7 125<\/strong><\/p>\n\n\n\n

(e) 504 \u00d7 35<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

(a) 728 \u00d7 101 <\/p>\n\n\n\n

= (728 \u00d7 100) + (728 \u00d7 1)<\/p>\n\n\n\n

= 72800 + 728 <\/p>\n\n\n\n

= 73528<\/p>\n\n\n\n

(b) 5437 \u00d7 1001<\/p>\n\n\n\n

= (5437 \u00d7 1000) + (5437 \u00d7 1)<\/p>\n\n\n\n

= 5437000 + 5437<\/p>\n\n\n\n

= 5442437<\/p>\n\n\n\n

(c) 824 \u00d7 25<\/p>\n\n\n\n

= (800 + 24) \u00d7 25<\/p>\n\n\n\n

= (800 + 25 \u2013 1) \u00d7 25<\/p>\n\n\n\n

= (800 \u00d7 25) + ( 25 \u00d7 25) \u2013 (1 \u00d7 25)<\/p>\n\n\n\n

= (20000 \u00d7 (625 \u2013 25)<\/p>\n\n\n\n

= 20000 + 600 = 20600<\/p>\n\n\n\n

(d) 4275 \u00d7 125<\/p>\n\n\n\n

= (4000 + 25 + 200 + 50) \u00d7 (100 + 25)<\/p>\n\n\n\n

= (4000\u00d7100) + (25\u00d7100) + (200\u00d7100) + (50\u00d7100) + (4000\u00d725) + (25\u00d725) + (200\u00d725) + (50\u00d725)<\/p>\n\n\n\n

= 400000 + 2500 + 20000 + 5000 + 100000 + 625 + 5000 + 1250<\/p>\n\n\n\n

= 534375<\/p>\n\n\n\n

(e) 504 \u00d7 35<\/p>\n\n\n\n

= (500 + 4) \u00d7 35 <\/p>\n\n\n\n

= (500 \u00d7 35) + (4 \u00d7 35) <\/p>\n\n\n\n

= 17500 + 140 = 17640<\/p>\n\n\n\n

5. Study the pattern : 1 \u00d7 8 + 1 = 9<\/strong><\/p>\n\n\n\n

1234 \u00d7 8 + 4 = 9876 <\/strong><\/p>\n\n\n\n

12 \u00d7 8 + 2 = 98 <\/strong><\/p>\n\n\n\n

12345 \u00d7 8 + 5 = 98765 <\/strong><\/p>\n\n\n\n

123 \u00d7 8 + 3 = 987 <\/strong><\/p>\n\n\n\n

Write the next two steps. Can you say how the pattern works? (Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).<\/strong><\/p>\n\n\n\n

Answer<\/strong><\/p>\n\n\n\n

123456 \u00d7 8 + 6 = 987648 + 6 = 987654<\/p>\n\n\n\n

1234567 \u00d7 8 + 7 = 9876536 + 7 = 9876543<\/p>\n\n\n\n

Pattern are use in following ways<\/p>\n\n\n\n

123456 = 123456 \u00d7 8 (111111+11111+1111+111+11+1) \u00d7 8<\/p>\n\n\n\n

= 111111 \u00d7 8 + 11111 \u00d7 8 +1111 \u00d7 8 + 111 \u00d7 8 + 11 \u00d7 8 + 1\u00d7 8<\/p>\n\n\n\n

= 888888 + 88888 +8888 +888 +88 + 8 = 987648<\/p>\n\n\n\n

123456 \u00d7 8 +6 = 987648 + 6 = 987654<\/p>\n\n\n\n

NCERT 6th Maths Chapter 2, class 6 Maths Chapter 2 solutions<\/p>\n\n\n\n

NCERT Solutions for 6th Class Maths: Chapter 2: Download PDF<\/strong><\/h2>\n\n\n\n

NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers<\/p>\n\n\n\n

Download PDF<\/strong>: NCERT Solutions for 6th Class Maths: Chapter 2-Whole Numbers PDF<\/a><\/p>\n\n\n\n

Chapterwise NCERT Solutions for Class 6 Maths :<\/strong><\/h2>\n\n\n\n