Solution:
Let the point at which the charged particle enters the electric field, be origin O (0, 0), then after travelling a horizontal displacement L, it gets deflected by displacement y in vertical direction as it comes out of electric field. So, co-ordinates of its initial position are x1 = 0 and y1 = 0 and final position on coming out of electric field are

and of initial velocity are ux = vx and uy = 0 so, by 2nd equation of motion in horizontal direction,

This gives the vertical deflection of the particle at the far edge of the plate.
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NCERT Solutions for 12th Class Physics: Chapter 1-Electric Charges And Fields